Multi-digit Numerical Long Division 1 © 2013 Meredith S. Moody.
-
Upload
kelly-perkins -
Category
Documents
-
view
216 -
download
1
Transcript of Multi-digit Numerical Long Division 1 © 2013 Meredith S. Moody.
1
The Number SystemMulti-digit Numerical Long Division
© 2013 Meredith S. Moody
2
Divide numbers with 2 or more digits using a variety of methods for long division
Divide numbers with 2 or more digits using the standard algorithm for long division
Objective: You will be able to…
© 2013 Meredith S. Moody
3
Division is determining how many groups of one number can be made out of another number
For example, I have the number 15 and I want to make 3 groups; how many will be in each group? The answer would be 5
That is the same as dividing 15 by 3
What is division?
© 2013 Meredith S. Moody
4
What if there are not a whole number of groups?
Let’s say I have 15 cookies and I want to make 4 bags (equal groups) of cookies.
If I divide 15 into 4 equal groups, I would have 3 cookies in each bag, but I would have 3 cookies left over.
3 cookies would ‘remain’ In other words, 3 is my remainder if I want
to divide 15 by 4
Remainders
© 2013 Meredith S. Moody
5
Mathematical operations come in pairs Which operations do you think are pairs? Addition and subtraction are a pair Multiplication and division are a pair In order to divide, you have to understand
multiplication
Inverse operations
© 2013 Meredith S. Moody
6
Multiplication is repeated addition◦ 3 x 5 = 15◦ 3 + 3 + 3 + 3 + 3 = 15
Division is repeated subtraction◦ 15 ÷ 5 = 3 (3 groups of 5, none left over)◦ 15 – 5 – 5 – 5 = 0
Relationships
© 2013 Meredith S. Moody
7
If I have 15 cookies and want to make 5 equal bags of cookies, there must be 3 cookies in each bag
I can make 5 bags of 3 cookies. 5 x 3 = 15 15 ÷ 3 = 5 15 ÷ 5 = 3 Division and multiplication are inverse
operations
How dividing & multiplying are related
© 2013 Meredith S. Moody
8
What happens if the numbers are too large to divide mentally?
What if I want to divide 487 by 32? How could I do that? I could use a calculator, yes, but what if I
don’t have one? Let’s look at three different methods of
dividing by hand◦ Repeated subtraction◦ Standard algorithm◦ Scaffold division
Example 1
© 2013 Meredith S. Moody
9
Division is actually repeated subtraction How many times can I subtract 32 from
487? 487–32=455–32=423–32=391–32=359
359-32=327-32=295-32=263-32=321 321-32=199-32=167-32=135-32=103 103-32=71-32=39-32=7
How many times did we subtract 32? 15 How many is left over? 7 Wow! That took a long time. Is there
another way?
Example 1, repeated subtraction
© 2013 Meredith S. Moody
10
An “algorithm” is a step-by-step procedure for calculations
We can use a division algorithm for multi-digit division
In this method, there are specific parts with universal names
Knowing these names are important so everyone can discuss division without becoming confused
Standard algorithm
© 2013 Meredith S. Moody
11
The division bracket is the “box” into which we put the dividend
© 2013 Meredith S. Moody
Example 1, standard algorithm, continued
12
487 is the dividend, it goes in the “box”
32 is the divisor, it goes outside the “box”
The answer is called the “quotient”
The left over amount is called the “remainder”
Example 1, standard algorithm, continued
© 2013 Meredith S. Moody
13
The most efficient way to divide multi-digit numbers by hand is called ‘long division’
How many groups of 32 are in the number 4? 0. 32x0=0. subtract 4-0=4. ‘Bring down’ the next digit (8)
How many groups of 32 are in the number 48? 1. 32x1=32. subtract 48-32=16. ‘Bring down’ the next digit (7)
How many groups of 32 are in the number 167? 32x5=160. subtract 167-160=7
Example 1, standard algorithm, continued
© 2013 Meredith S. Moody
14
Wow, that standard algorithm doesn’t make sense to me
Is there another way? Yes Instead of trying to divide 487 by 32, we
can break up our steps into smaller chunks This is called scaffold division
Example 1, scaffold division
© 2013 Meredith S. Moody
15
We can break up large numbers using the place value system
487 becomes 400+80+7 How many groups of 32 can I make out of
400? Well, I know 3x4=12; I should be able to make about 12 groups of 32 out of 400
Well, if I make 12 groups of 32, how much of the 400 have I ‘used’? 12x32=384
How much of the 400 do I still have to ‘use’? 400-384=16; I have 16 ‘left over’
Example 1, scaffold division, continued
© 2013 Meredith S. Moody
16
Now I work with the number 80 How many groups of 32 can I make out of
the number 80? I know 3x3=9, but 90 is too much; I should
be able to make 2 groups of 32 out of 80 If I make 2 groups of 32, how much of the
80 have I ‘used’? 32x2=64 How much do I have left to ‘use’? 80-
64=16; I have 16 ‘left over’
Example 1, scaffold division, continued
© 2013 Meredith S. Moody
17
Now I have to look at the number 7 How many groups of 32 can I make out of 7? None Let’s use our ‘leftovers’ I had 16 left over from the 400, 16 left over
from the 80, and 7 left over from my original work
16 + 16 + 7 = 39 How many groups of 32 can I make out of 39? I can make 1 group of 32 out of 39, with 7 left
over
Example 1, scaffold division, continued
© 2013 Meredith S. Moody
18
Now I just add my groups together: I had 12 groups in the 400 I had 2 groups in the 80 I had 1 group in the ‘leftovers’ 12+2+1=15 I have 7 ‘left over’ now, so the answer to my
problem: what is 487÷32, is 15 remainder 7 That was a little hard to follow; is there an
easier way to write this? Yes
Example 1, scaffold division, continued
© 2013 Meredith S. Moody
19
Let’s put our scaffold method into an easy-to-read structure:
487 = 400 + 80 + 7 400÷32 = 12
◦ 32 x 12 = 384◦ 400-384 = 16
80÷32 = 2◦ 32 x 2 = 64
◦ 80-64 = 16 7÷32 = 0 16+16+7 = 39 39÷32 = 1
◦ 32 x 1 + 32◦ 39-32 = 7
12+2+1 = 15 487÷32 = 15 r7
Example 1, scaffold division, visual
© 2013 Meredith S. Moody
20
The scaffold method took quite a while, too Is there a more efficient way to scaffold? Yes
Example 1, efficient scaffold division
© 2013 Meredith S. Moody
21
Let’s try another together Two individuals are to equally share an
inheritance of $860. How much should each receive?
To solve the problem, we want to divide 860 by 2
Let’s look at the three ways we could solve (no calculators!)
Example 2
© 2013 Meredith S. Moody
22
Trying to repeatedly subtract 2 from 860 would take a LONG time
It makes sense to use a faster method
Example 2, repeated subtraction
© 2013 Meredith S. Moody
23
Let’s use the extended scaffold division method
First, we break up 860 using place values:
800 + 60 = 860 We can easily divide 800
by 2. 800÷2=400. Each person would get
$400 so far 400+400=800. Since we
have ‘used’ $800, we subtract 860-800 = 60. We still have $60 to share.
Example 2, scaffold division
© 2013 Meredith S. Moody
24
Next, we share the $60. Dividing $60 by 2 is easy.
Each person would get $30.
We need to add another 30 to our quotient.
Notice we place the 30 in the proper place value above the 400. We have ‘used’ the last $60, 60-60 = 0.
We have no money left to share.
Example 2, scaffold division, continued
© 2013 Meredith S. Moody
25
The last step is to sum the two partial quotients to obtain the final quotient 400+30=$430
Each person would each receive $430
Example 2, scaffold division, continued
© 2013 Meredith S. Moody
26
Let’s use the standard algorithm
The dividend is 860 The divisor is 2 There are 4 groups of 2
in 8 ‘bring down’ the 6 There are 3 groups of 2
in 6 ‘bring down’ the 0 There are 0 groups of 2
in 0 The quotient is 430
Example 2, standard algorithm
© 2013 Meredith S. Moody
27
What if we had three people and they needed to split $986 evenly among them?
Repeated subtraction would take too long The extended scaffold division method
would take a long time, too Let’s start with the efficient scaffold division
method
Example 3
© 2013 Meredith S. Moody
28
Example 3, scaffold division How much money
would each person receive if 3 people had to split $986 evenly?
Each person would receive $328
There would be $2 left over
© 2013 Meredith S. Moody
29
Let’s use the standard algorithm to solve
Example 3, standard algorithm
© 2013 Meredith S. Moody
30
If 14 children had 239 cookies, what is the highest number of cookies each child could receive if each one had to have the same number?
Repeated subtraction would take too long. The extended scaffold method would take
too long Let’s start with the efficient scaffold method
and then try the standard algorithm
Example 4
© 2013 Meredith S. Moody
31
Example 4, efficient scaffold division
© 2013 Meredith S. Moody
239 ÷ 14 = 17 r 1
Each child would receive 17 cookies
There would be 1 cookie left over
32
Example 4, standard algorithm
© 2013 Meredith S. Moody
33
Use either the traditional scaffold division, efficient scaffold division, or standard algorithm method to solve: 236÷4
You try
© 2013 Meredith S. Moody
34
Traditional scaffold solution
© 2013 Meredith S. Moody
35
Efficient scaffold solution
© 2013 Meredith S. Moody
36
Standard algorithm solution
© 2013 Meredith S. Moody
37
Use any long division method (repeated subtraction, standard, scaffold, or extended scaffold) to solve 193 ÷ 11
Repeated subtraction solution: 193-11=182-11=171-11=160-11=149-11=138
138-11=127-11=116-11=105-11=94-11=83-11=72 72-11=61-11=50-11=39-11=28-11=17-11=6
17 remainder 6
You try
© 2013 Meredith S. Moody
38
Traditional scaffold solution
© 2013 Meredith S. Moody
39
Efficient scaffold solution
© 2013 Meredith S. Moody
40
Standard algorithm solution
© 2013 Meredith S. Moody