MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 –...
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Transcript of MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 –...
MTH 065Elementary
Algebra IIChapter 6 – Polynomial Factorizations
and Equations
Section 6.1 – Introduction to Polynomial Factorizations and Equations
Polynomial Equations
Definition An equation that states that two
polynomials are equal to each other. Standard Form
p(x) = 0 Combine like terms Terms from highest to lowest degree Leading coefficient positive
Degree of a Polynomial Equation Degree of the leading coefficient when in
standard form.
Polynomial Equations
Solution A value for the variable that makes the
equation true.
Solution Set Set of all solutions.
Fundamental Theorem of Algebra An nth degree polynomial equation will
have at MOST n solutions.
Polynomial Equations – Examples
2x – 5 = 13 Standard form: 2x – 18 = 0 Degree 1 (linear) Solution: x = 9
x2 + 2x = 5x – 2 Standard form: x2 – 3x + 2 = 0 Degree 2 (quadratic) Solutions: x = 1, 2
x3 + 3 = 5x – x2
Standard form: x3 + x2 – 5x + 3 = 0 Degree 3 (cubic) Solutions: 1, –3
Graphical Solutions
1. Put the equation in standard form. p(x) = 0
2. Graph the function p(x). Use a graphics calculator or software.
3. Determine the x-intercepts. Where the graph intersects the x-axis. Values of x where p(x) equals 0. These are the solutions.
NOTE: The values of x where p(x) = 0 are called …
zeros of p(x) & roots of p(x) = 0
Graphical Solutions – Example 1
2x – 5 = 13 2x – 18 = 0
Solution aka: zeros or roots x = 9
Graphical Solutions – Example 2
x2 + 2x = 5x – 2 x2 – 3x + 2 = 0
Solutions aka: zeros or roots x = 1, 2
Graphical Solutions – Example 3
x3 + 3 = 5x – x2
x3 + x2 – 5x + 3 = 0 Solutions
aka: zeros or roots x = 1, –3
Factored Polynomials
A polynomial written as a product of two or more polynomials.
Examples: x2 – 3x + 2 = (x – 1)(x – 2) x3 + x2 – 5x + 3 = (x – 1)2(x + 3)
The Principle of Zero Products
If ab = 0, then a = 0,b = 0,or both are zero.
Examples: If 5x = 0,
then x = 0. If 3(x – 1) = 0,
then x – 1 = 0(i.e. x = 1)
Solving FactoredPolynomial Equations
NOTES One side of the equation MUST be zero. The other side must be factored.
1. Set each factor equal to zero.
2. Solve each simpler equation.
3. Solution set is all of the solutions.
Solving FactoredPolynomial Equations – Example 1 (x – 1)(x – 2) = 0
x – 1 = 0 x = 1
x – 2 = 0 x = 2
Solutions: x = 1, 2
Solving FactoredPolynomial Equations – Example 2 (x – 1)2(x + 3) = 0
x – 1 = 0 x = 1
x + 3 = 0 x = –3
Solutions: x = 1, –3
Solving FactoredPolynomial Equations – Example 3 7x(3x – 2)(5x + 1) = 0
x = 0
3x – 2 = 0 x = 2/3
5x + 1 = 0 x = –1/5
Solutions: x = 0, 2/3, –1/5
Solving Polynomial Equationsby Factoring
Using the “Principle of Zero Products” p(x) = 0 can be solved …
1. Factor p(x)
2. Set each factor equal to zero
3. Solve these simpler equations
NOTE: If the equation is not originally in the form p(x) = 0, first determine this equivalent standard form.
The primary topic of this chapter!
Factoring – Step 1
Distributive Property ax + ay = a(x + y) ax – ay = a(x – y)
Factoring Out Common Factors If ALLALL of the terms of a polynomial
have a common factor, that common factor may be “factored out.”
Example: 5x2 – 15x =
CommonFactors
5x(x – 3)
Factoring – Step 1
NoteNote: If the leading coefficient is negative, it is common to factor out the negative.
Examples: –3x + 21 = –3(x – 7) –x2 + 15x = –x(x – 15) –x3 – 7 = –(x3 + 7) –6x2 – 2x = –2x(3x + 1)
Notice that the sign of each term is changed when factoring out a negative.
CommonFactors
Factoring – Step 2
NoteNote: This method is used with 4-term polynomials.
x2 + 5x + 2x + 10
1. Make two groups of two terms.(x2 + 5x) + (2x + 10)
2. Factor out common factors from each pair.x(x + 5) + 2(x + 5)
3.3. IfIf the remaining polynomials are the same, factor out the polynomial.
(x + 5)(x + 2)
Factoringby Grouping
NOTE: Be careful with negative terms!
Clarifying Terminology!!!!!
Expressions can be factored. 2x3 – 12x2 = 2x2(x – 6)
Equations can be solved. 2x3 – 12x2 = 0 x = 0, 6
Sometimes, an expression in an equation is factored in order to solve the equation. 2x3 – 12x2 = 0 2x2(x – 6) = 0 x = 0 or x – 6 = 0 x = 0, 6