MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 –...

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MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations

Transcript of MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 –...

Page 1: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

MTH 065Elementary

Algebra IIChapter 6 – Polynomial Factorizations

and Equations

Section 6.1 – Introduction to Polynomial Factorizations and Equations

Page 2: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Polynomial Equations

Definition An equation that states that two

polynomials are equal to each other. Standard Form

p(x) = 0 Combine like terms Terms from highest to lowest degree Leading coefficient positive

Degree of a Polynomial Equation Degree of the leading coefficient when in

standard form.

Page 3: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Polynomial Equations

Solution A value for the variable that makes the

equation true.

Solution Set Set of all solutions.

Fundamental Theorem of Algebra An nth degree polynomial equation will

have at MOST n solutions.

Page 4: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Polynomial Equations – Examples

2x – 5 = 13 Standard form: 2x – 18 = 0 Degree 1 (linear) Solution: x = 9

x2 + 2x = 5x – 2 Standard form: x2 – 3x + 2 = 0 Degree 2 (quadratic) Solutions: x = 1, 2

x3 + 3 = 5x – x2

Standard form: x3 + x2 – 5x + 3 = 0 Degree 3 (cubic) Solutions: 1, –3

Page 5: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Graphical Solutions

1. Put the equation in standard form. p(x) = 0

2. Graph the function p(x). Use a graphics calculator or software.

3. Determine the x-intercepts. Where the graph intersects the x-axis. Values of x where p(x) equals 0. These are the solutions.

NOTE: The values of x where p(x) = 0 are called …

zeros of p(x) & roots of p(x) = 0

Page 6: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Graphical Solutions – Example 1

2x – 5 = 13 2x – 18 = 0

Solution aka: zeros or roots x = 9

Page 7: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Graphical Solutions – Example 2

x2 + 2x = 5x – 2 x2 – 3x + 2 = 0

Solutions aka: zeros or roots x = 1, 2

Page 8: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Graphical Solutions – Example 3

x3 + 3 = 5x – x2

x3 + x2 – 5x + 3 = 0 Solutions

aka: zeros or roots x = 1, –3

Page 9: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Factored Polynomials

A polynomial written as a product of two or more polynomials.

Examples: x2 – 3x + 2 = (x – 1)(x – 2) x3 + x2 – 5x + 3 = (x – 1)2(x + 3)

Page 10: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

The Principle of Zero Products

If ab = 0, then a = 0,b = 0,or both are zero.

Examples: If 5x = 0,

then x = 0. If 3(x – 1) = 0,

then x – 1 = 0(i.e. x = 1)

Page 11: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Solving FactoredPolynomial Equations

NOTES One side of the equation MUST be zero. The other side must be factored.

1. Set each factor equal to zero.

2. Solve each simpler equation.

3. Solution set is all of the solutions.

Page 12: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Solving FactoredPolynomial Equations – Example 1 (x – 1)(x – 2) = 0

x – 1 = 0 x = 1

x – 2 = 0 x = 2

Solutions: x = 1, 2

Page 13: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Solving FactoredPolynomial Equations – Example 2 (x – 1)2(x + 3) = 0

x – 1 = 0 x = 1

x + 3 = 0 x = –3

Solutions: x = 1, –3

Page 14: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Solving FactoredPolynomial Equations – Example 3 7x(3x – 2)(5x + 1) = 0

x = 0

3x – 2 = 0 x = 2/3

5x + 1 = 0 x = –1/5

Solutions: x = 0, 2/3, –1/5

Page 15: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Solving Polynomial Equationsby Factoring

Using the “Principle of Zero Products” p(x) = 0 can be solved …

1. Factor p(x)

2. Set each factor equal to zero

3. Solve these simpler equations

NOTE: If the equation is not originally in the form p(x) = 0, first determine this equivalent standard form.

The primary topic of this chapter!

Page 16: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Factoring – Step 1

Distributive Property ax + ay = a(x + y) ax – ay = a(x – y)

Factoring Out Common Factors If ALLALL of the terms of a polynomial

have a common factor, that common factor may be “factored out.”

Example: 5x2 – 15x =

CommonFactors

5x(x – 3)

Page 17: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Factoring – Step 1

NoteNote: If the leading coefficient is negative, it is common to factor out the negative.

Examples: –3x + 21 = –3(x – 7) –x2 + 15x = –x(x – 15) –x3 – 7 = –(x3 + 7) –6x2 – 2x = –2x(3x + 1)

Notice that the sign of each term is changed when factoring out a negative.

CommonFactors

Page 18: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Factoring – Step 2

NoteNote: This method is used with 4-term polynomials.

x2 + 5x + 2x + 10

1. Make two groups of two terms.(x2 + 5x) + (2x + 10)

2. Factor out common factors from each pair.x(x + 5) + 2(x + 5)

3.3. IfIf the remaining polynomials are the same, factor out the polynomial.

(x + 5)(x + 2)

Factoringby Grouping

NOTE: Be careful with negative terms!

Page 19: MTH 065 Elementary Algebra II Chapter 6 – Polynomial Factorizations and Equations Section 6.1 – Introduction to Polynomial Factorizations and Equations.

Clarifying Terminology!!!!!

Expressions can be factored. 2x3 – 12x2 = 2x2(x – 6)

Equations can be solved. 2x3 – 12x2 = 0 x = 0, 6

Sometimes, an expression in an equation is factored in order to solve the equation. 2x3 – 12x2 = 0 2x2(x – 6) = 0 x = 0 or x – 6 = 0 x = 0, 6