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    Fundamentals of Materials Science and Engineering

    MSE 20 (B2 and B3)

    Vera Marie M. Sastine

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    Why Mechanical Properties?

    Need to design materials that can withstand applied load

    e.g. materials used in

    building bridges that can

    hold up automobiles,

    pedestrians

    materials for and

    designing MEMs

    and NEMs

    mater

    space

    explo

    materials for

    skyscrapers

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    Stress and Strain

    Stress pressure due to applied load

    Tension, Compression, Shear, Torsion, and Combination

    Strain response of the material tostress (i.e. physical deformation such

    as elongation due to tension).

    Tension

    Comp

    Torsion

    Sh

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    Common States of Stress

    Simple tensionExample, for a cable

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    Common States of Stress

    Simple compression

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    Tension and CompressionTension

    Compr

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    Elastic Deformation

    Elastic means reversi

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    Plastic Deformation

    Plastic means perma

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    Stress-strain Test

    Initially

    Elastic

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    Axial Load, P

    One of the important developments in

    understanding mechanical properties:

    The strength of a uni-axially loaded

    specimen is related to the magnitude o

    cross-sectional area,A

    In detail

    Sample calculation of surface density for Fe:

    NS~ 1015atoms/cm2is true for most materials

    Interplanar

    Bonds (imagined

    to be spring-

    like)

    f, UTS, Ultimate tensile strength

    Pf, load at fracture

    A0

    , original cross-sectional area

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    Sample Problem

    Soln:

    4

    2d

    A

    Using for cross-sectional

    area

    Carbon steel has UTS=1200 MPa. Use conse

    safety factor, set to 600MPa

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    Hookes Law (as long as the loads were relatively small):

    P, load

    k, stiffness (lb/in) or N/m

    , deformation

    , strain

    , deformation

    L0, original length

    E, Youngs modulus or modulus of

    elasticity

    Youngs Modulus

    Strength the materials resistance to failure by fracture or exce

    permanent deformation

    Stiffness the load needed to induce a given deformation in the

    ut tensio, sic vis As the Extension, so the F

    To normalize the eqn, making the

    stiffness purely a material property,

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    A positive (tensile) strain in one direction willalso contribute a negative (compressive) strainin the other direction, just as stretching a

    rubber band to make it longer in one directionmakes it thinner in the other directions

    Poissons ratio (dime

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    p, hydrostatic pressure needed for a unit relative decrease in volum

    (-) sign indicates compressive produces a negative

    The Poissons ratio is also relatedto the compressibility of the

    material.

    The Bulk Modulus

    - K, also called the modulus of

    compressibility.

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    Sample Problem

    Two timbers, of cross-sectional dimension bh, are

    glued together using a tongue-and-groove joint as sh

    the figure, and we wish to estimate the depth dof t

    joint so as to make the joint approximately as strontimber itself.

    If the bond fails at f, the load at failure will be ff bdP 2

    Soln:

    The load needed to fracture will be where f is the ultimate tensile strength of ff bhP

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    Shear Stresses & Strains

    yx yx

    xy

    yxsubscript:

    stress is on theyplane in thex-direc

    xysubscript:

    stress is on thexplane in they-direc

    xyyx For rotational equilibrium:

    Shearing counterpart of Hookes Law:

    G, shear modulus

    For isotropic materials (properties same in all directions), there is

    no Poisson-type effect to consider in shear, so that the shear strain is

    not influenced by the presence of normal stresses.

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    Shear Stresses & Strains

    For plane stress situations (no normal or shearing stress com

    the z direction), the constitutive equations are

    For isotropic materials, if any two of the three properties E, known, the other is determined

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    Stress Strain Curves- Importantgraphical measure of a materials

    mechanical properties

    Engineering Stress

    Engineering Strain

    Ratio of measured load over the original

    specimen cross-sectional area, A0.

    0A

    F

    E

    Degree of deformation with respect to the

    original length, L0.

    0

    0

    0 L

    LL

    L

    f

    E

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    Stress Strain Curves

    True Stress

    True Strain

    Ratio of the applied load, F (or P), to the

    instantaneous cross-sectional area,Ai, overwhich deformation is occurring.

    i

    T

    A

    F

    Incremental increase in displacement dLdivided by the current length, L.

    0

    ln1

    0

    L

    LdL

    Ll

    dLd

    L

    L

    TT

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    True Stress-Strain

    Engg Stress-Strain

    Neck forms where local x-sectional are

    decreases resulting in an increase in T

    On ENGG stress-strain curve, necking

    decrease in stress

    In engineering applications, the EnggStress-Strain Curve is More Us

    critical points are emphasized!

    Limitations of True Stress- Strain Curve:

    when necking starts!

    inaccurate at small strains

    UTS

    Stress-Strain Curve of Typical

    Structural Steel

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    Some stress-strain curves of

    conventional materials