Monte Carlo Integration

59
Monte Carlo Integration Digital Image Synthesis Yung-Yu Chuang 11/30/2006 with slides by Pat Hanrahan and Torsten Moller

description

Monte Carlo Integration. Digital Image Synthesis Yung-Yu Chuang 11/30/2006. with slides by Pat Hanrahan and Torsten Moller. Introduction. The integral equations generally don’t have analytic solutions, so we must turn to numerical methods. - PowerPoint PPT Presentation

Transcript of Monte Carlo Integration

Page 1: Monte Carlo Integration

Monte Carlo Integration

Digital Image SynthesisYung-Yu Chuang11/30/2006

with slides by Pat Hanrahan and Torsten Moller

Page 2: Monte Carlo Integration

Introduction

• The integral equations generally don’t have analytic solutions, so we must turn to numerical methods.

• Standard methods like Trapezoidal integration or Gaussian quadrature are not effective for high-dimensional and discontinuous integrals.

)ωp,( ooL )ω,p( oeL

iiiio ωθcos)ωp,()ω,ωp,(2

dLf is

Page 3: Monte Carlo Integration

Numerical quadrature • Suppose we want to calculate , but can

’t solve it analytically. The approximations through quadrature rules have the form

which is essentially the weighted sum of samples of the function at various points

b

adxxfI )(

n

iii xfwI

1

)(ˆ

Page 4: Monte Carlo Integration

Midpoint rule

convergence

Page 5: Monte Carlo Integration

Trapezoid rule

convergence

Page 6: Monte Carlo Integration

Simpson’s rule

• Similar to trapezoid but using a quadratic polynomial approximation

convergence

assuming f has a continuous fourth derivative.

Page 7: Monte Carlo Integration

Curse of dimensionality and discontinuity• For a sd function f,• If the 1d rule has a convergence rate of O(n-r), t

he sd rule would require a much larger number (ns) of samples to work as well as the 1d one. Thus, the convergence rate is only O(n-r/s).

• If f is discontinuous, convergence is O(n-1/s) for sd.

Page 8: Monte Carlo Integration

Randomized algorithms

• Las Vegas v.s. Monte Carlo• Las Vegas: gives the right answer by using rand

omness.• Monte Carlo: gives the right answer on the ave

rage. Results depend on random numbers used, but statistically likely to be close to the right answer.

Page 9: Monte Carlo Integration

Monte Carlo integration

• Monte Carlo integration: uses sampling to estimate the values of integrals. It only requires to be able to evaluate the integrand at arbitrary points, making it easy to implement and applicable to many problems.

• If n samples are used, its converges at the rate of O(n-1/2). That is, to cut the error in half, it is necessary to evaluate four times as many samples.

• Images by Monte Carlo methods are often noisy.

Page 10: Monte Carlo Integration

Monte Carlo methods

• Advantages– Easy to implement– Easy to think about (but be careful of statistical

bias)– Robust when used with complex integrands

and domains (shapes, lights, …)– Efficient for high dimensional integrals

• Disadvantages– Noisy– Slow (many samples needed for convergence)

Page 11: Monte Carlo Integration

Basic concepts

• X is a random variable• Applying a function to a random variable gives

another random variable, Y=f(X).

• CDF (cumulative distribution function)

• PDF (probability density function): nonnegative, sum to 1

• canonical uniform random variable ξ (provided by standard library and easy to transform to other distributions)

dx

xdPxp

)()(

}Pr{)( xXxP

Page 12: Monte Carlo Integration

Discrete Probability Distributions

• Discrete events Xi with probability pi

• Cumulative PDF (distribution)

• Construction of samples• To randomly select an event,

• Select Xi if

0ip 1

1n

ii

p

1i iP U P

ip

1

j

j ii

P p

U

1

0Uniform random variable 3X

iP

Page 13: Monte Carlo Integration

Continuous Probability Distributions• PDF

• CDF1

0

( ) Pr( )P x X x

Pr( ) ( )

( ) ( )

X p x dx

P P

( )p x

10

Uniform

( ) 0p x

0

( ) ( )x

P x p x dx(1) 1P

( )P x

Page 14: Monte Carlo Integration

Expected values

• Average value of a function f(x) over some distribution of values p(x) over its domain D

• Example: cos function over [0, π], p is uniform

Dp dxxpxfxfE )()()(

00

1cos)cos( dxxxE p

Page 15: Monte Carlo Integration

Variance

• Expected deviation from the expected value• Fundamental concept of quantifying the error

in Monte Carlo methods

2)()()]([ xfExfExfV

Page 16: Monte Carlo Integration

Properties

)()( xfaExafE

ii

ii XfEXfE )()(

)()( 2 xfVaxafV

22 )()()( xfExfExfV

Page 17: Monte Carlo Integration

Monte Carlo estimator

• Assume that we want to evaluate the integral of f(x) over [a,b]

• Given a uniform random variable Xi over [a,b], Monte Carlo estimator

says that the expected value E[FN] of the estimator FN equals the integral

N

iiN Xf

N

abF

1

)(

Page 18: Monte Carlo Integration

General Monte Carlo estimator

• Given a random variable X drawn from an arbitrary PDF p(x), then the estimator is

• Although the converge rate of MC estimator is O(N1/2), slower than other integral methods, its converge rate is independent of the dimension, making it the only practical method for high dimensional integral

N

i i

iN Xp

Xf

NF

1 )(

)(1

Page 19: Monte Carlo Integration

Convergence of Monte Carlo

• Chebyshev’s inequality: let X be a random variable with expected value μ and variance σ2. For any real number k>0,

• For example, for k= , it shows that at least half of the value lie in the interval

• Let , the MC estimate FN becomes)(/)( iii XpXfY

N

iiN Y

NF

1

1

2

1}|Pr{|

kkX

2)2,2(

Page 20: Monte Carlo Integration

Convergence of Monte Carlo

• According to Chebyshev’s inequality,

• Plugging into Chebyshev’s inequality,

So, for a fixed threshold, the error decreases at the rate N-1/2.

YVN

YVN

YVN

YN

VFVN

ii

N

ii

N

iiN

1111][

12

12

1

}

][|][Pr{|

21

NNN

FVFEF

}

][1|Pr{|

21

YV

NIFN

Page 21: Monte Carlo Integration

Properties of estimators

• An estimator FN is called unbiased if for all N

That is, the expected value is independent of N.

• Otherwise, the bias of the estimator is defined as

• If the bias goes to zero as N increases, the estimator is called consistent

QFE N ][

QFEF NN ][][

0][lim N

NF

QFE NN

][lim

Page 22: Monte Carlo Integration

Example of a biased consistent estimator• Suppose we are doing antialiasing on a 1d pixe

l, to determine the pixel value, we need to evaluate , where is the filter function with

• A common way to evaluate this is

• When N=1, we have

1

0)()( dxxfxwI )(xw

1

01)( dxxw

N

i i

N

i iiN

Xw

XfXwF

1

1

)(

)()(

IdxxfXfEXw

XfXwEFE

1

011

111 )()]([

)(

)()(][

Page 23: Monte Carlo Integration

Example of a biased consistent estimator• When N=2, we have

• However, when N is very large, the bias approaches to zero

Idxdxxwxw

xfxwxfxwFE

1

0

1

0 2121

22112 )()(

)()()()(][

N

i i

N

i ii

N

XwN

XfXwNF

1

1

)(1

)()(1

Idxxfxwdxxw

dxxfxw

XwN

XfXwNFE

N

i iN

N

i iiN

NN

1

01

0

1

0

1

1)()(

)(

)()(

)(1

lim

)()(1

lim][lim

Page 24: Monte Carlo Integration

Choosing samples

• Carefully choosing the PDF from which samples are drawn is an important technique to reduce variance. We want the f/p to have a low variance. Hence, it is necessary to be able to draw samples from the chosen PDF.

• How to sample an arbitrary distribution from a variable of uniform distribution?– Inversion– Transform– Rejection

N

i i

iN Xp

Xf

NF

1 )(

)(1

Page 25: Monte Carlo Integration

Inversion method

• Cumulative probability distribution function

• Construction of samplesSolve for X=P-1(U)

• Must know:1. The integral of p(x)

2. The inverse function P-1(x)

U

X

1

0

( ) Pr( )P x X x

Page 26: Monte Carlo Integration

Proof for the inversion method

• Let U be an uniform random variable and its CDF is Pu(x)=x. We will show that Y=P-1(U) has the CDF P(x).

because P is monotonic Thus, Y’s CDF is exactly P(x).

)())(()(Pr)(PrPr 1 xPxPPxPUxUPxY u

Page 27: Monte Carlo Integration

Inversion method

• Compute CDF P(x)

• Compute P-1(x)

• Obtain ξ

• Compute Xi=P-1(ξ)

Page 28: Monte Carlo Integration

Example: Power Function

• Assume( ) ( 1) np x n x

11 1

0 0

1

1 1

nn x

x dxn n

1( ) nP x x

1 1~ ( ) ( ) nX p x X P U U

1 2 1max( , , , , )n nY U U U U 1

1

1

Pr( ) Pr( )n

n

i

Y x U x x

Trick

It is used in sampling Blinn’s microfacet model.

(It only works for sampling power distribution)

Similarly, a trick to obtain a Gaussian distribution is to take average.

Page 29: Monte Carlo Integration

• Compute CDF P(x)

• Compute P-1(x)

• Obtain ξ• Compute Xi=P-1(ξ)

Example: exponential distribution

useful for rendering participating media.

Page 30: Monte Carlo Integration

Transformation of variables

• Given a random variable X from distribution px

(x) to a random variable Y=y(X), where Y=y(X) and y is one-to-one, i.e. monotonic. We want to derive the distribution of Y, py(y).

• • PDF:

)(}Pr{)}(Pr{)( xPxXxyYyP xy

dx

xdP

dx

ydPxy )()(

)(xpx

dx

dy

dy

ydP

dx

dyyp y

y

)()(

)()(1

xpdx

dyyp xy

Page 31: Monte Carlo Integration

Example

XY

xxpx

sin

2)(

2

11

1

sin2

cos

2)()(cos)(

y

y

x

xxpxyp xy

Page 32: Monte Carlo Integration

Transformation method

• A problem to apply the above method is that we usually have some PDF to sample from, not a given transformation.

• Given a source random variable X with px(x) and a target distribution py(y), try transform X into to another random variable Y so that Y has the distribution py(y).

• We first have to find a transformation y(x) so that Px(x)=Py(y). Thus,

))(()( 1 xPPxy xy

Page 33: Monte Carlo Integration

Transformation method• Let’s prove that the above transform works. We first prove that the random variable Z= Px(x)

has a uniform distribution. If so, then should have distribution Px(x) from the inversio

n method.

Thus, Z is uniform and the transformation works.

• It is an obvious generalization of the inversion method, in which X is uniform and Px(x)=x.

)(1 ZPy

xxPPxPXxXPxZ xxxx ))(()(Pr)(PrPr 11

Page 34: Monte Carlo Integration

Thus, if X has the distribution , then the random variable has the distribution

Example

xxpx )( yy eyp )(

2)(

2xxPx y

y eyP )(

2lnln2)2

ln())(()(2

1 xx

xPPxy xy

yyPy ln)(1

2lnln2 XYxxpx )(

yy eyp )(

Page 35: Monte Carlo Integration

Multiple dimensions

We often need the other way around,

Page 36: Monte Carlo Integration

Spherical coordinates

• The spherical coordinate representation of directions is

cos

sinsin

cossin

rz

ry

rx

sin|| 2rJT

),,(sin),,( 2 zyxprrp

Page 37: Monte Carlo Integration

Spherical coordinates

Page 38: Monte Carlo Integration

Rejection method

• AlgorithmPick U1 and U2

Accept U1 if U2 < f(U1)

• Wasteful?

1

0

( )

( )

y f x

I f x dx

dx dy

( )y f x

Efficiency = Area / Area of rectangle

• Sometimes, we can’t integrate into CDF or invert CDF

Page 39: Monte Carlo Integration

Rejection method

• Rejection method is a dart-throwing method without performing the above steps

1. Find q(x) so that p(x)<Mq(x)

2. Dart throwinga. Choose a pair (X, ξ), where X is sampled from q(x)

b. If (ξ<p(X)/Mq(X)) return X• Essentially, we pick a point (X, ξMq(X)). If it lies beneath p(X) then we are fine.

Page 40: Monte Carlo Integration

Why it works

• For each iteration, we generate Xi from q. The sample is returned if ξ<p(X)/Mq(X), which happens with probability p(X)/Mq(X).

• So, the probability to return x is

• Thus, when a sample is returned (probability 1/M), then Xi is distributed according to p(x).

M

xp

xMq

xpxq

)(

)(

)()(

Page 41: Monte Carlo Integration

Example: sampling a unit sphere

void RejectionSampleDisk(float *x, float *y) {

float sx, sy;

do {

sx = 1.f -2.f * RandomFloat();

sy = 1.f -2.f * RandomFloat();

} while (sx*sx + sy*sy > 1.f)

*x = sx; *y = sy;

}

π/4 ~ 78.5% good samples, gets worse in higher dimensions, for example, for sphere, π/8 ~ 39.3%

Page 42: Monte Carlo Integration

Multidimensional sampling

Page 43: Monte Carlo Integration

Sampling a hemisphere

2

1)( p

2

sin),( p

Page 44: Monte Carlo Integration

Sampling a hemisphere

Page 45: Monte Carlo Integration

Sampling a hemisphere

Page 46: Monte Carlo Integration

Sampling a disk

1

2

2 U

r U

1

2

2 U

r U

RIGHT Equi-ArealWRONG Equi-Areal

Page 47: Monte Carlo Integration

Sampling a disk

RIGHT Equi-ArealWRONG Equi-Areal

1

2

2 U

r U

1

2

2 U

r U

Page 48: Monte Carlo Integration

Sampling a disk

Page 49: Monte Carlo Integration

Shirley’s mapping

1

2

14

r U

U

U

Page 50: Monte Carlo Integration

Sampling a Triangle

121 1 1

0 0 00

(1 ) 1(1 )

2 2

u uA dv du u du

( , ) 2p u v

0

0

1

u

v

u v

u

v

1u v

( ,1 )u u

Page 51: Monte Carlo Integration

)(

),()|(

vp

vupvup

Sampling a Triangle

• Here u and v are not independent!• Conditional probability

( , ) 2p u v

00 0 00 0

0 0

1( | ) ( | )

(1 ) (1 )o ov v v

P v u p v u dv dvu u

1( | )

(1 )p v u

u

0 20 00

( ) 2(1 ) (1 )u

P u u du u

1

0

( ) 2 2(1 )u

p u dv u

0 11u U

0 1 2v U U

dvvupup ),()(

Page 52: Monte Carlo Integration

Cosine weighted hemisphere

cos)( p

dp )(1

2

0 0

2 sincos1 ddc

ddd sin

2

0sincos21

dc

1c

sincos1

),( p

Page 53: Monte Carlo Integration

Cosine weighted hemisphere

sincos1

),( p

2sinsincos2sincos1

)(2

0 dp

2

1

)(

),()|(

p

pp

12

12cos

2

1)( P

22)|(

P

)21(cos2

11

1

22

Page 54: Monte Carlo Integration

Cosine weighted hemisphere

• Malley’s method: uniformly generates points on the unit disk and then generates directions by projecting them up to the hemisphere above it.

Vector CosineSampleHemisphere(float u1,float u2){

Vector ret;

ConcentricSampleDisk(u1, u2, &ret.x, &ret.y);

ret.z = sqrtf(max(0.f,1.f - ret.x*ret.x -

ret.y*ret.y));

return ret;

}

Page 55: Monte Carlo Integration

Cosine weighted hemisphere

• Why Malley’s method works?• Unit disk sampling• Map to hemisphere here

rrp ),(),(sin),( r

),(),,( XrY

Page 56: Monte Carlo Integration

Sampling Phong lobe np cos)(

ncp cos)(

2

0

2/

0

1sincos ddc n

0

1cos

1coscos2

dc n 11

2

n

c

21

n

c

sincos2

1),( nn

p

Page 57: Monte Carlo Integration

Sampling Phong lobe

'cos1

1

cos)1(coscos)1(

sincos)1()'(

sincos)1(sincos2

1)(

1

'cos

1cos

1'

0

'

0

2

0

n

nn

n

nn

nndn

dnP

ndn

p

11

1cos n

sincos2

1),( nn

p

Page 58: Monte Carlo Integration

Sampling Phong lobe

2

'

2

1)|'(

2

1

sincos)1(

sincos

)(

),()|(

'

0

21

dP

np

pp

n

nn

22

sincos2

1),( nn

p

Page 59: Monte Carlo Integration

Sampling Phong lobe

)2,(cos),( 1,n 211

211 2),21(cos

2

1),(

cosine-weighted hemisphere

2

12cos

2

1)( P 21 cos1cos1)( nP

222 cos1sin2

1)sin21(

2

1

2

12cos

2

1

When n=1, it is actually equivalent to