Moment

clc; close all; clear all; fid=fopen('beam.txt','w'); fprintf(fid,'program 1. Moment of resistance of beam \n'); fprintf(fid,' ---------------------------- \n'); fck=input('\nEnter the grade of concrete fck(N/mm^2) '); fy=input('\nEnter the grade of steel fy(N/mm^2) '); fprintf(fid,'\nGrade of concrete fck(N/mm^2)%10.2f\n', fck); fprintf(fid,'\nGrade of steel fy(N/mm^2))%10.2f\n',fy) ; fyd=fy/1.15; Es=2*10^5; k=menu('Select type of beam','T beam','L beam',' Rectangular beam'); if k==1 fprintf(fid,'T beam \n'); bw=input('\nEnter the width of web bw(mm) '); Df=input('\nEnter the depth of flange Df(mm) '); D=input('\nEnter the depth of section D(mm) '); L=input('\nEnter the effective span of beam L(m) '); k=1; fprintf(fid,'\n Width of web bw(mm))%10.2f\n',bw); fprintf(fid,'\n Depth of flange Df(mm) %10.2f\n',Df); fprintf(fid,'\n Depth of section D(mm) %10.2f\n',D); fprintf(fid,'\n Effective span of beam L(m) %10.2f\n',L); elseif k==2 fprintf(fid,'L beam \n'); bw=input('\nEnter the width of web bw(mm) '); Df=input('\nEnter the depth of flange Df(mm) '); D=input('\nEnter the depth of section D(mm) '); L=input('\nEnter the effective span of beam L(m) '); k=.5; fprintf(fid,'\n Width of web bw(mm))%10.2f\n',bw); fprintf(fid,'\n Depth of flange Df(mm) %10.2f\n',Df); fprintf(fid,'\n Depth of section D(mm) %10.2f\n',D); fprintf(fid,'\n Effective span of beam L(m) %10.2f\n',L); else fprintf(fid,'Rectangular section \n'); b=input('\nEnter the width of beam b(mm) '); D=input('\nEnter the depth of beam D(mm) '); L=input('\nEnter the effective span of beam L(m) '); k=0; bw=b; Df=D; fprintf(fid,'\n Width of beam b(mm))%10.2f\n',b); fprintf(fid,'\n Depth of beam D(mm) %10.2f\n',D); fprintf(fid,'\n Effective span of beam L(m) %10.2f\n',L); end s=menu('Select type of section','singly reinforced section','Doubly reinforced section'); if s==1 fprintf(fid,'singly reinforced section \n'); nt=input('\nEnter the number of bars in tension '); dt=input('\nEnter the diameter of bars in tension dt(mm) '); fprintf(fid,'\n Number of bars in tension %10.2f\n',nt); fprintf(fid,'\n Diameter of bars in tension dt(mm) %10.2f\n',dt); Asc=0; Dl=0; else

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Transcript of Moment

7/17/2019 Moment

http://slidepdf.com/reader/full/moment-568f1e077946f 1/3

7/17/2019 Moment

http://slidepdf.com/reader/full/moment-568f1e077946f 2/3

fprintf(fid,'Doubly reinforced section \n'); nt=input('\nEnter the number of bars in tension '); nc=input('\nEnter the number of bars in compression '); dt=input('\nEnter the diameter of bars in tension dt(mm) '); dc=input('\nEnter the diameter of bars in compression dc(mm) '); Asc=nc*(.785)*dc^2; cc=input('\nEnter the cover at top cc(mm) '); Dl=cc+(dc/2); fprintf(fid,'\n Number of bars in tension %10.2f\n',nt); fprintf(fid,'\n Number of bars in compression %10.2f\n',nc); fprintf(fid,'\n Diameter of bars in tension dt(mm) %10.2f\n',dt); fprintf(fid,'\n Diameter of bars in compression %10.2f\n',dc); fprintf(fid,'\n Area of steel in compression(mm^2) %10.2f\n',Asc); end Ast=nt*(.785)*dt^2; fprintf(fid,'\n Area of steel in tension(mm^2) %10.2f\n',Ast);ct=input('\nEnter the cover at bottom ct(mm) ');Lo=menu('Select the type of beam','Simply Supported','Continuous beam'); if Lo==1 fprintf(fid,'Simply Supported \n'); Lo=L; else fprintf(fid,'Continuous beam \n');

Lo=.7*L; endbf=k*(Lo/6+(6*Df))+bw;d=D-((dt/2)+ct);fsc=fyd;xumax=(.0035/(.0055+(fyd/Es)))*d;xu=((fyd*Ast)-(fsc*Asc))/(.36*fck*bf); fprintf(fid,'\n xu(mm)=%10.2f\n',xu); fprintf(fid,'\n xumax(mm)=%10.2f\n',xumax);if k==0 if xu<=xumax Mu=(.36*fck*b*xu*(d-(.42*xu)))+(fsc*Asc*(d-Dl)); fprintf(fid,'\nMoment of resistance of beam Mu(kNm)%10.2f\n',Mu/(10^6));

elsefprintf(fid,'over reinforced section \n'); Mu=(.36*fck*b*xumax*(d-(.42*xumax)))+(fsc*Asc*(d-Dl));

fprintf(fid,'\n Moment of resistance of beam Mu(kNm)=%10.2f',Mu/(10^6)); endelse if xu<Df Mu=(.36*fck*bf*xu*(d-(.42*xu))); fprintf(fid,'\n Moment of resistance of beam Mu(kNm)=%10.2f',Mu/(10^6)); else if xu<(7*Df/3) xu=((fyd*Ast)-(.2899*fck*(bf-bw)*Df))/((.36*fck*bw)+(0.0669*fck*(bf-bw)));

yf=(.15*xu)+(.65*Df); Mu=(.36*fck*bw*xu*(d-.42*xu))+(.446*fck*(bf-bw)*yf*(d-(yf/2))); fprintf(fid,'\n xu(mm)=%10.2f\n',xu); fprintf(fid,'\n Moment of resistance of beam Mu(kNm)=%10.2f',Mu/(10^6));

elsexu=((fyd*Ast)-(.446*fck*(bf-bw)*Df))/(.36*fck*bw);

Mu=(.36*fck*bw*xu*(d-.42*xu))+(.446*fck*(bf-bw)*Df*(d-(Df/2))); fprintf(fid,'\n xu(mm)=%10.2f\n',xu);