Molarity Lab
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Molarity LabMolarity Lab4/12/114/12/11Let’s make a solution or 2.Let’s make a solution or 2.1) With a partner, make 20 milliliters of a 2.0 Molar 1) With a partner, make 20 milliliters of a 2.0 Molar
solution of NaCl.solution of NaCl.2)Next, make exactly 175 mL of a 0.147M solution 2)Next, make exactly 175 mL of a 0.147M solution
of NaCl.of NaCl.3) How much solution is created, in a 0.45M 3) How much solution is created, in a 0.45M
solution if we use 25.6 grams of sucrose (in solution if we use 25.6 grams of sucrose (in yellow packet) to make the solution.yellow packet) to make the solution.
Be sure to record the mass of salt used in each. Be sure to record the mass of salt used in each. Make this neat and easy for me to read/grade.Make this neat and easy for me to read/grade.
Molarity cont.Molarity cont.
4) Dilute the 0.147M solution to a 0.08 M 4) Dilute the 0.147M solution to a 0.08 M solution. How do you do this? What is new solution. How do you do this? What is new volume? How much water?volume? How much water?
M1V1=M2V2
0.147M(.167L) = 0.08M(V2)
V2= 0.307L
Add .140 L of water
Daily EQ:What is stoichiometry?Daily EQ:What is stoichiometry?
warm-upwarm-up
Mole conversions (Do you remember these?)Mole conversions (Do you remember these?)
1) How many moles are there in 500 grams of O1) How many moles are there in 500 grams of O22??
2) At STP, how many moles of O2) At STP, how many moles of O22 are in 500 L? are in 500 L?
3) How many molecules of O3) How many molecules of O22 are in 25.5 moles are in 25.5 moles
of Oof O22??
4) How many atoms are in 25.5 moles of O4) How many atoms are in 25.5 moles of O22??
Stoichiometry Chapter 12 in your bookStoichiometry Chapter 12 in your book
mole ratio-mole ratio-
stoichiometry - stoichiometry -
a conversion factor derived from the a conversion factor derived from the
coefficients of a balanced chemical coefficients of a balanced chemical
equationequation
Calculation of quantities in Calculation of quantities in chemical reactionschemical reactions
NN2 2 + H+ H2 2 NH NH33
Must balance equations correctlyMust balance equations correctly
3 2
Balanced equation can be interpreted in terms of different quantitites.
atoms, molecules, moles, mass and volume
NN2 2 + H+ H2 2 NH NH33
Must balance equations correctlyMust balance equations correctly
3 2
What are the 6 mole ratios for the reaction?
1 mol N2
3 mol H2
1 mol N2
2 mol NH3
3 mol H2
2 mol NH3
3 mol H2
1 mol N2
2 mol NH3
1 mol N2
2 mol NH3
3 mol H2
NN2 2 + 3H+ 3H2 2 2NH 2NH33
How many atoms of each?How many atoms of each?
molecules? molecules?
moles?moles?
mass?mass?
volume?volume?
Mass and atoms must be conserved but not necessarily Mass and atoms must be conserved but not necessarily molecules, fu,moles, or volumemolecules, fu,moles, or volume
Practice problemsPractice problems
Complete p379Complete p379
#36 write mole ratios#36 write mole ratios
Do #40,41,42Do #40,41,42
4/14/114/14/11
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
How many moles of nitrogen are needed to How many moles of nitrogen are needed to react with 5.2 moles hydrogen gas?react with 5.2 moles hydrogen gas?
How many moles of ammonia (NHHow many moles of ammonia (NH33) can be ) can be
produced from 54 g of nitrogen?produced from 54 g of nitrogen?
How many grams of hydrogen are needed to How many grams of hydrogen are needed to produce 100.0 grams of ammonia gas?produce 100.0 grams of ammonia gas?
Limiting reagentLimiting reagent
What is it? What is it? The thing (reactant) that runs out first, Just like in a recipe.
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
How many moles of nitrogen are needed to How many moles of nitrogen are needed to completely react with 15 moles of Hcompletely react with 15 moles of H2 2 in the above in the above
reaction ?reaction ?
Limiting reagentLimiting reagent
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
How many grams of nitrogen are needed to How many grams of nitrogen are needed to completely react with 8 grams of Hcompletely react with 8 grams of H2 2 in the in the
above reaction ?above reaction ?
How many grams of NH3 can be produced in this reaction?
Limiting reagentLimiting reagent
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
What is the limiting reagentWhat is the limiting reagent in the above in the above
reaction , if 10 moles of hydrogen gas react reaction , if 10 moles of hydrogen gas react with 10 moles of nitrogen gas?with 10 moles of nitrogen gas?
Limiting reagentLimiting reagent
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
What is the limiting reagentWhat is the limiting reagent in the above in the above
reaction , if 4 grams of hydrogen gas react reaction , if 4 grams of hydrogen gas react with 14 grams of nitrogen gas?with 14 grams of nitrogen gas?
How many grams of NH3 can be produced in this reaction?
Limiting reagent (cooke method)Limiting reagent (cooke method)NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
What is the limiting reagentWhat is the limiting reagent in the above in the above
reaction , if 10 moles of hydrogen gas react reaction , if 10 moles of hydrogen gas react with 10 moles of nitrogen gas?with 10 moles of nitrogen gas?
N2
H2
Limiting
Reagent
1 mol
3 mol
10 mol
10 mol1
x
x
.33
Limiting ReagentsLimiting Reagents
2AgNO2AgNO33 + Cu + Cu Cu(NO Cu(NO33))22 + 2Ag + 2Ag
There are 4.3 moles of AgNOThere are 4.3 moles of AgNO33 and 12.3 and 12.3
moles of Cu. Which is the limiting reagent?moles of Cu. Which is the limiting reagent?
AgNO3
Cu
Limiting
Reagent
2 mol
1 mol
4.3 mol
12.3 mol2 0.35
AgNO3 is the limiting reagent. It runs out first.
Limiting ReagentsLimiting Reagents
2AgNO2AgNO33 + Cu + Cu Cu(NO Cu(NO33))22 + 2Ag + 2Ag
There are 500g of AgNOThere are 500g of AgNO33 and 1200g of Cu. and 1200g of Cu.
Which is the limiting reagent? Which is the limiting reagent?
AgNO3
Cu
Limiting
Reagent
2 mol
1 mol
500 g 1 mol 1 169.88 g
1200 g 1 mol 1 63.55 g
2.94 mol
18.9 mol2 0.15
x
x
AgNO3 is the limiting reagent. It runs out first.
Percent Yield Percent Yield
4/13/104/13/10
Actual yieldActual yield X 100 X 100
theoretical yieldtheoretical yield
Limiting reagentLimiting reagent
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
How many grams of nitrogen are needed to How many grams of nitrogen are needed to completely react with 8 grams of Hcompletely react with 8 grams of H2 2 in the in the
above reaction ?above reaction ?
Limiting reagentLimiting reagent
NN2(g) 2(g) + 3H+ 3H2(g)2(g) 2NH 2NH3(g)3(g)
What is the limiting reagentWhat is the limiting reagent in the above in the above
reaction , if 2 grams of hydrogen gas react reaction , if 2 grams of hydrogen gas react with 14 grams of nitrogen gas?with 14 grams of nitrogen gas?
Yeah!TODYeah!TOD
4/15/114/15/11
2Al2Al(g) (g) + 3Cl+ 3Cl2(g)2(g) 2AlCl 2AlCl3(g)3(g)
1) List all mole ratios.1) List all mole ratios.
2)How many moles of aluminum are needed 2)How many moles of aluminum are needed to react with 5.2 moles chlorine gas?to react with 5.2 moles chlorine gas?
3)How many moles of aluminum chloride 3)How many moles of aluminum chloride (AlCl(AlCl33) can be produced from 54 g of ) can be produced from 54 g of
chlorine?chlorine?
Practice problems/HomeworkPractice problems/Homework
Complete p370Complete p370
#25,26,27,28#25,26,27,28
Lab demoLab demo
CuClCuCl2 2 + Al + Al
Ticket out the door retakeTicket out the door retake
Warm-up 4/15/11Warm-up 4/15/11
HH2(g) 2(g) + O+ O2(g)2(g) H H22OO(g)(g)
How many moles of oxygen are needed to How many moles of oxygen are needed to react with 3.7 moles hydrogen gas?react with 3.7 moles hydrogen gas?
How many moles of water can be produced How many moles of water can be produced from 12.5 g of oxygen?from 12.5 g of oxygen?
How many grams of hydrogen are needed to How many grams of hydrogen are needed to produce 67.0 grams of water?produce 67.0 grams of water?