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![Page 1: Modes of Radioactive Decay GE-PP-22502 Author: Ken Jenkins Approved: Michael J. Kurtzman Date: 06/14/2003 Revision: 00.](https://reader036.fdocuments.us/reader036/viewer/2022062516/56649d985503460f94a81e44/html5/thumbnails/1.jpg)
Modes of Radioactive DecayGE-PP-22502
Author: Ken Jenkins
Approved: Michael J. KurtzmanDate: 06/14/2003
Revision: 00
![Page 2: Modes of Radioactive Decay GE-PP-22502 Author: Ken Jenkins Approved: Michael J. Kurtzman Date: 06/14/2003 Revision: 00.](https://reader036.fdocuments.us/reader036/viewer/2022062516/56649d985503460f94a81e44/html5/thumbnails/2.jpg)
GE-PP-22502-00 2
Nuclear StabilityForces Acting Within the
Nucleus
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Nuclear StabilityThe repulsive electrostatic forces between the
protons have an impact on nuclear stabilityThe number of neutrons must increase more
rapidly than the number of protons to provide ‘dilution’ and to add additional nuclear forces
If the nuclear (attractive) and electrostatic (repulsive) forces do not balance, the atom will not be stable
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Nuclear StabilityAn unstable nucleus will eventually achieve
stability by changing its nuclear configuration
This includes changing neutrons to protons, or vice versa, and then ejecting the surplus mass or energy from the nucleus
This emitted mass or energy is called radiation
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Nuclear StabilityWhen an atom transforms to become more
stable it is said to disintegrate or decayThe time required for half of a sample of atoms
to decay is known as the half-lifeThe property of certain nuclides to
spontaneously disintegrate and emit radiation is called radioactivity
The atom before the decay is the parent and the resulting atom is called the daughter
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Neutron / Proton Ratio
0 20 40 60 80 100 120 1400
20
40
60
80
100
NU
MB
ER
OF
PR
OT
ON
S (
Z)
NUMBER OF NEUTRONS (N=A-Z)
LINE OFSTABILITY
Z
N1
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Beta DecayBetas are physically the same as electrons,
but may be positively or negatively chargedNegative beta is a beta minus or negatronPositive beta is a beta plus or positronBetas are ejected from the nucleus, not from
the electron orbitals In all beta decays the atomic number changes
by one while the atomic mass is unchanged
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Beta (β-) Minus DecayOccurs in neutron-rich nuclidesThe nucleus converts a neutron into a proton
and a beta minus (which is ejected from the nucleus with an anti-neutrino)
Mass and charge are conserved
epn 01
11
10
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Beta (β-) Minus DecayFor beta minus decays,
011YX A
ZAZ
01
9039
9038 YSr
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Beta (β-) Minus Decay
ParentK-40
Beta Particle
Anti-neutrino
01
DaughterCa-40
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Beta (β-) Minus DecayDuring radioactive decay energy is released Source of this energy is from the conversion
of massSince energy is conserved, energy equivalent
of the parent must equal energy equivalent of daughter, particles, and any energy released
Energy is released as kinetic energy of beta minus particle and an anti-neutrino
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Beta (β-) Minus DecayFor beta minus, energy of decay reaction (Q) is,
)5.931)((1 amu
MeVMMQ
YX AZ
AZ
Mass of beta minus particle is not included since an additional electron is gained due to increase of Z
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Beta (β-) Minus DecayCalculate Q for β- decay of Co-60.
01
6028
6027 NiCo
Mass of Co-60 is 59.933813 amuMass of Ni-60 is 59.930787 amu
)amu
MeVmu)(931.559.930787a-mu59.933813a(Q
MeVQ 819.2
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Beta (β-) Minus DecayThe Q value for beta minus decay of Co-60,
for example, is always the sameHowever, negatrons rarely are emitted with
the same energiesTheir energies can range from 0 MeV to the
calculated maximum, Emax
The anti-neutrino carries energy difference between actual and calculated values
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Beta (β-) Minus Decay#
of b
etas
wit
h en
ergy
E
EnergyMaxE3
1 MaxE
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Co6027
Ni6028
99+%
0.013%
0.12%
1.17
3
2.15
8
0.83
1.33
2
Co-60 Decay Scheme
Q
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Beta (β+) Plus DecayOccurs in proton-rich nuclidesThe nucleus converts a proton into a neutron
and a beta plus (which is ejected from the nucleus with a neutrino)
As with negatrons, the positron can have a range of energies from 0 to EMax MeV
Positron is the negatron’s anti-particleA positron and a negatron will annihilate one
another and release two 0.511 MeV photons
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01
136
137 CN
Beta (β+) Plus DecayFor beta plus decays,
011YX A
ZAZ
enp 01
10
11
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Beta (β+) Plus Decay
ParentF-18
Beta Particle
Neutrino
01
DaughterO-18
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Beta (β+) Plus DecayFor beta plus, energy of decay reaction (Q) is,
)5.931)](2()[( 011 amu
MeVMMMQ
eYX AZ
AZ
Since the energy equivalent of two electron masses is 1.022 MeV, the equation can be rewritten as,
MeVamu
MeVMMQ
YX AZ
AZ
022.1)]5.931)([(1
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Beta (β+) Plus Decay
C136N13
7
•••
• •••
•
••••••
•+
e-
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Beta (β+) Plus DecayCalculate Q for β+ decay of F-18.
01
188
189 OF
Mass of F-18 is 18.000937 amuMass of O-18 is 17.999160 amu
MeVQ 022.1)]amu
MeVmu)(931.517.999160a-amu000937.18[(
MeVQ 633.0
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Electron CaptureProton-rich nuclides may also decay via orbital
electron capture (EC)Usually an innermost K shell electron is
captured and often referred to as K-captureThe electron and a proton are converted into a
neutron and a neutrino is emitted Electrons from higher orbitals will fill vacancy
and usually emit characteristic x-rays
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CrMn EC 5324
5325
Electron CaptureFor electron capture decays,
YeX AZ
AZ 1
01
nep 10
01
11
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Electron CaptureFor electron capture, energy of decay reaction
(Q) is,
)5.931)((1 amu
MeVMMQ
YX AZ
AZ
Since the electron was absorbed into the nucleus and not removed, there is no need to account for electron mass
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Auger ElectronsWhen electrons change shells, x-rays are
usually emitted In some instances, the excess energy is
transferred to another orbital electron, which is then ejected from the atom
This ejected electron is known as an Auger electron
Another orbital vacancy now exists and x-rays may be emitted if they are filled
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••
Auger Electrons
•• •
•
•
• ••
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Beta InteractionsExcitation
The beta, via coulombic interaction, transfers enough energy to an orbital electron to move it to a higher energy level, but not to remove it from the atom
The atom remains electrically neutralThe excited electron will then return to its ground
state and emit the excess energy as x-rays
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Excitation
•
••
•••
- •
•x-ray
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Beta Interactions Ionization
The beta, via coulombic interaction, transfers enough energy to an orbital electron to overcome its binding energy and remove it from the atom
With the loss of the negative electron, the remaining atom is now a positive ion
If the vacancy is filled, an x-ray will be emittedThe formation of each ion pair in air (gas)
requires about 34 eV of energy from the beta
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Ionization
••
••
- •
• ••
•e-
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Beta InteractionsBremsstrahlung
German for ‘braking radiation’Occurs when beta is deflected by the positively
charged nucleusThe kinetic energy lost by the beta is emitted as a
photon (x-ray)Bremsstrahlung increases with higher Z materialsFor example, a lead blanket may shield betas, but
generate higher levels of Bremsstrahlung (x-rays)
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Bremsstrahlung
••
••• • •
- •
x-ray
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Beta InteractionsBetas travel in zig-zag or tortuous paths
Collisions and deflectionsCoulombic interactionsNot mono-energetic
Because of this, betas have a definite, predictable range (given in mg/cm2)
Basic thumb rule is that a 1.0 MeV beta will travel approximately 12 feet in air
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Beta Interactions
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Beta InteractionsAll betas can be stopped, but Bremsstrahlung
photons can be produced Intensity is proportional to number of betas,
their energy, and Z of the absorberShielding is designed to minimize and/or shield
BremsstrahlungLow Z materials such as plastic (hydrocarbons)
or aluminum are common
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Beta InteractionsThe fraction of beta energy that appears as
photon energy (Bremsstrahlung) can be estimated with the following equation:
f = E x Z x 10-3
E = beta energy in MeV
Z = atomic number of target (shield) material
Average energy of the Bremsstrahlung photons is about 1/4 Emax
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Alpha DecayAlphas are large particles ejected by the heavier
nuclidesAlpha decay is primarily limited to nuclides
with Z > 82Source is mainly from fuel-related materialsAlpha contains two protons and two neutrons
(no electrons) and is, in effect, a helium nucleusThus, the atomic number decreases by two and
the mass number decreases by four
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Alpha DecayFor alpha decays,
242
42
HeYX A
ZAZ
242
20682
21084
HePbPo
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Alpha Decay
ParentU-235
Daughter Th-231
242
He
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Alpha DecaySince nothing else is emitted, all energy of
decay goes to the alpha particle (except for a small amount towards recoil of nucleus)
Alphas, therefore, are mono-energeticFor alpha, energy of decay reaction (Q) is,
)5.931)](([ 42
42 amu
MeVMMMQ
HeYX AZ
AZ
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Alpha DecayCalculate Q for the decay of Rn-222.
242
21884
22286
HePoRnMass of Rn-222 is 222.017610 amuMass of Po-218 is 218.009009 amu
)amu
MeVu)](931.54.002603am9amu(218.00900-amu017610.222[ Q
MeVQ 6.5
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Alpha InteractionsAlphas interact primarily through Coulombic
interactions due to their +2 chargeEnergy transfer occurs through excitation and
ionizationOrbital electrons may receive enough energy
to allow them to cause secondary ionizations of other atoms
Bremsstrahlung does not occur since the large alphas are not easily deflected
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Alpha InteractionsBecause of their mass and charge, alphas
travel in relatively straight paths over short distances (higher Z of absorber, less distance)
A 7 MeV alpha travels only about 0.0002 cm in lead
Alphas are considered internal hazards onlyWhen an alpha slows enough, it captures two
free electrons and converts to a helium atom
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Alpha Interactions
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Nuclear De-excitationDaughter nuclei from radioactive decays are
often ‘born’ with excess energyOccasionally the excited nucleus will emit
additional alphas or betasUsually the excited nucleus reaches ground
state via nuclear de-excitationThe excited nucleus and the final ground state
nucleus have the same Z and A and are called isomers
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Nuclear De-excitation If the excited state has a half-life >1 sec, it is
said to be a metastable stateThe metastable state is denoted by the use of a
lowercase ‘m’, such as Ba-137mThe longest known excited state is Bi-210m
with a half-life of 3.5 x 106 yearsDuring de-excitation no nuclear transformation
occurs, so no ‘new’ element is formed
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Nuclear De-excitation Internal Conversion
The excess nuclear energy is transferred to an inner orbital (usually K or L) electron
This electron is then ejected from the atom with a distinct energy
X-ray emission may follow as electrons shift orbitals to fill vacancies
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Nuclear De-excitationGamma emission
Most frequently the excess energy is relieved via the emission of one or more gamma rays
Gammas have no mass or electric chargeIf gammas are emitted by an isomer in the
metastable state, the emission is known as an isomeric transition (IT)
Photon Energy (E) = hf where h is Planck’s Constant (4.14 x 10-15 eV-sec)f is frequency (sec-1)
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Gamma Ray Radiation
ParentCo-60
Gamma Rays
01
DaughterNi-60
Anti-neutrino
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Co6027
Ni6028
99+%
0.013%
0.12%
1.17
3
2.15
8
0.83
1.33
2
Co-60 Decay Scheme
Q
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Gamma InteractionsAlphas and betas (charged particles) interact
multiple times along their pathsGammas usually have only one or two
interactions and all of their energy is transferred
Gammas interact with matter typically through three processes: photoelectric effect, Compton effect, and pair production
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Photoelectric EffectThe gamma ray photon transfers all of its
energy to an orbital electron (usually K shell)The electron is then ejected from the atom
(photoelectron)Probability of the photoelectric effect increases
with increasing Z of the absorberProbability of the photoelectric effect increases
with decreasing gamma energy (<1 MeV)
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Photoelectric Effect
••
••• •
•
•e-
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Compton Effect (Scattering)The gamma ray photon transfers some of
its energy to an orbital electronThe electron is ejected (recoil electron) and
the photon is scattered with a lower energyProbability of the Compton effect
decreases with increasing gamma energy (200 keV 5 MeV)
Compton effect is more common with absorbers of intermediate Z
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Compton Effect
••
••• •
•
•e-
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Pair ProductionPhoton travels in the vicinity of the nucleusPhoton spontaneously converts into a pair of
particles - an electron and a positronSince the rest mass energy of an electron is
0.511 MeV (from E = mc2), the photon must have an initial energy of at least 1.022 MeV
All photon energy in excess of 1.022 MeV is shared as kinetic energy between the particles
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Pair Production
••
••• ••e-
•e+
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Pair ProductionThe electron and positron will lose energy
through excitation, ionization, and Bremsstrahlung interactions
When the positron slows sufficiently it will be attracted to an electron and the two will annihilate one another (anti-particles) resulting in the formation of two 0.511 MeV photons
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Pair ProductionThough pair production is possible at 1.022
MeV, the process rarely occurs until approximately 5 MeV photon energy
The likelihood of pair production also increases proportionally with increasing Z of the absorber
Few isotopes at Vogtle have sufficient energies for pair production to occur
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Gamma Ray AttenuationGammas interact within an absorber via
photoelectric effect, Compton scattering, and pair production
Compton scattering and pair production events result in the emission of photons
The average probability of an event must be considered for shielding
Theoretically no amount of shielding can reduce the gamma dose rate to zero
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Gamma Ray AttenuationGamma ray intensity is reduced exponentially
with a linear increase in absorber thickness
xeII 0
Where:I = emerging gamma intensityI0 = incident gamma intensityx = thickness of absorber (cm) = linear attenuation coefficient (cm-1)
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Gamma Ray Attenuation
Compton Scatter
Photoelectric Effect
No Interaction
Pair Production (annihilation photons)
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Gamma Ray AttenuationA more simplified shielding calculation uses
the concepts of Half Value Layers (HVL) and Tenth Value Layers (TVL)
HVL is the thickness of an absorber necessary to decrease the gamma radiation to one half of the incident value
TVL is the thickness of an absorber necessary to decrease the gamma radiation to one tenth of the incident value
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Gamma Ray AttenuationTo perform calculations with these concepts
use the following equations:
nII )2
1(0 nII )
10
1(0
Where n = the number of HVLs or TVLs respectively
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Decay SchemesVertical lines represent energyHorizontal lines indicate atomic number (Z)Beta minus points down to the rightAlpha and EC point down to the leftBeta plus points down to the left with a 1.022
MeV offsetParent half-lives are shown
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Decay Schemes
Ground states are bold horizontal linesExcited states are light horizontal lines Isomeric states are medium horizontal linesTotal amount of energy for the reaction is
shown (Q)Abundances (probabilities) of transitions are
shown
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Decay SchemesWhat is the half-life of Ar-41?1.83 hoursWhat percentage of the Zr-95 beta minus
decays result in an isomer of Nb-95?2%Cr-51 decays by what method(s)?Electron capture (EC)
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Decay SchemesFor every 100 decays of Rb-86, about how
many 1.078 MeV gammas will be produced?9 (100 x 8.8%)For every 100 decays of Mn-56, about how
many 1.811 MeV gammas will be produced?29 (100 x 30% x 97.8%)What will be the most abundant gamma
energy produced during the decay of Fe-59?1.095 MeV
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Chart of the Nuclides
I1318.040 d
- 0.606, . . .
364.5, . . .
0.7, 8
E 0.971
Isotope
Half-life (color indicates 1-10 days)
Beta decay with most prominent energy (MeV)
Most prominent gamma energy (keV)
Thermal neutron cross-section (barns)Beta disintegration energy (MeV)
Fission product
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GE-PP-22502-00 71
Chart of the NuclidesWhite backgrounds are artificially radioactiveGray backgrounds are stable and include
percent abundancesLower half colors represent neutron absorption
propertiesBlack bar across top of box indicates a
naturally-occurring radioactive isotopeHeavy black outlines indicate ‘magic’ numbers