Modeling excess heat in the Fleischmann-Pons experiment Peter L. Hagelstein 1 and Irfan Chaudhary 2...
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![Page 1: Modeling excess heat in the Fleischmann-Pons experiment Peter L. Hagelstein 1 and Irfan Chaudhary 2 1 Research Laboratory of Electronics Massachusetts.](https://reader037.fdocuments.us/reader037/viewer/2022110207/56649d585503460f94a380bc/html5/thumbnails/1.jpg)
Modeling excess heat in the Fleischmann-Pons experiment
Peter L. Hagelstein1 and Irfan Chaudhary2
1Research Laboratory of ElectronicsMassachusetts Institute of Technology
2Department of Computer Science and Engineering
University of Engineering and Technology, Lahore
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Outline
Energy without energetic particles Converting a big quantum into small ones Excitation transfer Simulating Conclusions
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Excess energy
M Fleischmann et al, J Electroanalytical Chem 287 293 (1990)
4 MJ observedduring 80 hours
Would get 1.2 kJfor detonation ofequivalent cathodevolume (0.157 cc)of TNT
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Energy and momentum conserved in nuclear reactions
E. Rutherford
p1 p2
Initial:
p’1 p’2
Final:
p1 + p2 = p’1 + p’2
M1v21/2 + M2v2
2/2 + Mc2 = M1’(v’1)2/2 + M2’(v’2)2/2
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Excess energy expressed as product kinetic energy
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No energetic particles commensurate with energy
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Only two possibilities
Nuclear energy produced without commensurate
energetic particles
Is a mistake, experimentalists need to go back into the lab
There is a new physical effect responsible for
the observations
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Helium
4He is observed in the gas correlated with the energy produced
•No evidence that helium is energetic
•Positive evidence (lack of large amounts of Pd K x-rays) that helium is born with less than 20 keV
•Some helium retained in cathode
•Hinders accurate Q-value measurements
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Two observations so far with stripping of 4He from cathode
Results in both cases consistent with Q = 24 MeV
M4 cell at SRILaser-3 experiment at ENEA Frascati
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4He as ash with Q=24 MeV
Mass difference between two deuterons and 4He:
MDc2 + MDc2 = M4Hec2 + 23.86 MeV
Q-value consistent with deuterons reacting in new process to make 4He
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Experimental input for new process
?D+D 4He
Q = 23.86 MeVno energetic particles
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Theoretical problem
Although many more results available from experiment, we have enough so far to pose the key theory problem:
How to split up a large E quantum into lots of small quanta?
The major implication of the Fleischmann-Pons experiment is that this is possible and occurs in energy production
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Basic toy model
Two-level systems Macroscopi
cexcited mode
0
E
0 E
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Many-spin spin-boson model
† †0
ˆ 2ˆ ˆ ˆ ˆ ˆ xz SSH E aa V a a
Two-level systemsenergy
Harmonic oscillatorenergy
Linear couplingbetween two-level
systems and oscillator
C. Cohen-Tannoudji
Earlier versions of the model due to Bloch and Siegert (1940)
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Coherent energy exchange
Numerical results for exchanging energy between1700 oscillator quanta and 100 two-level systems
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Thinking about toy model
Coherent multi-quantum energy exchange predicted by toy model
•Effect is weak•Stringent resonance requirements•Can exchange up to about 100 quanta coherently•Exactly kind of model needed, except energy
exchange effect is too weak
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Improved toy model
Two-level systems
Macroscopic
excited mode
0
E
0 E Loss near E
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Lossy version of model
† †0
ˆ 2ˆ ˆ ˆ ˆ ˆ 2
xz SSH E aa V a a i E
Loss term, which allows the system todecay when a large energy quantum isavailable
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Perturbation theory
Finite basis approximation for 5 1n M n M
Many paths from initial to final state, with interference between upper and lower paths
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Perturbation theory
Loss channels available for off-resonant states with energy excess, which spoils the destructive interference
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Enhancement due to loss
M
-50 -40 -30 -20 -10 0 10 20 30 40 50
F(S
,M)
0.0
0.5
1.0
1.5
x106
1,12 1,12 0( ) ( ) ( , )V E V E F S M
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Lossy version of model
Loss spoils the destructive interference
Coherent energy exchange rates increased by orders
of magnitude
Much stronger effect
Model capable of converting 24 MeV to atomic scale
quanta
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Thinking about PdD
D2
4He
Phonon mode
Unfortunately, coupling is too weak because of Coulomb repulsion
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Excitation transfer
D2
4He
Phonon mode
AZ*
AZ
Indirect evidence from experiment implicates AZ = 4He, and theory and experiment suggest that AZ* is a localized two-deuteron state
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Basic model
(1) (2)†
1 2 0
(1) (2)† †
1 2
ˆ ˆˆ ˆ ˆ
2
2 2ˆ ˆ ˆ ˆ
z z
G x x
S SH E E aa i E
S SV e a a V a a
This kind of model is first one relevant to experiment
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Strong-coupling limit
When the coupling between the receiver-side two-level systems and oscillator is strong, then the problem simplifies
01 GV ne S M S M
E
0
ˆ, , , 1,
S M n n H S M n
E g
When the excitation transfer step is the bottleneck, then
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Coupling between nuclei and phonons
*f , , , , , ,
, ,
fi f f n i i i
i f i f i f i f
M V
d d d d
ξ q ξ q
q q ξ ξ q q ξ ξ
, i f i f q q q A q b f i q A q b
, f ii f
ξ ξ r r
P. L. Hagelstein et al, Proc. ICCF14
Strong force interaction matrix element expressed in terms of phonon coordinates and internal nuclear coordinates
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Can we calculate it for real?
Recent work focuses on computation of phonon nuclear coupling for the simpler 3-body version of the problem p+d 3He + Q
First need wavefunctions and nuclear force model
2
2 2 21 2 3 1 2 3 1 2 3 1 2 3, , , , , ,
2 nE VM
r r r r r r r r r
Simplest reasonable approximation for wavefunction
1 2 3 S D D D
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Full computational mesh
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Example S channel wavefunction using the Hamada-Johnston potential
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Simplest model for dynamics
02 2
2 0 22
0
0 2
00 2
0
=
D DD D He thresh
D
He HeHe D He thresh
He
J D He threshp
N NdN N N n n
dt
N NdN N N n n
dt
n nd En N N n n
dt
Molecular D2 in lattice lost in reaction, replaced by diffusion4He created in reaction, removed by diffusionPhonons produced by reaction and by deuterium flux, lost to thermalization
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Where is the D2?
No D2 in the bulk due to occupation of antibonding sites
Conjecture that D2 forms at vacancy sites in codeposition region near cathode surface
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What oscillator modes?
Beat frequency (THz)
0 5 10 15 20 25 30
Exc
ess
pow
er (
mW
)
0
100
200
300
Frequency width (THz) (THz) 8.3 0.70 15.3 0.44 20.4 0.68
Results from dual laser experiments of Letts, Proc. ICCF14 and ACS Sourcebook vol 2
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Dispersion curve for PdD
L E Sansores et al J Phys C 15 6907 (1982)
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Trying out the model
02 2
2 0 22
0
0 2
00 2
0
=
D DD D He thresh
D
He HeHe D He thresh
He
J D He threshp
N NdN N N n n
dt
N NdN N N n n
dt
n nd En N N n n
dt
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Example: fast He diffusion
Active region:A = 1 cm2
r = 100 nm
D2 parameters:f[vacancy] = 0.25f[D2] = 0.005N[D2] = 1.8 x 1015
D2 = 2 x 10-8 sec
4He parameters:DHe = 1.3 x 10-14 cm2/secHe = r2/DHe = 2.1 hr
Phonon mode:f0 = 8.3 THzQ = 20
Deuterium flux:Pflux = 1 Watt/cm3
nthresh = 100
Basic reaction rate:0 = 1/(3 hr)
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Evolution of dideuterium, 4He
t (hr)
0 5 10 15 20
ND
2,
N4
He
x10
14
0
1
2
3
4
5
6
D2
4He
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Excess power
t (hr)
0 5 10 15 20
Pxs
(W
atts
)
0.00
0.02
0.04
0.06
0.08
0.10
0.12
0.14
0.16
0.18
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Number of phonons
t (hr)
0 5 10 15 20
n
10-1
100
101
102
103
104
105
106
107
Thermal: 0.36 Flux generated (1 W/cm3): 700 Pxs generated: 107
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Example: slow He diffusion
Active region:A = 0.1 cm2
r = 500 nm
D2 parameters:f[vacancy] = 0.25f[D2] = 0.005N[D2] = 3.0 x 1014
D2 = 2 x 10-8 sec
4He parameters:DHe = 1.3 x 10-14 cm2/secHe = r2/DHe = 53.4 hr
Phonon mode:f0 = 8.3 THzQ = 20
Deuterium flux:Pflux = 1 Watt/cm3
nthresh = 100
Basic reaction rate:0 = 1/(1.5 hr)
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Evolution of dideuterium, 4He
t (hr)
0 50 100 150 200
ND
2, N
4H
e
1013
1014
1015
1016
1017
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Excess power
t (hr)
0 50 100 150 200
Pxs
(W
atts
)
0.0
0.2
0.4
0.6
0.8
1.0
1.2
1.4
1.6
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Thinking about simulations
There are several other parts to the problem:
•Loading•Codeposition•Dideuterium•Deuterium flux
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Loading deuterium into Pd
D2O
OD-
D
M. Volmer
Electrochemical current density J loads 1 D per charge.
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Deuterium loss from PdD
D
DD2
J Tafel
Deuterium on the surface combines to make D2 gas. Rate depends on deuterium potential and the surface blocking.
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Simple loading model
Electrochemical current density J determines surface loading x = D/Pd given surface coverage
x R x J
Surface loading determined by balance between deuterium input from J, and D2 gas release
Kunimatsu et al Proc. ICCF3 (1992)
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An additional pathway
D2O
OD-
D2
D
J Heyrovsky
If the chemical potential of deuterium is high, then the electrochemical current density J contains a part that deloads deuterium
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Reduction of loading at high J
Data of Akita et al,ICCF4 (1994)
Model of Zhang et al,J Electronal. Chem.(1997).
Volmer-Tafel
Volmer-Tafel-Heyrovsky
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Electrochemical models
•S. Szpak, C. J. Gabriel, J. J. Smith, R. J. Nowak, J. Electroanalyt. Chem. 309 273 (1991)
•T. Green and D. Britz, J. Electroanalyt. Chem. 412 59 (1996)
•W-S Zhang, X-W Zhang, H-Q Li, J. Electroanalyt. Chem. 434 31 (1997)
•W-X Chen, Int. J. Hydrogen Energy, 26 603 (2001)
…and many others
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Deuterium diffusion model
DD D
nBn
t
Diffusion model in - region with flat chemical potential:
D Dn D nt
Onsager-type diffusion model for higher loading:
Data available for low concentration, but little available for high loading
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Chemical potential model
! !
! ! !
O O T T
O T
M E M EO TO T
M M O O O T T T
N NQ e M M M
M N M M N M
H/Pd
0.0 0.2 0.4 0.6 0.8 1.0 1.2
rela
tive H
(eV
)0.1
0.2
0.3
0.4
0.5
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Relation to Voc
E. Storms, Proc. ICCF7 p. 356 (1998)
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Connection with electrochemical models
W-S Zhang et al (1997)
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Codeposition
Pd+2Pd+2
Anodic current Cathodic current
Conjecture that a small amount of Pd is stripped off during anodic current cycles, and then codeposited during subsequent cathodic loading [most of the Pd in solution is Pd(OH)4
-2 , Mountain and Wood (1988)]
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Argument for codeposition
The elemental analysis of the surface of Pd cathodes used in Fleischmann-Pons experiments show Pt, Cu and other impurities at depths > 100 nm [Hagans, Dominguez, and Imam ICCF6 p. 249 (1996)]
Szpak experiment gives similar results with codeposition on Cu
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Vacancies in host lattice
Vacancies in host metal lattice are thermodynamicallyfavored at high loading
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Pd lattice structure (fcc)
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PdD lattice structure (fcc)
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PdD Host lattice vacancy
Deuterium atoms relax toward host vacancy
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D2 near vacancy
Propose that molecular D2 can occur near vacancy
•Little in the way of discussion in literature•Possible to test with NMR experiments•Precedent in dihydrogen molecules•First QM computation of Me-H2 done for Pd-H2
Pd-H2: dPdH = 1.67-2.05 Angstroms dHH < 0.81 Angstroms
Experimental verification of Pd-H2 in low temperature experiments (1986)
G J Kubas, Metal dihydrogen and -bond complexes, (2001)
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Dihydrogen complex
Pd
H H
PdH2
Pd
H2
Pd-H2
Palladium sigma-bonded dihydrogen
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Molecular D2 fraction
D/Pd
0.0 0.2 0.4 0.6 0.8 1.0Fra
ctio
nal D
2 o
ccup
atio
n of
vac
ancy
site
s
0.000
0.001
0.002
0.003
0.004
0.005
Need high loading to make vacancies during codeposition, then need high Loading for D2 to form near the vacancies
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Flux heating
The deuterium flux produces local heating
In an Osager formulation the current is related to the chemical potential
The resistive power per unit volume is
J D DP J
D DBn J
2
J
D
P
V n B
J
Important as mechanism to stimulate optical phonon modes
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Conclusions
•Biggest theory issue is splitting big quantum into many small ones
•Donor-receiver type spin-boson model augmented with loss proposed
•Coupling matrix (with Ue=115 eV) estimated to be about right size
•Detailed computation in progress
•Basic model proposed for dynamics
•Dideuterium formation in vacancies in outer codeposited layer
•Deuterium flux stimulates optical phonons