Microsoft Power Point - Phan Tich Trai Phieu
Transcript of Microsoft Power Point - Phan Tich Trai Phieu
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CHUYN
PH N T CH L A CHN TR I PHI U
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I. Li tc v ri ro ca u t tri phiu
II. nh i tri hiu
III. o lng li sut tri phiu
IV. Thi gian o hn bnh qun (Duration)
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I. Li tc v ri ro ca u t tri phiu
II. nh gi tri phiu
1.1. Li tc:
I. Li
tc v + Tin li nh kIII. o lng li sut tri phiu
IV. Thi gian o hn bnh qun (Duration)
ri rotri
phiu
+ Chnh lch gi
+ Li ca li
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+ Ri ro li sut
+ Ri ro ti u t
1.2. Ri ro:
I. Li
+ Ri ro thanh ton
+ Ri ro lm pht
+ Ri ro t gi hi oi
+ Ri ro thanh khon
ri rotri
phiu
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1.3. Cc nhn t nh hng gi tri phiu
1.3.1. Kh nng ti chnh ca ngi cung
cp tri phiu1.3.2. Thi gian o hn
1.3.3. D kin v lm pht
1.3.4. Bin ng li sut th trng
1.3.5. Thay i t gi hi oi
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2.1. nh gi tri phiu thng thng
II. nh gi tri phiu
2.2. nh gi tri phi u khng tr li nh k
2.3. nh gi tri phiu chuyn i
2.4. nh gi tri phiu c li sut th ni
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Xc nh gi tr l thuyt ca tri phiu mt cch
II. nh gi tri phiu
c n x c v c ng ng.
Gi tr ca tri phiu c nh gi bng cch xc
nh hin gi ca ton b thu nhp nhn c trongthi gian hiu lc ca tri phiu.
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2.1. nh gi tri phiu thng thng
(Straight Bond)
( ) ( ) ( )nn2 r1
F
r1
C
r1
C
r1
CP
++
+++
++
+=
Trong :P: gi tri phiu
n: s nm cn li cho n khi o hnC: s tin li couponr: li sut chit khuF: mnh gi tri phiu
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Cng thc tng qut:
+=
n
nt
FC
P =
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Trng hp 1: tr li nh k mt nm mt ln
-nn1 - (1 r) +
r
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VD: Cng ty A pht hnh tri phiu li sut
15%/nm, mnh gi 1.000.000 , 15 nm o hn.
Li sut ang lu hnh 10%/nm. Tr li nh k
n m n. y t n n g c a tr p u
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-2n2nC 1 - (1 r/2) +
Trng hp 2: tr li nh k 6 thng mt ln
r2 r/2
=
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VD: Cng ty A pht hnh tri phiu li sut
12%/nm, mnh gi 500.000 , 10 nm o hn.
Li sut ang lu hnh 10%/nm. Tr li nh k
.
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2.2. nh gi tri phiu khng tr li nh k
(Zero coupon bond)
Fn(1 r)
=+
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VD: mt tri phiu c thi gian o hn l 20nm, nhng khng tr li nh k m ch tr vn
gc l 1.000.000 vo cui nm th 20. Nu hin
nay, li sut trn th trng l 10% th ngimua tri phiu phi tr bao nhiu tin mua
tri phiu ny?
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Gi tri phiu c quan h nghch bin vi li sut
K o hn cng xa th gi tri phiu cng nhy cm
Quan h gia tri phiu v li sut
vi bin i li sut
Vi mt mc bin i li sut nht nh, mc bin
ng gi tri phiu (tnh bng %) gim dn nu kodi k o hn.
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Vi cng 1 k o hn, cng mc bin ng li sut,
% Lndo gim li sut cao hn % l do tng li sut
Quan h gia tri phiu v li sut
Li sut danh ngha cng nh, nh hng ca bin
ng li sut th trng cng ln.
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D on li sut gim mua tri phiu c li sut
danh ngha thp v k o hn xa.
Chin lc:
D on li sut tng bn khng tri phiu c
li sut danh ngha thp v k o hn xa.
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- Gi chuyn i (Conversion Price):
2.3. nh gi tri phiu chuyn i
(Convertible Bond)
Mnh gi ca tri phiu chuyn i
- T l chuyn i (Conversion Ratio):
T l chuyn i =Mnh gi ca tri phiu chuyn i
Gi chuyn i
T l chuyn i
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- Gi tr tri phiu khng thc hin chuyn i = gi
tr tri phiu thng thng
=
- Gi tr li ch chuyn i = Max (gi tr chuyn
i, gi tr tri phiu khng thc hin chuyn i)
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VD: Cui nm 2005, cng ty ABC pht hnh mt loitri phiu chuyn i vi li coupon 2,5%/nm,
mnh gi 1 triu ng, o hn ngy 1/1/2011.
Coupon c tr vo u mi nm, bt u t nm2007, bit t l chuyn i l 10. Vo 1/1/2006, cp
c giao dch vi gi 81.000 vi mc li sut yu
cu 5%/nm.Nh u t c nn thc hin quyn chuyn i vo
ngy 1/1/2006 khng?21
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Dng tin ca tri phiu th ni:
Dng tin c li sut th ni nhn c t li sut
th trn khn c hn chnh l ch. Dn tin n
2.4. nh gi tri phiu c li sut th ni
(Floating rate Bond)
bao gm c khon thanh ton mnh gi vo lc o
hn. l dng tin ca ck tham chiu.
Dng tin bit da trn khon chnh lch giacc khon thanh ton ca tri phiu. Dng tin ny
c nh gi theo cc k thut v gi tr hin ti.22
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Gi ca tri phiu l tng hai mc gi trn.
Cng c tham chiu lun c nh gi theo mnh gi.
Gi ca cng c th ni li sut s bng gi ca chngkhon tham chiu cng vi dng tin ca khon chnh
lch c nh.
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VD: cng ty X pht hnh tri phiu c mnh gi500.000 , k hn 7 nm, vi li sut bng bnh qun li
sut tin gi tit kim 12 thng tr sau ca VCB, ACB,
STB, OCB, MHB cng thm 4,5%/nm. Hy nh gitr p u tr n t r ng su t t tr ng u t
tri phiu ny l li sut bnh qun cng 2,5%/nm, li
sut bnh qun ca 5 ngn hng trn ang l 11,5%.
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III. o lng li sut tri phiu
3.1. Thc o li sut hin hnh (Current Yield)
3.2. Thc o li sut o hn (Yield to Maturity)
3.3. Thc o li sut chuc li (Yield to Call)
3.4. Thc o li sut chnh lch gi (Capital Gain Yield)
3.5. Li ca li
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Li sut hin hnh (CY) l t l gia li coupon hng
nm vi gi th trng.
3.1. Thc o li sut hin hnh (Current Yield)
CY = C / P
ngha: mt ng vn u t b ra cho tri phiu th
hng nm thu c bao nhiu ng tin li.
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Vd: mt tri phiu c mnh gi 1.000.000 , li sut
coupon 10% hin ang c bn trn th trng vi
3.1. Thc o li sut hin hnh (Current Yield)
g . . . u mua r p u n y
sut sinh li hin hnh l bao nhiu ?
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Li sut o hn l mc li sut s lm cho gi tr hin
ti ca cc dng tin m ngi u t nhn c t tri
phiu bng vi gi tri phiu.
3.2. Thc o li sut o hn (Yield to Maturity)
( ) ( )
n
t nt 1
C FP
1 y 1 y== +
+ +
ngha: mc li sut tng hp m NT nhn c
trn tri phiu t khi mua nm gi n cho n khi
o hn. 28
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3.3. Thc o li sut chuc li (Yield to Call)
Li sut chuc li l li sut hon vn lm cho gi tr
hin ti ca cc dng tin trn tri phiu c mua li
( ) ( )
m
t mt 1
C FP 1 y 1 y=
= + + +
trc khi o hn b ng vi gi ca tri phi u hin nay.
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1 0
0
P PCG
P
=Li tc do chnh lch gi:
3.4. Thc o li sut chnh lch gi
(Capital Gain Yield)
Total Yield = CY + CG
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VD: ng A mua tri phiu c mnh gi 1.000.000 ,vi gi 990.000 , tri phiu ny tr li 9% cho tri ch.
D kin cui nm gi tri phiu tng ln l 1.080.000 .
Gi s ng A bn tri phiu vo cui nm sau khi nhn li tri phiu. Vy cc mc li tc ng nhn c
sau 1 nm nm gi l bao nhiu?
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Tng li tc tim nng ca 1 tri phiu bng tng hai
khon l li coupon v li ca li:
3.5. Li trn li
n(1 r) 1C x
r
+
n(1 r) 1
C x nCr
+
Li coupon + Li trn li =
Li trn li =
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VD: tri phiu c li sut danh ngha 14%, k hn 5
nm, mnh gi 100.000. Gi s nh u t lnh licoupon hng nm v u t ngay vo tin gi tit kim
ngn hng vi li sut 12%. Hi cho n khi o hn
tng li tc tim nng l bao nhiu? Li trn li l bao
8.940812%
112%)(1
x100.00014%
5
=
+
nhiu?
Li trn li = 88.940 14.000 x 5 = 18.940 33
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IV. Thi gian o hn bnh qun (DURATION)
Duration l thi gian o hn bnh qun gia quyn
ca cc dng tin ca tri phiu.
( ) ( ) ( )nn2 y1y1y1y1P
++
+++
++
+=
Trong :F: gi tr hon tr khi o hny: li sut cho ti khi o hn hay li sut theo yu cu
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( ) ( ) ( )
++
+++
++
++= nn2
1nF
y1nC
12C
y11C
11dP
yyydy
Thi gian o hn bnh qun Macaulay:
( ) ( )1 1 1
n
t nt
tC nF
y yMacaulayDurationP
=
+
+ +=
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MDyPdy
dP
+=
1
11
dP 1= - MD dy
P 1+y
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( )1
acaulayDurationModifiedDuration
y=
+
dP= -ModifiedD dy
P
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VD: Tri phiu mnh gi 100.000 c pht hnh vo
1/3/2005, k hn 10 nm, li sut 7,5%/nm, tr li 6
thng/ln. Hin nay (1/3/2010) tri phiu c bn vi gi
bng mnh gi. Tnh thi gian o hn bnh qun ca triphiu trn.
Hy xem xt s bin ng gi tri phiu trn nu li sut
o hn tng hay gim 2,5%?
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F () C YTM P ()
100000 7.50% 7.50% 100000
K tr li C PV PV *t
t ()
1 3750 3614.458 3614.458
2 3750 3483.815 6967.63
3 3750 3357.894 10073.68
1/3/2011
1/9/2011
1/9/2010
Thi gian o hn
1/3/2015
Ngy tr li
4 3750 3236.524 12946.1
5 3750 3119.541 15597.71
6 3750 3006.787 18040.72
7 3750 2898.108 20286.75
8 3750 2793.357 22346.86
9 3750 2692.392 24231.53
10 103750 71797.12 717971.2
100000 852076.7
MD = 4.26
1/3/2014
1/9/2014
1/3/2015
1/3/2012
1/9/2012
1/3/2013
1/9/2013
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F () C YTM P ()
100000 7.50% 5.00% ?
K tr li C PV
t ()
1 3750 3658.537
2 3750 3569.304
3 3750 3482.248
1/9/2010
Thi gian o hn
1/3/2015
Ngy tr li
1/3/2011
1/9/2011
4 3750 3397.315
5 3750 3314.454
6 3750 3233.613
7 3750 3154.745
8 3750 3077.8
9 3750 3002.731
10 103750 81049.33
PV = 110940
1/3/2014
1/9/2014
1/3/2015
1/3/2012
1/9/2012
1/3/2013
1/9/2013
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F () C YTM P ()
100000 7.50% 10.00% ?
K tr li C PV
t ()
1 3750 3571.429
2 3750 3401.361
3 3750 3239.391
1/3/2011
1/9/2011
1/9/2010
Thi gian o hn
1/3/2015
Ngy tr li
4 3750 3085.134
5 3750 2938.223
6 3750 2798.308
7 3750 2665.055
8 3750 2538.148
9 3750 2417.283
10 103750 63693.5
PV = 90348
1/3/2014
1/9/2014
1/3/2015
1/3/2012
1/9/2012
1/3/2013
1/9/2013
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VD: Tri phiu quc t do VN pht hnh vo 10/2005 c
thi gian o hn l 10 nm, mnh gi $100, tr li hng
nm vi li sut l 7,125%/nm. Vo thng 10/2009, li
sut th trng dng chit khu i vi tri phiu ny l
6,875%/nm. Hy xc nh thi gian o hn bnh qun
ca tri phiu trn.
Cng vo thi im trn, thng tin cng b nh mc tn
nhim ca VN gim xung, iu ny lm cho li sut chitkhu tng ln 7%/nm, theo bn gi tri phiu trn s
bin ng nh th no?42
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Gi
Mi quan h gia gi tri phiu v li sut
Li sut
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V. li (Convexity)
2 n
d P 1 t(t+1)C n(n+1)F 1= = li( ) ( )
t+2 n+22t=1dy P P1+y 1+y
2dP 1= Convexity (dy)P 2
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2dP 1= - ModifiedD x dy + Convexity (dy)P 2
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Cng thc tnh gn ng Duration v Convexity
Effective Duration (ED)
ED =
Gi khi ls gim x% - Gi khi ls tng x%
Effective Convexity (EC)
.
ED =Gi khi ls gim x% + Gi khi ls tng x% - 2 . Gi ban u
2 . Gi ban u . x246
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Cc thuc tnh ca li
+ Khi y tng (gim) li gim (tng)
+ Khi v n l xc nh, li sut cou on cn
thp li ca tri phiu cng ln
+ Khi y v ModifiedD l xc nh, li sut coupon
cng thp li cng nh
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Gi A B
B c li ln hn A
Li sut
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F () C YTM P ()
100000 7.50% 7.50% 100000
K tr li C PV V *t*(t+1t ()
1 3750 3358 6716
2 3750 3237 19422
3 3750 3120 37440
4 3750 3007 60140
1/9/2010
Thi gian o hn
1/3/2015
Ngy tr li
1/3/2011
1/9/2011
1/3/20125 3750 2898 86940
6 3750 2793 117306
7 3750 2692 150752
8 3750 2595 186840
9 3750 2501 225090
10 103750 66701 7337110
= 8227756
Convexity (na nm) 82.28
Convexity (nm) = 20.57
1/3/2014
1/9/2014
1/3/2015
1/9/2012
1/3/2013
1/9/2013
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VD: Tri phiu pht hnh vo thng 9/2005 c thi hn 7nm, mnh gi 100.000 , li sut 10%/nm. Vi li sut
th trng vo 9/2010 l 12%/nm, hy tnh li ca
tri phiu trn bit rng tri phiu tr li mt nm 2 ln
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