mgng molecules ftoI¥e x atoms - Open Computing Facility · I mol H atoms H: (11.19g) 1.008 I mol O...

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by Remi Leano | Fall 2019 ocf.berkeley.edu/~rleano CHEM001 NOTESHEET : CHAPTERS 7 & 8 CHAPTER 7 EMPIRICAL FORMULAS TELL YOU THE MOLECULAR FORMULAS ELL YOU HOW MANY LAW OF MULTIPLE PROPORTIONS : TWO SIMPLEST OR MOST REDUCED RATIO OF ATOMS OF EACH ELEMENT ARE IN THE COMPOUNDS CAN HAVE IDENTICAL ELEMENTS IN A COMPOUND . COMPOUND . EMPIRICAL FORMULAS AND DIFFERENT MOLECULAR FORMULAS . AVOGADRO 'S NUMBER × ( # ATOMS PER ÷ molar mass MOLECULE ) GRAMS - MOLES # MOLECULES - # ATOMS ng x mg = my x AVOzmomfY = molecules x ftoI¥e = atoms CHAPTER 8 =

Transcript of mgng molecules ftoI¥e x atoms - Open Computing Facility · I mol H atoms H: (11.19g) 1.008 I mol O...

Page 1: mgng molecules ftoI¥e x atoms - Open Computing Facility · I mol H atoms H: (11.19g) 1.008 I mol O atoms O: (88.79 g) 16.00 go — 11.10 mol H atoms 5.549 mol O atoms The formula

by Remi Leano | Fall 2019 ocf.berkeley.edu/~rleano

CHEM001 NOTESHEET : CHAPTERS 7 & 8

CHAPTER 7

EMPIRICAL FORMULAS TELL YOU THE MOLECULAR FORMULAS ELL YOU HOW MANY LAW OF MULTIPLE PROPORTIONS : TWO

SIMPLEST OR MOST REDUCED RATIO OF ATOMS OF EACH ELEMENT ARE

IN THE COMPOUNDS CAN HAVE

IDENTICAL

ELEMENTS IN A COMPOUND . COMPOUND .EMPIRICAL FORMULAS AND DIFFERENT

MOLECULAR FORMULAS .

AVOGADRO 'S NUMBER

× (# ATOMS PER÷molar mass MOLECULE )

GRAMS - MOLES # MOLECULES - # ATOMS

ngxmg = myxAVOzmomfY = molecules xftoI¥e = atoms

CHAPTER 8

=

7.1 Moles and Molar Masses - chemhelp.us6+Notes,+16-17.pdfEx. 1.00 mol C = 6.022e23 atoms C = 12.011 g C mol Avo's # Molar Mass 7.1 Moles and Molar Masses ~ 2 ~ ... atoms of one element

7.1 Moles and Molar Masses - chemhelp.us6+Notes,+16-17.pdfEx. 1.00 mol C = 6.022e23 atoms C = 12.011 g C mol Avo's # Molar Mass 7.1 Moles and Molar Masses ~ 2 ~ ... atoms of one element

mol/(l.pHM )

mol/(l.pHM )

mrvriend.weebly.commrvriend.weebly.com/uploads/5/6/7/0/5670602/answers_unit...4 15 x 10 molecx 1 mol 1 mol 23 16.Og -1.10 x 10 1 mol g atoms 6.02x 10 molecules 1 mol 175 atoms x 23

mrvriend.weebly.commrvriend.weebly.com/uploads/5/6/7/0/5670602/answers_unit...4 15 x 10 molecx 1 mol 1 mol 23 16.Og -1.10 x 10 1 mol g atoms 6.02x 10 molecules 1 mol 175 atoms x 23

Dr. S. M. Condren Polonium-210 Poisoning #atoms Po 210 = (1.0 gPo 210 Cl 2 )(1g/10 6 g) (6.02x10 23 atoms/mol) (1mol/280gPoCl 2 ) = 2.2x10 15 atoms t 1/2.

Dr. S. M. Condren Polonium-210 Poisoning #atoms Po 210 = (1.0 gPo 210 Cl 2 )(1g/10 6 g) (6.02x10 23 atoms/mol) (1mol/280gPoCl 2 ) = 2.2x10 15 atoms t 1/2.

Molar Mass - Chemchem.ws/dl-1007/ch02c-molar_mass.pdf · ‣ molar mass grams amu mol atoms (& molecules) molecular scale Avogadro’s molar scale number 1 mol = 6.022 x 1023 Atomic

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Mgng People Ppt

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12.1 Using Everyday Equations - Preston Treend...Given 6.70 mol of Na and 3.20 mol of Cl2. Step 1. What is the limiting reagent? HAVE NEED 6.70 mol Na 3.20 mol Cl2 2 mol Na 1 mol Cl2

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How many grams in 2.00 mol Fe? or 3.00 mol Fe? or 0.0587 mol Fe? Molar Mass Conversions 1 mol of Fe atoms is 55.85 g/mol.

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The MoleThe Mole...3 1 mol AgNO 3 1.96 24 10 formula units of AgNO 3 4. Challenge Calculate the number of oxygen atoms in 5.0 mol of oxygen molecules. Oxygen is a diatomic molecule,

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Chemistry. Atomic structure ATOMS, ATOMS, ATOMS!!!!!!!!

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5.1 Atoms are the smallest form of elementsimages.pcmac.org/.../Uploads/Presentations/Ch_5.pdf1 5.1 Atoms are the smallest form of elements. 2 All matter is made of atoms ... 1 mol.

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ars.els-cdn.com · Web viewis Faraday’s constant (96485.3 C mol-1). And n is the number of moles of metal on the electrode (mol cm-2). All the Co atoms were assumed to be accessible

ars.els-cdn.com · Web viewis Faraday’s constant (96485.3 C mol-1). And n is the number of moles of metal on the electrode (mol cm-2). All the Co atoms were assumed to be accessible

Chapter 23 Solutions - · PDF fileChapter 23 Solutions ... 6.02 ×10 23 atoms mol 47.0 electrons atom ... each person has a charge q =(0.01)(1.6×10 −19 C)

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Periodic Properties electron configurations properties hydrogen atom1 electron to remove e - n f = ∞ E = x 6.022 x 10 23 atoms atommol = 1311 kJ mol.

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