MF1 DESIGN

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    529 TECHNICAL UNIVERSITY OF CLUJ-NAPOCA

    ACTA TECHNICA NAPOCENSIS

    International Conference on Engineering Graphics and Design

    12-13 June 2009

    MF1 DESIGN

    Florian Ion PETRESCU, Relly Victoria PETRESCU

    Abstract: The paper presents a new and original internal-combustion engine. It is presenting a method in

    determining the kinematics and the efficiency of a new mechanism, MF1, proposed (designed) to work

    and be tested like an internal-combustion engine. One determines the mechanical momentary efficiency,

    when the mechanism works like a steam roller and when the mechanism works like a motor. The

    determined efficiency is different in the two described situations. One presents an original way to

    determine the dynamic efficiency too. The dynamic momentary efficiency is the same in the two

    situations: when the mechanism works like a steam roller and when it works like a motor. One

    determines the efficiency without friction, but one can anytime add the effect of friction modulus. One

    presents the dynamic kinematics of this mechanism too: the dynamic velocity and the dynamic

    acceleration. When the constructive parameters are normal, the dynamic velocities take the same values

    like the classical speeds and the dynamic accelerations take the same values like the classical

    accelerations.

    Key words: Efficiency, force, piston, crank, connecting-rod, motor, stroke, bore, dynamic-velocity,

    dynamic-acceleration, dynamic-efficiency.

    1. INTRODUCTION

    The paper presents shortly a new andoriginal internal-combustion engine, MF1. The

    originality consists in the way of determining

    the mechanical and dynamic efficiency and in

    the way of determining the dynamic velocities

    and accelerations. In this paper one determines

    the efficiency of piston mechanism in two

    ways: 1.When the piston mechanism works like

    a motor; 2.When the piston mechanism works

    like a steam roller.

    2. PRESENTING THE KINEMATICS OF

    MF1

    In the picture number 1, one can see the

    kinematics outline of the new presented motor

    mechanism (Motor, Florio 1), [2].

    The first modification of this model, having

    in view the classical model (Otto engine

    mechanism), is the use of two connecting-rod,

    (2 and 3) and the use of B couple, a dual

    couple: of rotation and translation.

    This motor mechanism is a new mechanism

    and his functionality will be different from the

    classical mechanisms functionality. The greatadvantage of this mechanism is that it can be

    regulated to have a bigger zone with constant

    acceleration at the piston (the element number

    five). The efficiency of this mechanism is the

    same like the Otto mechanism. The structural

    group 2-4 (a dyad) can improve the motor

    functionality without damage of power. The

    kinematics relations are the following (1-11):

    110

    2

    1

    2

    0

    2

    sin2 +=

    lllla (1)

    a

    l 112

    coscos

    = (2)

    3

    2211

    3

    coscoscos

    l

    lle

    = (3)

    332211 sinsinsin ++= lllyD (4)

    1

    211

    2

    )cos(

    =

    a

    l (5)

    a

    lla 1110

    cos=& (6)

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    530

    )]cos()cos(

    )sin(cos[

    2321

    2310

    3

    113

    +

    =

    b

    lla

    l+

    (7)

    333222

    111

    coscoscos

    +++=

    lllyD

    &

    (8)

    x

    1

    2

    3

    4

    5

    O

    y

    A

    B

    C

    D

    0

    0

    l1

    l2

    l3

    l0

    e

    1

    2

    3

    0

    MOTOR FLORIO1-MF1

    2003 FlorianPETRESCU

    The Copyright-Law

    Of March, 01, 1989

    U.S. Copyright Office

    Library of Congress

    Washington, DC 20559-6000

    202-707-3000

    yD

    a

    b

    Fig. 1. The MF1 kinematics outline

    a

    al &= 22121112

    )sin()( (9)

    3

    232123

    232121

    231230

    23110

    3

    113

    )]sin()cos()(

    )cos()sin()(

    )cos(cos)(

    )sin(sin[

    +

    +

    =

    a

    a

    b

    b

    l

    lla

    l

    &

    (10)

    333

    33

    2

    3222

    22

    2

    211

    2

    1

    cos

    sincos

    sinsin

    +

    ++

    +=

    l

    ll

    llyD&&

    (11)

    3. DETERMINING THE MOMENTARY

    MECHANICAL EFFICIENCY

    WHEN THE MECHANISM WORKS LIKE

    A STEAM ROLLER

    One can determine the momentary

    mechanical efficiency, when the mechanism

    works like a steam roller, if one determines the

    distribution of forces, from the crank to the

    piston (figure 2); relations (12-19) [2]:

    =

    =

    )cos(

    )sin(

    12

    12

    m

    mn

    FF

    FF

    A

    (12)

    )cos( 12 == mFb

    aF

    b

    aF

    AC (13)

    =

    =

    )sin(

    )cos(

    32

    32

    CCFF

    FF

    I

    nIn

    (14)

    )]sin()cos(

    )cos()[sin(

    )sin()cos(

    )cos()sin(

    )sin(

    )cos(

    3212

    3212

    3212

    3212

    32

    32

    +

    +=

    =+

    +=

    =+

    +=+=

    b

    a

    F

    Fb

    a

    F

    F

    FFFF

    m

    m

    m

    n

    II

    nT

    C

    C

    (15)

    =

    =

    3

    3

    cos

    sin

    TR

    TU

    FF

    FF (16)

    )]sin()cos(

    )cos(

    )[sin(sin

    3212

    32

    123

    +

    +

    =

    b

    a

    FF mU

    (17)

    xO

    A

    B

    C

    D

    1

    2

    3

    a

    b

    1

    Fm 2- 1

    FA

    Fn

    2

    2-

    3Fn

    FC

    3

    FT

    FR

    FU

    0

    MOTOR FLORIO1-MF1

    2003 Florian PETRESCU

    The Copyright-Law

    Of March, 01, 1989U.S. Copyright Office

    Library of Congress

    Washington, DC 20559-6000

    202-707-3000 Fig. 2. The MF1 distribution of forces, when the

    mechanism works like a steam roller

    ]cos

    )cos()cos()sin(cos

    )cos(cos[cos

    3

    23212310

    21221

    +

    +

    =

    a

    bl

    a

    lvv mU

    (18)

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    531

    ]cos

    )cos()cos()sin(cos

    )cos(cos[cos

    )]sin()cos(

    )cos()[sin(sin

    3

    23212310

    21221

    3212

    32123

    +

    +

    +

    +=

    =

    a

    bla

    l

    b

    a

    vF

    vF

    mm

    UU

    iC

    (19)

    4. DETERMINING THE MOMENTARY

    MECHANICAL EFFICIENCY

    WHEN THE MECHANISM WORKS LIKE

    A MOTOR

    One can determine the momentary

    mechanical efficiency, when the mechanismworks like a motor, if one determines the

    distribution of forces, from the piston to the

    crank (figure 3); relations (20-25) [2]:

    xO

    A

    B

    C

    D

    1

    2

    a

    b

    1

    Fm

    1- 2

    FA

    3

    2-

    3

    Fn

    FC

    3

    FRFN

    0

    FN

    2

    3

    Fn

    Fu1

    Fu2

    MOTOR FLORIO1-MF1

    2003 Florian PETRESCU

    The Copyright-Law

    Of March, 01, 1989

    U.S. Copyright Office

    Library of Congress

    Washington, DC 20559-6000

    202-707-3000

    Fig. 3. The MF1 distribution of forces, when the

    mechanism works like a motor

    =

    =

    3

    3

    cos

    sin

    mR

    mN

    FF

    FF (20)

    =

    =

    )sin(

    )cos(

    32

    32

    N

    Nn

    FF

    FF

    C

    (21)

    )sin(sin 323 == mFa

    bF

    a

    bF

    CA(22)

    =

    =

    )cos(

    )sin(

    212

    211

    AFF

    FF

    u

    nu (23)

    )]cos()sin(

    )sin()[cos(

    sin

    2132

    2132

    321

    =+=

    a

    b

    FFFF muuu

    (24)

    =

    +

    +=

    =

    n

    N

    a

    l

    a

    bl

    n

    a

    b

    N

    iM

    )cos(cos

    )cos()cos()sin(cos

    coscos

    )]cos()sin(

    )sin()[cos(sin

    2122

    23212310

    31

    2132

    21323

    (25)

    5. DETERMINING THE MOMENTARY

    DYNAMIC EFFICIENCY

    The dynamic efficiency of the mechanism is

    the same, anytime (when the mechanism works

    like a steam roller and when its working like a

    motor). It can be determined approximately

    with the relation (26):

    =

    ===

    312

    2

    3

    2

    2:

    sinsin

    with

    D

    iC

    D

    iM

    D

    i

    (26)

    One can determine the exactly momentary

    dynamic efficiency of the mechanism, if one

    takes in calculation the dynamic velocities (in

    this case the speeds distribution is the same like

    the forces distribution), see the relations (27-

    29):

    )]cos()sin(

    )cos()[sin(sin

    1232

    32123

    +

    =

    a

    b

    F

    F

    m

    u

    (27)

    )]cos()sin(

    )cos()[sin(sin

    1232

    32123

    +

    =

    b

    a

    v

    v

    m

    u

    (28)

    )]}(2sin[)](2sin[4

    )(cos)(sin

    )(cos)({sinsin

    3212

    22

    12

    2

    32

    2

    32

    2

    12

    2

    3

    2

    ++

    ++

    +=

    baba

    D

    i

    (29)

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    532

    6. THE DYNAMIC KINEMATICS OF THE

    MECHANISM

    One can determine now the dynamic

    velocity (30) and the dynamic acceleration ofthe piston (31):

    )]cos()sin(

    )cos()[sin(sin

    1232

    3212311

    +

    =

    b

    a

    lvDin

    D

    (30)

    1132122

    3212

    323212

    12321232

    32121232

    1233212

    321233

    )]}sin()cos(

    )sin()cos(

    )()cos()cos(

    )()sin()sin()(

    )sin()sin()()cos(

    )[cos(sin)]sin()cos(

    )cos()[sin(cos{

    +

    ++

    ++

    +

    +

    +=

    lb

    aa

    b

    a

    b

    a

    b

    a

    b

    a

    aDinD

    &

    &

    (31)

    7. DISCUTION

    -2

    -1.5

    -1

    -0.5

    0

    0.5

    1

    1.5

    2

    0 100 200 300 400

    V(Din)/(l1.w)

    V(Cin)/(l1.w)

    n=5000[rot/min];l1=0.08;l2=0.3;l3=0.5;l0=0.15;e=0

    Fig. 4. The kinematical and dynamic velocities

    When the values of the constructive

    parameters are different from the normal, the

    dynamic speeds and the dynamic acceleration

    of the piston (30-31), are not the same like the

    classical kinematics values (8-11), see the

    pictures number (4 and 5):

    -200000

    -150000

    -100000

    -50000

    0

    50000

    0 100 200 300 400

    aD(D)

    aD(Cin)

    n=5000[rot/min];l1=0.08;l2=0.3;l3=0.5;l0=0.15;e=0

    Fig. 5. The kinematical and dynamic accelerations

    8. CONCLUSION

    Some mechanisms have the same parameters

    for the classical and for the dynamic kinematics

    (gears, cams with plate followers). At the

    presented mechanism, the dynamic-kinematics

    is different from the classical-kinematics, but, if

    the constructive parameters are normal, the

    dynamic velocities and accelerations practically

    take the same values like the classical speeds

    and accelerations.

    9. REFERENCES

    [1] Pelecudi, Chr., s.a. Mecanisme, E.D.P.,

    Bucuresti, 1985.

    [2] Petrescu, F.I., Petrescu, R.V., An original

    internal combustion engine, Proceedings of

    9th International Symposium SYROM, Vol.

    I, p. 135-140, Bucharest, 2005.

    DESIGNUL MOTOARELOR MF1Rezumat:Lucrarea prezintun nou motor cu ardere internde tip Otto. Se prezintcinematica i randamentul nouluimotor cnd mecanismul principal lucreazn regim de compresor i de motor. Se determindeasemenea randamentuldynamic, viteza i acceleraia dinamic.

    Florian Ion Petrescu, PhD. Eng. Assistant Professor at Polytechnic University of Bucharest, TMR

    Department (Theory of Mechanisms and Robots Department), [email protected],

    0214029632.

    Relly Victoria Petrescu, PhD. Eng., Lecturer at Polytechnic University of Bucharest, GDGI

    Department (Department of Descriptive Geometry and Engineering Graphics),

    [email protected], 0214029136.