Mean Absolute Deviation Statistics. 2 Vocabulary Mean Absolute Deviation (MAD) – the average...
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Transcript of Mean Absolute Deviation Statistics. 2 Vocabulary Mean Absolute Deviation (MAD) – the average...
Mean AbsoluteDeviation
Statistics
2
Vocabulary
Mean Absolute Deviation (MAD) – the average distance of data values from the mean
3
Example
3, 7, 10, 13, 17
What is the Mean Absolute Deviation of the data set:
4
Example
(3+7+10+13+17) / 5 = 10
Mean of these numbers is 10
Step 1: Find the mean of the data:
5
ExampleStep 2: Find the deviations (distance) of each value to the mean of the data:
Value Mean Deviation
3 10
7 10
10 10
13 10
17 10
7
3
0
3
7
6
ExampleStep 3: Find the mean (average) of the deviations:
Value Mean Deviation
3 10 7
7 10 3
10 10 0
13 10 3
17 10 7
7 + 3 + 0 + 3 + 7 = 20 / 5 = 4
7
ExampleSo, the Mean Average Deviation
= 4 What does this mean?
All the values, are, on average, 4 away from the mean
8
Example
0, 1, 5, 7, 11, 12, 20
What is the Mean Average Deviation of the data set:
9
Example
(0+1+5+7+11+12+20) = 56 / 7 = 8
Mean of these numbers is 8
Step 1: Find the mean of the data:
10
ExampleStep 2: Find the deviations (distance) of each value to the mean of the data:
Value Mean Deviation
0 8
1 8
5 8
7 8
11 8
12 8
20 8
8
7
3
1
3
4
12
11
ExampleStep 3: Find the mean (average) of the deviations:
8+7+3+1+3+4+12 = 38 / 7 = 5.4
Value Mean Deviation
0 8 8
1 8 7
5 8 3
7 8 1
11 8 3
12 8 4
20 8 12
12
ExampleSo, the Mean Average Deviation
= 5.4 What does this mean?
All the values, are, on average, 5.4 away from the mean
13Copyright © 2013 by Monica Yuskaitis
Bus Routes
14Copyright © 2013 by Monica Yuskaitis
Parents were complaining that their children were getting off the bus at different times every day, so the director decided to collect data to see whose times varied the most. He had two different drivers record the time it took to complete their bus routes for 5 days. Each had the same route but on different days.
Other Things You Should Be Aware of When Displaying Your Data
Copyright © 2013 by Monica Yuskaitis 15
Number of Observations 5
How it was measured Record Time elapsed on Bus route
Unit of Measurement Minutes
Nature of attribute Times to complete bus route
Overall Pattern To be seen
16Copyright © 2013 by Monica Yuskaitis
Here were the times in minutes for bus driver A and bus driver B:
A 55 45 60 59 50
B 54 52 51 56 55
Find the mean absolute deviation for each driver and compare as to which
driver’s times varied the most.
17Copyright © 2013 by Monica Yuskaitis
Step 1 – Find the mean of both sets of data.
A 55 45 60 59 50
B 54 52 51 56 55A5545605950+
269
B5452515655+
268/ 5 = 54 / 5 = 54
18Copyright © 2013 by Monica Yuskaitis
Step 2 – Subtract each time from the Mean. (Make a table to keep track.)
Time Mean Deviation
55 54
45 54
60 54
59 54
50 54
Driver A
1
96
5
4
19Copyright © 2013 by Monica Yuskaitis
Step 2 – Subtract each time from the Mean. (Make a table to keep track.)
Time Mean Deviation
54 54
52 54
51 54
56 54
55 54
Driver B
1
2
32
0
20Copyright © 2013 by Monica Yuskaitis
Step 3 – Find the mean of the Deviation Values
Deviation
1
9
6
5
4
Driver A Driver BDeviation
0
2
3
2
1
25 /5 = 5 8 = 1.6 /5
21Copyright © 2013 by Monica Yuskaitis
Step 4 – Compare the Mean Absolute Deviation Scores
Driver A Driver B
MAD = 5 MAD = 1.6
Which bus driverdid the director
need to reprimand?
Driver A
22Copyright © 2013 by Monica Yuskaitis 22Copyright © 2013 by Monica Yuskaitis
The owner of a drive-in wanted to make sure the customers were getting the same
amounts in their smoothies. So he had the waiters weigh and record the weight of each smoothie they made for 7 times.
Other Things You Should Be Aware of When Displaying Your Data
Copyright © 2013 by Monica Yuskaitis 23
Number of Observations 7 per waiter
How it was measured Weighed
Unit of Measurement Ounces
Nature of attribute Finding the Weight of smoothies
Overall Pattern To be seen
24Copyright © 2013 by Monica Yuskaitis 24Copyright © 2013 by Monica Yuskaitis
Here are the weights of the smoothies in ounces from waiter A and waiter B.
A 16.1 15.9 16 15.8 16.2 16.1 15.8
B 15.7 16.4 15.6 16.5 15.9 16.8 15.3
2525
How to Find the Mean Absolute Deviation
Step 1 – Find the mean weight from each waiter.
A16.115.916. 15.816.216.115.8+
B15.716.4
15.6 16.515.916.815.3+
.9
7)111.9
15.9
7)112.2
1 .16 6 0 16
111 211 .2
26Copyright © 2013 by Monica Yuskaitis
26
How to Find the Mean Absolute DeviationStep 2 – Subtract Each Weight from the
Mean. (Make a table to keep track.)Weight Mean Deviation
16.1 16
15.9 16
16 16
15.8 16
16.2 16
16.1 16
15.8 16
Wai
ter
A
.1
.1
0.2.2
.1
.2
27Copyright © 2013 by Monica Yuskaitis
27
How to Find the Mean Absolute DeviationStep 2 – Subtract Each Weight from the
Mean. (Make a table to keep track.)Weight Mean Deviation
15.7 16
16.4 16
15.6 16
16.5 16
15.9 16
16.8 16
15.3 16
Wai
ter
B
.3.4
.4
.5.1.8
.7
28Copyright © 2013 by Monica Yuskaitis
28
How to Find the Mean Absolute DeviationStep 3 – Find the mean of the deviations
Deviation.1
.1
0
.2
.2
.1
.2Wai
ter
A
Deviation.3
.4
.4
.5
.1
.8
.7Wai
ter
B0.9 /7 = 0.13 3.2 /7 = 0.46
29Copyright © 2013 by Monica Yuskaitis
How to Find the Mean Absolute DeviationStep 4 – Compare the Mean Absolute
Deviation scores.Waiter A Waiter B
MAD = .13 MAD = .46
Which waiterhas the leastamount ofvariance inpreparing
smoothies?
Waiter A