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Transcript of Mathematics* · PDF fileMathematics* St.*Bonaventure*College*and*High*School*...
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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Name: Class: ( ) Date: Mark: /29
Time: 40min, Full Marks: 29 SECTION A: Structure Questions 1. HKCEE MATH 1988 Q4
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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2. HKCEE A.MATH 1998 Q2
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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3. HKCEE MATH 1993 Q6
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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SECTION B: Multiple Choices (Correct answer 2M, Wrong answer -1M) Each question carry one CORRECT answer only. 4. HKCEE MATH 2008 II Q7
5. HKCEE MATH 2007 II Q4
Let x be the smaller one of two consecutive integers. If the sum of the squares of the two integers is less than three times the product of the two integers by 1, then
A. x2 + (x + 1)2 = 3x(x + 1) – 1 B. x2 + (x + 1)2 = 3x(x + 1) + 1 C. 3[x2 + (x + 1)2] = x(x + 1) - 1 D. 3[x2 + (x + 1)2] = x(x + 1) + 1
6. HKCEE MATH 2006 II Q8
7. HKCEE MATH 2006 II Q9
8. HKCEE MATH 2005 II Q5
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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9. HKCEE MATH 2005 II Q7
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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Solution: 1. (a) 9𝑥! − 𝑘 + 1 𝑥 + 1 = 0… ∗ ℎ𝑎𝑠 𝑒𝑞𝑢𝑎𝑙 𝑟𝑜𝑜𝑡, 𝑡ℎ𝑒𝑟𝑒𝑓𝑜𝑟𝑒,∆= 0 …1M
(𝑘 + 1)! − 4 9 1 = 0 …1M 𝑘! + 2𝑘 + 1− 36 = 0 𝑘! + 2𝑘 − 35 = 0 𝑘 − 5 𝑘 + 7 = 0 𝑘 = 5 𝑜𝑟 𝑘 = −7 …1A (b) If k takes the negative value obtained in part (a), that means take k=-‐7, then we have 9𝑥! − −7+ 1 𝑥 + 1 = 0… ∗ …1M 9𝑥! − −6 𝑥 + 1 = 0 9𝑥! + 6𝑥 + 1 = 0 (3𝑥 + 1)! = 0 …1M 3𝑥 + 1 = 0 𝑥 = − !
! …1A
Mathematics St. Bonaventure College and High School
Form 4, Quiz 4 (Ch1&2: Quadratic Equation I & II)
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2.