Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas...

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Mathematics of Chemistry The Mole

Transcript of Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas...

Page 1: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Mathematics of ChemistryThe Mole

Page 2: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Mole = a specific Quantitylike 1 dozen = 12

1. 22.4L of any gas2. 6.02x1023 molecules3. GFM gram formula mass

H2O H 2 x 1 = 2 O 1 x 16 = 16 18g = 1 mole**GFM is the mass of a 1mole sample of any

substance.**All base on C12 as the standard so……H1 has a mass of 1 and = 1/12 of Carbon

Page 3: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Gas Amount Volume Molecules Mass

H2 1 Mole

O2 1 Mole

CO2 1 Mole

Page 4: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Volume

MoleMoleculeMolecule

MassMass

Volume

22.4L22.4L

6.02x1023

GFM

GFM

6.02x1023

÷ X

Doc’s Mole Bridge

Page 5: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

What about atoms or particles?

Substance Quantity Volume(L)(L)(

Molecules Mass(grams)

AtomsOr

Particles

Mg 1 Mole 22.4L 6.02x1023 24g 6.02x1023

Atoms

H2 1 Mole 22.4L 6.02x1023 2g 1.02x1024

Particles

CO2 1 Mole 22.4L 6.02x1023 44g 1.86x1024

Particles

X 1

X 2

X 3

Page 6: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Mass to Mole and Mole to Mass

Page 7: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Volume to Mole and Mole to Volume

Page 8: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Volume to Mole and Mole to Volume

Page 9: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Determine percent compositionMass of the part x 100 = % comp.

Whole1. Determine the GFM

H2O H 2 x 1 = 2 O 1 x 16 = 16

18gpart x 100 =%

whole 2/18 x 100 = 11% for H16/18 x 100 = 89% for O

100%

Page 10: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.
Page 11: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Determine the molecular (True) formula from the empirical formula and molecular mass.

Empirical is NO2 and the molecular mass is 92g1. Determine the empirical mass

NO2 N 1 x 14 = 14 O 2 x 16 = 32

46g2. determine how many times this goes into the

molecular mass = quantity Molec Mass = quantity empirical mass

92/46 = 2

Molecular formula is N2O4

Page 12: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Determine Molecular (True) Formula from Empirical Formula.

The empirical formula of a compound is CH2. Its molecular mass is 70g/mole. What is its molecular formula?

A compound is found to be 40.0% Carbon, 6.7% Hydrogen and 53.5% Oxygen.Its molecular mass is 60. g/mole. What is its Molecular formula?

Page 13: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Determine the Empirical Formula from percent composition.

Steps1. Change percent to gram 75% C = .75g

25% H = .25 g

2. Go from gram to moleC .75/12 = .0625 moleH .25/1 = .25 mole

3. Determine mole ratio (divide each by the lowest).0625/.0625 = 1 C.25/ .0625 = 4 H

Empirical Formula is CH4

Page 14: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.
Page 15: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Percent Composition of a Hydrate1. Same as a % comp problem2. Hydrate is a crystal that contains water

CuSO4 . 5 H2O This says that 1 mole of Copper II Sulfate contains 5 moles of water

****Calculate the percent of Water in the Hydrate?Steps H2O

1. Calculate the gfm Cu 65, S 32 and 4 Oxy 64 + 5(18) = 251

part x 100 90 x 100 = 36% Whole 251

2. Determine percent of water in Na2S . 9 H20?

Page 16: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.

Stoichiometry made Simple

• Remember not to panic, just do ratios• Piece of cake

Page 17: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.
Page 18: Mathematics of Chemistry The Mole. Mole = a specific Quantity like 1 dozen = 12 1. 22.4L of any gas 2. 6.02x1023 molecules 3. GFM gram formula mass H.