Math fact:

6
Evaluating Algebraic Expressions 4-7 Estimating Square Roots Math fact: Math fact: The sum of any number of The sum of any number of consecutive odd whole numbers, consecutive odd whole numbers, beginning with 1, is a perfect beginning with 1, is a perfect square square e.g. 1+3=4, 1+3+5=9, 1+3+5+7=16 e.g. 1+3=4, 1+3+5=9, 1+3+5+7=16

description

Math fact: The sum of any number of consecutive odd whole numbers, beginning with 1, is a perfect square e.g. 1+3=4, 1+3+5=9, 1+3+5+7=16. 55. 55 is between 7 and 8 because 55 is between 49 and 64. 49 < 55 < 64. 7 < 55 < 8. Example 1: Estimating Square Roots of Numbers. - PowerPoint PPT Presentation

Transcript of Math fact:

Page 1: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square Roots

Math fact:Math fact:

The sum of any number of The sum of any number of consecutive odd whole numbers, consecutive odd whole numbers,

beginning with 1, is a perfect squarebeginning with 1, is a perfect square

e.g. 1+3=4, 1+3+5=9, 1+3+5+7=16e.g. 1+3=4, 1+3+5=9, 1+3+5+7=16

Page 2: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square RootsExample 1: Estimating Square Roots of Numbers

The 55 is between two integers. Name the integers. Explain your answer.

List perfect squares near 55.36, 49, 64, 81

49 < 55 < 64

Find the square roots of the perfect squares.

55

55 is between 7 and 8 because 55 is between 49 and 64.

Find the perfect squares nearest 55.

49 < 55 < 64

7 < 55 < 8

Page 3: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square RootsExample 2: Approximating Square Roots to the Nearest

Hundredth

121 < 135 < 144

The whole number part of the answer is 11.

Find the perfect squares nearest 135.

Find the square roots of the perfect squares.

√121 < √135 < 144√

11 < 135 < 12√

Step 1 Find the value of the whole number.

The number will be between 11 and 12.

Approximate √135 to the nearest hundredth.

Page 4: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square RootsExample 2 Continued

135 – 121 = 14

14 ÷ 23 ≈ 0.609

Find the difference between the given number, 135, and the lower perfect square.

Approximate √135 to the nearest hundredth.

Step 2 Find the value of the decimal.

Write the difference as a ratio.

144 – 121 = 23Find the difference between the greater perfect square and the lower perfect square.

1423

Divide to find the approximate decimal value.

Page 5: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square RootsExample 2 Continued

11 + 0.609 = 11.609 Combine the whole number and decimal.

Step 3 Find the approximate value.

11.609 ≈ 11.61 Round to the nearest hundredth.

The approximate value of 135 to the nearest hundredth is 11.61.

Approximate √135 to the nearest hundredth.

Page 6: Math fact:

Evaluating Algebraic Expressions

4-7 Estimating Square RootsExample 3: Using a Calculator to Estimate the Value of a

Square Root

Use a calculator to find 600. Round to the nearest tenth.

600 ≈ 24.5

600 ≈ 24.494897… Use a calculator.

Round to the nearest tenth.

600 rounded to the nearest tenth is 24.5.