MASTER THESIS PRESENTATION NUMERICAL SIMULATION OF …€¦ · MASTER THESIS PRESENTATION NUMERICAL...

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MASTER THESIS PRESENTATION NUMERICAL SIMULATION OF THE 3D FLOW AROUND JUNCTURES by: VŨ MINH TUẤN Supervisor: Adrian Lungu Outline 1) Introduction 2) The studied problem 3) Choosing the best grid and turbulence model 4) The solution of steady simulation 5) The solution of unsteady simulation 6) Conclusion and future work NUMERICAL SIMULATION OF THE 3D FLOW AROUND JUNCTURES 2

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MASTER THESIS PRESENTATIONNUMERICAL SIMULATION OF THE 3D

FLOW AROUND JUNCTURESby: VŨ MINH TUẤN

Supervisor: Adrian Lungu

Outline

1) Introduction 2) The studied problem 3) Choosing the best grid and turbulence model 4) The solution of steady simulation 5) The solution of unsteady simulation 6) Conclusion and future work

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Introduction Junction flow is characterized by the horseshoe vortex and the boundary

layer separation caused by the adverse pressure gradient. The circularcylinder mounted on the plate is the most popular representative juncture

Many studies have been conducted for recent decades, but, there is noestablished method to understand the 3D flow around the cylindermounted on the curved plate.

Primary objective: The 3D flow around the inclinded cylinder mounted theflat and curved plate at Re=3,900 and Re=106.

Rear view of the horseshoe vortex at Re=3,900 at Re=106

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The studied problem

Flat plate case The radius of cylinder is 0.1m The depth of cylinder is 1m. The plate is either flat or curved (convex or concave) The three different curvature radii of the plate: 30D, 40D, 50D, where D is the

diameter of cylinder. The cylinder is inclined at every 10 degrees, from 0o to 30o laterally, downstream and

upstream 140 configurations to cover all the combinations

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Choosing the best grid and turbulence model> FVM used to discretize the equations in space,> H-O type grids are used for the PDE discretization,> Re=3,900 and Re = 1,000,000,

Grid 1 Grid 2 Grid 3The number of cells in each Grid

Which is the best mesh?

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0.00011,526,76016,964Grid 3

0.00051,934,28021,492Grid 2

0.00011,356,12015,068Grid 1

First cell size3D2DType of grid

Choosing the best grid and turbulence modelThe drag coefficient of an upright circular cylinder at Re=106

The S-A model is the most suitable turbulent model and the Grid 3 is thebest mesh which will be used to simulate the next complex cases.

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The solution of steady simulation The upright cylinder mounted on the flat plate:

From simulation at Re = 3,900 From Baker’s test with Re = 4370

From simulation at Re=106

The vortex structure in front of the cylinder

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The solution of steady simulation The upright cylinder mounted on the flat plate:

Flow topology around the cylinder in front of cylinder

Flow topology around the cylinder in the rear side of cylinderRe=3,900 Re=106

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The solution of steady simulation The inclined cylinder mounted on the flat plate:

Re = 3,900

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Pressure fields around a cylinderinclined laterally

Pressure fields around a cylinderinclined longitudinally

The solution of steady simulation The inclined cylinder mounted on the flat plate:

Re = 106

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Pressure fields around a cylinderinclined longitudinally

Pressure fields around a cylinderinclined laterally

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The solution of steady simulation The upright cylinder mounted on the curved plate:

Re = 3,900

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Pressure fields in concave plate case Pressure fields in convex plate case

The solution of steady simulation The upright cylinder mounted on the curved plate:

Re = 106

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Pressure fields in concave plate case Pressure fields in convex plate case

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The solution of steady simulation The inclined cylinder mounted on the curved plate:

Re = 3,900 Re = 106

Transversal streamlines around the cylinder inclined at 20o

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The solution of steady simulation The inclined cylinder mounted on the curved plate:

Re = 3,900 Re = 106

Curvature influence on the drag coefficient of the cylinder

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Convex case

0.91

0.92

0.93

0.94

0.95

0.96

0.97

0.98

0.99

1.00

1.01

0 5 10 15 20 25 30

Cd

Upstream with R=30DDownstream with R=30DLateral with R=30DUpstream with R=40DDownstream with R=40DLateral with R=40DUpstream with R=50DDownstream with R=50DLateral with R=50DUpstream with flat plateDownstream with flat plateLateral with flat plate

Concave case

0.91

0.92

0.93

0.94

0.95

0.96

0.97

0.98

0.99

1.00

1.01

0 5 10 15 20 25 30

Cd

Upstream with R=30DDownstream with R=30DLateral with R=30DUpstream with R=40DDownstream with R=40DLateral with R=40DUpstream with R=50DDownstream with R=50DLateral with R=50DUpstream with flat plateDownstream with flat plateLateral with flat plate

Concave case

0.35

0.4

0.45

0.5

0.55

0 5 10 15 20 25 30

CdUpstream with R=30DDownstream with R=30DLateral with R=30DUpstream with R=40DDownstream with R=40DLateral with R=40DUpstream with R=50DDownstream with R=50DLateral with R=50DUpstream with flat plateDownstream with flat plateLateral with flat plate

Convex case

0.35

0.4

0.45

0.5

0.55

0 5 10 15 20 25 30

CdUpstream with R=30DDownstream with R=30DLateral w ith R=30DUpstream with R=40DDownstream with R=40DLateral w ith R=40DUpstream with R=50DDownstream with R=50DLateral w ith R=50DUpstream with flat plateDownstream with flat plateLateral w ith flat plate

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The solution of steady simulation The inclined cylinder mounted on the curved plate:

Concave case

Convex caseThe drag coefficient of the cylinder

Inclined downstream Velocity fields

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Cylinder mounted on the convex plate and inclined downstream

0.386

0.388

0.39

0.392

0.394

0.396

0.398

0.4

0 5 10 15 20 25 30

Cd

R=30D

R=30D

R=50D

flat plate

Cylinder mounted on the convex plate and inclined downstream

0.3860.388

0.390.3920.3940.3960.398

0.40.4020.404

0 5 10 15 20 25 30

Cd

R=30D

R=40D

R=50D

flat plate

The solution of unsteady simulation

> The circular cylinder is inclined laterally with an angle of 30o and mounted on theconvex plate that has the curvature radius of 50D.

> Re=3,900> The turbulence model: Spalart-Allmaras model> Computational time: time step of 0.005s, number of time steps of 50,000, residuum of

10-6.

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The solution of unsteady simulation

Velocity contours at the different time The velocity vectors existing near the cylinder

The unsteady simulation shows that the total drag coefficient of the cylinder isreduced comparing with the steady simulation

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1.1154241.0544992Drag coefficient of the plate0.9569290.95035344Drag coefficient of the cylinderSteadyUnsteady

The solution of unsteady simulation

The pressure contour around the cylinder

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ConclusionNUMERICAL SIMULATION OF THE 3D FLOW AROUND JUNCTURES 19

The direction of cylinder inclination affects the juncture flow. The strongerpressure gradients reveals at the root of the cylinder inclinedlongitudinally towards to upstream.

The smaller curvatures determine the larger pressure. This leads to anincrease of the total drag coefficient.

At Re = 3,900, the total drag coefficients decrease when the inclinationangle of cylinder increases, regardless the direction of the cylinderinclination as well as the plate curvature.

At Re = 106, the total drag coefficient mostly increases along with theincrease of cylinder inclination angle in upstream and downstream cases,except for the case of 10o angle in downstream for all convex andconcave cases.

Future work Carrying out the experiments with the circular cylinder mounted on the

curved plate. The simulation of free surface.

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