BEAMProject: PROPOSED HOUSESheet No.Client:Ref.Design: ExampleChecked:Date:Part of StructureMaterial Properties:fcu=25N/mm2fy=250N/mm2yc=23.6kN/m3REF.CALCULATIONSOUTPUT3.0 BEAM DESIGN __----Tee Beam [on Grid 5: The Most Crtical]3.1 LoadingTake unit weight of concrete to be23.6kN/m3consider span L=5.000m2.4.1Dead loads fromself weigth of slabs=3.54self weigth of beam=2.12finishes=0.50fixtures=0.00partitions=1.50Total dead loads (gk)7.665kN/m2gk(kN/m2)=7.665[4]Live load (qk) =2.50kN/m2qk(kN/m2)=2.503.5.3.2 &Ultimate Design Load (n)=(1.4gk+1.6qk)L =30.73kN/mn(kN/m)=30.73table 2.13.2 Ultimate Bending Moment & Sheartable 3.13Midspan: design ultimate moment (M) =57.62kNmMmidspan(kNm)=57.62Support: design ultimate moment (M) =48.40kNmMsupp=(kNm)48.40Design ultimate shear (V) =69.14kNV(kN)=69.14typeGreekc3.3 Durability and Fire Resistancetables 3.3&For mild conditions of exposure and 1.5 hours of fire resistance choose a3.4cover of 25mm cover=25mmC(mm)=253.4 Preliminary Sizing of Membertable 3.91. For no compression reinforcement, M/bwd2fcu [M/0.156bwfcu]1/2=249mm2.For link (mm) =10Main bars (mm) =16Overall depth,h (mm) =450h=d+cover+link+0.5xdia.of main barsTherefore d (mm)=4073.Shear stress v=V/bd=0.85N/mm2For a concrete of grade 25, max. shear stress allowed vc(N/mm2)=0.8fcu1/2v