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BIOLOGY IN FOCUS
1
Copyright © 2008 McGraw-Hill Australia. Permission is granted to reproduce for classroom use.
MAINTAINING A BALANCE
CHAPTER
1
Answers to end of chapter revision questions
1. Describe the importance of homeostasis in living organisms.Answer: Living organisms are made of cells, which must function efficiently to
maintain life. Cells are extremely sensitive to changes in their environment. They
function properly only within relatively narrow ranges of pH and temperature,
they require particular concentrations of nutrients such as glucose and oxygen
and they can tolerate very little build-up in levels of waste products. If a change
in the external environment occurs, this must not affect the balance in the
internal environment of the organism and so a mechanism is needed to ensure
homeostasis—that the internal environment is maintained, despite fluctuations in
the external environment. The mechanism that allows this to occur is a negative
feedback mechanism, co-ordinated by the nervous system.
2. DescribeDescribe the role of receptors in homeostasis.Answer: Receptors play an essential role in homeostasis by receiving information
from the environment and passing it on to the central nervous system (the brain or
spinal cord) in order to trigger an appropriate response. The response is often one
which counteracts the change in stimulus and thereby maintains a stable internal
environment by means of a negative feedback mechanism.
3. ExplainExplain, using an example, what is meant by a negative feedback mechanism andits importance in living systems.
Answer: To minimise changes in the cellular environment, homeostasis is maintained
by a negative feedback mechanism—where a change in the environment is
counteracted by a response that returns the body to the state of homeostasis. It
is termed negative because it reverses the disturbance to the body’s condition.For example, if there is an increase in a variable (such as temperature) beyond
its accepted narrow range for humans, the person’s internal environment begins
to overheat. This change is detected by thermoreceptors in the hypothalamus and
a message is sent via the nervous system to effector organs, which then produce a
response to counteract the change—it decreases the variable (temperature change).
Similarly, a decrease in environmental temperature is counteracted by a response
that brings about heating, to stabilise the system within the normal temperature
range.
A negative feedback mechanism is therefore essential for homeostasis, allowing
the body to constantly monitor itself and to correct any deviation from the stable
state.
Temperature regulation
Please note that the following answers are sample answers only. There may be many alternative answers to the same question that are also correct. These are examples of correct answers.
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4. ExplainExplain the relationship between metabolic rate and temperature regulation inbirds and mammals.
Answer: It is well known that birds and mammals regulate their body temperatures
by increasing or decreasing their metabolic rate (and therefore their rate of heat
production), despite fluctuations in ambient temperature. At high temperatures,
metabolic heat production is reduced and evaporative cooling such as sweating or
panting is initiated. As the environment gets colder, they increase their metabolic
rate and as a result metabolic heat production is increased. This may involve
shivering, but some mammals have brown adipose tissue, which burns up energy
rapidly to release heat.
5. DescribeDescribe the advantage to ectotherms of allowing their body temperature tofluctuate with the ambient temperature, especially at low temperatures.
Answer: The main advantage is that the animal will not need to use valuable
energy to try to maintain a higher body temperature (thermoregulation uses a
large amount of energy, particularly when the internal body temperature needs to
be much higher than the ambient temperature). In addition, metabolic rate slows
down at low temperatures and so the animal will use up less energy and therefore
requires less food. Since food is often scarce in winter, this is of further advantage.
6. Draw a graph to illustrate the differences in body temperatures recorded inan ectothermic reptile and an endothermic mammal who are subjected toenvironmental temperatures that increase steadily (in 10°C increments) over aperiod of time from 10°C to 40°C. What is the optimum temperature range foran endotherm?
Answer:
0 10 20
endotherm
30 40 50
B o d y t e m p e r a t u r e ( ° C )
Environmental temperature (°C)
10
20
30
40
50
ectotherm
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Copyright © 2008 McGraw-Hill Australia. Permission is granted to reproduce for classroom use.
7. IdentifyIdentify whether each of the following is a structural, behavioural or physiologicalresponse or adaptation to assist in heat gain or heat loss and explainexplain how it assiststemperature regulation in living organisms. Give an example of an animal thatexhibits each. (Answer in the form of a table.)
Answer:
Type of response
or adaptation
Example
of animal
in which it
occurs Explanation
(a) Animal curls in a
ball, limbs drawn in
Behavioural
(heat gain)
Mountain
pygmy possum
Reduces the surface of the body
exposed to cold and so reduces
the rate of heat loss by radiation
(b) Large, thin ears Structural
(heat loss)
Bilby Large surface area to radiate heat
into the surrounding air
(c) Burrowing Behavioural
(heat loss or gain)
Brown snake;
fairy penguin
Avoids extremes in temperature by
reducing exposure of body to heator cold
(d) Basking in the sun Behavioural
(heat gain)
Frill-necked
lizard
Warms the body by exposing its
surface to heat
(e) Shivering Physiological
(heat gain)
Birds Movement of muscles increases
heat production by the body
(f) Panting Physiological
(heat loss)
Dogs Evaporation of saliva from the
tongue removes heat from the
blood to cool the body (evaporative
cooling)
(g) Red face Physiological
(heat loss)
Humans Peripheral blood vessels dilate to
increase blood supply (carrying
heat) to the body surface so thatheat can radiate out
(h) Lips and nose
appear blue
Physiological
(heat gain)
Humans Vasoconstriction of peripheral
vessels to reduce blood supply to
the extremities and retain heat in
the core of the body
(i) Thick fur Structural
(heat gain)
Polar bear To insulate the body and retain
heat (prevent heat loss from body
surface by radiation, convection or
conduction)
CHAPTER
2Transport: dissolved nutrients and gases
1. CompareCompare the role of haemoglobin in transporting oxygen and carbon dioxide inthe blood.
Answer: Haemoglobin readily binds with oxygen when the blood oxygen
concentration is low (for example, in capillaries carrying blood from the heart
to the lungs) and it combines easily with carbon dioxide when its levels in the
blood are lower than the carbon dioxide concentration of the surrounding tissue
(for example, in actively respiring cells). The oxygen molecule combines with
the iron part of the Hb molecule, whereas the carbon dioxide combines with
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Copyright © 2008 McGraw-Hill Australia. Permission is granted to reproduce for classroom use.
an amino group on the protein (globin) part of the Hb. The presence of oxygen
increases the affinity of Hb to pick up more oxygen atoms. Once one oxygen
atom has combined with haemoglobin, it has an increased affinity for oxygen. This
continues with each subsequent atom that combines, giving it a greater affinity
for oxygen. Carbon dioxide lowers the affinity of Hb with oxygen, causing it to
release oxygen.
2. ExplainExplain the adaptive advantage of haemoglobin in terms of its being pH sensitive.Answer: When the pH drops, haemoglobin changes shape and tends to lose its
affinity for oxygen. This has an adaptive advantage because, in the body, blood
with lower pH contains carbon dioxide and this is exactly where oxygen is most
needed. Carbon dioxide combines with water to form carbonic acid, which powers
the pH. This changes the shape of the Hb and so it drops off oxygen at sites in
the body which have a high carbon dioxide (and low oxygen) concentration. If
haemoglobin retained a strong affinity for oxygen at all times, it would readily
pick up oxygen, but would not release it. This adaptation in haemoglobin shape is
therefore essential for the release of oxygen at sites that are oxygen depleted.
3. In a table, identifyidentify the forms in which carbon dioxide is transported in the bloodand the proportion of each form.
Answer:
Form in which carbon dioxide is transported in blood Percentage
Dissolved in the plasma 7%
In red blood cells as carbaminohaemoglobin 23%
In plasma as hydrogen carbonate ions 70%
4. DistinguishDistinguish between the terms oxygenated and deoxygenated blood and identifyin which blood vessels in the body one would expect to find the most highlyoxygenated blood and why.
Answer: Oxygenated blood carries oxygen and is bright red in colour due to the
presence of oxyhaemoglobin, whereas deoxygenated blood carries carbon dioxide
and is a dark red in colour.
5. CompareCompare arteries, capillaries and veins in terms of the structure of their walls, thesize of the lumen and the direction of blood flow.
Answer:
Arteries Capillaries Veins
Similarity All have an inner endothelial layer lining their lumens.
Structure of walls Three layers, with thick middle
layer with large amount of
smooth muscle and elastic fi bres
One layer of endothelial cells only;
no elastic or smooth muscle
layers
Three layers, with thinner middle
layer with less smooth muscle
than arteries and very few elastic
fi bres
Size of lumen Relatively smaller than that of
a vein, but larger than that of a
capillary
Small lumen—the size of the
diameter of a red blood cell
Large lumen
Direction of blood
fl ow
From heart to tissues of the body Within tissues, from arterioles to
venules
From tissues back to the heart
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6. ExplainExplain, in terms of their functions, why: (a) the walls of arteries need to be thicker than those of veins (b) the walls of capillaries are so thin (c) veins have valves.Answer:
(a) The thicker walls of arteries are necessary to withstand the higher pressure of
blood arriving from the heart as a result of its pumping action. More smooth
muscle strengthens the wall to withstand the pressure, and more elastic fibres
enable the wall to expand with the arrival of blood and then to propel the
blood forwards as the wall recoils.
The walls of veins must have less smooth muscle and fewer elastic fibres so
that the thinner wall can be easily compressed by the surrounding muscles to
assist with the return of blood to the heart, since blood seeps into veins from
capillaries and there is no pumping force to drive the blood towards the heart.
This lack of a pumping action also means that the veins receive blood under
less pressure and therefore they do not need thick layers of strengthening(muscle) tissue or elastic tissue for recoil.
(b) Thin walls in capillaries are essential for efficient exchange of nutrients and
wastes (largely by diffusion) between blood and body cells. Thinner walls of
cells mean there is an increased surface area over which exchange of gases
(and exchange of other substances such as nutrients into cells and wastes out
of cells) can occur.
(c) Valves are essential to prevent the backflow of blood in veins, since veins do
not receive blood that is pumped to propel it forwards. Blood seeps into veins
from capillaries, and valves are essential for the continued movement of blood
in one direction only (towards the heart), especially in the arms and legs
where venous blood must flow against the force of gravity.7. OutlineOutline the advantages of the use of blood products as opposed to whole blood.Answer: The use of various products rather than whole blood promotes more
effective treatment because patients can receive only the blood components that
they require. It also increases (up to three times) the number of patients who can
benefit from each unit of whole blood donated.
8. IdentifyIdentify the main substances that need to be transported in plants and state theimportance of these substances in the plant.
Answer: The main substances that must be transported in plants are:
■ water and inorganic mineral ions, absorbed by the roots and required for
metabolism and photosynthesis
■ food (organic nutrients, especially sugars) that are produced as a result ofphotosynthesis and need to be transported to other parts of the plant.
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9. With the aid of a labelled diagram, illustrate the forces involved in lifting waterand dissolved mineral ions up the xylem.
Answer:
phloem
xylem
phloem
xylem
transverse sectionyoung root
transverse sectiondicot stem
transverse sectiondicot leaf
1 Transpiration: as the sun warms the leaves, stomataopen and water evaporates through the openings
2 Suction force: increased evaporation at the leafsurface creates a pull at the upper end of the watercolumn
3 Cohesion–adhesision and capillarity: the pullingforce is extended to the water column and
creates a force that pulls water upwards–thetranspiration stream (depends on properties of water)
4 this creates a force that pulls water into the roots byosmosis
1
2
3
4
4
1
Xylem Phloem
Substances
carried
Water
Dissolved inorganic minerals
Organic nutrients (such as sugars)
Main direction of
fl ow
Upwards, from roots to leaves Both upwards (e.g. from leaves to
fl owers and buds near the top of
the plant) and downwards (e.g. from
leaves towards the roots)
Mechanism of
transport (current
theory)
Transpiration stream—dependent
on evaporative suction pull of
transpiration, as well as adhesion,
cohesion and capillarity
Pressure fl ow—dependent on a
difference in the osmotic pressure
gradient between the source (leaves,
where sugars are loaded) and sink
(tissues where sugars are offl oaded)
Similarity The translocation in both types of tissue relies on a pressure-fl ow mechanism
which moves liquid contents from their source in the plant to where they are
needed.
10. In a table, comparecompare the translocation of materials in xylem with translocation inphloem.
Answer:
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1. In the form of a table, summarise the features in plants that minimise water lossunder the following headings:
Include the following mechanisms (in the first column): ■ features to reduce the internal temperature of plants ■ adaptations to reduce exposure of the leaves (or stomata) to the sun: —reduced exposure of stomata —reduced surface area of leaves or leaf-like structures
■
adaptations to reduce the difference in water concentration between theplant and the outside air ■ features related to water storage: —storing water —reducing water loss in fruits.Answer:
CHAPTER
3
Excretion: wastes, water and salt balance
Include the following mechanisms (in the first column):
Mechanisms that minimise
water loss Features evident in plants
Explanation of how this
conserves water
7
Mechanisms that minimise
water loss Features evident in plants Explanation of how this conserves water
Features to reduce the internal
temperature of plants
Shiny, refl ective waxy leaves
Thick, insulating cuticle
Temperature is kept lower in the plant, requiring
less water to be lost by evaporative cooling.
Adaptations to reduce the
exposure of the leaves (stomata) to the sun
■ reduced exposure of stomata
■ reduced surface area of
leaves or leaf-like structures
(and the organs that have
the highest proportion of
stomata)
■ Leaf orientation in eucalypts
■ Leaves reduced to leafl ets
■ Leaves reduced to scales (phyllodes and
cladodes)
■ Rolled leaves
■ Complete loss of leaves/fl owers
Stomata remain closed and so less transpiration
occurs.
Fewer stomata, ensuring less water loss. (This is
usually accompanied by some other modifi cation
to compensate for the lack of photosynthetic
surface area, such as cladodes and phyllodes.)
Adaptations to reduce
the difference in water
concentration between the plant
and the outside air
■ Sunken stomata
■ Hairs on leaves
■ Rolled leaves
A decreased concentration gradient results in
less water leaving the plant tissues by osmosis
and less water diffusing out of the stomata of
leaves. This is achieved by producing a micro-
climate immediately around the leaf, where
moist water can be trapped and a barrier is
created to prevent its evaporation or removal by
currents of dry air.
Features related to water
storage:
■ storing water
■ reducing water loss in fruits
Succulent plant organs (for example leaves
or stems)
Woody fruits
In areas of inconsistent rainfall water can be
stored during wet periods, for use during times
of drought.
Less water is lost from the plant when fruits
are dispersed if the fruit is woody and stores no
water (compared with fl esh fruits).
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2. ExplainExplain why it is essential to remove carbon dioxide and the nitrogenous wasteammonia from cells.
Answer: These are wastes that become toxic if they accumulate in cells. Carbon
dioxide combines with water to lower pH, and ammonia raises pH. This reduces
the metabolic efficiency of cells since all chemical reactions in cells are controlled
by enzymes and enzymes are pH-specific, only functioning efficiently at optimal
pH. They do not function at all outside a narrow range of pH.
3. IdentifyIdentify three reasons why it is essential to maintain the water concentration inliving organisms.
Answer:
■ Water provides the medium for biochemical reactions in cells.
■ Water is essential for the removal of wastes.
■ A change in water concentration would affect the osmotic balance of the cell
and this could affect pH and enzyme activity.
4. ExplainExplain why energy is required for the reabsorption of glucose and amino acidsin nephrons.
Answer: Glucose and amino acids are required by the body and should not be lost
in urine. Therefore they are reabsorbed from the nephron into the surrounding
kidney tissue and back into the blood capillaries, despite the fact that they may be
in lower concentration in the nephron than they are in the blood. Active transport
is the type of movement required to move substances against a concentration
gradient, and this type of transport utilises energy.
5. Copy a version of Figure 3.17 and complete the figure, showing the movementof water, salts, urea, drugs and hydrogen ions. Provide a key and indicate whichmovement is by means of active transport and which by means of passive
transport (distinguish between osmosis and diffusion).
glomerulus neck
proximal
arm
intermedia
segment
(loop of Henle)
distal arm
collecting
duct
glucose
divalentions
aminoacids
Figure 3.17
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Answer:
6. nalyse Analyse the information in Figure 3.18 and then use evidence from the diagramto explain the relationship between the type of nitrogenous waste produced and
the type of environment in which the organism lives.
Answer: The diagram indicates that a tortoise produces the excretory waste uric
acid in a semi-solid form. The diagram of a nephron provides evidence that the
uric acid is a waste that is excreted. Since uric acid is less toxic than other forms of
nitrogenous wastes, it requires very little water to be flushed out of the body. This
is typical of organisms that inhabit an environment where water is a limiting factor
and there is a need to conserve water within the body. Therefore we can deduce
that the tortoise lives in a dry area (an environment where water is limited).
filtrate
H2O (water)
salts (NaCI, etc)
HCO3–
(bicarbonate ions)
H+ (hydrogen ions)
urea
glucose; amino acids
some drugs
active transport
passive transport
NaCINaCI
nutrientsHCO3
– HCO3–
H2O
H2O
H2O
K +
K + H+H+ NH3
NaCI
H2O
urea
NaCI
NaCI
cortex
outer
medulla
innermedulla
1 proximal tubule
2 descending
limb of loop
of Henle
3 thick segment
of ascending
limb
3 thin segment
of ascending
limb
4 distal tubule
5 collectingduct
Figure 3.18
reptile
semi-solid uric acid
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7. In renal dialysis, blood is taken from a vein and run past a dialysate fluid,separated by a selectively permeable membrane. DescribeDescribe what would happen ifthe concentration of glucose in the dialysate was lower than the concentrationof the patient’s blood.
Answer: Glucose would diffuse out of the patient’s blood into the dialysate since
molecules move passively from a high to a low concentration. This would lead to
a shortage of glucose in the patient.
8. CompareCompare the chemical composition of blood arriving at the glomerulus with thecomposition of glomerular filtrate.
Answer:
9. Identify the hormone absent from people who suffer from Addison’s disease andexplain the main role of this hormone in kidney functioning.
Answer: These people lack the hormone, aldosterone. Its main function is to
increase the permeability of the membranes of the ascending limb of the loop of
Henle to salts. This results in an increase in salt reabsorption in the nephron and
so salt is conserved in the body, blood volume increases and blood pressure is
maintained.
10. Name one Australian insect and one Australian plant that are adapted tominimise water loss and describedescribe this adaptation in each.
Answer: The blowfly is an Australian insect that excretes uric acid, which requires
very little water to flush it out, and the blowfly is able to reabsorb a large amount
of water from its digestive tract, via rectal pads, into the kidney tubules, which lie
in close proximity to the rectal pads.
The she-oak is an Australian plant that reduces water loss by having a
decreased surface area of leaves and therefore fewer stomata exposed to the air.
The leaves of the she-oak are reduced to scales at the nodes of the stems and the
stem has taken over the photosynthetic function of leaves (which appear as thin,
needle-like branches). Stems have fewer stomata than leaves and therefore lose
less water by transpiration.
9. I enti y the hormone absent from people who suffer from Addison’s disease and
Blood arriving at the glomerulus Glomerular filtrate
Both contain a large amount of water and dissolved substances.
Plasma proteins, red blood cells and white blood
cells are present in the blood.
Plasma proteins and blood cells are too large to
fi lter through and so they are absent from thefi ltrate in a kidney that is functioning normally.
End products of digestion are present in the
blood, including amino acids.
Glucose and amino acids are present in the
fi ltrate as they are small enough to move out of
the capillary and into the Bowman’s capsule by
fi ltration.