Lpw Circuit Theory 2013

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    INSTITUTE OF TECHNOLOGY, NIRMA UNIVERSITY

    B.Tech. Semester IV (IC)

    2EE225:CIRCUIT THEORY

    INDEX

    SR.

    NO.TITLE

    PAGEDATE SIGN

    REMAR

    KSFROM TO

    1. To verify Superposition Theorem.

    2. To verify Thevenin Theorem.

    3. To verify Reciprocity Theorem.

    4. To verify Norton Theorem.

    5. To verify Maximum Power Transfer Theorem.

    6.

    (i) To determine the zparameters of atwo port resistive network.

    (ii)To determine the zparameters ofSeries connection of two 2-port resistive

    networks and verify the result by direct

    calculation.

    7.

    (i) To determine the y parameters of a twoport resistive network.

    (ii) To determine the y parameters of the

    parallel connection of two 2-port resistive

    networks and verify the result by direct

    calculation.

    8.

    (i) To determine the ABCD parameters of atwo port resistive network.

    (ii) To determine the ABCD parameters of the

    cascade connection of two 2-port resistive

    networks and verify the result by direct

    calculation.

    9.

    (i) To determine the hparameters of a twoport resistive network.

    (ii) To determine the h parameters of the

    series parallel connection of two 2-port

    resistive networks and verify the result by

    direct calculation.

    10.

    (i) To determine the gparameters of a twoport resistive network.

    (ii)To determine the g parameters of theparallel-series connection of two 2-port

    resistive networks and verify the result by

    direct calculation.

    11.Simulation of series RC,RL and RLC circuits

    with Virtual Laboratory.

    12.Simulation of Parallel RC,RL and RLC

    circuits with Virtual Laboratory.

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    EXPERIMENT NO: 1 DATE

    AIM : To verify Superposition Theorem.

    APPARATUS:

    (1) Regulated power supply (D.C) 0 - 30V 2

    (2) Board containing the network 1

    (3) Ammeters 0 - 250 mA 3

    (4) Voltmeter 0 - 30 V 1

    SUPERPOSITION THEOREM

    THEORY:

    The superposition theorem states that the response in any element of a linear bilateral

    network containing two or more sources is the algebraic sum of the responses obtained by

    each source acting separately at a time and with all the other sources set equal to zero,

    leaving behind their internal resistance in the network.

    According to this theorem, if there are a number of e.m.fs acting simultaneously in any

    linear bilateral network, each e.m.f acts independently of the others i.e as if the other

    e.m.fs doesn't exist. The value of current in any element of the netwrok is the algebraic

    sum of the currents due to each e.m.f. Similarly voltage across any element/branch is the

    algebraic sum of the voltages which each e.m.f would have produced while

    acting separately at a time. In other words, current through or voltage across

    any conductor of the network is obtained by superimposing the currents and voltages

    due to each e.m.f. in the network .It is important to note that this theorem is applicable

    only to linear networks.

    The superposition theorem is applied to determine currents and voltages which are

    linearly related to the sources acting on the network. Power can not be determined by

    superposition principle since the relationship between power and current or voltage is

    quadratic.

    In Fig(a) I1, I2and I3represent values of currents due to simultaneous action of the two

    sources of e.m.fs in the network. In fig(b) I1', I2' and I' represent values of currents due to

    source of e.m.f E1 alone. In fig (c) I1", I2" and I" represent values of currents due to

    source of e.m.f E2alone. By superimposing the current values of fig (b) and fig (c)

    the actual values of currents due to both the sources can be obtained as under:

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    Obviously : I1= I1' + I1" (algebraic)

    I2= I2" + I2' (algebraic)

    I = I' + I" (algebraic)

    PROCEDURE :

    1. Connect the circuit diagram as shown in the fig .2. Connect the network with two e.m.f sources and adjust the source voltages such that

    current values are not exceeded beyond the ranges and ratings of the resistance and

    note down the meter readings.

    3. Set the e.m.f E2 to zero and note down the readings. due to E1 alone. If any meterindicates negative, interchange the connection of that meter and consider that reading

    as negative.

    4. Adjust E2 as before (as per step. 2) and set E1 to zero and note down the meterreadings If any meter indicates negative, interchange the connection of that meter

    and note down the reading of that meter with opposite sign w.r.t. the step 3.

    5. Verify the superposition theorem and tabulate the results.

    OBSERVATION TABLE:

    SR.

    NO

    E1

    Volts

    E2

    Volts

    I1

    mA

    I2

    mA

    I3

    mA

    V1

    Volts

    V2

    Volts

    V3

    Volts

    1

    2 0

    3 0

    CALCULATION:

    I1 = I1' + I1" (Algebraic) V1 = V1' + V1" (Algebraic)

    I2 = I2' + I2" (Algebraic) V2 = V2' + V2" (Algebraic)

    I3 = I3' + I3" (Algebraic) V3 = V3' + V3" (Algebraic)

    RESULT TABLE:

    SR.

    NO

    I1

    mA

    I2

    mA

    I3

    mA

    V1

    Volts

    V2

    Volts

    V3

    Volts

    Practical

    Theoretical

    CONCLUSION:

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    EXPERIMENT NO: 3 DATE

    AIM : To verify Reciprocity Theorem.

    APPARATUS:

    (1) Regulated power supply (D.C) 0 - 30V 2

    (2) Board containing the network 1

    (3) Ammeters 0 - 250 mA 3

    (4) Voltmeter 0 - 30 V 1

    RECIPROCITY THEOREM:

    THEORY:

    The reciprocity theorem states that in a linear, bilateral, single source network the ratio of

    excitation to response is constant when the positions of excitation and response are

    interchanged.

    On the basis of mesh current analysis with a single voltage source acting in the network, the

    theorem may be demonstrated by considering the following equation for mesh current Ir.

    Ir = V1(1r/z) + V2(2r/z) +.. + Vr(rr/ z) + Vs(sr/ z)

    Let the only source in the network be Vsthen

    Ir = Vs (sr/ z)

    The ratio of excitation to response is

    Vs/ Ir= z/ sr= Ztransfer sr ------------------------------(1)

    Now when the position excitation and response are interchanged the source becomes Vrand

    the current Is.

    Is= Vr(rs/ z)

    The ratio of excitation to response is

    Vr / Is= z/ rs= Ztransfer rs --------------------------(2)

    The two transfer impedances in (1) and (2) are equal in any linear, bilateral network since in

    such networks the impedance matrix [z] is symmetrical with respect to the principal diagonal,

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    and the cofactors rs and sr are equal. Thus the current in mesh r which results from a

    voltage source in mesh s is the same as the current in mesh s when the voltage source is

    moves to mesh. It must be noted that currents in other parts of the network will not remain

    same.

    The reciprocity theorem also applies to networks containing a single current source. Here the

    theorem states that the voltage which results at a pair of terminal m n due to a current source

    acting at terminals a b is the same as the voltage at terminals a b when the current source is

    moved at terminals m n. It should be noted that voltages at other points in the network would

    not remain the same.

    PROCEDURE:

    1. For the circuit shown in figure1 calculate the values of current (I) for different values ofsource voltage and record them in the observation table.

    2. Connect the circuit as shown in figure1 , measure then values of current (I) (for sourcevoltage of same values in step 1) and record them in the observation table.

    3. For the circuit shown in figure (2), calculate the values of current (I) (for source voltage ofsame values as in step 1) and record them in the observation table.

    4. Connect the circuit as shown in figure (2), measure the values of current (I)(for sourcevoltage of same values as in step 1) and record them in the observation table.

    OBSERVATION TABLE:

    Sr No. Voltage

    (V)

    Current (I) A/mA Voltage

    (V)

    Current (I) (A/mA)

    Exp. The. Exp. The.

    1.

    2.

    3.

    4.

    CONCLUSION:

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    QUIZ :

    1. Superposition theorem can be applied only to circuits having ________.

    2. Superposition theorem requires as many circuits to be solved as there are

    (a) sources , nodes and meshes

    (b) sources and nodes

    (c) sources

    (d) nodes.

    3. Total resistance of a parallel circuit is _______ the smallest branch resistance.

    4. Is superposition theorem applicable to POWER as it is applicable to voltage and current?

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    EXPERIMENT NO: 2 DATE

    AIM : To verify Thevenin Theorem.

    APPARATUS:

    (1) Board containing network 1

    (2) Milli ammeter (MC) 0 - 50 mA. 1

    (3) Voltmeter (MC) 0 - 10V 1

    (4) Regulated power supply 0-30V 1

    THEVENIN THEOREM:

    THEORY:

    Thevenins theorem state that any two terminal network whether simple or complex can

    be replaced by a single source of voltage Vth in series with a single resistance Rth (in

    case of d.c) or impedance Zth(in case of a.c) Hence Thevenin's equivalent circuit consists

    of Vthin series with Rth(or Zth) as shown in fig(B). Once a Thevenin's circuit is obtained

    it is connected across the resistance RL in which current is to be determined. Once the

    current value in RLis known, potential difference across it can be calculated if required.

    For obtaining Thevenin's circuit, proceed as follows:

    1. Remove the resistance RL and measure (or calculate) voltage Ethbetween theterminals from where RL has been removed.

    2. Replace all the e.m.f sources by their internal resistance (or impedances) andmeasure (or calculate) Rth (or Zth) between the terminals from where RL has been

    disconnected.

    3. Draw the Thevenin's equivalent network.4. For calculating current in RL, connect RL which was removed earlier across this

    Thevenin's circuit.

    5. Current through RLis given byVth

    IL = -----------

    Rth+ RL

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    PROCEDURE:

    1. Connect the circuit as shown in the fig(1).2. Switch on the supply and adjust the supply voltage such that meter readings are not

    exceeded their ranges and ratings of the resistances. Note down the current through the

    load resistance RL.

    3. Disconnect the resistance RL from the circuit and measure the voltage across theterminals from where the resistance RL is disconnected. This voltage is known as Eth.

    Refer fig(2).

    4. Replace source of e.m.f. by its internal resistance and measure the total resistance (orimpedance) of the network between the terminals from where the resistance RL is

    disconnected. This resistance (or impedance) is known as Rth(or Zth). Refer fig(3).

    5. Calculate the current through RLusing the formula.Vth

    IL = -----------

    Rth + RL

    6. Compare it with the value obtained in step (2)

    OBSERVATION TABLE:

    SR.

    NO

    VOLTAGE

    ACROSS

    RL

    VLvolts

    CURRENT

    THROUGH

    RL

    ILmA

    RL=

    VL/IL

    Eth

    Volts

    REMARKS

    1

    2- - Disconnect the

    resistance RL

    (Measurement of Rth)

    SR

    NO

    SUPPLY

    VOLTAGE

    V volts

    CURRENT

    I mA

    Rth=

    V / I

    REMARKS

    1 Set source e.m.f to zero

    2 Set source e.m.f to zero

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    CALCULATION :

    (1) RL= VL/IL = =

    (2) Rth= V/I = =

    Vth

    (3) IL = ----------- = =

    Rth + RL

    RESULT TABLE :

    THEORETICAL PRACTICAL

    Vth

    Rth

    IL

    CONCLUSION:

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    EXPERIMENT NO: 4 DATE

    AIM : To verify Norton Theorem.

    APPARATUS:

    (1) Board containing network 1

    (2) Milli ammeter (MC) 0 - 50 mA. 1

    (3) Voltmeter (MC) 0 - 10V 1

    (4) Regulated power supply 0-30V 1

    NORTON THEOREM:

    THEORY :

    This theorem is an alternative to the Thevenin's theorem. In fact, it is the dual of

    Thevenin's theorem. Where as Thevenin's theorem reduces a two - terminal active

    network to an equivalent constant voltage source and series resistance Norton's theorem

    replaces the network by an equivalent constant current source and a parallel resistance.

    It states that any two - terminal active network containing voltage/current sources and

    resistances/impedances when viewed from its output terminals is equivalent to a

    constant current source and a parallel resistance (or impedance). The constant current is

    equal to the current which would flow in a short - circuit placed across the terminals

    and parallel resistance (or impedance) is the resistance (or impedance) of the network

    when viewed from these open circuited terminals after all sources of e.m.fs have been

    supressed and replaced by their internal resistances (or impedances).

    PROCEDURE for analysis of network:

    1. Remove the resistance RL, short the terminals through an ammeter from where RLhas been removed and observe ( or calculate) the reading of the ammeter. This gives

    the value of the current of the Nortons current source, Isc.

    2. Replace the source by its internal resistance (or impedance) and measure (orcalculate) the resistance RN(or impedance ZN) between the terminals from where RL

    has been removed.

    3. Connect the RN(or ZN) in parallel with the current source and connect RL whichwas disconnected earlier across Norton's equivalent circuit.

    4. Current through the resistance RL is given byRth

    IL = Isc ----------Rth+ RL

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    PROCEDURE:

    1. Connect the circuit as shown in fig 1.2. Switch on the power supply and adjust the supply voltage such that meter readings

    are not exceeded their ranges and ratings of the resistances. Note down the current

    through the resistance RL.

    3. Disconnect the resistance RL and short the terminals through the ammeter fromwhere RLhas been removed and measure(or calculate) the current. This gives the

    value of the current (Isc) of the current source. Refer fig(2).

    4. Replace source of e.m.f by its internal resistance (or impedance) and measure the totalresistance (or impedance) of the network between the terminals from where the

    resistance(RL) has been removed. This is known as RN(or ZN).

    5. Calculate the current through RL according toRN

    IL = Isc -----------

    RN+ RL

    and compare its value obtained in step (2)

    OBSERVATION TABLE:

    SR.

    NO

    VOLTAGE

    ACROSSRL

    VLvolts

    CURRENT

    THROUGHRL

    ILmA

    RL=

    VL/IL

    ISC

    mA

    REMARKS

    1 -

    2 Disconnect RL and

    short the terminals

    through ammeter

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    (Measurement of RN)

    SR.

    NO

    SUPPLY

    VOLTAGE

    V volts

    CURRENT

    I mA

    RN= V / I REMARKS

    1 Set source e.m.f. to zero

    2 Set source e.m.f. to zero

    CALCULATION :

    (1) RL= VL/IL = =

    (2) RN= V/I = =

    RN

    (3) IL = Isc ----------- = =

    RN+ RL

    RESULT TABLE:

    THEORETICAL PRACTICAL

    ISC

    RN

    IL

    CONCLUSION: -

    QUIZ: -

    1. For which type of network the Norton's theorem is applicable?2. The circuit whose parameters change with voltage or current is called a _______ circuit.

    3. _________ theorem is quite useful when the current in one branch of a network is to be

    determined or when the current in an added branch is to be calculated.

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    4.. The circuit whose parameters are constant is called a linear circuit. (yes/no)

    5. In Thevenin's theorem to find Zth,all independent ________ are set to zero and allindependent_______ are open circuited.

    6. Thevenin equivalent circuit is preferred when the circuit is analyzed in terms of _________and __________ .

    7. Norton equivalent circuit is preferred when the circuit is analyzed in terms of _________ and__________ .

    8. When connected to a 4 resistor, a battery has a terminal voltage of 10.8 V but produces 12V on an open circuit. Determine the Thevenin equivalent circuit for the battery.

    9. Given the Thevenin`s equivalent of an electric circuit, how will you determine the Norton`sequivalent?

    .

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    EXPERIMENT NO: 5 DATE

    AIM: To verify Maximum Power Transfer Theorem and Tellegan`s Theorem.

    APPARATUS:

    (1) Board

    (2) Ammeter 0 - 10 ma 01

    (3) Voltmeter 0 - 10V 01

    (4) Regulated power supply 0-30V 01

    MAXIMUM POWER TRANSFER THEOREM

    THEORY :

    Maximum power transfer theorem deals with transfer of maximum power from a

    source to load. This theorem in d.c circuit states the relationship between the load

    resistance and the internal resistance of the source for maximum power transfer from

    source to load. This condition is also referred as resistance matching and it is

    very important in electronics and communication circuits for obtaining maximum

    output. Let us consider a circuit supplying a power to a load of resistance RL ohms.

    The circuit of fig (1) can be simplified to the circuit of fig (2) by using Thevenin's

    theorem, From fig (2) the current through RL is given by

    E

    I = -------Ri + RL

    Power transferred to the load

    PL= I2RL

    E 2

    = -------- RL

    Ri + RL

    E2

    RL= ----------- -----------(1)

    (Ri + RL)2

    In the above expression the resistance Rs and voltage E are constant. Hence PL varies

    wth respect to only variable RL Power delivered to the load is a maximum if,

    d PL

    ------ = 0

    d RL

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    Differentiating the expression (1) w.r.to RL and equating to zero, we obtain the

    condition for maximum power i.e RL = Ri

    Hence for maximum power transfer the load resistance should be equal to the internal

    resistance of the source,

    E2RL

    Pmax = ------------

    (RL+ Ri)

    2

    E2

    = ------- watts (because RL= Ri)

    4RL

    PROCEDURE:

    (1)Connect the circuit as shown in the fig.(3)(2)Switch on the supply and adjust suitable voltage of the supply.(3)Vary the load resistance from zero onward in suitable steps. For each step take meter

    readings.

    (4)Calculate the power taken by the load for each value of the load resistance.(5)Draw the graph of PLv/s RL.

    OBSERVATION TABLE :

    SR.

    NO

    SUPPLY

    VOLTAGE

    Vs (Volts)

    LOAD

    CURRENT

    IL( mA)

    VOLTAGE

    ACROSS

    LOADVL(Volts)

    LOAD

    RESISTANCE

    RL= VL/IL

    POWER

    DELIVERED TO

    THERESISTANCE,

    RL

    PL= IL2XRL

    1.2.3.4.5.

    CALCUATION :

    VL

    (1) RL= -----

    IL

    (2) PL= IL2. RL

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    CONCLUSION: -

    QUIZ: -

    1. When a source is delivering maximum power to a load, the efficiency of the circuit is___________ .

    2. Assuming that we can determine the Thevenin equivalent resistance of our wall socket,why don`t heater, microwave oven and TV manufacturer match each appliances

    Thevenin equivalent resistance of this value? Would not is permited max power transfer

    from the utility company to our household appliances?

    3. A black box with a circuit in it is connected to a variable resistor. An ideal ammeter andan ideal voltmeter are used to measure current and voltage respectively. The results are:

    R V I

    2 3 1.5 Determine the maximum power from the box.

    8 8 1.0

    14 10.5 0.75

    4. Maximum power transfer theorem is particularly useful for analyzing _________networks.

    5. For high efficiency of transfer of power, internal resistance of the source should be__________.

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    EXPERIMENT NO: 6 DATE

    AIM : (i) To determine z parameters of a given TwoPort Resistive

    Network.

    (ii) To determine the z parameters of series connection of two 2-port

    resistive networks and verify the result by direct calculation.

    APPARATUS :

    (1) Ammeter 0-50mA 2

    (2) Voltmeter 0-10V 1

    (3) Regulated power supply 0 - 30V. 1

    (4) Board containing two port network 1

    THEORY:

    In electrical network theory a port may be regarded as a pair of terminals in which

    current in to one terminal equals the current out of the other. A network may have one,

    two or n ports in general. A one port network is completely identified when voltage

    current relationship at the terminals of the port is given.

    A general two port network shown in fig (1) has two pairs of voltage - current

    relationships. The V1 and I1 are the variables at port 1 and V2 and I2 are the variables

    at port 2. Only two of the four variables are independent and specifications of any two

    of them determine the remaining two. The dependence of two of the four variables on

    the other two is described in a number of ways, depending on which of the variables

    are chosen to be independent variables. As such there are six possible sets of equations

    describing a two port network, six different types of parameters are defined as z

    parameters, y parameters, transmission parameters, inverse transmission parameters,

    hybrid parameters and inverse hybrid parameters.

    Z - parameters:

    In case of z parameters, V1and V2are expressed in terms of I1 and I2.

    i.e. V1= z11I1 + z12I2 - (1)

    V2= z21I1+ z22I2 - (2)

    These parameters may be defined in terms of a single voltage and current by letting either

    I1= 0 or I2= 0.

    Thus,

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    V1

    z11 = ___

    I1 I2= 0

    V1

    z12 = ___

    I2 I1= 0

    V2

    z21 = ___

    I1 I2= 0

    V2

    z22 = ____

    I2 I1= 0

    It may be observed that (i) all the z parameters have the dimensions

    of impedance and (ii) they are specified only when the current in one of ports is

    zero i.e open circuit at port 1 or port 2. Hence z parameters are designated as

    open circuit impedance parameters.

    ZPARAMETERS OF SERIES CONNECTION OF TWO 2-PORT

    RESISTIVE NETWORK:

    Two port network analysis is useful for finding different parameters. The z

    Parameters are useful in characterizing series connected two port networks. They

    are found under open circuit conditions and hence they are referred as open circuit

    impedance functions. They are defined and found as under:

    The z parameters are useful in characterizing series connected two port

    networks. The overall z parameters from the individual z parameters can be

    found as under when the networks are connected in series.

    For network Na

    V1a

    =

    z11a z12a I1a

    V2a z21a z22a I2a ---------(1)

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    For network Nb

    V1b

    =

    z11b z12b I1b

    V2b z21b z22b I2b ---------(2)

    For overall network N

    V1

    =

    z11 z12 I1

    V2 z21 z22 I2 ---------(3)

    Note that

    I1= I1a= I1band V1= V1a+ V1b

    I2= I2a= I2band V2= V2a+ V2b------(4)

    Combining equation (1), (2) and (4), we get

    V1

    =

    Z11a+z11b z12a +z12b I1

    V2 Z21a+z21b z22a +z22b I2 ---------(5)

    Comparing equation (5) with equation (3), we get

    z11= z11a + z11b

    z12= z12a + z12b

    z21= z21a + z21b

    z22= z22a + z22b----------------(6)

    This result may be generalized for any number of networks

    connected in series. The individual parameters are added to determine the

    overall Z parameters.

    PROCEDURE :

    (1) Connect the circuit for Network Naas shown in fig (1).

    (2) Apply voltage at port 1 keeping port 2 open circuited as shown in

    fig (2). Measure voltages and current at the port terminals. Keep levels of voltages

    and current such that meter readings are not exceeded their ranges and ratings of

    the resistances.

    (3) Apply voltage at port 2 keeping port 1 open circuited as shown in

    fig (3). Measure voltages and current at the port terminals.

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    (1)Calculate z parameters using measured values of voltages and currentsand verify the results theoretically.

    (2)Connect the circuit as shown in fig (4) for network Nb only. Repeat steps 2 to4 for Network Nb

    (6) Connect the networks Na and Nb in series as shown in fig(5) to form

    the overall network N.

    (7) Repeat steps 2 to 4 to find the z - parameters of network N and Verify the

    results theoretically.

    (8) Keep levels of voltages and currents such that the meter readings are

    not exceeded their ranges and ratings of resistances.

    OBSERVATION TABLE :

    (1) Network : Na

    SR.

    NO.

    V1a

    Volts

    I1a

    mA

    V2a

    Volts

    I2a

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 open circuited

    (2) Network : Nb

    SR.

    NO.

    V1b

    Volts

    I1b

    mA

    V2b

    Volts

    I2b

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 open circuited

    (3) Network N :

    SR.

    NO.

    V1

    Volts

    I1

    mA

    V2

    Volts

    I2

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 open circuited

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    CALCULATION :

    For Network Na :

    V1a

    z11a = ___ = _________________________________

    I1a I2a= 0

    V1a

    z12a = ___ = _________________________________

    I2a I1a = 0

    V2a

    z21a = ___ = ________________________________

    I1a I2a= 0

    V2a

    z22a = ___ = ________________________________

    I2a I1a= 0

    For Network Nb :

    V1b

    z11b = ___ = _________________________________

    I1b I2b= 0

    V1b

    z12b = ___ = _________________________________

    I2b I1b= 0

    V2b

    z21b = ___ = ________________________________

    I1b I2b= 0

    V2b

    z22b = ___ = ________________________________

    I2b I1b= 0

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    For Network N :

    V1

    z11 = ___ = _________________________________

    I1 I2= 0

    V1

    z12 = ___ = _________________________________

    I2 I1= 0

    V2

    z21 = ___ = ________________________________

    I1 I2= 0

    V2

    z22 = ___ = ________________________________

    I2 I1= 0

    Check :

    (1) z11= z11a+ z11b = ____________ = ____________

    (2) z12= z12a+ z12b = ____________ = ____________

    (3) z21= z21a+ z21b=____________ = ____________

    (4) z22= z22a+ z22b = ____________ = ____________

    RESULT TABLE :

    NETWORK Practical Theoratical

    Network Na

    z11a=______ z21a= ______

    z11a=______ z21a= ______

    z11a=______ z21a= ______

    z11a=______ z21a= ______

    z11b =______ z21b = ______ z11b=______ z21b= ______

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    Network Nb

    z11b=______ z21b= ______ z11b=______ z21b= ______

    Network N

    z11=______ z21= ______

    z11=______ z21= ______

    z11=______ z21= ______

    z11=______ z21= ______

    CONCLUSION: -

    QUIZ: -

    1. What do you mean by two port network?2. z parameters are known as _________ circuit parameters.3. If for any two port passive network z12is 4 ohm, what will be the value of z21?4. What are the applications of two port parameters?5. Why two networks are connected in series to get overall z parameters?6. For two networks connected in series if z21 a= 4 ohm and z21b= 6 ohm , what will

    be the value of z21 ?

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    EXPERIMENT NO: 7 DATE

    AIM : (i) To determine y parameters of a given TwoPort Resistive

    Network.

    (ii) To determine the y parameters of the parallel connection of two

    2-port resistive networks and verify the result by direct

    calculation.

    APPARATUS :

    (1) Ammeter 0-50mA 2

    (2) Voltmeter 0-10V 1

    (3) Regulated power supply 0 - 30V. 1

    (4) Board containing two port network 1

    THEORY:

    y parameters :

    In case of y parameters , I1 and I2 are expressed in terms of V1 and V2

    i.e I1 = y11V1 + y12V2

    I2 = y21V1 + y22V2

    The individual y parameters are defined by

    I1

    y11 = ___

    V1 V2= 0

    I1

    y12 = ___

    V2 V1= 0

    I2

    y21 = ____

    V1 V2 = 0

    I2

    y22 = ___

    V2 V1= 0

    It may be observed that

    (i) All the y-parameters have the dimensions of admittance.

    (ii) They are specified only when voltage at one of the ports is zero i.e short

    circuit at port 1 or port 2. Hence y parameters are known as short circuit

    admittance parameters.

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    YPARAMETERS OF PARALLEL CONNECTION OF TWO 2- PORT

    RESISTIVE NETWORK.

    The y - parameters ( short - circuit admittance parameters ) are useful in

    characterizing parallel connected two - port networks.

    They are found under short circuit conditions and hence they are referred

    as short circuit admittance parameters.

    The y-parameters are useful in characterizing parallel connected two port

    networks. The overall y parameters from the individually parameters can be

    found as under when the networks are connected in parallel.

    For network Na

    I1a y11a y12a V1a

    I2a

    =

    y21a y22a V2a

    ---------(1)

    For network Nb

    I1b y11b y12b V1b

    I2b

    =

    y21b y22b V2b

    ---------(2)

    For overall network N

    I1 y11 y12 V1

    I2

    =

    y21 y22 V2

    ---------(3)

    Note that

    V1= V1a= V1band I1= I1a+ I1b

    V2= V2a= V2band I2= I2a+ I2b------(4)

    Combining equation (1), (2) and (4), we get

    I1 y11a+y11b y12a +y12b V1

    I2

    =

    y21a+y21b y22a +y22b V2

    ---------(5)

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    Comparing equation (5) with equation (3), we get

    y11= y11a + y11b

    y12= y12a + y12b

    y21= y21a + y21b

    y22= y22a + y22b----------------(6)

    This result may be generalised for any number of networks connected

    in parallel. The individual short circuit admittance parameters are added to

    determine the overall Y parameters.

    PROCEDURE :

    (1)Connect the circuit diagram of Network Na as shown in fig(1).(2)Apply voltage at port 1 short circuiting the port 2 through

    an ammeter as shone in fig (2). Measure voltage and currents at both

    the port terminals.

    (3)Apply voltage at port 2 short circuiting the port 1 throughan ammeter as shown in fig (3). Measure voltage and currents at both

    the ports.

    (4)Calculate y parameters using measured values of voltageand currents and verify the results theoretically.

    (5)Connect the circuit as shown in fig (4) for network Nb only. Repeatsteps 2 to 4 for Network Nb.

    (6)Connect the networks Na and Nb in parallel as shown in fig(5)to form network N and repeat steps 2 to 4 for Network N. find its

    y - parameters. Verify the results theoretically.

    (7)Keep levels of voltages and currents such that the meterreadings are not exceeded their ranges and ratings of resistances

    OBSERVATION TABLE :

    (1) Network : Na

    SR.

    NO.

    V1a

    VOLTS

    I1a

    mA

    V2a

    VOLTS

    I2a

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 short circuited

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    (2) Network : Nb

    SR.

    NO.

    V1b

    VOLTS

    I1b

    mA

    V2b

    VOLTS

    I2b

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 short circuited

    (3) Network N :

    SR.

    NO.

    V1

    VOLTS

    I1

    mA

    V2

    VOLTS

    I2

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 short circuited

    CALCULATION :

    For Network Na :

    I1a

    y11a = ___ = ________________________________

    V1a V2a= 0

    I1a

    y12a = ___ = ________________________________

    V2a V1a= 0

    I2a

    y21a = ___ = _________________________________

    V1a V2a= 0

    I2a

    y22a = ___ = ________________________________

    V2a V1a= 0

    For Network Nb :

    I1b

    y11b = __ = _________________________________

    V1b V2b= 0

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    I1b

    y12b = ___ = _________________________________

    V2b V1b= 0

    I2b

    y21b = ___ = _________________________________

    V1b V2b= 0

    I2b

    y22b = ___ = ________________________________

    V2b V1b= 0

    For Network N :

    I1

    y11 = ___ = ________________________________

    V1 V2= 0

    I1

    y12 = ___ = ________________________________

    V2 V1= 0

    I2

    y21 = ___ = _________________________________

    V1 V2= 0

    I2

    y22 = ___ = ________________________________

    V2 V1= 0

    Check :

    (1) y11= y11a+ y11b = ____________ = ____________

    (2) y12= y12a+ y12b = ____________ = ____________

    (3) y21= y21a+ y21b =____________ = ____________

    (4) y22= y22a+ y22b = ____________ = ____________

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    RESULT TABLE :

    NETWORK Practical Theoretical

    Network Nay11a=______ y21a= ______

    y11a=______ y21a= ______

    y11a=______ y21a= ______

    y11a=______ y21a= ______

    Network Nb

    y11b =______ y21b = ______

    y11b=______ y21b= ______

    y11b=______ y21b= ______

    y11b=______ y21b= ______

    Network N

    y11=______ y21= ______

    y11=______ y21= ______

    y11=______ y21= ______

    y11=______ y21= ______

    CONCLUSION: -

    QUIZ: -

    1. y parameters are also known as _______ circuit parameters.2. If for any two port passive network y12is 0.4 mho, y21= ______.3. If two networks Naand Nbare connected in parallel y11a= 3 mho and y11b= 4 mho

    what will be the value of y11= ______.

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    EXPERIMENT NO: 8 DATE

    AIM : (i) To determine ABCD parameters of a given twoport resistive

    network.

    (ii) To determine the ABCD parameters of the cascade connection of

    two 2-port resistive networks and verify the result by direct

    calculation.

    APPARATUS :

    (1) Network board

    (2) Ammeters 0 - 50mA 2

    (3) Voltmeter 0 - 10V 1

    (4) Regulated power supply 0-30 V 1

    THEORY :

    The transmission parameters serve to relate the voltage and current at one port to

    voltage and current at the other port. In equation form,

    V1 = AV2 - BI2

    I1 = CV2 - DI2

    where A, B, C and D are the transmission parameters. They are also known

    as chain parameters, the ABCD parameters and general circuit parameters.

    Their first use is in the analysis of power transmission lines. From the

    circuit conditions, they can be found as follows,

    V1

    A = _____

    V2 I1=0

    V1

    -B = _____

    I2 V2=0I1

    C = _____

    V2 I2=0

    I1

    -D = _____

    I2 V2=0

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    ABCD PARAMETERS OF CASCADE CONNECTION OF TWO 2-PORT

    RESISTIVE NETWORK.

    The transmission parameters are useful in describing two port networks which

    are connected in cascade or in a chain arrangement. The overall parameters

    from the individual parameters can be found as under when the networks are

    connected in cascade.

    For network Na

    V1a Aa Ba V2a

    I1a= Ca Da -I2a

    ---------(1)

    For network Nb

    V1b Ab Bb V2b

    I1b

    =

    Cb Db -I2b

    ---------(2)

    For overall network N

    V1 A B V2

    I1

    =

    C D -I2

    ---------(3)

    Note that

    V1a= V1 V2a = V1b I2b= I2

    I1a = I1 I1b = - I2a V2b = V2 ------(4)

    Substituting these in equation (1) and equation (2), we get

    V1 Aa Ba Ab Bb V2

    I1

    =

    Ca Da Cb Db -I2

    ---------(5)

    Comparing equation (5) with equation (3), we get

    A B Aa Ba Ab Bb AaAb+BaCb AaBb+ BaDb

    C D=

    Ca Da Cb Db=

    CaAb+ DaCb CaBb+ DaDb------(6)

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    PROCEDURE :

    (1)Connect circuit diagram of Network Naas shown in fig (1).(2)Apply voltage at port 1 of network Na short circuiting the port

    2 through an ammeter as shown in fig (4). Measure voltages and

    currents at both the ports.

    (3)Apply voltage at port 1 of network Na keeping port 2 open circuited asshown in fig (5). Measure voltages and currents at both the ports.

    (4)Calculate ABCD parameters using measured values of voltagesand currents.

    (5)Connect the circuit as shown in fig (2) for network Nb only. Repeatsteps 2 to 4 for network Nb.

    (6)Connect both the networks in cascade as shown in fig (3). This formsnetwork N.

    (7)To measure parameters of network N follow the steps 2 to 4.(8)Verify the parameters theoretically and tabulate the results.(9)For each network verify that AD - BC = 1.

    OBSERVATION TABLE :

    (1) Network : Na

    SR.

    NO.

    V1a

    Volts

    I1a

    mA

    V2a

    Volts

    I2a

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 2 open circuited

    (2) Network : Nb

    SR.

    NO.

    V1b

    Volts

    I1b

    mA

    V2b

    Volts

    I2b

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 2 open circuited

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    (3) Network N :

    SR.

    NO.

    V1

    Volts

    I1

    mA

    V2

    Volts

    I2

    mA

    REMARK

    1 0 Port - 2 short circuited2 0 Port - 2 open circuited

    CALCULATION :

    For Network Na :

    V1a

    Aa = ___ = _________________________________

    V2a I2a= 0

    V1a

    Ba = ___ = _________________________________

    -I2a V2a= 0

    I1a

    Ca = ___ = _______________________________

    V2a I2a= 0

    I1a

    Da = ___ = _______________________________

    -I2a V2a= 0

    For Network Nb :

    V1b

    Ab = ___ = _________________________________

    V2b I2b= 0

    V1b

    Bb = ___ = _________________________________

    -I2b V2b= 0

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    I1b

    Cb = ___ = _______________________________

    V2b I2b= 0

    I1b

    Db = ___ = ________________________________

    -I2b V2b= 0

    For Network N :

    V1

    A = ___ = _________________________________

    V2 I2= 0

    V1

    B = ___ = _________________________________

    -I2 V2= 0

    I1

    C = ___ = ________________________________

    V2 I2= 0

    I1

    D = ___ = ________________________________

    -I2 V2= 0

    Check :

    A = AaAb+BaCb =_________________

    B = AaBb+ BaDb =_________________

    C = CaAb+ DaCb =_________________

    D = CaBb+ DaDb =_________________

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    RESULT TABLE :

    NETWORK - Na NETWORK - Nb NETWORK - N

    Pract. Theo. Pract. Theo. Pract. Theo.

    Aa Ab ABa Bb B

    Ca Cb C

    Da Db D

    CONCLUSION :

    QUIZ :

    1. ABCD parameters are also known as ___________ or _________ parameters.2. Why two networks are connected in cascade connection to get overall ABCD

    parameter?

    3. If A= 7 , B= 8 ohm and C = 2.5 mho , what will be the value of D?

    4. Ratio of driving voltage in one mesh to resulting current in other mesh is knownas ________ impedance.

    5. State the conditions for a network to be loss less in terms of ABCD parameters?6. State the condition for a network to be reciprocal and symmetrical.7. For _________ connection of two 2-port networks, ABCD parameters have to be

    multiplied.

    8. Are the ABCD parameters A(s), B(s),C(s) and D(s) the network functions?9. The relation ADBC = 1 is valid for ________ and _________ networks.10.Why negative sign is introduced in the equations?

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    EXPERIMENT NO: 9 DATE

    AIM : (i) To determine h - parameter of a given TwoPort Resistive

    Network.

    (ii) To determine the hparameters of the series parallel

    connection of two 2-port resistive networks and verify the result

    by direct calculation.

    APPARATUS :

    (1) Network board

    (2) Ammeters 0 - 50mA 2

    (3) Voltmeter 0 - 10V 1

    (4) Regulated power supply 0-30 V 1

    THEORY :

    h parameters representation is widely used in modeling of electronic

    components and circuits, particularly transistors. As both short circuit

    and open circuit terminal conditions are utilized hence, this parameter

    representation is known as hybrid parameter representation. In this form

    of representation, the voltage of the input poet and the current of the

    output port are expressed in terms of the current of the input poet and the

    voltage of the output port.

    We know that

    V1= h11I1 + h12V2

    I2= h21I1+ h22V2

    In matrix form

    V1 h11 h12 I1

    I2=

    h21 h22 V2---------(1)

    Where

    V1

    h11 = ___ = Input impedance when output is short circuited

    I1 V2= 0

    V1

    h12

    = ___ = Reverse voltage ratio when input open circuited

    V2 I1= 0

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    I2

    h21 = ___ = Forward current ratio when output short circuited

    I1 V2= 0

    I2

    h22 = ___ = Output admittance when input is open circuited

    V2 I1= 0

    h PARAMETERS FOR SERIES PARALLEL CONNECTION OF

    TWO 2-PORT NETWORK.

    Two port networks are said to be connected in series-parallel if the input

    ports are connected in series while the output ports are connected inparallel.

    For network Na

    V1a h11a h12a I1a

    I2a

    =

    h21a h22a V2a

    ---------(2)

    For network Nb

    V1b h11b h12b I1b

    I2b

    =

    h21b h22b V2b

    ---------(3)

    For overall network Nc

    V1 h11 h12 I1

    I2

    =

    h21 h22 V2

    ---------(4)

    Note that

    I1= I1a= I1band V1= V1a+ V1b

    I2= I2a+ I2band V2= V2a= V2b------(4)

    Combining equation (2), (3) and (4), we get

    V1 h11a+h11b h12a +h12b I1

    I2

    =

    h21a+h21b h22a +h22b V2

    ---------(5)

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    Comparing equation (5) with equation (3), we get

    h11= h11a+h11b

    h12= h12a +h12b

    h21= h21a+h21b

    h22= h22a +h22b----------------(6)

    This result may be generalized for any number of networks

    connected in series-parallel. The overall h-parameter matrix for series-

    parallel connected two port networks is simply the sum of h-parameter

    matrices of each individual two-port network connected in series-parallel.

    PROCEDURE :

    (1)Connect the circuit diagram of network Naas shown in fig (1).(2)Apply voltage at port 1 keeping port 2 short-circuited. Measure

    voltages and current at the port terminals as shown in fig (4). Keep

    levels of voltages and current such that meter readings are not

    exceeded their ranges and ratings of the resistances.

    (3)Apply voltage at port 2 keeping port 1 open circuited as shown in fig(5). Measure voltages and current at the port terminals.

    (4)Calculate h parameters using measured values of voltagesand currents and verify the results theoretically

    (5)Connect the circuit as shown in fig (2) for network Nb only. Repeatsteps 1 to 4 for network Nb.

    (6)Connect the networks Naand Nbin series parellel as shown in fig (3) toform the network N.

    (7)Repeat steps 2 to 4 to find h parameter for network N and verify resultstheoretically.

    (8)Keep levels of voltages and currents such that the meterreadings are not exceeded their ranges and ratings of resistances

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    OBSERVATION TABLE :

    (1) Network : Na

    SR.

    NO.

    V1a

    Volts

    I1a

    mA

    V2a

    Volts

    I2a

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 open circuited

    (2) Network : Nb

    SR.

    NO.

    V1b

    Volts

    I1b

    mA

    V2b

    Volts

    I2b

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 open circuited

    (3) Network N :

    SR.

    NO.

    V1

    Volts

    I1

    mA

    V2

    Volts

    I2

    mA

    REMARK

    1 0 Port - 2 short circuited

    2 0 Port - 1 open circuited

    CALCULATION :

    For Network Na :

    V1a

    h11a = ___ =

    I1a V2a= 0

    V1a

    h12a = ___ =

    V2a I1= 0

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    I2a

    h21a = ___ =

    I1a V2a= 0

    I2a

    h22a = ___ =

    V2a I1a= 0

    For Network Nb :

    V1b

    h11b = ___ =

    I1b V2b= 0

    V1b

    h12b = ___ =

    V2b I1= 0

    I2b

    h21b = ___ =

    I1b V2b= 0

    I2b

    h22b = ___ =

    V2b I1b= 0

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    For Network N :

    V1

    h11 = ___ =

    I1 V2= 0

    V1

    h12 = ___ =

    V2 I1= 0

    I2

    h21 = ___ =

    I1 V2= 0

    I2

    h22 = ___ =

    V2 I1= 0

    Check :

    (1) h11= h11a+h11b = ____________= ____________

    (2) h12= h12a +h12b = ____________= ____________

    (3) h21= h21a+h21b =____________ = ____________

    (4) h21= h21a+h21b= ____________ = ____________

    CONCLUSION: -

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    EXPERIMENT NO: 10 DATE

    AIM : (i) To determine g - parameter of a given TwoPort Resistive

    Network.

    (ii) To determine the g parameters of the parallel-series

    connection of two 2-port resistive networks and verify the result

    by direct calculation.

    APPARATUS :

    (1) Network board

    (2) Ammeters 0 - 50mA 2

    (3) Voltmeter 0 - 10V 1

    (4) Regulated power supply 0-30 V 1

    THEORY :

    Hybrid parameters (h parameters) and Inverse hybrid parameters (g parameters) are

    dual of each other. For g parameters both short circuit and open circuit terminal

    conditions are utilized. In this form of representation, the current of the input port and

    the voltage of the output port are expressed in terms of the voltage of the input port

    and the current of the output port.

    In case of g parameters, I1and V2are expressed in terms of V1 and I2.

    i.e. I1= g11V1 + g12I2 - (1)

    V2= g21V1+ g22I2 - (2)

    I1 g11 g12 V1

    V2=

    g21 g22 I2---------(1)

    Where

    I1

    g11 = ___ = Input admittance when output is open circuited

    V1 I2= 0

    g12 = I1 = Reverse current ratio when input short circuited

    I2 V1= 0

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    V2

    g21 = ___ = Forward voltage ratio when output open circuited

    V1 I2= 0

    V2

    g22 = ___ = Output impedance when input is short circuited

    I2 V1= 0

    PARAMETERS FOR PARALLEL - SERIES CONNECTION OF TWO 2-PORT

    RESISTIVE NETWORK

    Two port networks are said to be connected in parallel series if the input ports are

    connected in parallel while the output ports are connected in series.

    For network Na

    I1a g11a g12a V1a

    V2a

    =

    g21a g22a I2a

    ---------(2)

    For network Nb

    I1b g11b g12b V1b

    V2b

    =

    g21b g22b I2b

    ---------(3)

    For overall network Nc

    I1 g11 g12 V1

    V2

    =

    g21 g22 I2

    ---------(4)

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    Note that

    I1= I1a+ I1band V1= V1a= V1b

    I2= I2a= I2band V2= V2a+ V2b------(5)

    Combining equation (2), (3) and (5), we get

    I1 g11a+g11b g12a +g12b V1

    V2

    =

    g21a+g21b g22a +g22b I2

    ---------(6)

    Comparing equation (6) with equation (4), we get

    g11= g11a+g11b

    g12= g12a +g12b

    g21= g21a+g21b

    g22= g22a +g22b----------------(6)

    This result may be generalized for any number of networks connected in parallel-series.

    The overall g-parameter matrix for parallel-series connected two port networks is simply

    the sum of g-parameter matrices of each individual two-port network connected in

    parallel-series.

    PROCEDURE :

    (1)Connect the circuit diagram of network Naas shown in fig (1).(2)Open the output port and excite the input port with a known voltage

    source Vs as shown in fig (2) so that V1= Vs and I2= 0.

    (3)Determine I1and V2to obtain g11and g21.(4)Then the input port is short circuited and output port is excited with the

    same voltage source Vs as shown in fig (3) so that V2= Vs and V1= 0.(5)Determine I1and I2to obtain g12and g22.(6)Connect the circuit as shown in fig (4) for network Nb only. Repeat

    steps 2 to 4 for network Nb.

    (7)Connect the networks Na and Nb in parallel-series as shown in fig (5) toform the network N.

    (8)Repeat steps 2 to 4 for Network N and verify results theoretically.(9)Keep levels of voltages and currents such that the meter

    readings are not exceeded their ranges and ratings of resistances

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    OBSERVATION TABLE :

    (1) Network : Na

    SR.

    NO.

    V1a

    Volts

    I1a

    mA

    V2a

    Volts

    I2a

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 short circuited

    (2) Network : Nb

    SR.

    NO.

    V1b

    Volts

    I1b

    mA

    V2b

    Volts

    I2b

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 short circuited

    (3) Network N :

    SR.

    NO.

    V1

    Volts

    I1

    mA

    V2

    Volts

    I2

    mA

    REMARK

    1 0 Port - 2 open circuited

    2 0 Port - 1 short circuited

    CALCULATION :

    For Network Na :

    I1a

    g11a = ___ =

    V1a I2a= 0

    I1a

    g12a = ___ =

    I2a V1a= 0

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    V2a

    g21a = ___ =

    V1a I2a= 0

    V2a

    g22a = ___ =

    I2a V1= 0

    For Network Nb :

    I1b

    g11b = ___ =

    V1b I2b= 0

    I1b

    g12b = ___ =

    I2b V1b= 0

    V2b

    g21b = ___ =

    V1b I2b= 0

    V2b

    g22b = ___ =

    I2b V1b= 0

    For Network N

    I1

    g11 = ___ =

    V1 I2= 0

    I1

    g12 = ___ =

    I2 V1= 0

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    V2

    g21 = ___ =

    V1 I2= 0

    V2

    g22 = ___ =

    I2 V1= 0

    Check :

    (1) g11= g11a+g11b = ____________

    (2) g12= g12a +g12b = ____________

    (3) g21= g21a+g21b =____________

    (4) g21= g21a+g21b= ____________

    CONCLUSION: -

    QUIZ: -

    1. Will the g parameter matrix of a passive network always be symmetric?2. g-parameters matrix will not exist for which type of two port networks?3. If for any two port passive network g12is 0.6, g21= ______.4. If two networks Naand Nbare connected in parallel, g11a= 1.2 and g11b= 0.8

    what will be the value of g11?

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    EXPERIMENT NO: 11 DATE :

    AIM: Simulation of series RC,RL and RLC circuits with Virtual Laboratory.

    PROCEDURE:

    1. Open the link www.vlab.co.in

    2. Click on Amrita University

    3. Click on Virtual Electric Circuits.

    4. Click on series RC circuits. Login through Google/Yahoo ID.

    5. Click on procedure tab . Now click on simulator tab. According to procedure

    prepare circuit and plot the graph.

    6. Repeat step 4 and 5 for Series LC circuit and Series RLC circuit.

    7. Save all the results in Network drive .

    http://www.vlab.co/http://www.vlab.co/http://www.vlab.co/
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    EXPERIMENT NO: 12 DATE :

    AIM: Simulation of Parallel RC, RL and RLC circuits with Virtual Laboratory.

    PROCEDURE:

    1. Open the link www.vlab.co.in

    2. Click on Amrita University

    3. Click on Virtual Electric Circuits.

    4. Click on Parallel RC circuits. Login through Google/Yahoo ID.

    5. Click on procedure tab . Now click on simulator tab. According to procedure

    prepare circuit and plot the graph.

    6. Repeat step 4 and 5 for Parallel LC circuit and Parallel RLC circuit.

    7. Save all the results in Network drive .

    http://www.vlab.co/http://www.vlab.co/http://www.vlab.co/