Primary Division Deployment of returning Teachers – 2016-2017
Long Division Methods - Primary Resources
Transcript of Long Division Methods - Primary Resources
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Long Division Methods
Method 1
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We are going to try to solve
839 ÷ 27
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270)
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270) 5 6 9
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)5 6 9
2 9 9
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
5 6 9
2 9 9
2 9
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
5 6 9
2 9 9
2 9- 2 7 (27 x 1 = 27)
2
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839 ÷ 27
Method 18 3 9
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
- 2 7 0 (27 x 10 = 270)
5 6 9
2 9 9
2 9- 2 7 (27 x 1 = 27)
2 10 + 10 + 10 + 1 = 31
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839 ÷ 27
Method 1
= 3 1 r 2Or 31 2
27
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Long Division Methods
Method 2
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We are going to try to solve
839 ÷ 27
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839 ÷ 27
Method 2
becomes
27 ) 8 3 9
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839 ÷ 27
Method 2
27 ) 8 3 9
27 x 10 = 270
Miles off!
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839 ÷ 27
Method 2
27 ) 8 3 9
27 x 10 = 27027 x 20 = 540Getting better!
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839 ÷ 27
Method 2
27 ) 8 3 9
27 x 10 = 27027 x 20 = 54027 x 30 = 810
Much better!
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839 ÷ 27
Method 2
27 ) 8 3 9
27 x 30 = 810Put the 810 underneath.
- 8 1 0 2 9
27 x 30 = 810
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839 ÷ 27
Method 2
27 ) 8 3 9- 8 1 0 2 9
27 x 30 = 81027 x 1 = 27- 2 7
2
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839 ÷ 27
Method 2
27 ) 8 3 9- 8 1 0 2 9
27 x 30 = 81027 x 1 = 27
- 2 72
30 + 1 = 31
3 1
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839 ÷ 27
Method 2
27 ) 8 3 9- 8 1 0 2 9 Don’t forget
the remainder!- 2 72
3 1 r 2
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839 ÷ 27
Method 2
= 3 1 r 2Or 31 2
27
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Long Division Methods
Method 3
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We are going to try to solve
839 ÷ 27
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839 ÷ 27
Method 3
becomes
27 ) 8 3 9
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839 ÷ 27
Method 3
27 ) 8 3 9
Calculate 8 ÷ 27
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839 ÷ 27
Method 3
27 ) 8 3 9
We can’t do it, so we write the answer 0 here0
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839 ÷ 27
Method 3
27 ) 8 3 9
So we next look at 83 ÷ 27
0
Use you repeated subtraction here if this helps
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839 ÷ 27
Method 3
27 ) 8 3 90
2 x 27 = 543 x 27 = 81
3
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839 ÷ 27
Method 3
27 ) 8 3 90
3 x 27 = 81
3
- 8 12
We need to take off 81 from the 83 to get the remainder
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839 ÷ 27
Method 3
27 ) 8 3 90 3
- 8 12 9
Drop the next digit next to the 2
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839 ÷ 27
Method 3
27 ) 8 3 90 3 1
- 8 12 9
Now we are going to do 29 ÷ 27 and put the answer here
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839 ÷ 27
Method 3
27 ) 8 3 90 3 1
- 8 12 9
Now we are going to do 29 - 27 to get the remainder
2 7
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839 ÷ 27
Method 3
27 ) 8 3 90 3 1 r 2
- 8 12 92 7
2
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839 ÷ 27
Method 3
= 3 1 r 2
or 31 227