Lesson 3.6

14
Lesson 3.6 Prove Theorems about Perpendicular Lines

description

Lesson 3.6. Prove Theorems about Perpendicular Lines. Objective. Find the distance between a point and a line. Standard. 7.0 – Students prove and use theorems involving the properties of parallel lines cut by a transversal. Academic Language. Distance from a point to a line. Example. - PowerPoint PPT Presentation

Transcript of Lesson 3.6

Page 1: Lesson 3.6

Lesson 3.6Prove Theorems

about Perpendicular Lines

Page 2: Lesson 3.6

Objective

• Find the distance between a point and a line

Page 3: Lesson 3.6

Standard

• 7.0 – Students prove and use theorems involving the properties of parallel lines cut by a transversal

Page 4: Lesson 3.6

Academic Language

• Distance from a point to a line

Page 5: Lesson 3.6
Page 6: Lesson 3.6
Page 7: Lesson 3.6

Example

Page 8: Lesson 3.6
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Page 11: Lesson 3.6

Example

Page 12: Lesson 3.6

Distance from a point to a line

• The distance from a point to a line is the length of the perpendicular segment from the point to the line

Page 13: Lesson 3.6

Prove

Page 14: Lesson 3.6

Homework

• p.194 #1, 4, 6, 7, 22, 23, 31, 45


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The Honorable Christine A. Carney...Judge Christine A. Carney Attorney Survey Average Grades: Communications 3.6 3.6 3.5 3.6 3.6 3.6 3.5 3.6 3.4 3.8 3.8 3.8 1.0 1.5 2.0 2.5 3.0 3.5

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Solution: Electricity: 1 kw-hr = (1 x10 3 J/s)(3.6 x10 3 s) = 3.6 x10 6 J 1 kw-hr = (1 x10 3 J/s)(3.6 x10 3 s) = 3.6 x10 6 J E/$ = 3.6 x10 6 /$0.1 = 3.6.

Solution: Electricity: 1 kw-hr = (1 x10 3 J/s)(3.6 x10 3 s) = 3.6 x10 6 J 1 kw-hr = (1 x10 3 J/s)(3.6 x10 3 s) = 3.6 x10 6 J E/$ = 3.6 x10 6 /$0.1 = 3.6.

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The Honorable Timothy J. Simmons...Timothy J. Simmons Attorney Survey Average Grades: Communications 3.4 3.7 3.6 3.6 3.6 3.4 3.7 3.6 3.7 3.6 3.5 3.7 3.5 3.8 3.7 1.0 1.5 2.0 2.5 3.0

Presentation (3.6 MB)

Presentation (3.6 MB)