Lesson 23 HEAD LOSS DEFINE the terms head loss, frictional loss, and minor losses. DETERMINE...
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Transcript of Lesson 23 HEAD LOSS DEFINE the terms head loss, frictional loss, and minor losses. DETERMINE...
Lesson 23HEAD LOSS
• DEFINE the terms head loss, frictional loss, and minor losses.
• DETERMINE friction factors for various flow situations using the Moody chart.
• CALCULATE the head loss in a fluid system due to frictional losses using Darcy’s equation.
• CALCULATE the equivalent length of pipe that would cause the same head loss as the minor losses that occur in individual components.
Head Loss
• A measure of the reduction in the total head (sum of elevation head, velocity head and pressure head) of the fluid as it moves through a fluid system.
• Unavoidable in real fluids.
• Caused by • Friction between the fluid and the walls of the pipe• Friction between adjacent fluid particles as they move relative to one another;• Turbulence caused whenever the flow is redirected
• Frictional loss - That part of the total head loss that occurs as the fluid flows through straight pipes.
• Head loss is directly proportional to – the length of pipe, – the square of the fluid velocity,– the friction factor.
• The head loss is inversely proportional to the diameter of the pipe
D
Lv f Loss Head
2
Friction Factor• Depends on – Reynolds number– Relative roughness of the pipe’s inner surface
• Obtained from the Moody Chart
D Roughness lativeRe
Darcy’s Equation
• Used to calculate frictional head loss
• Two forms– Losses in the system associated with the length of
the pipe.– “Minor” losses
Frictional Head Loss
where:
f = friction factor (unitless)L = length of pipe (ft)D = diameter of pipe (ft)v = fluid velocity (ft/sec)g = gravitational acceleration (ft/sec2)
g2D
LvfH
2
f
Minor Losses
• Losses in pipelines due to – Bends,– Elbows– Joints– Valves
• Often more important than the losses due to pipe friction• For turbulent flow, the head loss varies as the square of the velocity. • Expressed by means of a loss coefficient (k)
g2
vkH
2
f
Equivalent Pipe Length• Found by setting the two forms of Darcy’s
Equation equal to each other and solving for L to get
• Can also solve for k to get
f
DkLeq
D
Lfk eq