Lecture Objectives: Answer question related to Project 1 Finish with thermal storage systems Learn...
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Transcript of Lecture Objectives: Answer question related to Project 1 Finish with thermal storage systems Learn...
Lecture Objectives:
• Answer question related to Project 1
• Finish with thermal storage systems
• Learn about plumbing systems
Stratified chilled water tanks
Temperature and dynamics Temperature at outlet
Stratified chilled water tanksdiffuser geometry
Challenge:“Pull” large amount of energy withoutdisturbing stratification
Ice Storage Tank
Many issues !….As freezing progresses progress the ice becomes thicker and significantly impedes heat transfer
Open Ice Storage Tank
Also issues !…..
Fluid Flow Rate and Freeze ΔT
Impact on Chiller Efficiency
PCMs
A. Sharma et al. / Renewable and Sustainable Energy Reviews 13 (2009) http://www.docunator.com/bigdata/1/1367142535_c566e7d75e/reviewexample2.pdf
Other latent heat thermal storage systems (research is ongoing)
Construction and benefits Active
Passive (wall)
Modeling(stratified tank)
Write energy and mass balancer equation for each section
Installation of thermal storage system
DownstreamUpstream
• Increases chiller efficiency • Increases chiller capacity • Overall system efficiency ??? • Decreases storage capacity• Simplifies system layout• …..
• Decreases chiller efficiency• Decreases chiller capacityOverall system efficiency ???• Increases storage capacity•……• Does not allow chiller shut down!
Plumbing Systems - Hydronic Terms• Head loss
• Open-loop vs. closed loop
• Open System
• Closed System
Pump
h
Cooling coil in AHUChiller
Pump
Is this open or closed system ?
Cooling towers
Relationship between velocity in a pipe and pressure drop
Δp ~ v2
Δp = Constant × v2
Δp [
Pa o
r ft w
ater
]
v [m/s or fpm]
larger pipesmaller pipe
Required power (P) for the pump
P = V × Δp P –power [W], V –volume flow rate [m3/s], v – velocity [m/s] Δp – pressure drop [Pa]
Δp ~ v2 (Δp ~ V2 – when same pipe is used)P ~ V × V2 – when same pipe is used
P ~ V3 P2/P1 = (V2/V1)3 For the same pipe
When different pipe is used for the same flow rate:
For the same flow rate VReduction of D:
D1D2= D1/2 A1
V1
P1
A2=1/22 A1
V2=22 V1
P2/P1 = (D1/D2)4 - for the same flow rate
or 50% smaller diameter of the pipefor the same flow rate wee have: 4 times larger velocity 16 times larger pressure drop and16 times lager power for the pump
Head Loss
Fittings
gVkh2
2
Pumps• Raise pressure and produce flow• Main type
• Centrifugal
Inline Base mounted
Example of Turbine pump
Reading (textbook)Page 3-36 - 3-45
Pump curves
• NPSHR = Net Positive Suction Head Required
Changing Pump Speed
Net Positive Suction Head(cavitation)
Curve for Multiple Pumps
System Curves
A B∆p
V
A+B
Parallel A B
A B
∆p
V
A+B
A
B
Serial
Find a system curve for this plumbing configuration
Primary/Secondary and Tertiary Pumping (schematics A&B below)
System balancing
BOILER
HC2
AHU1 AHU2
HC1
pump
100 ft 1000 ft
2 gpm 10 gpm
10 ft