Lecture 5: Junctions

51
Lecture 5 Junctions! R. Treharne Nov 6 th 2014

Transcript of Lecture 5: Junctions

Page 1: Lecture 5: Junctions

Lecture 5Junctions!

R. TreharneNov 6th 2014

Page 2: Lecture 5: Junctions

Lecture OutlineL5

● Drawing Junctions

● Junction Formation – A Physical Picture

● Abrupt Junction

● Deriving Important Junction parameters

● Deriving diode equation

● Ideality Factor - Recombination

Page 3: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (n-type)

qφm

qφn

EG

EC

EV

EV

EF

Schottky Junction

Page 4: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (n-type)

qφm

qφn

EC

EV

EV

EF E

F

EG

One Rule!● Fermi level must be in equilibrium

Page 5: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (n-type)

qφm

qφn

EC

EV

EV

EF E

F

qφm

qφn

EC

EV

EV

metal SC (n-type)

EG E

G

“Intimate Contact”

Page 6: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (n-type)

qφm

qφn

EC

EV

EV

EF

metal SC (n-type)

EG

qφn

EC

EV

EV

EF

EG

qφm

qVbiqφ

B

Vbi = φ

m -

φ

s

φB = φ

m - χ

“Built-in Voltage”

Barrier Height

BAND BENDING!

Page 7: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (p-type)

qφm

qφp

EG

EC

EV

EV

EF

Page 8: Lecture 5: Junctions

Metal-SemiconductorL5

metal SC (p-type)

qφm

qφp

EG

EC

EV

EV

EF

qφp

EC

EV

EV

EF

EG

qφm

qVbi

qφB

metal SC (p-type)

Vbi = φ

m -

φ

p

φB = E

G/q - (φ

m - χ)

Page 9: Lecture 5: Junctions

Metal-SemiconductorL5

φB = φ

m - χ Why doesn't this rule hold?

Metal – SC interface effects

● Lattice Mis-match

● High density of defects

● Interface states in gap

Page 10: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

EC

Page 11: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

EF

EF

EC

Page 12: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

qφp

qχp

EF

qφn

qχn

EG

EF

p n

EG

EV

EC

EC

EC

EV

Page 13: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

EF

EF

p n

qVbi

Page 14: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

EF

EF

p n

qVbi

Ei

Ei

Page 15: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EG

EF

p n

qφn

qχn

EV

EF

EG

p-n homojunction

EF

EF

p n

qVbi

Ei

Ei

Defining Electrostatic potential, Ψ, for a SC● Difference between Ei and Ef

qΨn

qΨp

Vbi

= Ψn - Ψ

p

Ele

c tr o

s ta

tic P

ot e

ntia

l , Ψ

Ele

c tr o

n e

ne

r gy,

E

KNOW HOW TO DRAW THIS!

Coming back here shortly to get a more physical picture

Page 16: Lecture 5: Junctions

Semiconductor-SemiconductorL5

Everybody's favourite homojunction - Silicon

p-type n-type

http://electronics.howstuffworks.com/diode1.htm

Every bit of electronics you own is jam packed with silicon homojunctions

Extrinsically doped

iPhone 5:1 billion transistors!~ 45 nm wide

Mono-C solar cells~750 μm thickcell size = 1 cm2

Page 17: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EFp

p n

qφn

qχn

EFn

p-n heterojunction: Different band gaps

ΔEV

ΔEC

wide gap narrow gap

EF

1. Align the Fermi level. Leave some space for transition region.

Page 18: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EFp

p n

qφn

qχn

EFn

p-n heterojunction: Different band gaps

ΔEV

ΔEC

wide gap narrow gap

EF

2. Mark out ΔEC and ΔE

C at mid-way

points

ΔEC

ΔEC

Page 19: Lecture 5: Junctions

Semiconductor-SemiconductorL5

qφp

qχp

EFp

p n

qφn

qχn

EFn

p-n heterojunction: Different band gaps

ΔEV

ΔEC

wide gap narrow gap

EF

3. Connect the C.B. and V.B. keeping the band gap constant in each material

Barrier to hole transport

Difference in band gaps give rise to discontinuities in band diagrams. This limits the carrier transport by introducing potential barriers at the junction

Page 20: Lecture 5: Junctions

Semiconductor-SemiconductorL5

Examples of p-n heterojections

http://pubs.rsc.org/en/content/articlehtml/2013/ee/c3ee41981a#cit111

Most thin-film PV technologies

Page 21: Lecture 5: Junctions

Semiconductor-SemiconductorL5

Examples of p-n heterojections

III-V multi-junction devices

Being able to control the band offsets of a material can help eliminate barriers

Page 22: Lecture 5: Junctions

Physical PictureL5

Drawing band schematics for junctions all day is fun, but what is actually going on here?

http://www.youtube.com/watch?v=JBtEckh3L9Q

Excellent qualitative description6:27 – Didactic Model of Junction formation

Page 23: Lecture 5: Junctions

Physical PictureL5

Equilibrium Fermi Levels – Explained – our one rule for drawing band schematics!

J=J (drift )+J (diffusion)=0

In thermal equilibrium, i.e. steady state: not net current flows

http://en.wikipedia.org/wiki/File:Pn-junction-equilibrium.png

notice position of “metallurgical” junction. Usually call this x=0

Page 24: Lecture 5: Junctions

Physical PictureL5

Lets look at hole current first:

J p = J p(drift)+J p(diffusion)

= qμ p p ξ−qDpdpdx

Page 25: Lecture 5: Junctions

Physical PictureL5

Lets look at hole current first:

J p = J p(drift)+J p(diffusion)

= qμ p p ξ−qDpdpdx

μ p=e τ

mh

mobility: hole distribution: e-field: diffusion coefficient

p=ni e(E i−E F)/ kBT

OK to use Boltzmann as approx to Fermi-Dirac

dpdx

=p

k BT ( dE i

dx−dEF

dx )

ξ=1e

dEi

dxD p=(k BT /e )μ p

Einstein relation

will use this shortly

Page 26: Lecture 5: Junctions

Physical PictureL5

J p = J p(drift)+J p(diffusion)

= qμ p p ξ−qD pdpdx

= μ p pdEi

dx−μ p p(dEi

dx−dE F

dx )0 = μ p p

dEF

dx

Condition for steady state

Page 27: Lecture 5: Junctions

Physical PictureL5

dEF

dx=0

TA DA!

The same is true from consideration of net electron current, Jn

Page 28: Lecture 5: Junctions

Abrupt JunctionL5

Hook & Hall, “Soild State Physics”, 2nd ed. Chap 6, p. 171

outside depletion region:p = N

A and n = N

D

Space-charge conditionN

Aw

p = N

dw

ni.e. areas of rectangles must be the same

electric field

electrostaticpotential

charge density

I've already called this Vbi

Max field (at x=0):ξ

m = qN

Dx

n/ε

s = qN

Ax

p/ε

s

ξm

Area = Vbi

V bi=ϕn−ϕp=k BTq

ln(N AN D

ni2 )

Page 29: Lecture 5: Junctions

Abrupt JunctionL5

Hook & Hall, “Soild State Physics”, 2nd ed. Chap 6, p. 171

outside depletion region:p = N

A and n = N

D

Space-charge conditionN

Aw

p = N

dw

ni.e. areas of rectangles must be the same

electric field

electrostaticpotential

charge density

I've already called this Vbi

Max field (at x=0):ξ

m = qN

Dx

n/ε

s = qN

Ax

p/ε

s

ξm

Area = Vbi

V bi=ϕn−ϕp=k BT

qln( N AN D

ni2 )

Lets derive this!(but skip if I'm being slow)

Page 30: Lecture 5: Junctions

Abrupt JunctionL5

From Earlier:

ϕ =−1e

(E i−EF )

What is in p and n regions away from junction?ϕ

Here

p=ni e(E i−E F)/ kBT n=ni e

(Ei−EF )/kBTand

ϕp≡−1e(E i−EF)|x⩽−x p

=−k BTe ( N A

ni)

ϕn≡−1e(E i−EF)|x⩾−xn

=−k BTe ( N D

ni)

S. M. Sze, “Semiconductor Devices: Physics and Technology”, Chap 4, p.90

Page 31: Lecture 5: Junctions

Abrupt JunctionL5

Hence:

V bi=ϕn−ϕp=k BTq

ln( N A N D

ni2 )

Next Question:

How do I calculate in the depletion region? (And why would I want to?)

Must solve Poisson's Equation

ϕ

want to know what this is for Si? Go to: http://pveducation.org/pvcdrom/pn-junction/intrinsic-carrier-concentration

∇2ϕ=−

ρε

Go read some electrostatics if you're interested

Page 32: Lecture 5: Junctions

Abrupt JunctionL5

∇2ϕ=−

ρε ρ(x)={

−N Ae+N D e

0

−wp< x<0

0< x<w n

elsewhere

ξ=−d ϕ

dx={−

N A eε ( x+w p)

N Deε ( x+wn)

−wp< x<0

0< x<wn

ϕ( x)={−N A e2ε

(x+wp)2

N D e

2ε(x+wn)

2

INTEGRATE ONCE

INTEGRATE TWICE

−wp< x<0

0< x<wn

Page 33: Lecture 5: Junctions

Abrupt JunctionL5

V bi=e2ε

(N Aw p2+N Dwn

2)

Vbi

using result:

wn=√ 2 εN AV bi

eN D (N A+N D)

w p=√ 2εN DV bi

eN A(N A+N D)

and with some jiggery pokery:

W=w p+wn=√ 2ε

e (N A+N D

N A N D)

N Awp=N Dwn

V bi=ϕ(x=wn)−ϕ( x=−w p)

Page 34: Lecture 5: Junctions

Under BiasL5

What happens to our ideal p-n junction if we put a forward or reverse bias across it?

Page 35: Lecture 5: Junctions

Under BiasL5

p n

0 wn

-wp

W

EF

ZERO BIAS

Vbi

Page 36: Lecture 5: Junctions

Under BiasL5

p n

0 wn

-wp

W

EF

FORWARD BIAS

Vbi - V

EF

+ -

● Electron energy levels in p side lowered relative to those in n side

● Energy barrier qVbi

reduced● Flow of electrons from n to p

increases● Flow of holes from p to n increases● Depletion width decreases

Page 37: Lecture 5: Junctions

Under BiasL5

p n

0 wn

-wp

W

EF

REVERSE BIAS

Vbi + V

EF

- +

● Electron energy levels in p side raised relative to those in n side

● Energy barrier qVbi

increase by V● Flow of electrons from n to p

reduced● Junction width increases

Page 38: Lecture 5: Junctions

L5

Under Bias

Of course, you already know all about this:

Page 39: Lecture 5: Junctions

Ideal dark JV curveL2

J0 = 1 x 10-10 A/cm2

http://pveducation.org/pvcdrom/pn-junction/diode-equation

J=J 0[exp ( eVk BT )−1 ]

Page 40: Lecture 5: Junctions

Ideal dark JV curveL2

J0 = 1 x 10-10 A/cm2

http://pveducation.org/pvcdrom/pn-junction/diode-equation

J=J 0[exp ( eVk BT )−1 ]

Lets derive this by considering our band schematic. Fun fun fun!

Page 41: Lecture 5: Junctions

L5

Deriving Shockley Equation

Steady State again (i.e. no bias)Consider electron drift current – I

eo from p to n

Page 42: Lecture 5: Junctions

L5

Deriving Shockley Equation

Steady State again (i.e. no bias)Consider electron drift current – I

eo from p to n

I e0=e×(generationrate /volume)×(volumewithin Le of depletion zone )

W

Le

J e 0=e (npτ p

)Le

Page 43: Lecture 5: Junctions

L5

Deriving Shockley Equation

Steady State again (i.e. no bias)Consider electron drift current – I

eo from p to n

I e0=e×(generationrate /volume)×(volumewithin Le of depletion zone )

J e 0=e (npτ p

)Le

W

Le

number of electrons on p side

electron lifetime

Le=√D e τ pdiffusion length

Page 44: Lecture 5: Junctions

L5

Deriving Shockley Equation

Steady State again (i.e. no bias)Consider electron drift current – I

eo from p to n

W

Le

By assuming that all acceptors on p side are ionized:

np=n i

2

p p

=ni

2

N A

J e 0=eDe ni

2

LeN A

can re-write Je0

as:

Page 45: Lecture 5: Junctions

L5

Deriving Shockley Equation

What happens under forward bias?

● Drift (p to n)? - Nothing. No potential barrier in this direction

● Diffusion (n to p)? - Increases by exponential factor:

exp ( eVk BT )

If we assume occupation of states in CB is given by Boltzmann distribution

Page 46: Lecture 5: Junctions

L5

Deriving Shockley Equation

What happens under forward bias?

● Drift (p to n)? - Nothing. No potential barrier in this direction

● Diffusion (n to p)? - Increases by exponential factor:

exp ( eVk BT )

If we assume occupation of states in CB is given by Boltzmann distribution

Net electron current:

J e =−J e 0+J e 0 exp (eVk BT )= J e 0[exp (eVk BT )−1]

Page 47: Lecture 5: Junctions

L5

Deriving Shockley Equation

Can do the same for the net hole current:

J h=J h0 [exp( eVk BT )−1] J h0=

eDH ni2

Lh N D

where

Page 48: Lecture 5: Junctions

L5

Deriving Shockley Equation

Can do the same for the net hole current:

J h=J h0 [exp( eVk BT )−1] J h0=

eDH ni2

Lh N D

where

Therefore: Net Current!

J=J e+Jh=J0 [exp( eVkBT )−1] J 0=J e 0+J h0=eni

2( De

Ln N A

+D h

LhN A)

ideal diode equation reverse saturation current,a.k.a “dark current”

Page 49: Lecture 5: Junctions

L5

Deriving Shockley Equation

Previous derivation ignores the recombination and generation of carriers within the depletion layer itself!

J=J 0[exp ( eVnk BT )−1]

Page 50: Lecture 5: Junctions

L5

Deriving Shockley Equation

Previous derivation ignores the recombination and generation of carriers within the depletion layer itself!

J=J 0[exp ( eVnk BT )−1]

ideality factor – a complete FUDGE

Worth reading up about – but don't stress out about it.

● S. M. Sze, “Semiconductor Devices”, 2nd ed. Chap 4, pp 109 – 113● Hook & Hall “Solid State Physics”, 2nd ed. Chap 6, pp 178 – 179

I have these books if you want them.

Page 51: Lecture 5: Junctions

Lecture SummaryL5

● Drawing Junctions

● Junction Formation – A Physical Picture

● Abrupt Junction

● Deriving Important Junction parameters

● Deriving diode equation

● Ideality Factor - Recombination