Lecture 1 Temperature

8/8/2019 Lecture 1 Temperature

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Temperature Measurement

Temperature

Copyright 2005 by Pearson Education, Inc.

Publishing as Benjamin Cummings

Copyright 2007 by Pearson Education, Inc.Publishing as Benjamin Cummings


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Temperature

Temperature

Is a measure of how hot or coldan object is compared to another

object. Indicates that heat flows from the

object with a higher temperatureto the object with a lowertemperature.

Is measured using athermometer.



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Temperature Scales

Temperature scales

Are Fahrenheit,Celsius, andKelvin.

Have referencepoints for theboiling andfreezing points ofwater.



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A. What is the temperature of freezing water?

1) 0F 2) 0C 3) 0 K

B. What is the temperature of boiling water?1) 100F 2) 32F 3) 373 K

C. How many Celsius units are between the boiling and

freezing points of water?1) 100 2) 180 3) 273

Learning Check


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A. What is the temperature of freezing water?

2) 0C

B. What is the temperature of boiling water?3) 373 K

C. How many Celsius units are between the boiling and

freezing points of water?1) 100

Solution


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On the Fahrenheit scale, there are 180 F between the

freezing and boiling points and on the Celsius scale,there are 100 C.

180F = 9F = 1.8F100C 5C 1C

In the formula for the Fahrenheit temperature, adding 32adjusts the zero point of water from 0 C to 32 F.

TF = 9/5 TC + 32

or TF = 1.8 TC + 32

Fahrenheit Formula


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TC is obtained by rearranging the equation for TF.TF = 1.8TC + 32

Subtract 32 from both sides.

TF

- 32 = 1.8TC

( +32 - 32)

TF - 32 = 1.8TC Divide by 1.8 TF - 32 = 1.8 TC

1.8 1.8

TF - 32 = TC1.8

Celsius Formula


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Solving A Temperature Problem

A person with hypothermia has abody temperature of 34.8C. What isthat temperature in F?

TF = 1.8 TC + 32

TF = 1.8 (34.8C) + 32exact tenth's exact

= 62.6 + 32= 94.6Ftenths



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The normal temperature of a chickadee is 105.8F.What is that temperature on the Celsius scale?

1) 73.8C2) 58.8C

3) 41.0C

Learning Check


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3) 41.0 C

TC = (TF - 32)

1.8

= (105.8 - 32)

1.8

= 73.8F = 41.0C

1.8

Solution


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A pepperoni pizza is baked at 455F. Whattemperature is needed on the Celsius scale?

1) 423C

2) 235C

3) 221C

Learning Check


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A pepperoni pizza is baked at 455F. Whattemperature is needed on the Celsius scale?

2) 235C

TF - 32 = TC1.8

(455 - 32) = 235C

1.8

Solution


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On a cold winter day, the temperature is 15C.

What is that temperature in F?

1) 19F2) 59F

3) 5F

Learning Check


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3) 5F

TF = 1.8 TC + 32

TF = 1.8(

15C) + 32= 27 + 32

= 5F

Note: Be sure to use the change sign key onyour calculator to enter the minus sign.

1.8 x 15 +/ = 27

Solution


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The Kelvin temperature

Has 100 units between the freezing and boiling pointsof water.

100 K = 100C or 1 K = 1C

Is obtained by adding 273 to the Celsius temperature.

TK = TC + 273

0 K (absolute zero) is the lowest possible temperature.

0 K = 273C

Kelvin Temperature Scale


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Temperatures

TABLE 1.11



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What is normal body temperature of 37C in kelvins?

1) 236 K

2) 310. K

3) 342 K

Learning Check


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What is normal body temperature of 37C in kelvins?

2) 310. K

TK = TC + 273= 37C + 273

= 310. K

Solution

Lecture 1 Temperature

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