Lect07 Handout

31
Physics 102: Lecture 7, Slide 1 RC Circuits Physics 102: Lecture 7

Transcript of Lect07 Handout

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Physics 102: Lecture 7, Slide 1

RC Circuits

Physics 102: Lecture 7

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Physics 102: Lecture 7, Slide 2

Recall ….

• First we covered circuits with batteries and capacitors

– series, parallel

• Then we covered circuits with batteries and resistors

– series, parallel– Kirchhoff’s Loop and Junction Relations

• Today: circuits with batteries, resistors, and capacitors

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Physics 102: Lecture 7, Slide 3

RC CircuitsRC Circuits

RC Circuits

Charging Capacitors

Discharging Capacitors

Intermediate Behavior

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Physics 102: Lecture 7, Slide 4

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Physics 102: Lecture 7, Slide 5

RC CircuitsRC Circuits Circuits that have both resistors and capacitors:

With resistance in the circuits, capacitors do not charge and discharge instantaneously – it takes time (even if only fractions of a second).

V

R2

R1C

SS

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Physics 102: Lecture 7, Slide 6

CapacitorsCapacitors

Charge (and therefore voltage) on Capacitors cannot change instantly: remember VC = Q/C

Short term behavior of Capacitor: If the capacitor starts with no charge, it has no potential difference

across it and acts as a wire If the capacitor starts with charge, it has a potential difference across it

and acts as a battery.

Long term behavior of Capacitor: Current through a Capacitor eventually goes to zero. If the capacitor is charging, when fully charged no current flows and

capacitor acts as an open circuit. If capacitor is discharging, potential difference goes to zero and no

current flows.

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Physics 102: Lecture 7, Slide 7

Charging CapacitorsCharging Capacitors

Capacitor is initially uncharged and switch is open. Switch is then closed. What is current I0 in circuit immediately thereafter?

What is current I in circuit a long time later?

RC

S

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Physics 102: Lecture 7, Slide 8

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Physics 102: Lecture 7, Slide 9

Charging Capacitors: t=0Charging Capacitors: t=0

Capacitor is initially uncharged and switch is open. Switch is then closed. What is current I0 in circuit immediately thereafter?Capacitor initially unchargedTherefore VC is initially 0Therefore C behaves as a wire (short circuit)

- + I0 R = 0

» I0 = /R

RC

S

R

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Physics 102: Lecture 7, Slide 10

Charging Capacitors: t>0Charging Capacitors: t>0I0 = /RPositive charge flows

» Onto bottom plate (+Q)

» Away from top plate (-Q)

» As charge builds up, VC rises (VC=Q/C)

» Loop: - + VC + I R = 0 I = (-VC)/R Therefore I falls as Q rises

When t is very large ()» I = 0: no current flow into/out of capacitor for t large

» VC =

RC

+

-

R

Demo

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Physics 102: Lecture 7, Slide 11

ACT/Preflight 7.1

2R

C R

S2

Both switches are initially open, and the capacitor is uncharged. What is the current through the battery just after switch S1 is closed?

1) Ib = 0 2) Ib = E /(3R)

3) Ib = E /(2R) 4) Ib = E /R

S1

Ib

+

-

+

+

-

-

6%

17%

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Physics 102: Lecture 7, Slide 12

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Physics 102: Lecture 7, Slide 13

ACT/Preflight 7.3 Both switches are initially open, and the capacitor is uncharged. What is the

current through the battery after switch 1 has been closed a long time?

1) Ib = 0 2) Ib = E/(3R)

3) Ib = E/(2R) 4) Ib = E/R

2R

C R

S2

S1

Ib

+

-

+

+

-

-

5%

11%

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Physics 102: Lecture 7, Slide 14

Discharging CapacitorsDischarging Capacitors Capacitor is initially charged (Q) and

switch is open. Switch is then closed. What is current I0 in circuit immediately thereafter?

What is current I in circuit a long time later?

RC

S

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Physics 102: Lecture 7, Slide 15

Discharging CapacitorsDischarging Capacitors

Capacitor is initially charged (Q) and switch is open. Switch is then closed. What is current I0 in circuit immediately thereafter?-Q/C + I0R = 0I0 = Q/RC

What is current I in circuit a long time later?I = 0

RC

+-

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Physics 102: Lecture 7, Slide 16

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Physics 102: Lecture 7, Slide 17

ACT/Preflight 7.5After switch 1 has been closed for a long time, it is opened and

switch 2 is closed. What is the current through the right resistor just after switch 2 is closed?

1) IR = 0 2) IR = /(3R)

3) IR = /(2R) 4) IR = /R

2R

C R

S2S1

IR

+

-

+

+

-

-

+

-

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Physics 102: Lecture 7, Slide 18

ACT: RC CircuitsBoth switches are closed. What is the final charge on

the capacitor after the switches have been closed a long time?

1) Q = 0 2) Q = C E /3

3) Q = C E /2 4) Q = C E R

2R

C

S2S1

IR

+

-

+

+

-

-

+

-

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Physics 102: Lecture 7, Slide 19

RC Circuits: Charging

• Loop: - + I(t)R + q(t) / C = 0

• Just after…: q =q0– Capacitor is uncharged

– - + I0R = 0 I0 = / R

• Long time after: Ic= 0– Capacitor is fully charged

– - + q/C =0 q = C

• Intermediate (more complex)q(t) = q(1-e-t/RC)

I(t) = I0e-t/RC

C

R

S1

S2

+

+

+

I-

-

-

The switches are originally open and the capacitor is uncharged. Then switch S1 is closed.

t

q

RC 2RC

0

q

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Physics 102: Lecture 7, Slide 20

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Physics 102: Lecture 7, Slide 21

RC Circuits: Discharging• Loop: - q(t) / C - I(t) R = 0

• Just after…: q=q0

– Capacitor is still fully charged

– -q0 / C - I0 R = 0 I0 = -q0 / (RC)

• Long time after: Ic=0– Capacitor is discharged (like a wire)

– -q / C = 0 q = 0

• Intermediate (more complex)q(t) = q0 e-t/RC

Ic(t) = I0 e-t/RC

C

R

S1

-+

+

I-

+

-

S2

q

RC 2RC

t

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Physics 102: Lecture 7, Slide 22

What is the time constant?What is the time constant?

The time constant = RC.

Given a capacitor starting with no charge, the time constant is the amount of time an RC circuit takes to charge a capacitor to about 63.2% of its final value.

The time constant is the amount of time an RC circuit takes to discharge a capacitor by about 63.2% of its original value.

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Physics 102: Lecture 7, Slide 23

Time Constant Demo

• Which system will be brightest?• Which lights will stay on longest?• Which lights consumes more energy?

2

Each circuit has a 1 F capacitor charged to 100 Volts.When the switch is closed:

1

= 2RC = RC/2

2 I=2V/R1

Same U=1/2 CV2

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Physics 102: Lecture 7, Slide 24

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Physics 102: Lecture 7, Slide 25

Summary of Concepts• Charge (and therefore voltage) on Capacitors cannot change

instantly: remember VC = Q/C

• Short term behavior of Capacitor:– If the capacitor starts with no charge, it has no potential difference

across it and acts as a wire – If the capacitor starts with charge, it has a potential difference across it

and acts as a battery.

• Long term behavior of Capacitor: Current through a Capacitor eventually goes to zero.– If the capacitor is charging, when fully charged no current flows and

capacitor acts as an open circuit.– If capacitor is discharging, potential difference goes to zero and no

current flows.• Intermediate behavior: Charge and current exponentially

approach their long-term values = RC

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Physics 102: Lecture 7, Slide 26

Practice!

Calculate current immediately after switch is closed:

Calculate current after switch has been closed for 0.5 seconds:

Calculate current after switch has been closed for a long time:

Calculate charge on capacitor after switch has been closed for a long time:

R

CE

S1

R=10C=30 mF

E =20 Volts

I+

+

+

-

-

-

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Physics 102: Lecture 7, Slide 27

ACT: RC Challenge

1) 0.368 q0 2) 0.632 q0

3) 0.135 q0 4) 0.865 q0

R

CE 2R

S1

E = 24 Volts

R = 2

C = 15 mFAfter being closed for a long time, the switch is opened. What is the charge Q on the capacitor 0.06 seconds after the switch is opened?

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Physics 102: Lecture 7, Slide 28

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Physics 102: Lecture 7, Slide 29

RC Summary

Charging Discharging

q(t) = q(1-e-t/RC)

q(t) = q0e-t/RC

V(t) = V(1-e-t/RC)

V(t) = V0e-t/RC

I(t) = I0e-t/RCI(t) = I0e-t/RC

Short term: Charge doesn’t change (often zero or max)

Long term: Current through capacitor is zero.

Time Constant = RC Large means long time to charge/discharge

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Physics 102: Lecture 7, Slide 30

Charging: Intermediate Times

2R

C R

S2

S1

Ib

+

-

+

+

-

-

Calculate the charge on the capacitor 310-3

seconds after switch 1 is closed.

q(t) = q(1-e-t/RC)

= q(1-e-310-3 /(2010010-6)))

= q (0.78)

Recall q = C

= (50)(100x10-6) (0.78)

= 3.9 x10-3 Coulombs

R = 10

V = 50 Volts

C = 100F

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Physics 102: Lecture 7, Slide 31