Lab #2 Report due TODAY
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Transcript of Lab #2 Report due TODAY
![Page 1: Lab #2 Report due TODAY](https://reader035.fdocuments.us/reader035/viewer/2022062408/568131a5550346895d981449/html5/thumbnails/1.jpg)
Lab #2 Report due TODAY Individual Data Processing and
Individual Write Up Lab #2 Report is due TODAY by
midnight Answer Multiple Choice Questions
ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY
by midnight Submit the Lab Report #2 in the drawer
labeled “MECE204-Strength Lab” under M. E. Mail Folders
![Page 2: Lab #2 Report due TODAY](https://reader035.fdocuments.us/reader035/viewer/2022062408/568131a5550346895d981449/html5/thumbnails/2.jpg)
Torsion Testing Circular Cross-section Only Determine Material Properties in Torsion Draw Shear Stress-Strain Curve Ductile or Brittle Failure ? ASTM E-143 Test Method Compare results from Tensile, Poisson’s &
Torsion Test
Become familiar with Tinius Olsen Torsion Tester (10,000 in-lb capacity)
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Sign Convention
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Assumptions
Perfectly linear-elastic behavior Circular x-section (solid or hollow) Small rotations Constant length Constant diameter
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No deformation A highly
deformable member
A circular x-section
A grid of parallel circles and longitudinal lines on the outer surface
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After Deformation
Two torques are applied
Circles remain circles
Longitudinal lines become twisted
All angles are equal
End x-section remains flat
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Angle of Twist A prismatic circular
member Fixed at x = 0 Other end is FREE Loaded by a torque
at the free end Angle (x) - angle
of twist It depends on x:
/x=constant
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Shear Strain
Before After
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Shear Strain Distribution
max = c• max - occurs on the
outer surface• = (/c) max
• Result valid also for circular tubes within the material
• Valid for plastic deformation also
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Shear Strain Distribution
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Shear Strain & Angle of Twist
= * / L
max = * D / 2 / L
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Shear Stress Distribution - Elastic Deformation only
X-section: linear distribution Complimentary stresses in action Shear stress occur on axial planes (normal to the x-section
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Shear Stress & Torque- Linear Elastic Deformation Only
= T * / J
max = T * D / 2 / J
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Shear Stress-Strain Curve
max, rad
max, psi
Modulusof Rupture
Slope = = Shear Modulus, G
Figure 3.2 Typical shear stress-strain diagram from a Torsion Test
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Linear Elastic Region – Shear Modulus
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Failure Surface – Tensile Testing
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Failure Surface – Torsion Test
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Brittle Failure – Torsion Test
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Stresses on an Inclined Plane in an Axially Loaded Member Seek for equilibrium after
cutting along the oblique plane
n
P
NV
t
2sin)2/(sincos
)2cos1)(2/(cos
: )/ that note (and plane inclined on the
ly,respectivestresses,shear and normal the
obtain to with V and N Normalize
)cos(
:is plane inclined theof Area
)sin(:0
)cos(:0
xxnt
x2
xn
x
AP
A
AA
PVF
PNF
n
n
t
n
x
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Maximum Stress – Uniaxial Tension
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Comparing Tensile vs. Torsion Results
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Measuring Angle of TwistT=(R-R0)-(L-L0)
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Torsion Data Sheet
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Computing the Slip Angle
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Manually Recorded Data
R0
L0
T=(R-R0)-(L-L0)
slip= H-(LH/LT)T
cor = H - slip
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Shear Strain and Stress
=Radians(cor)*D/2/LH
=16T//D3
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Integrating Computer Data
slip= constant
cor=H - slip
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Selecting Computer Data
Head Angle = 30.00 deg
When Protractors taken OFF
Max Torque = 1931 in-lb
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Entire Stress Strain Curve
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Elastic Curve
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Proportional Limit
=G*
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Proportional Limit
Plot columns H, I, & J
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Key Ideas - Torsion Shear strain formula is valid in both
elastic & plastic region Torque formula is valid in linear
elastic region ONLY Thus, shear stress formula is valid
until proportional limit After proportional limit, shear stress
formula overestimates stress.
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Torsion Results
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Comparing Tensile vs. Torsion Results
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Comparing Lab 1, 2, & 3Experimental Results
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Lab #2 Report due TODAY Individual Data Processing and
Individual Write Up Lab #2 Report is due TODAY by
midnight Answer Multiple Choice Questions
ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY
by midnight Submit the Lab Report #2 in the drawer
labeled “MECE204-Strength Lab” under M. E. Mail Folders