L21_groundwater2_2

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Lecture 21: Groundwater: Hydraulic Conductivity Key Questions 1. What causes groundwater to move? 2. What is the hydraulic conductivity ? 3. What is Darcy’s Law? 4. How is groundwater velocity estimated? 5. What makes good aquifers in the Puget Lowlands? 6. What is a cone of depression? Niigata Japan, 1964 liquefaction

Transcript of L21_groundwater2_2

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Lecture 21: Groundwater: Hydraulic Conductivity

Key Questions 1. What causes groundwater to move?

2. What is the hydraulic conductivity?

3. What is Darcy’s Law?

4. How is groundwater velocity estimated?

5. What makes good aquifers in the Puget Lowlands?

6. What is a cone of depression?

Niigata Japan, 1964 liquefaction

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Groundwater supports streamflow in between rain events (baseflow)

groundwater

Time

Hydrograph

base flow

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Groundwater movement controls the transport of contaminants

A B

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A B

water has hydraulic head (pressure and gravitational energy) at location A

water has hydraulic head (pressure and gravitational energy) at location B

A hydraulic gradient causes water to move

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hydraulic gradient = Δh/ΔL

The hydraulic gradient is the change in total head divided the distance over which the change occurs.

Δh = hA - hBhA hB

ΔLΔh

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small area available for flow, low hydraulic condcutivty

large grains, large area available for flow, large hydraulic conductivity

The hydraulic conductivity of the sediment will resist the water flow

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Smaller grains, means smaller pores (area available for flow), and more frictional resistance, and hence lower hydraulic conductivity

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Q

Δh ΔL

Darcy’s Law

Q/A

Δh/ΔL

Q/A = -K(Δh/ΔL)

slope = K = hydraulic conductivity

K

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Q/A = -K(Δh/ΔL)

h1

h2

Δh = h2 –h1

ΔL

Q

A

Darcy’s Law states that the amount of water (Q) flowing through porous media depends on the energy driving the water flow (Δh/ΔL) and the hydraulic conductivity (K) of the porous media

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average pore water velocity v = -K/n(Δh/ΔL)

The average velocity of the water is the Darcy equation divided by the porosity of the sediment.

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Most aquifers in the Puget Lowlands are unconsolidated glacial deposits

http://pubs.usgs.gov/ha/ha730/ch_h/H-text10.html

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Glacial Deposits

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Till – deposited beneath a glacier, it is a well compacted mixture of grain sizes

(till does NOT make good aquifers)

ice weight

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till

receding glacier (melting)

outwash – loose (uncompacted) sands and gravels deposited by melt-water streams and rivers

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Glacial outwash makes the most productive aquifers

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glaciomarine drift – clay rich sediment deposited in the sea by melting ice

glaciomarine drift does NOT make good aquifers

melting floating ice

sea water

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Point Wilson Double Bluff

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Whatcom County Glacial Aquifers

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Whatcom County Glacial Deposits

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Abbotsford-Sumas Aquifer

The aquifer covers approximately 200 km2 and serves as a water supply for approximately 110,000 people in BC and WA.

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Ground Water Flow is from North-to-South

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BC WA

15 - 25 m

1 - 10 m

Sumas Outwash

Glaciomarine Drift

Abbotsford-Sumas Aquifer

The aquifer is unconfined and comprised of glacial outwash sands and gravels (Sumas Outwash) deposited about 10,000 years ago.

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Sumas Outwash

gravel mine in Whatcom County

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Well Sampling Sites

26 wells

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Water-level measurements

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Well Sampling Sites

26 wells

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Water Table Hydrographs

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hydraulic gradient = Δh/ΔL

Δh = hA - hBhA hB

ΔLΔh

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Well Sampling Sites

26 wells

Flow is in the southeast direction (155o) and is drive by a gradient of

ΔhΔL

=- 0.0055

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The average hydraulic conductivity of the glacial sediments is

K = 545 ft/day or K = 0.187 cm/sec

The average hydraulic gradient in the Abbotsford-Sumas aquifer is

Δh/ΔL = -0.0055

The average porosity of the glacial sediments is

n = 0.30

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The average pore-water velocity can be determined using

velocity = v = -K/n (Δh/ΔL)

Using the aquifer parameters in the equation above yields

velocity = v = -545/0.30(-0.0055) = 10 ft/day

which is very fast for groundwater

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The average groundwater velocity is 10 ft/day

How long would it take water to travel from well A to well B

If the distance from A to B is 1000 ft

A B

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Time = distance ⁄ velocity

Time = 1000 ft ⁄ 10 ft/day

Time = 100 days

A B

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If the aquifer were a fine sand with a hydraulic conductivity of 5.45 ft/day……then the

Velocity = 0.10 ft/day

Time = 1000 ft ⁄ 0.10 ft/day

Time = 10,000 days or 27 years!!

A B

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http://www.uwsp.edu/geo/faculty/ozsvath/images/cone_of_depression.htm

Pumping wells create a cone-of-depression in the water table

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well screen

the pump sits inside the well screen

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water flow

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sand gravelWell A Well B

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gravelsand

QA QB

cone of depression

QA = QB = pumping rate

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gravel

QB

The slope of the cone of depression is determined by the permeability

sand

QA

steep slopehigh permeability

shallow slope

low permeability

QA = QB = pumping rate

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The depth of the cone of depression is determined by the pumping rate

sand

QA

low permeability

sand

QBQA < QB

low permeability low permeability

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The radius of the cone of depression is determined by the pumping duration

sand

QA

sand

QB

low permeability

QB = QA

rA rB

rA rB<

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Study Area

~ 6 sq miles

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BC WA

Water table is just below the ground surface

Coarse gravels and sands

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Pumping wells can influence neighboring wells

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Irrigation Well

irrigation well

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Over pumping of irrigation well lowers the water table below the domestic well (water rights)

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Groundwater surface water interactions

A pumping well can influence streamflow

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Irrigation Wells in the study area

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Sate law highly restricts the water rights of farmers

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However, State law allows Exempt wells (low use wells). So, farmers could sell there land for subdivisions and many homes can drill a well without needing a water right. This is a problem.