L16 Population Genetics-2

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    Population genetics

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    Types of polymorphism

    Restriction fragment length polymorphism (RFLP)

    Single nucleotide polymorphism (SNP) 10 millions

    Minisatellites/variable number tandem repeats (VNTR)

    Microsatellites or short tandem repeats (STR)

    Frequencies of polymorphic alleles may varysignificantly in different populations

    Currently a new type of the genomic variation named CNV(copy number variation) is extensively studied.

    CNV range from Kb to MbMost CNV are rare variants

    Some CNV can be associated with the diseases.

    Just to remind

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    Your class of 100 people has been typed for a two-allele polymorphism (alleles labeled A and a), and the

    following 3 genotype counts were obtained:Genotype Number of individuals

    A,A 30A,a 50

    a,a 20Total number of allele = 100 x 2 = 200

    Number of allele A = (30 x 2)+ 50 = 110

    Number of allele a= 50 + (20 x 2) = 90

    Frequency of allele A = 110/200 = 0.55

    Frequency of allele a = 90/200 = 0.45

    Allele frequency ?

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    Neutral polymorphism : SNP rs213934 A/G(HapMap project)

    Japanese 0.434Caucasians 0.292African ancestry in SW USA 0.035Nigerian 0

    Frequencies of polymorphic alleles mayvary significantly in different populations

    Polymorphism associated with disease:

    sickle cell mutation

    African Americans 0.05Caucasians 0

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    Hardy-Weinberg equilibrium/law:I. Genotypes distribution

    Frequency of allele A = pFrequency of allele a = q

    p+q = 1

    1= p2

    + 2pq + q2

    p2= frequency of homozygote AA

    2pq = frequency of heterozygote Aa

    q2 = frequency of homozygote aa

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    Hardy-Weinberg Equilibrium:Single Nucleotide Polymorphism

    SNP A/C

    1 = p2

    + 2pq + q2

    p2= frequency of homozygote AA= 0.72= 0.492pq = frequency of heterozygote AC = 2x0.7x0.3= 0.42

    q2 = frequency of homozygote CC = 0.32= 0.09

    p = 0.7 (frequency of allele A)q = 0.3 (frequency of allele C)

    Expected distribution of genotypes in 100 individualsAA= 0.49 x 100 = 49 individualsAC = 0.42 x 100 = 42 individualsCC = 0.09 x 100 = 9 individuals

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    Single nucleotide polymorphism SNP17361 G/T:

    the frequency of a minor allele T is 0.4. What is

    the frequency of heterozygotes G/T?

    A. 18%

    B. 28%

    C. 38%

    D. 48%

    E. 58%

    Q

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    Single nucleotide polymorphism SNP17361 G/T:

    the frequency of a minor allele T is 0.4. What isthe frequency of heterozygotes G/T?

    A. 18%

    B. 28%C. 38%

    D. 48%

    E. 58%

    q = 0.4p=1 - 0.4 = 0.6

    2pq = 2 x 0.6 x 0.4 = 0.48 (48%)

    A

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    Hardy-Weinberg equilibrium inMendelian diseases

    1 = p2

    + 2pq + q2

    p2= frequency of normal homozygote NN

    2pq = frequency of heterozygote NM

    q

    2

    = frequency of mutant homozygote MM

    Frequency of normal allele N = pFrequency of mutant allele M = q

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    Hardy-Weinberg equilibriumAutosomal dominant disease

    1 = p2+ 2pq + q2p2= frequency ofhealthy (normal homozygote NN)

    2pq = frequency of affected(heterozygote NM)

    q2 = frequency of affected(mutant homozygote MM)

    Frequency of normal allele N = pFrequency of mutant allele M = q

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    Hardy-Weinberg equilibriumAutosomal recessive disease

    Frequency of normal allele N = pFrequency of mutant allele M = q

    1 = p2+ 2pq + q2

    p2= frequency ofhealthy (normal homozygote NN)

    2pq = frequency of healthy(heterozygote NM)

    q2 = frequency of affected(mutant homozygote MM)

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    Hardy-Weinberg equilibriumX-linked recessive disease

    Frequency of normal allele N = pFrequency of mutant allele M = q

    Males:p = frequency of healthy(normal hemizygote N)

    q = frequency of affected (mutant hemizygote M)

    Females:1 = p2+ 2pq + q2

    p2

    = frequency ofhealthy (normal homozygote NN)

    2pq = frequency of healthy(heterozygote NM)

    q2 = frequency of affected(mutant homozygote MM)

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    Most typical exam questions

    q is given

    Find carrier frequency

    Find disease frequency

    Disease frequency (incidence) is given

    Find disease allele frequency

    Find carrier frequency

    Carrier frequency is givenFind disease allele frequency

    Find disease frequency

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    Estimation of carrier frequency forautosomal recessive disease

    It is difficult and often impossible to identifycarrier frequency directly

    Hardy-Weinberg equilibrium allows for estimationof carrier frequency from disease incidence

    Incidence of phenylketonuria (PKU) in Caucasians :

    1 in 10,000Mutant allele frequency?

    Carrier frequency ?

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    Frequency of MM = q2 = 1/10,000q= square root of 1/10000= 1/10000 = 1/100p= 1 1/100 = 0. 99 1 (approximation can beused because the disease/mutation is rare)

    Carrier frequency = 2pq = 2 x1 x 1/100 = 1/50

    p2+ 2pq + q2p2= frequency of homozygote NN

    2pq = frequency of heterozygote NM

    q2 = frequency of homozygote MM

    Incidence of phenylketonuria (PKU) in Caucasians :1 in 10,000

    Mutant allele frequency

    Carrier frequency ?p= frequency of normal alleleq = frequency of mutant allele

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    PKU incidence in China : 1 in 100,000

    Carrier frequency ?

    optional

    i l

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    PKU incidence in China : 1 in 100,000

    Frequency of MM = q2 = 1/100,000q=1/100000 = 1/316p= 1 1/316 = 0. 999 1Carrier frequency = 2pq = 2 x1 x 1/316 = 1/158

    p2+ 2pq + q2

    p2= frequency of homozygote NN2pq = frequency of heterozygote NM

    q2 = frequency of homozygote MM

    p= frequency of normal alleleq = frequency of mutant allele

    Mutant allele frequency?Carrier frequency ?

    optional

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    Frequencies of mutant PKU allele andPKU carriers are different in Caucasians

    and Chinese

    PKU incidence in Caucasians : 1 in 10,000q= 1/100

    Carrier frequency = 1/50

    PKU incidence in China : 1 in 100,000q= 1/316

    Carrier frequency = 1/158

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    From carrier frequency to

    disease and allelefrequency

    A biochemical or enzymatic carriertesting is available just for a limited

    number of genetic disorders, particularlyfor Tay-Sachs disease

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    Tay-Sachs disease is an autosomal recessive

    disorder for which the carrier frequency inindividuals of Ashkenazi Jewish descent is

    about 1 in 30.

    How frequent is Tay-Sachs disease in this

    population?

    1 = p2+ 2pq + q2

    p2= frequency ofhealthy (normal homozygote NN)

    2pq = frequency of healthy(heterozygote NM)

    q2

    = frequency of affected(mutant homozygote MM)

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    Tay-Sachs disease is an autosomal recessivedisorder for which the carrier frequency inindividuals of Ashkenazi Jewish descent is about

    1 in 30.How frequent is Tay-Sachs disease in this

    population?

    2pq = 1/30In case of rare genetic disease the frequency ofmutant allele (q) is small, thus p 12pq 2q = 1/30

    q = 1/60The frequency of disease = q2 =( 1/60)2 = 1/3600

    Answer: 1 in 3600

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    Hardy-Weinberg equilibriumX-linked diseases

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    Because males have only a single X chromosome, each

    affected male has one copy of the disease-causing

    recessive mutation. Thus, the incidence of an X-linked

    disease in males is a direct estimate of the gene

    frequency in the population.

    X-linked diseases

    Disease frequency in males = q

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    X-linked recessive:

    Males:q affectedp - unaffected

    Females:q2affected2pq - carrierp2- unaffected

    X-linked dominant:

    Males:q affectedp - unaffected

    Females:

    q2affected2pq - affectedp2 - unaffected

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    Color blindness

    8% Caucasian males have color blindnessq= ?

    p = ?Females

    Normal non-carrier = ?

    Normal carrier = ?

    Color-blindness = ?

    X-linked recessive

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    X-linked recessive

    Color blindness

    Males

    q= 0.08p = 0.92

    8% Caucasian males have color blindness

    Females

    Normal non-carrier = p2= 0.922=0.846

    Normal carrier = 2pq = 2 x 0.92 x 0.08 = 0.1472

    Color-blindness = q

    2

    = 0.08

    2

    =0.0064

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    G6PD deficiency in 70 of 1080 males (70/1080= 0.065)q =p=

    FemalesNormal non-carrier =Carrier =

    G6PD deficiency

    Blood Cells Mol Dis, 2003, 31 (2) , 201-205

    optional

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    G6PD deficiency in 70 of 1080 males (70/1080= 0.065)q = 0.065

    p= 1- 0.065= 0.935

    FemalesNormal non-carrier = p2=0.9352 =0.874 (87.4%)Carrier = 2pq = 2 x 0.935 x 0.065 = 0.121 (12,1%)G6PD deficiency = q2= 0.0652= 0.0042 (0.4%)

    Blood Cells Mol Dis, 2003, 31 (2) , 201-205

    optional

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    Hardy-Weinberg equilibrium

    Autosomal dominant disease

    1 = p2+ 2pq + q2

    p2= frequency ofhealthy (normal homozygote NN)

    2pq = frequency of affected(heterozygote NM)

    q2 = frequency of affected(mutant homozygote MM)

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    Autosomal dominant diseases

    1= p2+ 2pq + q2

    Most dominant diseases are rare, it means q is smalland an approximation p 1 can be usedMost patients with AD disease are heterozygotesDisease frequency = 2pq + q2 2pq 2q

    q= disease frequency/2

    Familial hypercholesterolemia in USA : 1/500 or 0.002

    Therefore q= 0.001Frequency of homozygotes = q2= (0.001)2= 0.000 0011 in a million

    optional

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    Hardy-Weinberg Law:II. The population genotype frequencies from

    generation to generation will remain constant, if

    allele frequency remain constantIf you want to know why it is true see the

    following table

    optional

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    Large population

    Random mating

    No migration

    Assumptions underlying the

    Hardy-Weinberg law

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    Factors that disturb Hardy-Weinberg equilibrium

    Non-random matingStratificationAssortative mating

    Consanguinity/inbreedingGenetic drift in small population

    Founder effect

    Mutation selection

    Migration and gene flow

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    Non-random mating

    Assortative mating

    Consanguinity/inbreeding

    Stratification

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    Non-random mating: Assortative marriage

    The choice of the mate who possesses

    some particular trait

    Congenital deafness

    Congenital blindness

    Achondroplasia

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    Non-random mating: Consanguinity

    Marriage between relatives

    Non-random mating: Inbreeding

    In genetic isolates the chance of mating withanother carrier may be as high as in consanguineous

    marriages

    Geographically isolated populations

    Religious groups (Old Order Amish, Mennonites etc)

    Slide 1

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    Non-random mating: Stratification

    US population: many groups(strata)WhitesAfrican AmericansNative AmericansAsian AmericansHispanics

    African Americas 10% of US populationFrequency of SC mutation in African Americans qAA=0.05Frequency of SC mutation in other group is practically 0Frequency of SC mutation in US population qtotal= 0.05/10 =0.005

    (optional)

    Sickle cell (SC) mutation in the USA

    Stratification Slid 2

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    Stratification

    Frequency of the SC disease expected from Hardy-Weinberg equilibrium in US population:

    qtotal2= 0.0052= 0.000025

    However the mating is not random - most marriages areinside the group (stratum) and the real estimate of SCdisease in African Americans is

    qAA2= 0.052 = 0.0025

    Because African Americans are 10% of the US population,

    then the real frequency of the disease in the USpopulation is0.0025/10= 0.00025

    This is 10 times more than expected from Hardy-Weinberg equilibrium

    African Americas(AA) 10% of US populationFrequency of sickle cell (SC) mutation in AA = qAA=0.05Frequency of SC mutation in US population qtotal= 0.05/10 = 0.005

    Slide 2(optional)

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    Factors that disturb Hardy-Weinberg equilibrium

    Non-random matingStratificationAssortative mating

    Consanguinity/inbreedingGenetic drift in small population

    Founder effect

    Mutation selection

    Migration and gene flow

    Just to remindyou where weare

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    Increased fertility or survival of mutationcarriers for reason

    unrelated to carrying the mutation

    leads to a

    change in allele frequency

    Genetic drift in small populations -chance event

    In small populations allele frequencies canfluctuate form generation to generation by

    chance (genetic drift)

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    The founder effect is the loss of genetic

    variation that occurs when a new population is

    established by a very small number of individuals

    from a larger population

    Founder effect

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    Mutation selection

    Positive selection ( increased fertilityor survival because of mutation)

    Negative selection ( decreased fertilityor survival because of mutation)

    Eff t f t ti l ti i diff t i

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    PKU incidence in Caucasians : q2= 1/10,000

    Carrier frequency = 2pq = 2 x1 x 1/100 = 1/50

    Dominant disease:all mutant alleles are under negative selective

    pressure

    Autosomal recessive diseases:selection has less effect

    because most mutant alleles are in heterozygotesand therefore escape negative selection

    Number of mutant PKU alleles in carriers 1/50----------------------------= ---------- = 100Number of mutant PKU alleles in affected 2/10,000

    Effect of mutation selection is different indominant and recessive diseases

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    Positive selection for heterozygotes(Heterozygote advantage)

    Resistance to malariaSickle cell anemia/Thalassemia/G6PD deficiency

    Resistance to effect of chloride-secreting diarrhea

    Cystic fibrosis

    Resistance to some infectionsTay-Sachs disease

    fl

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    Migration and gene flow

    Migration can change allele frequency by gene flow slow diffusion of genes across a barriers

    Map of Ancient human migration

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    Ethnic differences in the frequency of geneticdiseases may be due to

    Genetic drift

    Founder effect

    Positive selection for heterozygotes(Heterozygote advantage)

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    Tay-Sachs disease is common in

    Ashkenazi Jews because of:

    Founder effect

    Inbreeding

    Heterozygote advantage

    Ashkenazi Jews (those originating from theWestern and Eastern Europe diaspora), who make upmore than 80 percent of world Jews and are

    believed to be descended from about 1,500 Jewishfamilies dating back to the 14th century

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    The end