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Transcript of Kinetic molecular theory and states of matter. A pure substance in its gaseous state is often...
CHAPTERS 10 AND 11
Kinetic molecular theory and states of matter
Gases
A pure substance in its gaseous state is often referred to as a vapor.
The molecules of a vapor are not tightly bound together and are move freely through space.
Gases form homogeneous mixtures regardless of the identities or relative proportions of the component gases.
The three most readily measured properties of a gas are, temperature, volume, and pressure.
Pressure
Pressure is measured as the force applied over a given area.
P = F/A Standard atmospheric pressure at sea level
is measured as 1 atmosphere (atm). Other units for pressure are: Torr mm Hg kPa 1 atm = 760 torr = 760 mm Hg = 101.3 kPa
Boyles Law
Boyles law relates the pressure of a gas and the volume of a gas at constant temperature.
Boyles law states that, the volume of a fixed quantity of gas maintained at constant temperature is inversely proportional to the pressure.
Boyle’s Law is represented by the equation:
P1V1= P2V2
Charles’s Law
Charles’s law relates the temperature of a gas and the volume of a gas.
This law states that the volume of a fixed amount of gas maintained at constant pressure is directly proportional to its absolute temperature (Kelvin)
Charles’s law is represented by: V1/T1 = V2/T2 or V2/V1 = T2/T1 or V1T2 =
V2T1
Avogadro’s Law
We know that if we add more air into a balloon it will get bigger.
Avogadro’s Law relates the amount of gas and the volume of a gas.
Avogadro’s Law states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.
What Avogadro found was that one mole of any gas at standard pressure (1 atm) and standard pressure (273.15 K) will have a volume of 22.4 L.
The Ideal Gas Equation
The ideal gas equation is written as:
PV = nRT
The term R is called the ideal gas constant. The values of R are… 0.0821 L-atm/mol-K 8.13 J/mol-K 62.4 L-torr/mol-K 8.31 volt-coulomb/mol-K
Using the Ideal Gas Equation
Calcium carbonate decomposes upon heating to give calcium oxide and carbon dioxide gas. A sample of calcium carbonate is decomposed, and the carbon dioxide is collected in a 250-mL flask. The pressure of the gas collected is measured at 1.3 atm at a temperature of 31o C. How many moles of gas were collected?
0.013 mol CO2
Tennis balls are usually filled with air or N2 gas to a pressure above atmospheric pressure to increase their “bounce”. If a particular tennis ball has a volume of 144 cm3 and contains 0.33 g of N2 gas, what is the pressure, in atmospheres, inside the ball at 24oC ?
2.0 atm
Gas Densities and Molar Mass
The ideal gas equation allows us to calculate gas density from the molar mass, pressure, and temperature.
Remember density is defined as mass/volume.
What is the density of carbon tetrachloride vapor at 714 torr and 125oC?
4.43 g/L
A large flask is evacuated and found to weigh 134.567 g. It is then filled with a gas to a pressure of 735 torr at 31oC and reweighed. Its mass is now 137.456 g. Finally the flask is filled with water at 31oC and found to weigh 1067.9 g. (The density of water at this temperature is 0.997 g/mL) calculate the molar mass of the unknown gas.
79.9 g/mol
Gas Mixtures and Partial Pressure
All gases form homogeneous mixtures. The pressure exerted by a particular
component of a mixture of gases is called the partial pressure of that gas.
Pt = P1 + P2 + P3 + ……
If P = n(RT/V) than P1 = n1(RT/V) So Pt = (n1 + n2 + n3 + ……) (RT/V)
Partial Pressure and Mole Fractions
If we have a mixture of gasses the mole ratio of gas number 1 is simply n1/nt.
A mixture of gas is composed of 1.5 mol percent CO2, 18.0 mol percent O2, and 80.5 mole percent Ar.
(a) Calculate the partial pressure of O2 if the total pressure of the mixture is 745 torr.
134 torr.
A gaseous mixture made from 6.00 g of O2 and 9.00 g of CH4 is placed ina 15. 0 L vessel at 0o C. What is the partial pressure of each gas and what is the total pressure in the vessel?
P (O2) = 0.281 atm P (CH4) = 0.841 atm Pt = 1.122 atm
Assuming ideal conditions, calculate the total pressure in 3.0 Liter container that contains 0.015 moles of carbon dioxide combined with 2.0 moles of oxygen at a temperature of 30 degrees Celsius?
(A) 1.65 atm (B) 22.4 atm (C) 16.7 atm (D) 17.8 atm (E) None of the Above
Kinetic Molecular Theory
The ideal gas equation explains how gases but it does not explain why they behave as they do.
The Kinetic Molecular Theory states that1. Gases consist of large numbers of molecules that are in
continuous, random motion. 2. The combined volume of all the molecules of the gas is
negligible relative to the total volume in which the gas is contained.
3. Attractive and repulsive forces between gas molecules are negligible.
4. Energy can be transferred between molecules during collisions but the average kinetic energy does not change. As long as the temperature remains constant.
5. The average kinetic energy of the molecules is proportional to the absolute temperature.
Distributions of Molecular Speed
Although the molecules in a sample of gas have and average kinetic energy (and therefore and average speed) some molecules may be moving faster than others.
At higher temperatures a larger fraction of molecules are moving at greater speeds.
A constant temperature means that the average kinetic energy of the gas molecules remains unchanged. This means that u is unchanged as well.
An increase of temperature will result in an increase of u and in result an increase in E.
Mass and average kinetic energy
As the molar mass of a gas increases the average kinetic energy of the sample will decrease. (If the temperature remains constant)
We use the equation below to find the average speed of gas molecules in a sample.
Calculate the average speed of a molecule of N2 at 25o
C.
Effusion vs. Diffusion
Effusion is the escape of gas molecules through a tiny hole into an evacuated space.
Diffusion is the spreading of one substance through a space or throughout a second substance.
Effusion
Diffusion
Comparing solids, liquids, and gases
Solids: Retain their own shape Virtually incompressible Do not flow Diffusion within a solid occurs extremely slowly
Liquids: Assume the shape of the container they occupy Do not expand to fill container Virtually incompressible Flow readily Diffusion with in a liquid occurs slowly
Gases: Assume both the volume and shape of their container Are compressible Flow readily Diffusion within a gas happens rapidly
These properties can be explained in terms of the kinetic energy of the particles. Gases:
In gases the average kinetic energy of the particles is much greater than the forces of attraction between the particles.
This allows gases to expand to fill their container. Liquids:
Liquids have much stronger intermolecular attractions than gases. This results in liquids being far less compressible than gases.
These intermolecular attractions are not strong enough to keep the molecules from moving around one another. This results in liquids being able to flow and be poured.
Solids: Solids have strong intermolecular attractive forces. These forces are greater than the average kinetic energy of
the particles. This causes solids to have a fixed shape and be
incompressible.
Solid
Gas: Total disorder, a large amount of empty space, particles can move freely, particles are far apart.
Liquid: Disorder, particles or clusters of particles are free to move relative to each other, particles close together
Solid: Ordered arrangement, particles are in fixed positions, particles are close together.
Intermolecular Forces
The strengths of intermolecular forces for different substances vary greatly.
The strength of intermolecular forces are much weaker than the bond forces that hold molecules together. Example:
The energy required to vaporize liquid HCL is only 16 kJ/mol where as the energy required to break the bond between the hydrogen and the chlorine atoms is 431 kJ/mol
Effects of Intermolecular Interactions
The properties of substances reflect the strengths of their intermolecular attractions.
A liquids boiling point is directly related to the intermolecular attractions.
Example: Water boils at 100o C. Liquid HCl boils at -85o
C. Which substance has greater intermolecular interactions?
Types of Intermolecular Interactions
Ion-Dipole Forces Dipole-Dipole Forces London Dispersion Forces Hydrogen Bonding
Ion-Dipole Forces
Ion-Dipole Forces happen between an ion and a polar molecule.
These are the forces that are present in aqueous solutions of ionic compounds.
In which of the following mixtures do you encounter ion-dipole forces: CH3OH in water, or Ca(NO3)2 in water?
Dipole-Dipole Forces
Dipole-Dipole forces happen between two polar molecules.
These forces are generally weaker than Ion-Dipole forces.
For molecules with approximately the same mass these forces get stronger with increasing polarity.
For which of the substances in the table below are the dipole-dipole attractive forces greatest?
Substance Molecular Mass Dipole Moment Boiling Point
CH3CH2CH3 44 amu 0.1 D 231 K
CH3OCH3 46 amu 1.3 D 248 K
CH3Cl 50 amu 1.9 D 249 K
CH3CHO 44 amu 2.7 D 294 K
CH3CN 41 amu 3.9 D 355 K
London Dispersion Forces
All substances experience London Dispersion Forces.
No dipole-dipole interactions happen between non-polar molecules.
The movement of molecules can cause momentary dipoles.
These temporarily created dipoles cause attractive forces between molecules.
London Dispersion Forces Cont.
The strength of London Dispersion Forces depend on an atom or a molecules polarizability.
Polarizability is the measure of how easily the electron cloud of an atom or molecule can be distorted.
The more polarizable a molecule or atom is the stronger London Forces it will experience.
Dispersion forces tend to increase with an increasing molecular weight. Why?
Pentane (C5H12)
n-Pentante:bp = 309.4 K
Neopentante:bp = 282.7
Hydrogen Bonds
Some molecules were found to have abnormally high boiling points considering their low molecular weights.
This lead scientists to believe that there were other, stronger, forces acting on these molecules.
Hydrogen Bonds
Hydrogen bonds occur between a hydrogen atom in a polar bond and a non-bonding pair of electrons on a small electronegative ion or atom. (F, O, N)
Examples: Water DNA
Hydrogen bonds can be thought of as extremely strong dipole-dipole attractions.
Properties of Liquids
Viscosity Viscosity is the resistance of a liquid to flow. Viscosity is related to how easily molecules of
a liquid are allowed to flow around one another.
Substance Formula Viscosity (kg/m-s)
Hexane CH3CH2CH2CH2CH2CH3 3.26 x 10-4
Heptane CH3CH2CH2CH2CH2CH2CH
3
4.09 x 10-4
Octane CH3CH2CH2CH2CH2CH2CH
2CH3
5.42 x 10-4
Nonane CH3CH2CH2CH2CH2CH2CH
2CH2CH2
7.11 x 10-4
Surface Tension
Surface tension Molecules in the center of
a liquid experience attractive forces from all directions.
Molecules on the surface experience a net inward force, pulling them into the bulk of the liquid and packing the surface molecules tighter together.
Stronger intermolecular forces result in higher surface tension.
Phase Changes
Energy of Phase Changes
Heat of fusion (ΔHfus) The energy required to melt a solid the heat of fusion for ice is 6.01 kJ/mol.
Heat of vaporization (ΔHVap) The energy required to turn a liquid into a gas. The heat of vaporization for liquid water is
40.7 kJ/mol. Heat of sublimation (ΔHsub)
A solid can be transformed directly into a gas. The heat of sublimation for ice is 47 kJ/mol.
Generally the hear of fusion is les than the heat of vaporization. Why? It takes more energy to completely separate
the particles than to just partially separate them.
Endothermic Process Heat solid Melt Heat liquid Boil Heat
gas Exothermic Process
Cool gas Condense Cool Liquid Freeze cool solid
Heating Curves
A heating curve is a plot of temperature change versus heat added.
During the plateaus the temperature does not change but we continue adding energy.
The extra energy is used to break intermolecular attractions rather than cause a temperature change.
Example Problem
Calculate the enthalpy change (total ΔH) to convert 1.00 mol of ice at -250 C to water vapor at 1250 C under a constant pressure of 1atm. The specific heats of ice, water, and steam are 2.03 J/g-K, 4.18 J/g-K, 1.84 J/g-K.
For H2O: ΔHfus = 6.01 kJ/mol ΔHvap = 40.67 kJ/mol
AB: heating solid ice. AB represents
heating ice from -250 C to 0.000 C.
We can use the specific heat of water to calculate ΔH
We have 18g of ice and the specific heat of ice is 2.03 J/g-K.
(18g)(2.03 J/g-k)(25K)
914J or 0.914 kJ
BC: For this section of the heating curve we are converting solid ice to liquid water at 0.00o C. We can use the heat of fusion.
(1.00mol H2O)(6.01 kJ/mol)
6.01 kJ
CD: For CD we are heating liquid water.
We need to use the specific heat of water. (4.18 J/g-k)
We sill have 18g of liquid water.
(18g)(4.18 J/g-k)(100K)
752 J or 0.752 kJ
DE: For DE we are converting 1.00 mol of liquid water into 1.00 mol of water vapor.
ΔHvap = 40.67 kJ/mol
(1.00 mol)(40.67 kJ/mol)
40.67 kJ
EF: FINALLY!! For EF we are
heating water vapor from 100o C to 125o C.
We use the specific heat of water vapor.
1.84 J/g-K (18g)(1.84 J/g-k)
(25K) 830 J or 0.830 kJ
But Wait!!!
We want the total ΔH for the full temperature change!
We need to add up the pieces. 0.91 kJ + 6.01 kJ + 7.52 kJ + 40.67 kJ +
0.83 kJ Total: 56.0 kJ
Gasses can be liquefied by increasing the pressure acting on them.
If we have a cylinder of water vapor at 100o C liquid water will start to form when the pressure is 760 torr, or 1 atm.
If, however, the temperature is 110o C the liquid phase does not form until 1075 torr.
At 374o C the liquid phase only forms at 1.655x105 torr.
What is happening with these numbers?
Critical Temperature and Pressure
A substances critical temperature is the highest temperature that the substance can exist as a liquid. What happens past this temperature?
The pressure required to liquefy a substance at its critical temperature is called it’s critical pressure.
Non-polar, low molecular weight substances usually have lower critical pressures and temperatures. Why?
Vapor Pressure Molecules are always escaping the surface of liquids
to move into the gas phase. The number of molecules that are leaving the liquid
phase and the number of molecules returning to it will reach equilibrium.
The amount of molecules that are able to leave the liquid phase contribute to a liquid’s vapor pressure.
The more molecules that are able to escape the liquid phase, the higher a substances vapor pressure.
The rate of evaporation increases with temperature. What kinds of molecules would have high vapor
pressure?
If a liquid is spilled and not cleaned up what will happen?
Liquids that evaporate readily are said to be VOLATILE.
Liquids evaporate when their vapor pressure equals the external pressure acting on the surface of the liquid.
The boiling point of a liquid at 1 atm is called its normal boiling point.
Phase Diagrams
A phase diagram is a graphic way to summarize the conditions under which a substance occupies certain states.
The triple point represents the pressure and temperature where all three phases are in equilibrium.
The Structure of Solids
Solids can either be crystalline or amorphous (noncrystalline)
In a crystalline solid the atoms, ions, or molecules are well ordered.
An amorphous solid is a solid in which the particles have no orderly structure.
Crystalline solids are constructed from individual identical units called unit cells.
Primitive Cubic
Atoms at the corners of a simple cube with each atom shared by eight unit cells.
Polonium is the only element that has this crystal structure.
Body-Centered Cubic
There are atoms at the corners of a cube plus one in the center of the body of the cube. The corner atoms are shared by eight unit cells, and the center atom is completely enclosed in one unit cell.
Many elements including Na, Li, and Fe have this crystal structure.
Face-Centered Cubic
There are atoms at the corners of a cube plus one atom in the center of each face of the cube. Eight unit cells share the corner atoms and two unit cells share the face atoms.
Copper is the most common element that has this crystal structure.