Junior Comprehensive Chuna Bremsstrahlung Interactions that occur after Beta Minus Decay.
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Transcript of Junior Comprehensive Chuna Bremsstrahlung Interactions that occur after Beta Minus Decay.
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Junior Comprehensiv
e
Chuna
Bremsstrahlung Interactions that occur after Beta Minus Decay
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Vocabulary• Beta Minus Decay
• End Point Energyo Difference in Rest Mass between
Parent and Daughter particles
• Bremsstrahlung Interaction
• E[F]- Expectation value function E[F] =
Introduction
Probability
Equation
Understanding The Equation
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Probability Distribution Equation
P()d=(1+−)[ln() ]• The “Extremely Simplified” Probability Distribution of
emitting a gamma with energy between and when the electron starts with an initial energy of
-Comprehensive Writer-
Introduction
Probability
Equation
Understanding the
Equation
1000 2000 3000 4000
0.0001
0.0002
0.0003
0.0004
0.0005
0.0006Probability
Energy
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P()d=(1+−)[ ln ()− ] - electron initial energy - classical electron radiusα - fine structure constant, Z - atomic number of the medium in which the bremsstrahlung is taking placeK - material constant
Substituting Variables ε = , where E is the energy after one bremsstrahlung event
= −E → E =
Probability
Equation
Understanding the
Equation
Formatting
Equation
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Note: Specifics – Equation above is for general Bremsstrahlung interactions, it must be formatted to beta decay.Caution – There are multiple Decay Types for beta decay
Energy (keV)
End-point energy
(keV)
Intensity (%)
Dose ( MeV/Bq-s )
866.8 10 2058.02 22 0.0082 % 6 7.1E-5 5 2481.5 10 5390.86 8 99.9913 % 8 2.4813 10 3286.2 10 7024.53 8 5E-4 % 5 1.6E-5 16
Beta-:
Understanding Equation
Formatting
Equation
Formatting
Equation
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Note : SpecificsBeta Decay of emits an Electron spectrum
To understand the spectrum of Consider = ¾, ½, and ¼ of the endpoint. = 4554.14 keV = .75 * 5390.86 +511.0034 →{F}= 3206.43 keV = .50 * 5390.86 +511.0034 →{G}= 1858.72 keV = .25 * 5390.86 +511.0034 →{H}
(I have included the rest mass of electron)
Formatting
Equation
Formatting
Equation
Normalizing the
Equation
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Normalization• F=(-k*4*(Z^2)(re^2)a*/((4.8793×10-61)x))
(1+ (((Eoa-x)/(Eoa))^2)-(((2/3)(Eoa-x))/(Eoa)))(Log[(2*(Eoa)*((Eoa-x)))/(me*(c^2)*(x))]-.5)
• = 4.8793×10-61
• = 4.64323×10-61 • = 4.25774×10-61
Formatting Equation
Normalizing Equation
Probability Distributio
n
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Normalizing the
Equation
Probability
Distribution
Expected Photon Energy
Probability Distribution of Photon EnergyF=(-k*4*(Z^2)(re^2)a*/((4.8793×10-61)x))(1+ (((Eoa-x)/(Eoa))^2)-(((2/3)(Eoa-x))/(Eoa)))(Log[(2*(Eoa)*((Eoa-x)))/(me*(c^2)*(x))]-.5)
Plot[ {F,G,H}, {x, 10 , Eoa}]
1000 2000 3000 4000
0.0001
0.0002
0.0003
0.0004
0.0005
0.0006Probability
Energy of Emitted Photon (keV)
= 4554.14 keV → {F}
= 3206.43 keV →{G}
= 1858.72 keV →{H}
Mathematica
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Expected Photon Energy
Univariate Continuous Distribution of a Random Variable
• E[F] = • E[G] = • E[H] =
<F˃ = 672.763 keV<G> = 502.016 keV<H> = 321.218 keV
Probability
Distribution
Expected Photon Energy
Application to
Experiment
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Transmission/Attenuation
Photons’ have 0% transmission rate
photons’ have >0% transmission rate
All the energy given off by Bremsstrahlung interactions trapped inside the crystal.
If no other energy escapes due to particle interaction than detector measures all other initial energy
Some photons escape with some of the electrons initial energy
The detector measures less than initial energy
Expected Photon Energy
Application to
Experiment
F Transmissio
n
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F Transmission• 672.763 keV - Average Energy of Photon
given off due to Bremsstrahlung interaction• RESULTS:• Attenuation [%]: 88.0411
Transmission [%]: 11.9589 – Likelihood of photon escaping the medium
• Interaction Probability [%]:Photo absorption: 9.6587Compton Scattering: 75.3758Rayleigh Scattering: 3.0066Nuclear Field Pair Production: 0.0000Electron Field Pair Production: 0.0000
Application to
Experiment
F Transmissio
n
G Transmissio
n
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G Transmission• 502.016 keV - Average Energy of Photon
given off due to Bremsstrahlung interaction• RESULTS:• Attenuation [%]: 92.9071
Transmission [%]: 7.0929 -Likelihood of photon escaping the medium
• Interaction Probability [%]:Photo absorption: 16.3393Compton Scattering: 72.0658Rayleigh Scattering: 4.5019Nuclear Field Pair Production: 0.0000Electron Field Pair Production: 0.0000
F Transmissi
on
G Transmissio
n
H Transmissio
n
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G Transmissi
on
H Transmissio
nResults
H Transmission• 321.218 keV - Average Energy of Photon
given off due to Bremsstrahlung interaction• RESULTS:• Attenuation [%]: 98.5999
Transmission [%]: 1.4001 - Likelihood of photon escaping the medium
• Interaction Probability [%]:Photo absorption: 35.1417Compton Scattering: 56.3727Rayleigh Scattering: 7.0855Nuclear Field Pair Production: 0.0000Electron Field Pair Production: 0.0000
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“Observed” Beta Spectrum
1” NaI Crystal 100” NaI Crystal
H Attenuation
Results Understanding Results
Counts
Energy (MeV) Energy (MeV)
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ResultsUnderstanding
ResultsBibliograp
hy
Calculated Efficiency Ratio
1” NaI Crystal 100” NaI Crystal
Ratio
Energy (MeV) Energy (MeV)
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Bibliography• http://web-docs.gsi.de/~stoe_exp/
web_programs/x_ray_absorption/index.php• http://www.wiikipedia.com – used to develop
general understanding and look up coefficient values.
H Attenuatio
n
Understanding Results
Bibliography