July 3, Week 5 Today: Finish Chapter 9, Begin...
Transcript of July 3, Week 5 Today: Finish Chapter 9, Begin...
![Page 1: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/1.jpg)
July 3, Week 5
Momentum 3rd July 2014
Today: Finish Chapter 9, Begin Chapter 10,Work
No Office Hours on Friday.
Homework Assignment #5 - Due Monday, July 7. (Homeworkassignment #6 will be due Friday, July 11)
Test #5 on Tuesday, July 8
There will be a reading quiz due Monday.
![Page 2: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/2.jpg)
Using Conservation of Momentum II
Momentum 3rd July 2014
Before
A
−→vAi
B
−→vBi
A
−→vAf
B
−→vBf
After
mA−→vAi +mB
−→vBi = mA
−→vAf +mB
−→vBf
![Page 3: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/3.jpg)
Using Conservation of Momentum II
Momentum 3rd July 2014
Before
A
−→vAi
B
−→vBi
A
−→vAf
B
−→vBf
After
mA−→vAi +mB
−→vBi = mA
−→vAf +mB
−→vBf
Component Form:
![Page 4: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/4.jpg)
Using Conservation of Momentum II
Momentum 3rd July 2014
Before
A
−→vAi
B
−→vBi
A
−→vAf
B
−→vBf
After
mA−→vAi +mB
−→vBi = mA
−→vAf +mB
−→vBf
Component Form:
mA (vAx)i +mB (vBx)i = mA (vAx)f +mB (vBx)f
![Page 5: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/5.jpg)
Using Conservation of Momentum II
Momentum 3rd July 2014
Before
A
−→vAi
B
−→vBi
A
−→vAf
B
−→vBf
After
mA−→vAi +mB
−→vBi = mA
−→vAf +mB
−→vBf
Component Form:
mA (vAx)i +mB (vBx)i = mA (vAx)f +mB (vBx)fmA (vAy)i +mB (vBy)i = mA (vAy)f +mB (vBy)f
![Page 6: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/6.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
![Page 7: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/7.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
![Page 8: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/8.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
mA−→vAi +mB
−→vBi
![Page 9: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/9.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
After
mA−→vAi +mB
−→vBi
![Page 10: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/10.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
B
A
After
mA−→vAi +mB
−→vBi
![Page 11: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/11.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
B
A−→vf
After
mA−→vAi +mB
−→vBi
![Page 12: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/12.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
B
A−→vf
After
mA−→vAi +mB
−→vBi (mA +mB)
−→vf
![Page 13: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/13.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
B
A−→vf
After
mA−→vAi +mB
−→vBi = (mA +mB)
−→vf
![Page 14: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/14.jpg)
Completely-Inelastic Collisions
Momentum 3rd July 2014
When the colliding objects stick together, the collision is calledcompletely inelastic.
Before
A
−→vAi
B
−→vBi
B
A−→vf
After
mA−→vAi +mB
−→vBi = (mA +mB)
−→vf
Component Form: mA (vAx)i +mB (vBx)i = (mA +mB) (vx)f
mA (vAy)i +mB (vBy)i = (mA +mB) (vy)f
![Page 15: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/15.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE
![Page 16: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/16.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
![Page 17: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/17.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s
![Page 18: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/18.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s (b) − (5/3) m/s
![Page 19: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/19.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s (b) − (5/3) m/s (c) −1m/s
![Page 20: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/20.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s (b) − (5/3) m/s (c) −1m/s
(d) 3m/s
![Page 21: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/21.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s (b) − (5/3) m/s (c) −1m/s
(d) 3m/s (e) −3m/s
![Page 22: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/22.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(a) (5/3) m/s (b) − (5/3) m/s (c) −1m/s
(d) 3m/s (e) −3m/s
![Page 23: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/23.jpg)
Conservation Exercise IV
Momentum 3rd July 2014
A 1-kg mass sliding to the right with speed 1m/s on a frictionlessfloor collides with a 2-kg mass going to the left at 2m/s. If themasses stick to each other, how fast is the combo going after?
BEFORE AFTER
?
(c) −1m/s
Conservation: (1 kg)(1m/s) + (2 kg)(−2m/s) = (1 kg + 2 kg)(vx)f(1 kg ·m/s)− (4 kg ·m/s) = (3 kg)(vx)f ⇒ −(3 kg ·m/s) = (3 kg)(vx)f
![Page 24: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/24.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
![Page 25: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/25.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
![Page 26: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/26.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦
![Page 27: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/27.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦ (b) 20m/s at 225◦
![Page 28: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/28.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦ (b) 20m/s at 225◦ (c) 40m/s at 225◦
![Page 29: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/29.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦ (b) 20m/s at 225◦ (c) 40m/s at 225◦
(d) 10m/s at 135◦
![Page 30: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/30.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦ (b) 20m/s at 225◦ (c) 40m/s at 225◦
(d) 10m/s at 135◦ (e) 40m/s at 135◦
![Page 31: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/31.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦ (b) 20m/s at 225◦ (c) 40m/s at 225◦
(d) 10m/s at 135◦ (e) 40m/s at 135◦
![Page 32: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/32.jpg)
2D-Conservation Exercise
Momentum 3rd July 2014
A 6 kg box-shaped firecracker explodes into two unequal pieces. Ifthe first piece of mass 2 kg has velocity 20m/s at 45◦, what speedand direction must the other piece have?
BEFORE
6 kg
AFTER
2 kg
45◦
20m/s
(a) 10m/s at 225◦
0 = mA−→vAf +mB
−→vBf ⇒
−→vBf = −
(
mA
mB
)
−→vAf = −
(
2
4
)
−→vAf
![Page 33: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/33.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
![Page 34: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/34.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
![Page 35: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/35.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
(b)√45m/s = 6.7m/s
![Page 36: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/36.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
(b)√45m/s = 6.7m/s
(c) 3m/s
![Page 37: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/37.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
(b)√45m/s = 6.7m/s
(c) 3m/s
(d)√5m/s = 2.236m/s
![Page 38: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/38.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
(b)√45m/s = 6.7m/s
(c) 3m/s
(d)√5m/s = 2.236m/s
(e) 1m/s
![Page 39: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/39.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(a) 9m/s
(b)√45m/s = 6.7m/s
(c) 3m/s
(d)√5m/s = 2.236m/s
(e) 1m/s
![Page 40: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/40.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
![Page 41: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/41.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
(vAx)i = 3m/s (vAy)i = 0
![Page 42: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/42.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
(vAx)i = 3m/s (vAy)i = 0
(vBx)i = 0 (vBy)i = 3m/s
![Page 43: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/43.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
(vAx)i = 3m/s (vAy)i = 0
(vBx)i = 0 (vBy)i = 3m/s
x-Component: (1 kg)(3m/s) + 0 = (3 kg) (vx)f ⇒ (vx)f = 1m/s
![Page 44: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/44.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
(vAx)i = 3m/s (vAy)i = 0
(vBx)i = 0 (vBy)i = 3m/s
x-Component: (1 kg)(3m/s) + 0 = (3 kg) (vx)f ⇒ (vx)f = 1m/s
y-Component: 0 + (2 kg)(3m/s) = (3 kg) (vy)f ⇒ (vy)f = 2m/s
![Page 45: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/45.jpg)
2D Exercise II
Momentum 3rd July 2014
A block with MA = 1 kg and velocity 3m/s to the right has aperfectly inelastic collision with MB = 2 kg that has velocity 3m/sup. How fast must the masses be going the instant after theircollision?
1 kg3m/s
2 kg
3m/s
(d)√5m/s = 2.236m/s
(vAx)i = 3m/s (vAy)i = 0
(vBx)i = 0 (vBy)i = 3m/s
x-Component: (1 kg)(3m/s) + 0 = (3 kg) (vx)f ⇒ (vx)f = 1m/s
y-Component: 0 + (2 kg)(3m/s) = (3 kg) (vy)f ⇒ (vy)f = 2m/s
vf =√
(vx)2
f + (vy)2
f=
√
1m2/s2 + 4m2/s2
![Page 46: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/46.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
![Page 47: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/47.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
![Page 48: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/48.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
![Page 49: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/49.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
−→F
![Page 50: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/50.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
−→F
![Page 51: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/51.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
−→F
−→d
−→d = displacement= distance anddirection traveled.
![Page 52: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/52.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
−→F
−→d
−→d = displacement= distance anddirection traveled.
Work done by the force: W = Fd
![Page 53: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/53.jpg)
Work and Energy
Momentum 3rd July 2014
Energy - The ability to do work or results from work being done tosomething.
Work - a measure of much effort goes into causing motion.
−→F
−→d
−→d = displacement= distance anddirection traveled.
Work done by the force: W = Fd
Unit: N ·m = kg ·m2/s2 = J
Joule
![Page 54: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/54.jpg)
Restrictions
Momentum 3rd July 2014
−→F
−→d
Work, W = Fd
This equation is correct only in the situation that:
![Page 55: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/55.jpg)
Restrictions
Momentum 3rd July 2014
−→F
−→d
Work, W = Fd
This equation is correct only in the situation that:−→F is constant
![Page 56: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/56.jpg)
Restrictions
Momentum 3rd July 2014
−→F
−→d
Work, W = Fd
This equation is correct only in the situation that:−→F is constant−→d is a straight line
![Page 57: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/57.jpg)
Restrictions
Momentum 3rd July 2014
−→F
−→d
Work, W = Fd
This equation is correct only in the situation that:−→F is constant−→d is a straight line−→F and
−→d are in the same direction.
![Page 58: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/58.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
![Page 59: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/59.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
![Page 60: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/60.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
(b) 0.5 J
![Page 61: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/61.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
(b) 0.5 J
(c) 5 J
![Page 62: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/62.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
(b) 0.5 J
(c) 5 J
(d) 10 J
![Page 63: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/63.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
(b) 0.5 J
(c) 5 J
(d) 10 J
(e) Not enough information to determine
![Page 64: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/64.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
(a) 0 J
(b) 0.5 J
(c) 5 J
(d) 10 J
(e) Not enough information to determine
![Page 65: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/65.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
−→T
−→w = 10N
(c) 5 J
∑
Fy = may ⇒
T − 10N = 0 ⇒ T = 10N
W = Td = (10N)(0.5m)
![Page 66: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/66.jpg)
Work Exercise I
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by the tension force?
10N
0.5m
−→T
−→w = 10N
(c) 5 J
∑
Fy = may ⇒
T − 10N = 0 ⇒ T = 10N
W = Td = (10N)(0.5m)
Note: W = work and w = weight
![Page 67: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/67.jpg)
Perpendicular Force
Momentum 3rd July 2014
A force perpendicular to the displacement does no work.
![Page 68: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/68.jpg)
Perpendicular Force
Momentum 3rd July 2014
A force perpendicular to the displacement does no work.
![Page 69: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/69.jpg)
Perpendicular Force
Momentum 3rd July 2014
A force perpendicular to the displacement does no work.
−→F
![Page 70: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/70.jpg)
Perpendicular Force
Momentum 3rd July 2014
A force perpendicular to the displacement does no work.
−→F
−→d
![Page 71: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/71.jpg)
Perpendicular Force
Momentum 3rd July 2014
A force perpendicular to the displacement does no work.
−→F
−→d
This force cannot be responsiblefor this motion ⇒ W = 0
![Page 72: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/72.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
![Page 73: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/73.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
![Page 74: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/74.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
![Page 75: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/75.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→d
![Page 76: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/76.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
![Page 77: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/77.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
![Page 78: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/78.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
![Page 79: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/79.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
![Page 80: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/80.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφ
![Page 81: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/81.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφ
![Page 82: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/82.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφF⊥
![Page 83: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/83.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφF⊥ −→
F⊥ does no work
![Page 84: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/84.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφF⊥ −→
F⊥ does no work
W = Fd cosφ
![Page 85: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/85.jpg)
Arbitrary Direction
Momentum 3rd July 2014
Only the component of the force parallel to the displacement doeswork.
−→F
−→dφ
φ = angle between−→F and
−→d
F‖
W = F‖d = Fd cosφF⊥ −→
F⊥ does no work
W = Fd cosφ
Only correct for Constant force & Straight-line displacement
![Page 86: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/86.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
![Page 87: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/87.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
![Page 88: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/88.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
(b) 5 J
![Page 89: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/89.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
(b) 5 J
(c) 5 J cos 180◦ = −5 J
![Page 90: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/90.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
(b) 5 J
(c) 5 J cos 180◦ = −5 J
(d) 10 J cos 180◦ = −10 J
![Page 91: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/91.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
(b) 5 J
(c) 5 J cos 180◦ = −5 J
(d) 10 J cos 180◦ = −10 J
(e) Not enough information to determine
![Page 92: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/92.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
(a) 0 J
(b) 5 J
(c) 5 J cos 180◦ = −5 J
(d) 10 J cos 180◦ = −10 J
(e) Not enough information to determine
![Page 93: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/93.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
10N
180◦
(c) 5 J cos 180◦ = −5 J
W = Fd cosφ
![Page 94: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/94.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
10N
180◦
(c) 5 J cos 180◦ = −5 J
W = Fd cosφ
⇒ W = (10N)(0.5m) cos 180◦
![Page 95: July 3, Week 5 Today: Finish Chapter 9, Begin …physics.unm.edu/Courses/morgan-tracy/151Summer/Slides/...2014/07/03 · July 3, Week 5 Momentum 3rd July 2014 Today: Finish Chapter](https://reader036.fdocuments.us/reader036/viewer/2022071114/5feb59d60c584e1f5e29252b/html5/thumbnails/95.jpg)
Work Exercise II
Momentum 3rd July 2014
A 10N block is pulled 0.5m upwards with constant speed by amassless rope. How much work is done by gravity?
10N
0.5m
10N
180◦
(c) 5 J cos 180◦ = −5 J
W = Fd cosφ
⇒ W = (10N)(0.5m) cos 180◦
Negative work slows an object down