Journal Chapter 5
description
Transcript of Journal Chapter 5
![Page 1: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/1.jpg)
Journal Chapter 5
![Page 2: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/2.jpg)
PERPENDICULAR BISECTOR
A line that bisects a segment and is perpendicular to that segment.
Any point that lies on the perpendicular bisector, is equidistant to both of the endpoints of the segment.
If it is equidistant from both of the endpoints of the segment, then it is on the perpendicular bisector.
![Page 3: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/3.jpg)
Examples of Perpendicular Bisector
A
B
C
D
EBE = DEAE = CEm<E = 90
![Page 4: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/4.jpg)
ANGLE BISECTOR A angle bisector is a ray that cuts an angle
into 2 congruent angles. It always lies on the interior of the angle.
Any point that lies on the angle bisector is equidistant to both of the sides of the angle.
If it is equidistant, then it lies on the angle bisector.
![Page 5: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/5.jpg)
Examples of Angle bisector
A
B
C
D
AB = BCADB = CDBM AB = M BC
![Page 6: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/6.jpg)
CONCURRENCY Concurrent is when three or more lines
intersect at one point. The concurrency of the perpendicular
bisector is the circumcenter because it is where 3 lines meet.
Circumcenter is the point of concurrency where the perpendicular bisectors of a triangle meet. It is equidistant to the 3 vertices.
![Page 7: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/7.jpg)
Examples of concurrency
A voting post would be an example of circumcenter because it is equidistant to all vertices so a voting post needs to be equidistant to 3 towns
![Page 8: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/8.jpg)
INCENTER The incenter is the point of concurrency of
the angle bisector because it is where 3 lines meet.
Incenter is the point where the angle bisector of a triangle intersect. It is equidistant to the sides of the triangle.
![Page 9: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/9.jpg)
Examples of Incenter
A restaurant in the Middle of 3 highways Is an example of incenterBecause it is equidistant to The 3 sides or highways
![Page 10: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/10.jpg)
MEDIAN Median is the segment that goes from the
vertex of a triangle to the opposite midpoint.
Centroid is the point where the medians of a triangle intersect.
When the median goes from the vertex to the opposite midpoint you can see that it makes to congruent parts so one side is concurrent to the other.
![Page 11: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/11.jpg)
Examples of Median
The cockpit of a jetWould be an example ofCentroid because it is the Center of balance.
![Page 12: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/12.jpg)
ALTITUDE The altitude of a triangle is a segment that
goes from the vertex perpendicular to the line containing the opposite side.
The orthocenter is where the altitudes intersect.
The concurrency of the altitudes is the orthocenter because it is where 3 lines meet.
![Page 13: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/13.jpg)
Altitude
![Page 14: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/14.jpg)
MIDSEGMENT Is a point that joins two midpoints of the
sides of the triangles. The midsegment is parallel to the opposite
side and the midsegment is half as long as the opposite side.
![Page 15: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/15.jpg)
Midsegment
![Page 16: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/16.jpg)
TRIANGLE SIDE ANGLE
RELATIONSHIP In any triangle the longest side is always
opposite the biggest angle, the shortest side is opposite the shortest angle.
![Page 17: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/17.jpg)
Triangle side angle relationship
A
B
C
AB > BC, m of angle C > m of angle A
X Y
Zm< Z < m< Y, XY>XZ
D
E
F
DE > EF, m< D < m< F
![Page 18: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/18.jpg)
EXTERIOR ANGLE INEQUALITY
The measure of an exterior angle of a triangle is equal to the sum of the measures of its remote interior angles
![Page 19: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/19.jpg)
Exterior angel inequality
1
2
3 4
M<4= m<1+m<2
60
6060M<4 = 120
90
45
45
M<4= 135
![Page 20: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/20.jpg)
TRIANGLE INEQUALITY
The two smaller sides of a triangle must add up to more than the length at the length of the 3rd side.
![Page 21: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/21.jpg)
Triangle inequalityA
B
C
AB+BC > ACBC+AC > ABAC+AB > BC
![Page 22: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/22.jpg)
INDIRECT PROOFS Indirect proofs are proofs that you use to
proof something that is not right by contradicting yourself at one point.
1. First you assume what you are proving is false.
2. Second use that as your given and start proving
3. Last you find a contradiction and prove it.
![Page 23: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/23.jpg)
Indirect proofsStatement Reason
1.FH is a medianof triangle DFGM<DHF > M< GHF
GIVEN
2. DH ≅ GH Definition of median3. FH ≅ HF Reflexive property4. DF > GF Hinge Theorem
Statement Reason
1. A triangle hasTwo right angles<1+<2
GIVEN
2. M<1=m<2=90 Def. right <
3. m<1+m<2 =180Substitution
4.M<1+m<2 +m<3=180Triangle sumTheorem
5. m<3 =o A triangleCan’t have2 right <‘sStatement Reason
1. a>0 so 1/a<0 Given2. 1/a<0 Given3. 1<0 Multiplicative prop.
Therefore if a>0 1/a>0
![Page 24: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/24.jpg)
HINGE THEOREM If two triangles have two sides that are
congruent, but the third side is not congruent, then the triangle with the larger included angle has the longer third side.
If the triangle with the larger included angle has the longer third side, but the third side is not congruent, then two triangles have two sides that are congruent.
![Page 25: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/25.jpg)
Hinge theorem
A
B
CD
E
F
m<A > m<DBC > EF
57
53
6
6
K
L
N
KL<MN 7 7
5.3 5.1P
Q
RS
m<PQS > m<RQS
![Page 26: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/26.jpg)
TRIANGLES 45-45-90, 30-60-90
In a 45-45-90 triangle, both legs are congruent, and the length of the hypotenuse is the length of a leg times √2
In a 30-60-90 triangle, the hypotenuse is twice as long as the shorter leg and the length of the longer leg is the length of the shorter leg times √3
![Page 27: Journal Chapter 5](https://reader035.fdocuments.us/reader035/viewer/2022081604/56815e07550346895dcc5b1c/html5/thumbnails/27.jpg)
Triangles 45-45-90, 30-60-90
45
45l√2
l
l7
x45
X= 7√2
30
60s
2ss√3
30
60
16
y
x
16=2x8=xy=x√3y=8√3