James Hawthorne Workshop: Conditionals Counterfactuals and Causes In Uncertain Environments

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A QUALITATIVE LOGIC OF COMPARATIVE EVIDENTIAL SUPPORT STRENGTH AN EXTENSION OF THE KOOPMAN-KEYNES APPROACH TO THE QUALITATIVE LOGIC OF COMPARATIVE EVIDENTIAL SUPPORT UNDERLYING THE PROBABILISTIC LOGIC OF THE POPPER FUNCTIONS James Hawthorne Workshop: Conditionals Counterfactuals and Causes In Uncertain Environments Düsseldorf 19/5/2011 – 22/5/2011 1

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A Qualitative Logic of Comparative Evidential Support Strength An Extension of the Koopman -Keynes Approach to The qualitative Logic of Comparative Evidential Support Underlying the Probabilistic Logic of the Popper Functions. James Hawthorne - PowerPoint PPT Presentation

Transcript of James Hawthorne Workshop: Conditionals Counterfactuals and Causes In Uncertain Environments

Page 1: James  Hawthorne Workshop:  Conditionals Counterfactuals and Causes In  Uncertain Environments

A QUALITATIVE LOGIC OF COMPARATIVE EVIDENTIAL SUPPORT STRENGTH

AN EXTENSION OF THE KOOPMAN-KEYNES APPROACH TO THE QUALITATIVE LOGIC OFCOMPARATIVE EVIDENTIAL SUPPORT

UNDERLYING THE PROBABILISTIC LOGIC OF THE POPPER FUNCTIONS

James HawthorneWorkshop: Conditionals Counterfactuals and Causes In

Uncertain EnvironmentsDüsseldorf 19/5/2011 – 22/5/2011

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Main QuestionWhy Measure Evidential Support Probabilistically?

That is: Why measure the support of H by E on a scale of real numbers between 0 and 1 that satisfies typical probabilistic axioms?

More specifically, I advocate a version of Bayesian Confirmation Theory

where the confirmation functions are so-called Popper Functions,

and I think that evidential support is often best represented by sets of Popper Functions, because individual probabilistic support functions seem to be overly precise measures of evidential support.

But isn’t the fact that probabilistic measures of support are overly precise just a symptom of the fact that probability functions are really ill-suited as measures of confirmation? More generally, why think that a probabilistic measure is at all the right sort of thing to use in

measuring evidential support ?The qualitative logic of evidential support I’ll present offers an answer to these questions.===============================================================================

More generally, if the Popper Functions provide a useful version of the notion of conditional probability used in a given project X, then this qualitative logic may provide a useful theoretical account of what the probability functions in project X really represent.

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Why measure the support of H by E with Probability Functions?

Several Kinds of Answers:

1. Show what results follow: that the resulting probabilistic system supplies an account of confirmation that has intuitively desirable properties.

2. Argue from fundamental principles: (i) argue that the probabilistic axioms themselves are reasonable constraints on

a measure of evidential support (i) (e.g. analyses of axioms ; Dutch Book arguments ; etc.)OR(ii) argue that the axiomatic system captures some deeper, more fundamental

logic of evidential support that is itself a compelling account (e.g. Representation Theorem arguments).

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Probabilistic Confirmation Functions

Conditional Probability Functions (equivalent to those proposed by Karl Popper, Logic of Scientific Discovery, 1959)

0. for some E, F, P[F | E] 1

1. 0 < P[A | B] < 1

2. if B |= A, then P[A | B] = 1

3. if C |= B and B |= C, then P[A | B] = P[A | C]

4. P[(AB) | C] = P[A | (BC)] P[B | C]

5. if C |= ~(AB), then P[(AB) | C] = P[A | C] + P[B | C] or P[D | C] = 1 for all D

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Probabilistic Confirmation Functions

Popper Probability Functions (only for Sentential Logic Languages)

(Karl Popper, Logic of Scientific Discovery, 1959)

0. each P[A | B] a real number and for some E, F, G, H,P[F | E] P[G | H]

1. P[A | A] P[B | B]

2. P[A | (BC)] P[A | (CB)]

3. P[A | C] P[(AB) | C]

4. P[(AB) | C] = P[A | (BC)] P[B | C]

5. P[A | B] + P[~A | B] = P[B | B]

unless P[D | B] = P[B | B] for all D

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Probabilistic Confirmation FunctionsPopper-Field Probability Functions (Extends Popper Functions to Predicate Logic Languages)(Hartry Field, “Logic, Meaning, and Conceptual Role”, JP, 7/1977)

Define a PF-Class M to be a set of functions P such that

0. P is a Popper Function (i.e. satisfies the previous rules)

1. P[((Fc1Fc2)...Fcm) | B] P[xFx | B]

2. if r > P[xFx | B] (for r a positive real), then for some P in M defined on a name extension of P’s language L, there are names e1, ..., en in P’s language such that r P[((Fe1Fe2)...Fen) | B]

(i.e. P[xFx | B] is a greatest lower bound on values of

2. P[((Fe1Fe2)...Fen) | B] in PF-Class M)

The Popper-Field Functions on a language and its name extensions is just the union of all PF-Classes M on that language and its name extensions.

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Why measure the support of H by E with Probability Functions?

Several Kinds of Answers:

1. Show what results follow: that the resulting probabilistic system supplies an account of confirmation that has intuitively desirable properties.

2. Argue from fundamental principles: (i) argue that the probabilistic axioms themselves are reasonable constraints on

a measure of evidential support (i) (e.g. analyses of axioms ; Dutch Book arguments ; etc.)OR(ii) argue that the axiomatic system captures some deeper, more fundamental

logic of evidential support that is itself a compelling account (e.g. Representation Theorem arguments).

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A More Fundamental Qualitative Logic of Evidential Support

Want to characterize comparative support relations ≽ of form H1 | E1 ≽ H2 | E2 :

conclusion H1 is supported by premise(s) E1

at least as strongly as conclusion H2 is supported by premise(s) E2

(under interpretation )

Think of this notion of comparative support strength under an interpretation of a language (for predicate logic) as a basic semantic notion – i.e. as basic in the same way that the notion of truth under an interpretation of a language (for predicate logic) is a basic semantic notion.

What semantic rules should all comparative support relations, ≽ , obey?

That is, what semantic rules should constrain how logical terms behave within a comparative support relation ≽?

(in the way that semantic rules constrain how logical terms behave w.r.t the notion of truth under interpretation)

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The Main IdeaThe semantic rules that govern ≽ should be intuitively plausible constraints on comparisons of evidential support strength.

Each such relation ≽ should be (at least) a partial order -- perhaps not every pair of cases of support strength may be directly comparable.

The semantic rules that govern ≽ should (if possible) not presuppose the notion of logical entailment – rather, logical entailment should fall out of the relations ≽ as a special case.

It should turn out that quantitative conditional probability functions (i.e. Popper Functions) merely provide a convenient way to represent the comparative support relations.

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A Few DefinitionsComparative Support Relation under an interpretation :H1|E1 ≽ H2|E2 : H1 is supported by E1 at least as strongly as H2 is supported by E2

Given a comparative support-strength relation ≽ , define four associated relations:(1) H1|E1 ≻ H2|E2 abbreviates H1|E1 ≽ H2|E2 and not H2|E2 ≽ H1|E1 : H1 is supported by E1 more strongly than H2 is supported by E2

(2) H1|E1 H2|E2 abbreviates H1|E1 ≽ H2|E2 and H2|E2 ≽ H1|E1 : H1 is supported by E1 to the same extent that H2 is supported by E2

(3) H1|E1 ≺≻ H2|E2 abbreviates not H1|E1 ≽ H2|E2 and not H2|E2 ≽ H1|E1 : the support-strength for H1 by E1 is not determinately comparable to that of H2 by E2.(4) E H abbreviates H|E ≽ E|E : E supportively entails HIt will turn out that:1. each supportive entailment relation (i.e. for each ≽) is a so-called Rational Consequence Relation2. indeed, each Rational Consequence Relation is represented by 2. a supportive entailment relation (for some ≽)3. Logical Entailment is just supportive entailment for every ≽

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The Main IdeaIt should turn out that quantitative conditional probability functions (i.e. Popper Functions) are merely a convenient way to represent the comparative support relations. (That’s the main point of this project.)

That is, ...

The rules that constrain the comparative support relations should be probabilistically sound in that each Popper Function should satisfy them.

For each Popper Function P , define the corresponding comparative relation ≽ such that, for all sentences H1, E1, H2, E2,

H1 | E1 ≽ H2 | E2 iff P[H1 | E1] P[H2 | E2].

Then, for each Popper Function P , we want its corresponding comparative relation ≽ to be a comparative support relations – i.e. to satisfy the rules for the comparative support relations.

And we want the rules that constrain the comparative support relations to be probabilistically complete in the sense that each comparative support relation ≽ that satisfies the specified rules should be representable by a Popper Function P.

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The Main IdeaThe rules that constrain the comparative support relations should be probabilistically sound and complete in that each Popper Function should corresponds to a comparative support relation, and each comparative support relation ≽ (that satisfies the rules) should be representable by a Popper Function P.=================================================================The strongest version of probabilistic representation for a comparative support relation would be this:

Strong Probabilistic Representation: For each comparative support relation ≽ (that satisfies the specified rules) there is

a (unique) Popper function P such that, for all H1, E1, H2, E2, P[H1 | E1] P[H2 | E2] if and only if H1 | E1 ≽ H2 | E2 .

Such a representation result will be forthcoming, but only for those comparative support relations ≽ that provide a complete order on comparative support-strength – i.e., only for those ≽ such that for all H1, E1, H2, E2,

either H1 | E1 ≽ H2 | E2 or H2 | E2 ≽ H1 | E1 (complete comparability)

However, that is a very strong constraint on comparative support strength. I’ll characterize comparative support relations that need not satisfy this condition.

Strong Probabilistic Representation will also require an Archimedean Condition – more on that next.

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The Main IdeaThe rules that constrain the comparative support relations should be probabilistically sound and complete in that each Popper Function should corresponds to a comparative support relation, and each comparative support relation ≽ (that satisfies the rules) should be representable by a Popper Function P.==========================================================================A weaker notion of probabilistic representation for comparative support relations would be this: Moderate Probabilistic Representation (but not permitting infinitesimally greater support):

For each comparative support relation ≽ there is a Popper Function P such that for all H1, E1, H2, E2,

(1) if H1|E1 ≻ H2|E2, then P[H1 | E1] > P[H2 | E2]; (2) if H1|E1 H2|E2, then P[H1 | E1] = P[H2 | E2]. (1) and (2) are jointly equivalent to the following conditions: if P[H1 | E1] > P[H2 | E2], then H1|E1 ≻ H2|E2 or H1|E1 ≺≻ H2|E2.

if P[H1 | E1] = P[H2 | E2], then H1|E1 H2|E2 or H1|E1 ≺≻ H2|E2.

The fact that comparative support strength is a partial order implies that probabilistic representations of evidential support tend to be overly precise. Thus, evidential support is often represented by a set of conditional probability functions rather than by a single conditional probability function.

In order to satisfy condition (1) the comparative support relations have to satisfy an Archimedean Condition – e.g. If H1|E1 ≻ H2|E2, then for an integer n 2 there are n sentences S1, ..., Sn such that:not E2~E2, E2(S1...Sn), (for distinct i, j) E2~(Si·Sj), Si|E2  Sj|E2, and H1|E1≻(SiH2)|E2

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The Main IdeaThe rules that constrain the comparative support relations should be probabilistically sound and complete in that each Popper Function should corresponds to a comparative support relation, and each comparative support relation ≽ (that satisfies the rules) should be representable by a Popper Function P.==========================================================================An even weaker notion of probabilistic representation for comparative support relations will apply more generally to all such relations – including those that provide only Non-Archimedean partial orders on support strength.

Weak Probabilistic Representation (permitting infinitesimally greater support): For each comparative support relation ≽ there is a Popper Function P such that for

all H1, E1, H2, E2, (1) if H1|E1 ≻ H2|E2, then P[H1 | E1] P[H2 | E2]; (2) if H1|E1 H2|E2, then P[H1 | E1] = P[H2 | E2]. (1) and (2) are jointly equivalent to the following condition: if P[H1 | E1] > P[H2 | E2], then H1|E1 ≻ H2|E2 or H1|E1 ≺≻ H2|E2.

Weak Probabilistic Representation still requires an axiom about partitions, but one that’s much weaker than the previous Archimedean Condition – e.g. an Arbitrarily Large Partitions Condition:

For each integer m 2 there is an integer n m such that for n sentences S1, ..., Sn

and some sentence E: not E~S1, (for distinct i, j) E~(Si·Sj), Si|E  Sj|E.

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The Comparative Support Rulesw/ Classical Logical Entailment

0. for some H1, E2, H2, E2, H1|E1 ≻ H2|E2 (non-triviality)

1. B|B ≽ H|E (maximality)

2. If H1|E1 ≽ H2|E2 , H2|E2 ≽ H3|E3, then H1|E1 ≽ H3|E3 (transitivity)

3. If E1|= E2, E2|= E1, then H|E1 ≽ H|E2 (Antecedent L-Equivalence)!

4. If H2|= H1, then H1|E ≽ H2|E (Consequent L-Consequence) !

{rule 4 yields Reflexivity: H|E ≽ H|E}

5. If H1|E1 ≽ H2|E2, then ~H2|E2 ≽ ~H1|E1 or E1 D (all D)(negation-symmetry)!

6. If H1|(E1F) ≽ H2|E2 and H1|(E1~F) ≽ H2|E2, then H1|E1 ≽ H2|E2 (alternate presumption)*

7. If EH, then E~F or (EF)H (Rational Monotonicity)

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The Comparative Support Rulesw/o Classical Logical Entailment

0. for some H1, E2, H2, E2, H1|E1 ≻ H2|E2 (non-triviality)

1. B|B ≽ H|E (maximality)

2. If H1|E1 ≽ H2|E2 , H2|E2 ≽ H3|E3, then H1|E1 ≽ H3|E3 (transitivity)

3. H|(E1E2) ≽ H|(E2E1) (Antecedent Commutivity) !

4.1 (HH)|E ≽ H|E (Consequent Repetition: CR) !

4.2 H1|E1 ≽ (H1H2)|E1 (Simplification) !

{4.1-4.2 jointly yield Reflexivity: H|E ≽ H|E}

5.1 If H1|E1 ≽ ~H2|E2, then H2|E2 ≽ ~H1|E1 or E1 D (all D)

5.2 If ~H1|E1 ≽ H2|E2, then ~H2|E2 ≽ H1|E1 or E1 D (all D)(negation-symmetry) !

6. If H1|(E1F) ≽ H2|E2 and H1|(E1~F) ≽ H2|E2, then H1|E1 ≽ H2|E2 (alternate presumption)*

7. If EH, then E~F or (EF)H (Rational Monotonicity)

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The Comparative Support Rules8. If H1|(A1·E1) ≽ H2|(A2·E2), A1|E1 ≽ A2|E2, then (H1·A1)|E1 ≽ (H2·A2)|E2

(composition)

8.1 If H1|(A1·E1) ≻ H2|(A2·E2), A1|E1 ≽ A2|E2, E2 ~(H2·A2), then (H1·A1)|E1 ≻ (H2·A2)|E2

8.2 If H1|(A1·E1) ≽ H2|(A2·E2), A1|E1 ≻ A2|E2, E2 ~(H2·A2), then (H1·A1)|E1 ≻ (H2·A2)|E2

8.3 If H1|(A1·E1) ≺≻ H2|(A2·E2), E2 ~(H2·A2), then (H1·A1)|E1 ≺≻ (H2·A2)|E2

8.4 If A1|E1 ≺≻ A2|E2, E2 ~(H2·A2), then (H1·A1)|E1 ≺≻ (H2·A2)|E2

======================================================================== If (H2·A2)|E2 ≽ (H1·A1)|E1, A1|E1 ≽ A2|E2, E2 ~(H2·A2), then H2|(A2·E2) ≽ H1|(A1·E1)

If (H2·A2)|E2 ≽ (H1·A1)|E1, H1|(A1·E1) ≽ H2|(A2·E2), E2 ~(H2·A2), then A2|E2 ≽ A1|E1

(decomposition)

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The Comparative Support Rules9. If H1|(A1·E1) ≽ A2|E2, A1|E1 ≽ H2|(A2·E2), then (H1·A1)|E1 ≽ (H2·A2)|E2

(composition)

9.1 If H1|(A1·E1) ≻ A2|E2, A1|E1 ≽ H2|(A2·E2), E2 ~(H2·A2), then (H1·A1)|E1 ≻ (H2·A2)|E2

9.2 If H1|(A1·E1) ≽ A2|E2, A1|E1 ≻ H2|(A2·E2), E2 ~(H2·A2), then (H1·A1)|E1 ≻ (H2·A2)|E2

9.3 If H1|(A1·E1) ≺≻ A2|E2, E2 ~(H2·A2), then (H1·A1)|E1 ≺≻ (H2·A2)|E2

==========================================================================

If (H2·A2)|E2 ≽ (H1·A1)|E1, A1|E1 ≽ H2|(A2·E2), E2 ~(H2·A2), then A2|E2 ≽ H1|(A1·E1)

If (H2·A2)|E2 ≽ (H1·A1)|E1, H1|(A1·E1) ≽ A2|E2, E2 ~(H2·A2), then H2|(A2·E2) ≽ A1|E1

(decomposition)

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Comparative Support Bayes’ TheoremsBayes’ Theorem 1: Suppose B~H1.

If E|(H1B) ≻ E|(H2B), H1|B ≽ H2|B, then H1|(EB) ≻ H2|(EB).

Bayes’ Theorem 2: Suppose B~H1, B~H2, B~(H1H2).

If E|(H1B) ≻ E|(H2B), then

H1|(EB(H1H2)) ≻ H1|(B(H1H2)) and H2|(B(H1H2)) ≻ H2|(EB(H1H2)).

==============================================================

Compare: Suppose P[H1 | B] > 0, P[H2 | B] > 0, P[H1H2 | B] = 0.

If P[E | H1B] > P[E | H2B], then

P[H1 | EB(H1H2)] P[H1 | EB] P[E | H1B] P[H1 | B] ------------------------- = --------------- = -------------- ------------ P[H2 | EB(H1H2)] P[H2 | EB] P[E | H2B] P[H2 | B]

P[H1 | B] P[H1 | B(H1H2)] > ------------ = ----------------------- P[H2 | B] P[H2 | B(H1H2)]

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The Comparative Support RulesExtendibility Rule(s):

≽ is extendable to a comparative support relation ≽

(i.e. whenever A|B ≻ C|D, A|B ≻ C|D ; whenever A|B C|D, A|B C|D )

such that ≽ satisfies all the other rules (1-9 thus far), and also satisfies the following rules:

10. H1|E1 ≽ H2|E2 or H2|E2 ≽ H1|E1 (complete comparability)=========================================================Example of an relation ≽ that satisfies rules 1-9 but is not extendable

to a relation ≽ that satisfies Complete Comparability

can have H|(BE) ≻ H|B and H|(B~E) ≻ H|B {but only if E|B ≺≻ E|(HB)}

==========================================================Theorem (from:1-5, 7-9): H|B ≺≻ H|(BE) or H|B ≺≻ H|(B~E) or E|B ≺≻ E|(HB)

or H|(BE) ≽ H|B ≽ H|(B~E) or H|(B~E) ≽ H|B ≽ H|(BE).

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The Comparative Support RulesExtendibility: ≽ is extendable to a comparative support relation ≽

(i.e. whenever A|B ≻ C|D, A|B ≻ C|D ; whenever A|B C|D, A|B C|D )

that satisfies all the other rules, and also satisfies the following rules:

10. H1|E1 ≽ H2|E2 or H2|E2 ≽ H1|E1 (complete comparability)

{follows that} For any integer n > 1, if A1, ..., An, and B1, ..., Bn are such that C(A1...An), C~(AiAj), An|C ≽ ... ≽ A1|C, not C~C, D(B1...Bn), D~(BiBj), Bn|D ≽ ... ≽ B1|D, not D~D, then An|C ≽ B1|D. (subdivision)*

11. For each integer m 2 there is an integer n m such that for n sentences S1, ..., Sn

and some sentence E: not E~S1, (for distinct i, j) E~(Si·Sj), Si|E  Sj|E.

(arbitrarily large partitions) or, alternatively,

11.+ If H1|E1 ≻ H2|E2, then for some integer n 2 there are n sentences S1, ..., Sn such that:

not E2~S1, (for distinct i, j) E2~(Si·Sj), Si|E2  Sj|E2,

E2(S1...Sn), and H1|E1 ≻ (SiH2)|E2.

The Representation Theorems hold for all comparative support relations that satisfy these rules. Strong Representation holds for each ≽ satisfying rules 0-10 and 11+. Moderate Representation holds for each ≽ satisfying rules 0-9 and extendable to rules 10-11+. Weak Representation holds for each ≽ satisfying rules 0-9 and extendable to 10-11.

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The Comparative Support RulesThe version of the rules that does not presuppose the deductive logical entailment relation also needs explicit rules for quantifiers. The following rules are analogous to those proposed by Hartry Field for the Popper Functions. (Here ‘CS’ stands for “Comparative Support”.)

Define a CS-Class M to be a set of relations ≽ such that

0. ≽ satisfies the comparative support rules 1-9.

1. ((Fc1Fc2)...Fcm) | B ≽ xFx | B

2. if A|B ≻ xFx | C, then for some ≽ in M defined on a name extension of ’s language L, there are names e1, ...,

en in ≽’s language such that

3. A|B ≽ ((Fe1Fe2)...Fen) | C

(unless for all n 2, for any n sentences S1, ..., Sn such that not C~S1, (for distinct i, j) C~(Si·Sj), Si|C  Sj|C, C(S1...Sn), we have (SixFx)|C ≻ A|B).

2. if ((Fe1Fe2)...Fen) | C ≻ A|B for all ≽ a name extension of ≽ in M, for all names e1, ..., en in ≽’s

language, then xFx | C ≽ A|B

(unless A|B≻xFx|C , but for all n 2, for any n sentences S1, ..., Sn such that not C~S1, (for distinct i, j) C~(Si·Sj), Si|C  Sj|C, C(S1...Sn), we have (SixFx)|C ≻ A|B).

{need both 1 and 2 only because the relation ≽ need not be a complete order}

The Comparative Support Relations on a language and its name extensions is just the union of all CS-Classes M (for that language and its name extensions) that are also extendable so as to satisfy rules 10 and 11 (rule 11+ for the Archimedean Comparative Support Relations).

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Representation TheoremsThe rules that constrain the comparative support relations are probabilistically sound and complete in that each Popper Function corresponds to a comparative support relation, and each comparative support relation ≽ (that satisfies the rules) is representable by a Popper Function P as follow:

Strong Probabilistic Representation (for Completely Comparable Archimedean CSRs):For each comparative support relation ≽ that satisfies 0-10 and 11+, there is

a unique Popper function P such that, for all H1, E1, H2, E2,P[H1 | E1] P[H2 | E2] if and only if H1 | E1 ≽ H2 | E2 .

Moderate Probabilistic Representation (for Archimedean CSRs):For each comparative support relation ≽ that satisfies 0-9 and is extendable to 10-11+,

there is a Popper Function P such that for all H1, E1, H2, E2, (1) if H1|E1 ≻ H2|E2, then P[H1 | E1] > P[H2 | E2]; (2) if H1|E1 H2|E2, then P[H1 | E1] = P[H2 | E2]. (1) and (2) are jointly equivalent to the following conditions: if P[H1 | E1] > P[H2 | E2], then H1|E1 ≻ H2|E2 or H1|E1 ≺≻ H2|E2.

if P[H1 | E1] = P[H2 | E2], then H1|E1 H2|E2 or H1|E1 ≺≻ H2|E2.

Weak Probabilistic Representation (for CSRs that may permit infinitesimally greater support):

For each comparative support relation ≽ that satisfies 0-9 and is extendable to 10-11,

there is a Popper Function P such that for all H1, E1, H2, E2, (1) if H1|E1 ≻ H2|E2, then P[H1 | E1] P[H2 | E2]; (2) if H1|E1 H2|E2, then P[H1 | E1] = P[H2 | E2]. (1) and (2) are jointly equivalent to the following condition: if P[H1 | E1] > P[H2 | E2], then H1|E1 ≻ H2|E2 or H1|E1 ≺≻ H2|E2.

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EXAMPLE: De Finetti Lottery–like casesWhen we permit a broad enough class of CSRs such that we merely have

Weak Probabilistic Representation (where some CSRs may permit infinitesimally greater support):

For each comparative support relation ≽ that satisfies 0-9 and is extendable to 10-11,

there is a Popper Function P such that for all H1, E1, H2, E2, (1) if H1|E1 ≻ H2|E2, then P[H1 | E1] P[H2 | E2]; (2) if H1|E1 H2|E2, then P[H1 | E1] = P[H2 | E2]. (1) and (2) are jointly equivalent to the following condition: if P[H1 | E1] > P[H2 | E2], then H1|E1 ≻ H2|E2 or H1|E1 ≺≻ H2|E2.

Then, there exist CSRs, ≽ , such that:

For a countably infinite set of sentences {S1, ..., Sn, ...} and a sentence F:

not F~S1 (i.e. S1|F ≻ ~F|F ), (for each distinct i, j) F~(Si·Sj), Si|F  Sj|F.

Follows that for this CSRs, ≽ :

For each integer n 2, for the n sentences S1, ..., Sn

and for a sentence E [i.e. for the sentence (F·(S1S2...Sn)) ] we have:

not E~S1 (i.e. S1| E ≻ ~E|E ) and (for distinct i, j) E~(Si·Sj),

E (S1S2...Sn)

Si|E  Sj|E .

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A QUALITATIVE LOGIC OF COMPARATIVE EVIDENTIAL

SUPPORT STRENGTHAN EXTENSION OF THE KOOPMAN-KEYNES APPROACH TO THE

QUALITATIVE LOGIC OFCOMPARATIVE EVIDENTIAL SUPPORT

UNDERLYING THE PROBABILISTIC LOGIC OF THE POPPER FUNCTIONS

James HawthorneWorkshop: Conditionals Counterfactuals and

Causes In Uncertain EnvironmentsDüsseldorf 19/5/2011 – 22/5/2011

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System R = P + (RM)The Preferential and Rational Consequence Relations

Weaker than Usual Axioms

0. for some E, F, E |/~ F (Nontriv)

1. A |~ A (Reflex)

2. if C |= B, B |= C, B |~ A, then C |~ A (LCE)

2. 3. if C |~ B, B |= A, then C |~ A (RW)

4. if (CB) |~ A and (C~B) |~ A, then C |~ A (WOR)

5. if C |~ (BA), then (CB) |~ A (VCM)============================================================================================================================================

{O: if (C~B) |~ B, C |~ A, then C |~ (BA) (WAND)}

P: 6. if C |~ B, C |~ A, then C |~ (BA) (AND)=============================================================================================================================================

{Q: if C |~ A and (C~B) |/~ A, then (CB) |~ A(NR)}

R: 7. if C |~ A, C |/~ ~B, then (CB) |~ A (RM)

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Probabilistic Confirmation Functions

Conditional Probability Functions (equivalent to those proposed by Karl Popper, Logic of Scientific Discovery, 1959)

0. for some E, F, P[F | E] 1

1. 0 < P[A | B] < 1

2. if B |= A, then P[A | B] = 1

3. if C |= B and B |= C, then P[A | B] = P[A | C]

4. P[(AB) | C] = P[A | (BC)] P[B | C]

5. if C |= ~(AB), then P[(AB) | C] = P[A | C] + P[B | C] or P[D | C] = 1 for all D

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Probabilistic Confirmation Functions

Conditional Probability Functions (Janina Hosiasson-Lindenbaum, JSL, 12/1940)

1. 0 < P[A | B] < 1 {and for some E, F, P[F | E] 1}

2. if B |= A, then P[A | B] = 1

3. if C |= B and B |= C, then P[A | B] = P[A | C]

4. P[(AB) | C] = P[A | (BC)] P[B | C]

5. if C |= ~(AB), then P[(AB) | C] = P[A | C] + P[B | C]unless |= ~C {thus, unless P[D | C] = 1 for all D}