ISAWWA WATER DISTRIBUTION CONFERENCE …4/24/2015 1 ISAWWA WATER DISTRIBUTION CONFERENCE APRIL 28TH,...
Transcript of ISAWWA WATER DISTRIBUTION CONFERENCE …4/24/2015 1 ISAWWA WATER DISTRIBUTION CONFERENCE APRIL 28TH,...
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ISAWWA WATER DISTRIBUTION CONFERENCE
APRIL 28TH , 2015
Basic Math Conversions
1ft3 = 7.48 gallons
1gallon = 8.34 lbs
1mg/l = 1ppm
1% = 10,000 mg/l
1psi= 2.31ft of water
1 in of mercury = 1.13 ft of water
1day = 1440 mins
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Basic Math Formulas
A= 3.14 R2 or A= .785 (D2) ( AREA OF A CIRCLE)
V= A X H ( VOLUME OF A RECTANGULAR TANK)
Q= VA ( VELOCITY FORMULA)
MG x mg/l x 8.34 = lbs ( POUNDS FORMULA)
QS CS = QW CW ( SOLUTIONS FORMULA)
TREATED WATER – BILLED WATER / TREATED WATER = ( UNACCOUNTED FOR WATER)
PUMPING LEVEL – STATIC LEVEL = ( DRAWDOWN)
GPM / DRAWDOWN = ( SPECIFIC CAPACITY)
CHLORINATION MATHThe Pounds Formula
QsCs = QwCw
Feed Rates
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The Pounds Formula lbs = MG x mg/L x 8.34
where
lbs = lbs of chemical
MG = volume of water in million gallons
8.34 = the factor converting mg/L to lbs.
Example 1. How many pounds of chlorine are needed to provide a 50 mg/L chlorine dosage in a 500,000 gallon storage tank?
lbsLmgMGlbs 5.20834.8/505.0
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Example 2. How many pounds of HTH (Calcium hypochlorite - 70% chlorine) are needed to provide a 50 mg/L chlorine dosage in a 500,000 gallon storage tank?
lbslb
LmgMGlbs 29870.
5.20834.8/505.0
Example 3. How many pounds of chlorine are contained in 209 lb of 70% HTH?
209 lb HTH x .70 = 146.3 lb chlorine
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QsCs = QwCwThe Solution Mixing Formula where:
Q is quantity
C is concentration
"s" is strong
"w" is weak.
How much 15 % NaOCl needs to be fed to a 1 MGD rate of flow for a 10 mg/L chlorine dosage? In other words, what will Qs be?
Qs = ? gallons
Cs = 150,000 mg/L
Qw = 1,000,000 gallons
Cw = 10 mg/L
Note that the units are the same now for Qs and Qw (gallons), and for Cs and Cw (mg/L).
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Do the Math …. Solve for Qs. (Qs) (Cs) = (Qw) (Cw)
(Qs)(150,000 mg/L) =(1,000,000 gal)(10 mg/L)
Qs = (1,000,000 gal) ( 10 mg/L)
150,000 mg/L
Qs = 66.7 gallons of 15 % NaOCl
Feed Rates: From the previous example, the 66.7
gal of 15% NaOCl is fed over 24 hours. What is the feed rate?
66.7 gallons = 2.78 gallons x 1 hour
24 hours 1 hour 60 min
= .0463 gpm
= .0463 gal x 3785 ml = 175 ml
min gal min
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UNACCOUNTED FOR WATER
The chief operator is presenting the annual report
To his city council as follows:
Raw Water Pumpage is 177,025,000 gallons
Treated Water Pumpage is 174,370,000 gallons
Billed Water ( Metered Water ) is 153,445,300 gallons
What is the percent of unaccounted for water ?
Do the math …..
Treated water Pumpage 174,370,000
Billed Water ( Metered water ) - 153,445,300
equals 20,924,700
20,924,770
174,370,000 = .12 or 12%
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Velocity of water
How many MGD can be delivered by a 12” DI water main if the velocity is 3.5 feet per second?
Do the math …..
Q= V * A
Q= .785 x 1 x 1 x 3.5 ft = 2.7475
sec
Q= 2.7475 x 7.48 x 60 sec = 1233 gpm
sec 1ft 3 min
Q= 1233 gpm x 1440 min = 1.78 MGD
1 day
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Drawdown
An air line is 80 feet long. After pumping it with air. The air line reads 20 psi. What is the static level?
20 psi x 2.31 = 46 feet.
80 feet – 46 feet = 34 feet ( static level)
The well pump is turned on and runs for two hours. The air line pressure gauge reads 10 psi. What is the pumping level?
10 psi x 2.31 = 23 feet
80 feet – 23 feet = 57 feet ( Pumping level)
Do the math …..
Drawdown = Pumping Level – Static Level
57 feet ( Pumping Level) – 34 feet ( Static Level)=
23 Feet ( Drawdown)
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Specific Capacity
Specific Capacity is = GPM
FEET OF DRAWDOWN
If the pumping flow from the previous problem was 460 gpm then the Specific Capacity will be as follows:
460 gpm
23 feet of Drawdown = 20
ANY QUESTIONS?