is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

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- is defined as the product of is defined as the product of the mass and velocity the mass and velocity -is based on Newton’s 2 -is based on Newton’s 2 nd nd Law Law F = m F = m a a F = m F = m Δ Δ v v t t F F t t = = m m Δ Δ v v IMPULSE MOMENTUM

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MOMENTUM (p). is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law. F = m a F = m Δ v t F t = m Δ v. IMPULSE. MOMENTUM. CHARACTERISTICS OF A MOVING OBJECT. A moving object has both kinetic energy and momentum. KE = ½ mass x velocity 2 - PowerPoint PPT Presentation

Transcript of is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

Page 1: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

-is defined as the product of the is defined as the product of the mass and velocitymass and velocity-is based on Newton’s 2-is based on Newton’s 2ndnd Law Law

F = mF = m aa

F = mF = m ΔΔvv

tt

FF tt == mm ΔΔvv IMPULSE

MOMENTUM

Page 2: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

CHARACTERISTICS OF A CHARACTERISTICS OF A MOVING OBJECTMOVING OBJECT

A moving object has both A moving object has both kinetic energy and kinetic energy and momentum.momentum.

KE = ½ mass x velocityKE = ½ mass x velocity22

P = mass x velocityP = mass x velocity

Page 3: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

Ex. Compare the KE and momentum of two Ex. Compare the KE and momentum of two objects with the following characteristics: objects with the following characteristics:

mm11 = 60 kg v = 60 kg v11 = 4 m/s = 4 m/s m m22 = 6 kg v = 6 kg v22 = 40 = 40 m/sm/s

Solving for momentum, p:Solving for momentum, p:

PP11 = m = m11 v v11 = (60 kg) (4 m/s) = 240 kg-m/s = (60 kg) (4 m/s) = 240 kg-m/s

PP22 = = mm22vv22 = = (6 kg) (40 m/s)(6 kg) (40 m/s) = = 240 kg-m/s240 kg-m/s

Solving for KE:Solving for KE:

KEKE11 = ½ m = ½ m11 v v11 22 = ½ (60 kg) (4 m/s) = ½ (60 kg) (4 m/s)22 = 480 J = 480 J

KEKE22 = = ½ m½ m22vv22 22 = = ½ (6 kg) (40 m/s)½ (6 kg) (40 m/s)22 = = 4800 J4800 J

Therefore object 2 has the same momentum Therefore object 2 has the same momentum but 10 times the KE of object 1but 10 times the KE of object 1

Page 4: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law
Page 5: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

Both KE and momentum are conserved in an elastic collision.

Page 6: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law
Page 7: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law
Page 8: is defined as the product of the mass and velocity -is based on Newton’s 2 nd Law

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