Introduction to Arithmetic Sequences 18 May 2011.
-
Upload
kimberly-carr -
Category
Documents
-
view
224 -
download
0
Transcript of Introduction to Arithmetic Sequences 18 May 2011.
Introduction to Arithmetic Sequences
18 May 2011
Arithmetic Sequences
When the difference between any two numbers is the same constant value
This difference is called d or the constant difference {4, 5, 7, 10, 14, 19, …} {7, 11, 15, 19, 23, ...}
← Not an Arithmetic Sequence
← Arithmetic Sequence
d = 4
Your Turn:
Determine if the following sequences are arithmetic sequences. If so, find d (the constant difference). {14, 10, 6, 2, –2, …} {3, 5, 8, 12, 17, …} {33, 27, 21, 16, 11,…} {4, 10, 16, 22, 28, …}
Recursive Form
The recursive form of a sequence tell you the relationship between any two sequential (in order) terms.
un = un–1 + d n ≥ 2
common difference
Writing Arithmetic Sequences in Recursive Form
If given a term and d
1. Substitute d into the recursive formula
Examples: Write the recursive form and find the next 3 terms
u1 = 39, d = 5 3
1d,
5
3u1
Your Turn: Write the recursive form and find the next 3 terms
u1 = 8, d = –2 u1 = –9.2, d = 0.9
Writing Arithmetic Sequences in Recursive Form, cont.
If given two, non-sequential terms
1. Solve for d
d = difference in the value of the terms
difference in the number of terms
2. Substitute d into the recursive formula
Example #1
Find the recursive formula u3 = 13 and u7 = 37
Example #2
Find the recursive formula u2 = –5 and u7 = 30
Example #3
Find the recursive formula u4 = –43 and u6 = –61
Your TurnFind the recursive formula:
1. u3 = 53 and u5 = 71 2. u2 = -7 and u5 = 8
3. u3 = 1 and u7 = -43
Explicit Form
The explicit form of a sequence tell you the relationship between the 1st term and any other term.
un = u1 + (n – 1)d n ≥ 1
common difference
Summary: Recursive Form vs. Explicit Form
Recursive Form
un = un–1 + d n ≥ 2
Sequential Terms
Explicit Form
un = u1 + (n – 1)d n ≥ 1
1st Term and Any Other Term
Writing Arithmetic Sequences in Explicit Form
You need to know u1 and d!!! Substitute the values into the explicit formula
1. u1 = 5 and d = 2 2. u1 = -4 and d = 5
Writing Arithmetic Sequences in Explicit Form, cont. You may need to solve for u1 and/or d.
1. Solve for d if necessary
2. Back solve for u1 using the explicit formula
u4 = 12 and d = 2
Example #2
u7 = -8 and d = 3
Example #3
u6 = 57 and u10 = 93
Example #4
u2 = -37 and u7 = -22
Your Turn:
Find the explicit formulas:
1. u5 = -2 and d = -6 2. u11 = 118 and d = 13
3. u3 = 17 and u8 = 92 4. u2 = 77 and u5 = -34
Using Explicit Form to Find Terms Just substitute values into the formula!
u1 = 5, d = 2, find u5
Using Explicit Form to Find Terms, cont.
u1 = -4, d = 5, find u10
Your Turn:
1. u1 = 4, d = ¼ 2. u1 = -6, d = ⅔
Find u8 Find u4
3. u1 = 10, d = -½ 4. u1 = π, d = 2
Find u12 Find u27
Summations Summation – the sum of the terms in a
sequence
{2, 4, 6, 8} → 2 + 4 + 6 + 8 = 20
Represented by a capital Sigma
Summation Notation
k
1nnuSigma
(Summation Symbol)
Upper Bound (Ending Term #)
Lower Bound (Starting Term #)
Sequence
Example #1
4
1nn2
Example #2
3
1n)3n(
Example #3
)2n3(3
1n
Your Turn: Find the sum:
5
1n)7n3(
4
1n)n45(
Your Turn: Find the sum:
5
1n)n37(
4
1n]4)1n(3[
Your Turn: Find the sum:
5
1n
2 )n30(
4
1n)2n(n
Partial Sums of Arithmetic Sequences – Formula #1
Good to use when you know the 1st term AND the last term
k
1nk1n )uu(
2
ku
# of terms
1st term last term
Formula #1 – Example #1Find the partial sum:
k = 9, u1 = 6, u9 = –24
Formula #1 – Example #2Find the partial sum:
k = 6, u1 = – 4, u6 = 14
Formula #1 – Example #3Find the partial sum:
k = 10, u1 = 0, u10 = 30
Your Turn:
Find the partial sum:
1. k = 8, u1 = 7, u8 = 42
2. k = 5, u1 = –21, u5 = 11
3. k = 6, u1 = 16, u6 = –19
Partial Sums of Arithmetic Sequences – Formula #2
Good to use when you know the 1st term, the # of terms AND the common difference
k
1n1n d
2
)1k(kkuu
# of terms
1st term common difference
Formula #2 – Example #1Find the partial sum:
k = 12, u1 = –8, d = 5
Formula #2 – Example #2Find the partial sum:
k = 6, u1 = 2, d = 5
Formula #2 – Example #3Find the partial sum:
k = 7, u1 = ¾, d = –½
Your Turn:
Find the partial sum:
1. k = 4, u1 = 39, d = 10
2. k = 5, u1 = 22, d = 6
3. k = 7, u1 = 6, d = 5
Choosing the Right Partial Sum Formula
Do you have the last term or the constant difference?
k
1n1n d
2
)1k(kkuu
k
1nk1n )uu(
2
ku
Examples Identify the correct partial sum formula:
1. k = 6, u1 = 10, d = –3
2. k = 12, u1 = 4, u12 = 100
Your Turn: Identify the correct partial sum formula
and solve for the partial sum
1. k = 11, u1 = 10, d = 2
2. k = 10, u1 = 4, u10 = 22
3. k = 16, u1 = 20, d = 7
4. k = 15, u1 = 20, d = 10
5. k = 13, u1 = –18, u13 = –102