INSTRUCTIONSQMB3200APPLICATION OF QUANTITATIVE METHODS IN BUSINESSInclude the name of students who participated in completing the assignmentINTERIM ASSIGNMENTProf. Gladys E. SimpsonName1Bruna Gomes

This assignments can be completed individually or in groups of up to 3 students.2Kathy CortezEach student is REQUIRED to submit a copy of the excel file and 3Michael Alvarezrespond to the questions on Blackboard.Students who do not submit the assignment and questionsWILL NOT receive a gradeThe questions on blackboard require individually prepared remarksabout the assignment results and also a peer evaluation of other group members. All submissions must include excel attachment.This excel file contains several worksheets that have specific questions (10 total).You can add additional worksheets if you need to include supplemental material.to support your answersView Instructions / video demo

ANSWER-SHEETTHIS WORKSHEET WILL BE USED FOR AUTOMATED GRADING OF YOUR ANSWERS (Except graphs), BE SURE THAT ALL SECTIONS HAVE ANSWERSYou cannot write directly on this worksheet, your responses on the corresponding worksheets have been imported automatically as long as you have left them in the cells marked for that end.GenderClassLevelAgeGPAFBMinutesFBFriendsQUESTION 1Type of VariableQualitativeQualitativeQuantitativeQuantitativeQuantitativeQuantitativeLevel of MeasurementNominalOrdinalIntervalRatioRatioRatio

FreshmanSophmoreJuniorSeniorQUESTION 2# students8697

FREQUENCYPROBABILITYQUESTION 3 & 5FreshmanSophmoreJuniorSeniorFreshmanSophmoreJuniorSeniorFemale31440.10.03333333330.13333333330.1333333333Male55530.16666666670.16666666670.16666666670.1TOTAL86970.26666666670.20.30.2333333333

QUESTION 6ItemABCDProbability0.3750.16666666670.33333333330.2333333333

QUESTION 7AgeTest Statistic-2.1229168974Gender#AverageStd DevPvalue0.0427359527Female1220.751.4847711792conclusion 5%There is a statisically significant difference between the mean AGE of Female and Male studentsMale1822.33333333332.5895718474Total3021.72.3215630882Conclusion 10%There is a statisically significant difference between the mean AGE of Female and Male students

QUESTION 8FBFriendsTest Statistic3.9782580113Gender#AverageStd deviation'Pvalue0.0002227089Female12296.6666666667147.0728535197conclusion 5%There is significante evidence that Avg FBFriends for Female students is greater than for MaleMale18121.777777777848.3827333755Total30191.7333333333131.0369606541Conclusion 10%There is significante evidence that Avg FBFriends for Female students is greater than for Male

QUESTION 9Point estimate FBTimeMargin of Error 95% CI95% Confidence IntervalSample Size Requ ( 10 min Error)161.851077737634.4752701259127.3758076117196.3263478636328

QUESTION 10Is there relationship ?THERE IS NO STRONG RELATIONSHIPR square0.0084EquationGPA = 2.5226+0.0009*Fbminutes

DATAThe data below is fictitious and has been created using formulas to generate differentClass LevelsGendervalues for each column of data for each file. 1Freshman1FemaleYou Need to Copy and Paste the VALUES below BEFORE analyzing the data2Sophmore2Maleto create your own version of the dataset.3Junior(All students will have different versions of this data)4SeniorDATAStudent#GenderClassLevelAgeGPAFBMinutesFBFriends1FemaleFreshman223.6798.74329QUESTION 1:Identify the Type of Variables and Levels of Measurement2MaleJunior193.55224.572003FemaleSenior182.34289.13129VariableTypeLevel of Measurement4MaleSophmore203.9051.0899GenderQualitativeNominal5MaleFreshman262.66289.2995ClassLevelQualitativeOrdinal6MaleSenior202.76176.87139AgeQuantitativeInterval7MaleJunior192.8691.9064GPAQuantitativeRatio8MaleFreshman191.65128.94193FBMinutesQuantitativeRatio9FemaleJunior223.5535.70129FBFriendsQuantitativeRatio10MaleSophmore262.36124.9810411FemaleSenior203.52299.72432Question 2. Create a Pie Chart to illustrate the distribution of the variable "ClassLevel"12MaleJunior233.04260.8890Make sure your graph has appropriate title and labels.13MaleFreshman243.96253.24149Font size should be readable. Display % and Category Name (Class level) on each Slice.14MaleJunior223.70288.979015FemaleSenior222.5532.10412Class Level# of Students16FemaleJunior211.86100.24421Freshman817FemaleSophmore191.34209.54115Sophmore618FemaleJunior213.3789.48119Junior919FemaleSenior211.20164.36485Senior720MaleSophmore252.7744.608021MaleSophmore192.7384.7717722FemaleFreshman211.1568.6618823MaleSenior233.5597.166024MaleSophmore221.85294.8910025MaleFreshman261.4192.1518326FemaleFreshman232.18298.8041027MaleJunior243.48250.9417828MaleSenior243.04200.345529FemaleJunior191.32118.1639130MaleFreshman212.6095.32136

Pivot tableFrequency Problem SheetCount of AgeColumn LabelsAge SheetRow LabelsFemaleMaleGrand TotalRow LabelsCount of AgeAverage of AgeStdDev of Age2Freshman358Female12.0020.751.48Junior459Male18.0022.332.59Senior437Grand Total30.0021.702.32Sophmore156Grand Total121830Friends SheetRow LabelsCount of FBFriendsAverage of FBFriends2StdDev of FBFriends3Female12.00296.67147.07Male18.00121.7848.38Grand Total30.00191.73131.04

FREQUENCY-PROBQUESTION 3: Create a frequency table for the variables gender and class levelQUESTION 5: Create a probability table for the distribution of gender and class level

Class LevelFemaleMaleTotalClass LevelFemaleMaletotalFreshman358Freshman0.100.170.27Sophmore156Sophmore0.030.170.20Junior459Junior0.130.170.30Senior437Senior0.130.100.23Total121830total0.400.601.00QUESTION 4:Illustrate the distribution of these two variables by creating a graph QUESTION 6:Answer the following questions based on your results.that includes both variables in a single Bar graph or Column graphAIf a random student is selected and it's a freshman, what is the probability that it is a female ?Answer A0.375

BIf a random student is selected, what is the probability that the student is a male sophmore ?Answer B0.17

CWhat proportion of female students are juniors ?Answer C0.3333333333

DWhat is the percentage of Seniors in the sample ?Answer D23%

AGEAssuming this data represents a random sample of all US college students, Use an appropriate statistical inference procedure from the ones we've studied so answer the questions below based on this sample.

QUESTION 7Is there evidence of a statistically significant difference in the mean age of female and male US college students ?Use significance level alpha=5%. Is the conclusion the same using signficance level 10% ? Comment on your resultsInclude a copy of all work, including pivot tables and/ or templates used. Templates can be included as an image or the actual worksheets.AgeGender#AverageStd DevFemale1220.751.48Male1822.332.59Total3021.702.32

Test Statistic(2.12)P-VALUE0.04274

Conclusion For 5% significanceThere is a statisically significant difference between the mean AGE of Female and Male studentsConclusion For 10% significanceThere is a statisically significant difference between the mean AGE of Female and Male students

CommentsP-value is smaller than significance level for both 5% and 10% significance level so we are rejecting the null hypothesis and thus the conclusion.

FRIENDSAssuming this data represents a random sample of all US college students, Use an appropriate statistical inference procedure from the ones we've studied so answer the questions below.

QUESTION 8Based on this sample, is the average number of Facebook friends of female students greater than that of male students ?Use significance level alpha=5%. Is the conclusion the same using significance level alpha = 10% ? Comment on your resultsInclude a copy of all work, including pivot tables and/ or templates used. Templates can be included as an image or the actual worksheets.FBFriendsGendernMeanStd deviationFemale12296.67147.07Male18121.7848.38Total30191.73131.04

Test Statistic3.98P-VALUE0.00022Conclusion For 5% significanceThere is significante evidence that Avg FBFriends for Female students is greater than for Male

Conclusion For 10% significanceThere is significante evidence that Avg FBFriends for Female students is greater than for Male

CommentsAs the p-value is smaller than significance level for both the significance levels thus we are rejecting the null hypothesis.

TIMEAssuming this data represents a random sample of all US college students, Use an appropriate statistical inference procedure from the ones we've studied so answer the questions below based on this sample.

QUESTION 9aProvide a point estimate and a 95% confidence interval for the average time spent on facebook by US college students.Comment on your resultsInclude a copy of all work, including pivot tables and/ or templates used. Templates can be included as an image or the actual worksheets.Point Estimate of the Average time spent on Facebook161.85Margin of Error for 95% confidence interval34.475270125995% Confidence Interval for Avg Time Spent on Facebook127.38to196.33QUESTION 9b If we wanted to estimate the 95% confidence interval above with a margin of error of ten minutes.How many students should we have in our sample ?Number of students328

REGRESSIONWe will be studying linear regression in subsequent weeeks. However, for now we will do some preliminary explorationbased on the data we have to analyze the relationship between two variables.

QUESTION 10Create a Scatterplot by selecting the FBMinutes and GPA variables. Select the points on the scatterplot and insert a "trendline"Display the regression equation and the value of R-square. Is there a strong relationship between the variables ?StudentFBMinutesGPA198.743.67Answer : THERE IS NO STRONG RELATIONSHIP2224.573.553289.132.34R-square0.0084Regression Equation :GPA = 2.5226+0.0009*Fbminutes451.083.905289.292.666176.872.76Include Graph Below. Add proper title and axis labels 791.902.868128.941.65935.703.5510124.982.3611299.723.5212260.883.0413253.243.9614288.973.701532.102.5516100.241.8617209.541.341889.483.3719164.361.202044.602.772184.772.732268.661.152397.163.5524294.891.852592.151.4126298.802.1827250.943.4828200.343.0429118.161.323095.322.60