Induction Motor Presentation
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INDUCTION MOTOR
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What is Induction Motor?
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PARTS AND ITS FUNCTION
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The Stator and the Rotor are each made up of:
An electric circuit(insulated copper or aluminum)
A magnetic circuit
(laminated steel)
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STATOR
Stationary electrical part of the motor Made up of several thin laminations of aluminum
or cast iron
Sometimes referred to as the windings
Consists of poles carrying supply current to
induce a magnetic field that penetrates the rotor
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The Stator
The stator is the outer stationary part ofthe motor
The Stator is consists of:
The ou ter cyl ind r ical frame of the moto r
The magnet ic path
A set of insu lated electr ical w ind ings
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The Stator
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Stator coil
The stator coils are the copper wiresembedded into the stator of the induction
motor.
The current flows into these wires toproduce a magnetic field making the rotor
of the motor rotate in one direction.
The direction of the mmf depends uponthe instantaneous current flows and using
the right hand rule.
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Three phase motor
The three phase induction motors are themotors mostly frequently encountered in
industry.
They run at essentially constant speedfrom zero to full-load.
The speed is frequency-dependent and,
consequently, these motors are not easilyadapted to speed control.
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The only way to solve theproblem of the singlephase is to build a 2-phase motor, derivingpower from single phase.
This requires a motor withtwo windings spacedapart 90 electrical, fedwith two phases ofcurrent displaced 90 in
time. This is called a
permanent-split capacitormotor.
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ROTOR
Rotating part of theelectromagnetic circuit
Most common type of rotor is
the squirrel cage
Consist of a group ofelectromagnets arranged
around a cylinder with a poles
facing towards the stator
poles
Located inside the stator
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The AC Induction Motor comprises 2
Electromagnetic Parts
Stationary part called the stator Rotating part called the rotor
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The Rotor
The Rotor is the rotating part of the motor constructed of copper or aluminum strips
consists of a set of slotted steel
laminations The electrical circuit of the rotor can be
either:
Wound rotor type
Squirrel cage roto r type
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The Rotor
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BEARING
Hold the rotating shaft to the motor frame support the rotor and allow it to turn
Common bearings are the sleeve type and
the ball type
Lubricated with oil
Bearing
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Bearing
the purpose of bearing is they avoid thedirect contact between the outer and innersurface and thus reducing the friction andthe given power can be used economical
The shaft is mounted onthe bearing so it canrotate freely.
Ball Bearing
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Bearing Lubrication
Reduce friction
Reduce Transfer heat
Carry away contaminants
and debris
Protect against wear Prevent corrosion
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FRAME
Holds all the parts in place
Provides a means of mounting
the motor to machinery
Conducts heat produced within
the motor to the surrounding air Protects the electrical and
operating parts of the motor
from harmful effects of the
environment in which the motoroperates
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FORMULAS
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Other Parts
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ADVANTAGES AND DISADVANTAGES
Advantages Simple and rugged in construction
Cheaper in cost due to the absence
of brushes, commutators, and slip
rings
They are maintenance free motors
unlike dc motors and synchronousmotors due to absence of brushes,
commutators and slip rings
Can be operated in polluted and
explosive environments as they do
not have brushes which can cause
sparks 3 phase induction motors will have
self starting torque, hence no
starting methods are employed
unlike synchronous motor
Disadvantages 3 phase induction motors have poor
starting torque and high in rush
current
They always operate under lagging
power factor and during light load
conditions they operate at veryworst power factor.
Hence capacitor banks should be
placed to deliver the reactive power
Speed control of induction motors
are difficult, hence for fine speed
control applications dc motors areused. Due to advance in power
electronics, variable frequency
drives using induction motors are
used in industries for speed control
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AC electric induction motors(Efficiencies)
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Definition of energy efficiency
Efficiency is the ratio of mechanical energyoutput divided by the electrical energy
input. There are different efficiency
definitions
that describe the relationship between a
motors rating and
efficiency test results
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Electrical Motor Efficiency when ShaftOutput is measured in Watt
If power output is measured in Watt(W), efficiency can be expressed as:
m=Pout/ PinWhere:
m= motorefficiency
Pout= shaft power out (Watt, W)Pin= electric power in to the motor (Watt,
W)
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Electrical Motor Efficiency when ShaftOutput is measured in Horsepower
If power output is measuredin horsepower (hp), efficiency can be
expressed as:m=Pout746 / Pin
Where:
Pout= shaft power out (horsepower, hp)Pin= electric power in to the motor (Watt,W)
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Minimum Nominal Efficiencies
Power
(hp) Minimum Nominal Efficiency1)
1 - 4 78.8
5 - 9 84.0
10 - 19
85.5
20 - 49 88.5
50 - 99 90.2
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1 - 4 78.8
5 - 9 84.0
10 - 19 85.5
20 - 49 88.5
50 - 99 90.2
100 - 124 91.7
> 125 92.4
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Several more innovative approaches toimproving efficiency are currently being
attempted in the industry. For induction
motors, the most notable change is the
move from cast aluminum rotors to cast
copper rotors. This can raise efficiency by
about 1% at three horsepower (3 hp).
However, the cost of cast copper rotors isa significant factor.
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Aluminum Vs Copper
Lower coefficient of expansion for copper:aluminium will creep and move approximately33% more than copper.
Higher tensile strength for copper: copper is
300% stronger than aluminium and thus ableto withstand high centrifugal force and therepeated hammering from currentinducedforces during each start.
Higher melting point of copper: copper canbetter withstand thermal cycling over the lifeof the motor.
Losses that may affect the
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Losses that may affect the
efficiency of an induction motor Primary and Secondary Resistance Losses
The electrical power lost in the primary rotorand secondary stator winding resistance are alsocalled copper losses. The copper loss varies withthe load in proportion to the current squared - and
can be expressed as
Pcl= R I2
Where:
Pcl= stator winding - copper loss (W)R= resistance ()
I = current (Amp)
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Iron LossesThese losses are the result of magnetic energy
dissipated when when the motors magnetic field
is applied to the stator core.
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Stray Losses
Stray losses are the losses that remains afterprimary copper and secondary losses, iron
losses and mechanical losses. The largestcontribution to the stray losses is harmonicenergies generated when the motor operatesunder load. These energies are dissipated as
currents in the copper windings, harmonic fluxcomponents in the iron parts, leakage in thelaminate core.
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Mechanical LossesMechanical losses includes friction in the motor
bearings and the fan for air cooling.
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ENDppt made by:
Capuno, Charles Brian C.