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    CHEMISTRY

    SECTION I

    Single Correct Choice Type

    This section contains 9 single correct choice type questions. Each question has 4 choices: (a),

    (b), (c) and (d) for its answer, out of which ONLY ONEis correct.

    1. The energy of the second Bohr orbit in the hydrogen atom is 3.41 eV. The energy of the

    second Bohr orbit of He+ion would be

    (a) 0.85 eV (b) 13.64 eV

    (c) 1.70 eV (d) 6.82 eV

    2. Which of the following statement for crystals having Frenkel defect is not correct?

    (a) Frenkel defects are observed where the difference in sizes of cations and anions is large.

    (b) The density of crystals having Frenkel defect is lesser than that of a pure perfect crystal.

    (c) An ionic crystal may have Frenkel defect along with the Schottky defect.(d) Pure alkali halides do not have Frenkel defect.

    3. The lattice energy of solid NaCl is 180 kcal/mol. The dissolution of the solid in water in the

    form of ions is endothermic to the extent of 1 kcal/mol. If the solution energies of Na+and Cl

    are in the ratio 6 : 5, what is the enthalpy of hydration of Na+ion?

    (a) 85.6 kcal mol1 (b) 97.6 kcal mol

    1

    (c) 82.6 kcal mol1 (d) +100 kcal mol

    (a)

    1

    4. Amongst the following carboxylic acids, the strongest acid is (for first dissociation of

    dicarboxylic acid)

    C CHOOC H

    COOHH(b) C C

    HH

    COOHHOOC

    (c) CH3CH2COOH (d) CH3COOH

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    5. C=NPh

    CH3 OH

    ..

    on treatment with acid followed by hydrolysis yields

    (a) CH3COH andNH2

    O

    (b) and CH3CH2NH2C

    OH

    O

    (c) and HCOHCH2NH2

    O

    (d)CH2COH and CH3NH2

    O

    6. The product (X) in the following reaction is

    CH3

    O + one equivalent of HI

    (X)

    (a) I

    OH

    CH3

    (b) O

    CH2l

    (c) OH

    CH2l

    CH3

    (d) I

    CH2l

    CH3

    7. The mechanism of ester formation in acidic medium is as follows.

    RCOH

    OH+

    RCOH RCOHStep (i)

    HO+ HO+ROH; H+

    RCOHHO

    OR

    H+

    Step (iii)Step (ii)RCOHHOH

    OR

    H2O

    Step (iv)

    +

    RCORH+

    Step (v)

    HO+

    RCOR

    O

    +

    The slowest step in the above mechanism is

    (a) Step (i) (b) Step (ii)

    (c) Step (iii) (d) Step (iv)

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    8. PCl3and PCl5both exist but only PH3exists while PH5does not exist. This is because

    (a) H is less electronegative than P.

    (b) the activation energy for the formation of PH5is very high.

    (c) PH5 immediately decomposes to PH3 and H2 as its equilibrium constant for the

    decomposition is very high.

    (d) Cl is more electronegative than P while it is not so for H and P.

    9. A galvanic cell is composed of two hydrogen electrodes, of which cathode is a standard

    hydrogen electrode. In which of the following solutions should the other half cell be

    immersed to get maximum EMF?

    (a) 0.1 M C6H5CO2H (b) 0.1 M CH3CO2H

    (c) 0.1 M HCO2H (d) 0.1 M H2C2O

    SECTION II

    4

    Multiple Correct Choice Type

    This section contains 4 multiple correct choice type questions. Each question has

    4 choices: (a), (b), (c) and (d) for its answer, out of which ONE OR MOREis/ are correct.

    10. Which of the following heterocyclic compound would not have aromatic character?

    (a)N

    N(b)

    NHN(c)

    NH

    NH(d) NH

    N

    11. The difference in properties of CH4and SiH4is due to

    (a) large difference in the electronegativity of carbon and silicon

    (b) large difference in size of carbon and silicon atoms

    (c) the inability of carbon to expand its octet(d) the inability of silicon to form double bonds

    12. On mixing 1 mole of C6H6(P = 42 mm Hg) and 2 mole of C7H8(P = 36 mm Hg), one can

    conclude that

    (a) total vapour pressure of mixture is 38 mm Hg.

    (b) mole fraction of C6H6in vapour state above liquid mixture is 7/19.

    (c) solution would show positive deviation from Raoults law.

    (d) ideal solution is formed.

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    13. 0.1 mole of 4MnO in acidic medium can oxidize

    (a) 0.5 mole of Fe+2 (b) 0.167 mole of FeC2O2

    42OC4

    (c) 0.25 mole of (d) 0.60 mole of 272OCr

    SECTION IIIReasoning Type

    This section contains 3 reasoning type questions numbered 14 to 16. Each question contains

    Statement-1 and Statement-2. Each question has 4 choices (a), (b), (c) and (d), out of which

    ONLY ONEis correct.

    Directions: Read the following questions and choose

    (A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for

    Statement-1.

    (B) Statement-1is True, Statement-2is True; Statement-2is not a correct explanation for

    Statement-1.(C) Statement-1is True, Statement-2is False.

    (D) Statement-1is False, Statement-2is True.

    14. Statement 1 : 3dxy, 4dxy, 5dxy all are having the same shape i.e., the double dumb bell.

    Statement 2 : The size of orbitals are independent of the principal quantum number.

    (a) A (b) B (c) C (d) D

    15. Statement 1 : Chloroform, bromoform and iodoform all form at the same rate in the alkaline

    medium from acetone.

    Statement 2 : Cl2, Br2and I2all are having same electrophilicity.

    (a) A (b) B (c) C (d) D

    16. Statement 1 : The addition of one equivalent of HCl on CH2= CHC CH takes place on

    C C bond and not on C = C bond.

    Statement 2 : The product is a conjugated diene which is more stable.

    (a) A (b) B (c) C (d) D

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    SECTIONIVMatrixMatch Type

    This section contains 2 questions. Each question contains statements given in two columns,

    which have to be matched. The statements in Column Iare labelled A, B, Cand D, while the

    statements in Column IIare labelled 1, 2, 3, 4 and 5. Any given statement in Column Icanhave correct matching with ONE OR MORE statement(s) in Column II. The appropriate

    bubbles corresponding to the answers to these questions have to be darkened as illustrated in

    the following example:

    If the correct matches are A 1, 4 and 5; B 2 and 3; C 1 and 2; and D 4 and 5; then the

    correct darkening of bubbles will look like the following.

    A 1 2 3 4

    1 2 3 4

    1 2 3 4

    1 2 3 4

    B

    C

    D

    1 2 3 45

    5

    5

    5

    5

    1.

    Column I Column II

    (A) 2p 1. n = 2x

    (B) 2s 2. no radial node is present

    (C) 2p 3. l= 0z

    (D) 3p 4. l= 1y

    5. are perpendicularly aligned

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    2.

    Column I Column II

    (A)

    CH3

    O1. No geometrical isomer on treatment with NH2OH, H

    +

    (B) = O 2. Racemisation on treatment with aqueous H+/OH

    (C) CH2 3. Michael addition with CH=CHCH=O 2(COOEt)2, EtO

    (D)

    CH3

    O

    4. Condensation with PhCHO, HO

    5. Molecule shows resonance