Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the...

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Horn’s problem, and Fourier analysis Horn’s problem, and Fourier analysis Jacques Faraut Symmetries in Geometry, Analysis, and Spectral Analysis, on the occasion of Joachim Hilgert’s 60th birthday Paderborn, July 26, 2018

Transcript of Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the...

Page 1: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Horn’s problem, and Fourier analysis

Jacques Faraut

Symmetries in Geometry, Analysis, and Spectral Analysis,on the occasion of Joachim Hilgert’s 60th birthday

Paderborn, July 26, 2018

Page 2: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Horn’s problem, and Horn’s conjecture

A and B are n × n Hermitian matrices, and C = A + B.Assume that the eigenvalues α1 ≥ · · · ≥ αn of A,and the eigenvalues β1 ≥ · · · ≥ βn of B are known.Horn’s problem : What can be said about the eigenvalues γ1 ≥ · · · ≥ γnof C = A + B ?

Weyl’s inequalities (1912)

γi+j−1 ≤ αi + βj for i + j ≤ n + 1,γi+j−n ≥ αi + βj for i + j ≥ n + 1.

Horn’s conjecture (1962) The set of possible eigenvalues γ1, . . . , γn forC = A + B is determined by a family of inequalities of the form∑

k∈K

γk ≤∑i∈I

αi +∑j∈J

βj ,

for certain admissible triples (I , J,K ) of subsets of {1, . . . , n}.Klyachko has proven Horn’s conjecture,and described these admissible triples (1998).

Page 3: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

n = 3, α = (3.5, 1.4,−4.9), β = (2,−0.86,−1.14).

Weyl’inequalities gives

a1 ≤ γ1 ≤ b1

a2 ≤ γ2 ≤ b2

a3 ≤ γ3 ≤ b3

In the planex1 + x2 + x3 = 0,

these inequalities determine a hexagon.

Page 4: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

(εij = ei − ej)

α + β

α

ε12

ε23 ε13

Page 5: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

One observes that the vertices of this hexagon are the points α + σ(β)(σ ∈ S3). This is a special case of the following

Theorem (Lidskii-Wielandt) The set H(α, β) of possibleγ = (γ1, . . . , γn) satisfies

H(α, β) ⊂ α + C (β),

where C (β) is the convex hull of the points σ(β) (σ ∈ Sn).

Page 6: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

We consider Horn’s problem from a probabilistic viewpoint.The set of Hermitian matrices X with spectrum {α1, . . . , αn}is an orbit Oα for the natural action of the unitary group U(n):X 7→ UXU∗ (U ∈ U(n)).Assume thatthe random Hermitian matrix X is uniformly distributed on the orbit Oα,and the random Hermitian matrix Y uniformly distributed on Oβ .

What is the joint distribution of the eigenvalues of the sum Z = X + Y ?

This distribution is a probability measure on Rn that we will determineexplicitly.

Page 7: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Orbits for the action of U(n) on Hn(C)Spectral theorem : The eigenvalues of a matrix A ∈ Hn(C) are realand the eigenspaces are orthogonal.The unitary group U(n) acts on Hn(C) by the transformations

X 7→ UXU∗

For A = diag(α1, . . . , αn), consider the orbit

Oα = {UAU∗ | U ∈ U(n)}, α = (α1, . . . , αn) ∈ Rn.

By the spectral theorem

Oα ={

X ∈ Hn(C) | spectrum(X ) = {α1, . . . , αn}}

Page 8: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Orbital measures

The orbit Oα carries a natural probability measure:the orbital measure µα,image of the normalized Haar measure ω of the compact group U(n)by the map U 7→ UAU∗. For a function f on Oα,∫

f (X )µα(dX ) =

∫U(n)

f (UAU∗)ω(dU).

A U(n)-invariant measure µ on Hn(C) can be seenas an integral of orbital measures:it can be written∫

Hn(C)f (X )µ(dX ) =

∫Rn

(∫U(n)

f (Udiag(t1, . . . , dtn)U∗)ω(dU))ν(dt),

where ν is a Sn-invariant measure on Rn, called the radial part of µ.

Page 9: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

If µ is a U(n)-invariant probability measure,and X a random Hermitian matrix with law µ,then the joint distribution of the eigenvalues of Xis the radial part ν of µ.

Assume that the random Hermitian matrix X is uniformly distributedon the orbit Oα, i.e. with law µα,and Y uniformly distributed on Oβ , i.e. with law µβ ,then the law of the sum Z = X + Y is the convolution product µα ∗ µβ ,and the joint distribution of the eigenvalues of Zis the radial part να,β of the measure µ = µα ∗ µβ .

Hence the problem is to determine this radial part να,β .

Page 10: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Fourier-Laplace transform

For a bounded measure µ on Hn(C),

Fµ(Z ) =

∫Hn(C)

etr (ZX )µ(dX ).

If µ is U(n)-invariant, then Fµ is U(n)-invariant as well, and hencedetermined by its restriction to the subspace of diagonal matrices.

For Z = diag(z1, . . . , zn), T = diag(t1, . . . , tn), define

E(z , t) :=

∫U(n)

etr (ZUTU∗)ω(dU).

Then Fµα(Z ) = E(z , α).

Page 11: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

If µ is U(n)-invariant,

Fµ(Z ) =

∫Rn

E(z , t)ν(dt),

where ν is the radial part of µ.

Taking µ = µα ∗ µβ ,

E(z , α)E(z , β) =

∫Rn

E(z , t)να,β(dt).

Page 12: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

This is the product formula of the spherical functions for the Gelfand pair(G ,K ).

G = U(n) nHn(C), K = U(n).

The group G acts on Hn(C) by the transformations

g · X = UXU∗ + A(g = (U,A)

).

The spherical functions are given by

ϕz(g) = E(z , t),

where t1, . . . , tn are the eigenvalues of the matrix g · 0. They satisfy thefunctional equation:∫

K

ϕz(g1Ug2)ω(dU) = ϕz(g1)ϕz(g2) (g1, g1 ∈ G ).

With the identification

ϕz(g1) = E(z , α), ϕz(g2) = E(z , β),

the functional equation becomes

E(z , α)E(z , β) =

∫Rn

E(z , t)να,β(dt).

Page 13: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Harish-Chandra-Itzykson-Zuber formula

A is an Hermitian matrix with eigenvalues α1, . . . , αn,and B with eigenvalues β1, . . . , βn.∫

U(n)

etr (AUBU∗)ω(dU) = δn!1

Vn(α)Vn(β)det(eαiβj

)1≤i,j≤n

Vn is the Vandermonde polynomial: for x = (x1, . . . , xn),

Vn(x) =∏i<j

(xi − xj)

and

δn = (n − 1, n − 2, . . . , 2, 1, 0), δn! = (n − 1)!(n − 2)! . . . 2!

Page 14: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Heckman’s measure

Consider the projection q : Hn(C)→ Dn onto the subspace Dn of realdiagonal matrices.Horn’s theorem The projection q(Oα) of the orbit Oα is the convex hullof the points σ(α)

q(Oα) = C (α) := Conv({σ(α) | σ ∈ Sn})

(σ(α) = (ασ(1), . . . , ασ(n)))

Heckman’s measure is the projection Mα = q(µα)of the orbital measure µα.It is a probability measure on Rn, symmetric, i.e. Sn-invariant,with compact support: support(Mα) = C (α).

Page 15: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Fourier-Laplace transform of a bounded measure M on Rn:

M(z) =

∫Rn

e(z|x)M(dx)

The Fourier-Laplace transform of Heckman’s measure Mα

is the restriction to Dn of the Fourier-Laplace transformof the orbital measure µα:for Z = diag(z1, . . . , zn),

Mα(z) = Fµα(Z )

Therefore Mα(z) = E(z , α),and by the Harish-Chandra-Itzykson-Zuber formula,

Mα(z) = δn!1

Vn(z)Vn(α)det(eziαj

)1≤i,j≤n

Page 16: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Define the skew-symmetric measure

ηα =δn!

Vn(α)

∑σ∈Sn

ε(σ)δσ(α)

(ε(σ) is the signature of the permutation σ).Fourier-Laplace of ηα:

ηα(z) =δn!

Vn(α)

∑σ∈Sn

ε(σ)e(z|σ(α)) =δn!

Vn(α)det(eziαj )1≤i,j≤n

By the Harish-Chandra-Itzykson-Zuber formula

ηα(z) = Vn(z)Mα(z).

Proposition

Vn

(− ∂

∂x

)Mα = ηα

Page 17: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Elementary solution of Vn

(∂∂x

)Proposition Define the distribution En on Rn

〈En, ϕ〉 =

∫R

n(n−1)2

+

ϕ(∑

i<j

tijεij)

dtij

(εij = ei − ej) Then

Vn

( ∂∂x

)En = δ0.

Proof: An elementary solution of the first order differential operator∂∂xi− ∂

∂xjis the Heaviside distribution

〈Yij , ϕ〉 =

∫ ∞0

ϕ(tεij)dt

Hence

En =∗∏

i<j

Yij

is an elementary solution of Vn

(∂∂x

).

Page 18: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Theorem

Mα = En ∗ ηα(ϕ(x) = ϕ(−x), 〈En, ϕ〉 = 〈En, ϕ)Heckman’s measure Mα is supported by the hyperplanex1 + · · ·+ xn = α1 + · · ·+ αn.

Next figure is for n = 3,drawn in the plane x1 + x2 + x3 = α1 + α2 + α3.

Page 19: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

(α1, α2, α3)(α2, α1, α3)

(α3, α1, α2)

(α3, α2, α1) (α2, α1, α3)

(α1, α3, α2)

ε12

ε23 ε13

Page 20: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

The radial part να,βRecallX is a random Hermitian matrix on Oα with law µα,and Y on Oβ with law µβ .The joint distribution of the eigenvalues of Z = X + Y is the radial partνα,β of µα ∗ µβ .Theorem

να,β =1

n!

1

δn!Vn(x)ηα ∗Mβ

=1

n!

1

δn!

Vn(x)

Vn(α)

∑σ∈Sn

ε(σ)δσ(α) ∗Mβ .

The sum has positive and negative terms.However να;β is a probability measure on Rn.The measure να,β is symmetric (invariant by Sn).

Page 21: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

This theorem can be seen as a special case of a result by Graczyk andSawyer (2002).A similar result, but slightly different, is given by Rosler (2003).

Page 22: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

The set of possible systems of eigenvalues for the sum Z = X + Y is

S(α, β) = support(να,β)

The proof amounts to check that the measure

ν =1

n!

1

δn!Vn(x)ηα ∗Mβ

satisfies the relation∫Rn

E(z , t)ν(dt) = E(z , α)E(z , β)

Next figure is for n = 3, α = (3, 0,−3), β = (1, 0,−1)

Page 23: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

α

β

α + β

ε = +1 ε = −1

Page 24: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Next figure is for n = 3, α = (3, 0,−3), β = (2, 0,−2)

Page 25: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

α

β

α + β

ε = +1 ε = −1ε = +1 ε = −1

Page 26: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

In the first case the condition

sup |βi − βj | < infi 6=j|αi − αj |

is satisfied, and, under that condition,

H(α, β) = S(α, β) ∩ Cn = α + C (β)

where Cn is the chamber

Cn = {x1 > x2 > · · · > xn}.

In the second case the condition is not satisfied. There are cancellationsand the situation is more complicated.

Page 27: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Page 28: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

Relation to representation theory

πλ irreducible representation of U(n) with highest weight λ,λ = (λ1 ≥ · · · ≥ λn) (λi ∈ Z).

Littlewood-Richardson coefficients cγα,β :

πα ⊗ πβ =∑γ

cγα,βπγ .

Theorem cγα,β 6= 0 if and only if γ ∈ H(α, β);i.e. there exist n × n Hermitian matrices A,B,C with C = A + B, the αi

are the eigenvalues of A, the βi of B, the γi of C .

(Klyachko, 1998; Knutson, Tao, 1999)

Page 29: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

In the case of the space of real symmetric matrices Hn(R),with the action of the orthogonal group O(n), for n ≥ 3,we don’t know any explicit formula for Heckman’s measure,and for the measures να,β .This setting is natural, however the problem is more difficultthat in the case of the space of Hermitian matrices,and one should not expect any explicit formula.However the supports should be the same as in the case of Hn(C)with the action of the unitary group U(n), according to Fulton (1998).

Page 30: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

There should be an analogue of our resultsin case of pseudo-Hermitian matrices.In this setting, an analogue of Horn’s conjecture has been established byFoth (2010).An analogue of our result could probably be obtained by using a formulafor the Laplace transform of an orbital measurefor the action of the pseudo-unitary group U(p, q)on the space Hn(Cn) (n = p + q).This formula is due Ben Saıd and Ørsted (2005).

Page 31: Horn’s problem, and Fourier analysis · Horn’s problem, and Fourier analysis In the case of the space of real symmetric matrices H n(R), with the action of the orthogonal group

Horn’s problem, and Fourier analysis

More generally one could consider Horn’s problemfor the adjoint action of a compact Lie group on its Lie algebra.The Fourier transform of an orbital measure is explicitely givenby the Harish-Chandra integral formula [1957].Heckman’s paper [1982] is written in this framework. One can expectthat there is an analogue of our result in this setting.In particular one can consider the action of the orthogonal groupon the space of real skew-symmetric matrices, as Zuber did (2017).

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Horn’s problem, and Fourier analysis

Bhatia, R. (2001). Algebra to quantum cohomology: the story ofAlfred Horn’s inequalities, Amer. Math. Monthly, 108, 289–318.

Lidskii, V. S. (1950). The proper values of the sum and product ofsymmetric matrices, Doklady Akademi Nauk SSSR, 75, 769–772.

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Knutson, A. & T. Tao (1999). The honeycomb model ofGLn(mathbbC ) tensor products, J. Amer. Math. Soc., 12,1055–1090.

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Horn’s problem, and Fourier analysis

Frumkin, A., & A. Goldberger (2006). On the distribution of thespectrum of the sum of two hermitian or real symmetric matrices,Advances in Applied Mathematicis, 37, 268–286.

Zuber, J.-B. (2017). Horn’s problem and Harish-Chandra’sintegrals. preprint.

Faraut, J. (2018). Horn’s problem, and Fourier analysis. preprint.

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