Homework (lecture 1): Prove the shell theorem for the ...

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Homework (lecture 1): Prove the shell theorem for the electrostatic force 3, 6, 9, 10, 16, 23, 33, 35 (page 575-577)

Transcript of Homework (lecture 1): Prove the shell theorem for the ...

Page 1: Homework (lecture 1): Prove the shell theorem for the ...

Homework (lecture 1): ● Prove the shell theorem for the electrostatic force ● 3, 6, 9, 10, 16, 23, 33, 35 (page 575-577)

Page 2: Homework (lecture 1): Prove the shell theorem for the ...

3. What must be the distance between point charge q1 = 26.0 C and point charge q2 = -47 C for the electrostatic force between them to have a magnitude of 5.70 N?

221

r

qqkF

F

qqkr

21

(m) 39.17.5

)1047)(1026(1099.8 669

r

CC 6101

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6. Two equally charged particles are held 3.2x10-3 m apart and then released from rest. The initial acceleration of the first particle is observed to be 6.0 m/s2 and that of the second to be 9.0 m/s2. If the mass of the first particle is 6.3x10-7 kg, what are (a) the mass of the second particle and (b) the magnitude of the charge of each particle.

1121 amF 2212 amF

:2112 FF 1

2

12 m

a

am

11221

2112 amr

qqkFF

)(106.6

1099.8

102.36103.6 11

9

237211 Ck

ramq

(pC) 66q

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9. Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.108 N when their center-to-center separation is 50.0 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.036 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other? Using the shell theorem: Before: After: the net charge is positive

)(100.3 12212

211 Cqq

r

qqkF

)(100.22 6

212

221

2

2

2 Cqqr

qq

kr

qkF

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The solutions: 1st: 2nd: Note: if the net charge is negative the solutions should be:

0100.3100.2 121

621 qq

)(100.1)(100.3 62

61 CqCq

)(100.3)(100.1 62

61 CqCq

)(100.2 621 Cqq

)(100.3)()(100.1)( 612

621 CqqCqq or or

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10. In the figure as shown, four particles form a square. The charges are q1 = q4 = Q and q2 = q3 = q. (a) What is Q/q if the net electrostatic force on particles 1 and 4 is zero? (b) Is there any value of q that makes the net electrostatic force on each of the four particles zero? explain. (a) q1 & q4 have the same sign, all three forces act on q1

as shown (b) if the net force acting on particle 3 is also zero: this is inconsistent with (a), so the answer is NO

312141 FFF

2141 2FF

83.222

2

2/3

22

2

q

Q

a

qQk

a

Qk

83.2Q

q

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16. See the figure as shown, particle 1 (of charge q1) and particle 2 (of charge q2) are fixed in place on an x axis, 8.0 cm apart. Particle 3 (of charge q3 = +6.0x10

-19 C) is to be placed on the line between particles 1 and 2 so that they produce a net electrostatic force F3,net on it. The diagram gives the x component of that force versus the coordinate x at which particle 3 is placed. What are (a) the sign of charge q1 and (b) the ratio q2/q1? ● at 2 cm: Fnet=0 so 1 and 2 must have the same sign. ● when q3 approaches q1,F13

increases in magnitude. Fnet

increases in the positive x direction, so F13 is a repulsive force, q1 > 0 23

232

132

31

r

qqk

r

qqk

92

622

13

23

1

2

r

r

q

q

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23. See the figure, particles 1 and 2 of charge q1 = q2 = +3.2x10-19 C are on a y axis at distance d = 17.0 cm from the origin. Particle 3 of charge q3 = +6.4x10

-19 C is moved gradually along the x axis from x = 0 to x = +5.0 m. At what values of x will the magnitude of the electrostatic force on the third particle from the other two particles be (a) minimum and (b) maximum? what are the (c) minimum and (d) maximum magnitudes? The net force acting on particle 3:

cos223

r

qqkFnet

r r

xdxr cos;22

2/32232

dx

xkqqFnet

maximum: 2/020 22' dxxdF net

minimum :0 x

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http://www.function-grapher.com/index.php

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33. Calculate the number of coulombs of positive charge in 250 cm3 of (neutral) water. (Hint: A hydrogen atom contains one proton; an oxygen atom contains eight protons) The mass of the sample: The number of moles: The positive charge:

)(2502501 gVm

9.1318

250

molarM

mn

)(1034.1106.11010023.69.13 71923 C

qnNQ A

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35. In crystals of the salt cesium chloride, cesium ions Cs+ form the eight corners of a cube and a chlorine ion Cl- is at the cube’s center. The edge length of the cube is 0.4 nm. The Cs+ ions are each deficient by one electron (and thus each has a charge of +e), and the Cl- ion has one excess electron (and thus has a charge of –e). (a) What is the magnitude of the net electrostatic force exerted on the Cl- ion by the eight Cs+ ions? (b) If one of the Cs+ ions is missing, the crystal is said to have a defect, what is the magnitude of the net force exerted on the Cl- ion by the seven remaining Cs+ ions? (a) The net force is zero due to the symmetric distribution of the eight Cs+ around Cl-

(b) 2

2

17r

ekFF CsCs

nmaaa

r 4.0;2

)2( 22

2

2

7)4/3( a

ekF Cs

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Homework (lecture 2): 1, 5, 14, 15, 19, 23, 27, 31, 35, 44, 54, 56, 59 (page 598-603)

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1. Sketch qualitatively the electric field lines both between and outside two concentric conducting spherical shells when a uniform positive charge q1 is on the inner shell and a uniform negative charge –q2 is on the outer. Consider the cases q1 > q2, q1 = q2, and q1 < q2.

q1 = q2

E=0

E=0

q1 > q2 q1 < q2

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5. What is the magnitude of a point charge whose electric field 50 cm away has the magnitude 2.0 N/C?

2r

qkE

)(106.51099.8

5.02 11

9

22

Ck

Erq

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14. See the figure, particle 1 of charge q1 = -4.0q and particle 2 of charge q2 = +2.0q are fixed to an x axis. (a) As a multiple of distance L, at what coordinate on the axis is the net electric field of the particles zero? (b) Sketch the net electric field lines.

- + E1 E2

22

22

11

Lx

qkE

x

qkE

Lx

x

Lx41.3

4

2

2

2

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15. The three particles are fixed in place and have charges q1 = q2 = +e and q3 = +2e. Distance a = 6.0 m. What are the (a) magnitude and (b) direction of the net electric field at point P due to the particles?

3

21 0

EE

EE

net

3E

2

2;

2

23a

OPOP

ekE

122

199

3100.6

106.141099.8

E

033 45),();/(160 OxECNE

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19. The figure shows an electric dipole. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the dipole’s electric field at point P, located at distance r >> d? • If x>>d: • points in the negative direction of the y axis

32

cos2r

kqd

r

qkEnet

moment dipole electric :qdp

netE

2/3

22

2

xd

kpEnet

3x

kpEnet

netE

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23. The figure shows two parallel nonconducting rings with their central axes along a common line. Ring 1 has uniform charge q1 and radius R; ring 2 has uniform charge q2 and the same radius R. The rings are separated by distance d = 3.0R. The net electric field at point P on the common line, at distance R from ring 1, is zero. What is the ratio q1/q2?

Note: q1 and q2 must have the same sign to produce a net electric field equal to zero

2/3220 )(4 Rz

qzE

2/3222

2/3221

)4(

2

)( RR

Rkq

RR

Rkq

51.055

24

2

1 q

q

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27. Two curved plastic rods, one of charge +q and the other of charge –q, form a circle of radius R = 8.5 cm in an xy plane. The x axis passes through both of the connecting points, and the charge is distributed uniformly on both rods. If q = 15.0 pC, what are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field produced at P, the center of the circle? Consider a differential charge dq: For two rods:

dq

Ed

1rod dθR

k

R

dskdE

coscos

)(

2

)( Rddsdq

2rods dθR

kdE

cos2

2

90

90

44cos2

R

kq

R

kdθ

R

kE

2rods

)/(8.23105.814.3

10151099.84

42

129

CNE

2rods

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31. A nonconducting rod of length L = 8.15 cm has charge –q = -4.23 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magnitude and (c) direction (relative to the positive direction of the x axis) of the electric field produced at point P, at a = 12.0 cm from the rod? What is the electric field magnitude at a = 50 m by (d) the rod and (e) a particle of charge –q = -4.23 fC that replaces the rod? (a) (b) (c) the negative direction of the x axis

)/(10519,01015.8

1023.4 13

2

15

mCL

q

2xaL

dxkdEx

)/(106.1 3 CN

aLa

qkEx

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2a

qkEx

:aL

)/(105.1 8 CNEx

(d) for a distant point, the rod acts like a point charge, so the electric field of the point charge is the same as that of the rod:

)/(105.1 8 CNEx

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35. At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.6 m is the magnitude of the electric field equal to one-half the magnitude of the field at the center of the surface of the disk?

At the center (very close to the center):

220

12 Rz

zEz

02

cE

:2

1cz EE

2

11

22

Rz

z

)(35.03/ mRz

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44. An alpha particle (the nucleus of a helium atom) has a mass of 6.64 x 10-27 kg and a charge of +2e. What are the (a) magnitude and (b) direction of the electric field that will balance the gravitational force on the particle?

gF

E

mgqE

e

mgE

2

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54. An electron is shot at an initial speed of v0=4.0x106 m/s, at

angle 0 = 400 from an x axis. It moves through a uniform electric field . A screen for detecting electrons is positioned parallel to the y axis, at distance x = 3.0 m. In unit vector notation, what is the velocity of the electron when it hits the screen?

So, we ignore gravity Time to hit the screen:

jE ˆ)0.5( N/C

F

)(108

)(109

19

30

NF

NFg

)/(1078.8

1011.9

0.5106.1

211

31

19

sm

m

eEay

)(1098.040cos104

3

cos

6

0600

sv

xt

)/(1071.1sin 600 smatvtavv yyy

jsmismv ˆ)/(1071.1ˆ)/(1006.3 66

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56. An electric dipole consists of charges +2e and -2e separated by 0.85 nm. It is in an electric field of strength 3.4 x 106 N/C. Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field. (a) (b)

(c)

Fr

sinpE

)0(0 net

6919 104.31085.0106.122 edEnet

).(103.9 22 mNnet

)180(0 0 net

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59. How much work is required to turn an electric dipole 1800 in a uniform electric field of magnitude E = 46.0 N/C if p = 3.02 x 10-25 C.m and the initial angle is 640?

cospEU

UWWEapplied

000 64cos)64180cos(00

pEpEUUWapplied

438.00.461002.32 25 appliedW

)(1022.1 23 JWapplied

064cos2pEWapplied