Homework due Wednesday night 11:59 PM Exam 2: Sunday … · Rivera, Rondel, Scot, Smith, Suresh,...
Transcript of Homework due Wednesday night 11:59 PM Exam 2: Sunday … · Rivera, Rondel, Scot, Smith, Suresh,...
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HomeworkdueWednesdaynight11:59PMExam2:SundayApril9,6:10-7:10PM,onBuschpracHceproblemspostedonwebsitestartmakingyourformulasheetnow!BEFORECLASS:PlaywithmagnetsandmovingchargedparHclesLectureslidespostedonmainclasswebsite
CONGRATSON3/3toAlnadi,Balance,AlisonBansil,Buznitsky,Dias,Dormer,Z.Feng,Huang,Johnson,Kanagala,Kershaw,McKeown,Motyala,Ning,Parikh,Ravichandran,Rivera,Rondel,Scot,Smith,Suresh,Thuel,Tournoux,Yao
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Chapter 28 Magnetic Field and Forces, part 2
2 Phys 272
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LodestoneandbarmagnetsexertforceonmovingchargedparHclesbycreaHngamagne&cfieldBarmagnetfield:(nearends)ForcedependsonqandandonthemagneHcfield
B(r)
NS
!v B(r)
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ThemagneHcforceonachargedparHcleatCrossproductoftwovectorsDirec&on:PerpendiculartodirecHonofPerpendiculartodirecHonof->normaltotheplanedefinedbyandTwochoices–useright-handruletochooseThumbalongv;fingersalongB:outofpalm
!F = q"v ×
!B
q
!r
!v!v
!v
!B !
B
!B
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ThemagneHcforceonachargedparHcleatCrossproductoftwovectorsIfthevelocityandmagneHcfieldvectorsaregivenincomponentform,computebyexpandingthetermsExample:
!F = q"v ×
!B
!r
!v = vxi!B = Bxi + By j!v ×!B = vxi × (Bxi + By j) = vxBx (i × i )+ vxBy (i × j)
= vxByk
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i-clicker:AparHcleofcharge+1.0Cwithvelocity(inm/s)movesthroughtheuniformmagneHcfield(inT)WhatisthemagnitudeofthemagneHcforceontheparHcle?a) 12Nb) 6.0Nc) 4.5Nd) 1.5Ne) Noneoftheabove
6Phys272
!v = 2i +3 j!B = 3i −1.5 j
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i-clicker:AparHcleofcharge+1.0Cwithvelocity(inm/s)movesthroughtheuniformmagneHcfield(inT)WhatisthemagnitudeofthemagneHcforceontheparHcle?a) 12Nb) 6.0Nc) 4.5Nd) 1.5Ne) Noneoftheabove
7Phys272
!v = 2i +3 j!B = 3i −1.5 j
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MoHonofachargedparHcleqinauniformfieldBv0perpendiculartothefieldIniHallyF=qv0Bdownward
Boutofthescreen
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MoHonofachargedparHcleqinauniformfieldBv0perpendiculartothefieldIniHallyF=qv0BdownwardVelocitystaysconstant:magneHcforcedoesnoworkFstaysqv0Bperpendiculartovelocity
Boutofthescreen
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MoHonofachargedparHcleqinauniformfieldBv0perpendiculartothefieldIniHallyF=qv0BdownwardVelocitystaysconstant:magneHcforcedoesnoworkFstaysqv0Bperpendiculartovelocity
Boutofthescreen
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MoHonofachargedparHcleqinauniformfieldBv0perpendiculartothefieldUniformcircularmoHonTogettheradiusofthecircle,setthemagneHcforceequaltothecentripetalforceqv0B=mv02/rsor=mv0/qB
Boutofthescreen
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Typicalproblem:x=2mv0/(qB)Bintothescreen:posbendslek,negbendsright
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MoHonofachargedparHcleqinauniformfieldBv0xperpendiculartothefieldv0zparalleltothefield
Boutofthescreen
helixElectronbeamdemo
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ForceonacurrentcarryingwireinauniformmagneHcfieldBpointsoutofthescreenMagneHcforceistotherightForceonthechargesistransmiledtothewire
Electronsarethefreechargeshere
isinthedirecHonofthecurrent!L
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TorquealongtherotaHonaxis=Ftr(posiHve)
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Phys272 16
i-clicker:WhatisthesignofthetorqueontherectangularlooprotaHngonthefixedaxiswithauniformBfieldpoinHngtotheright?a) PosiHve(upalongaxis)b) NegaHve(downalongaxis)c) Zerod) Justguessing
!B
ii
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Phys272 17
i-clicker:WhatisthesignofthetorqueontherectangularlooprotaHngonthefixedaxiswithauniformBfieldpoinHngtotheright?a) PosiHve(upalongaxis)b) NegaHve(downalongaxis)c) Zerod) Justguessing
Torque=2(iBa)(b/2)=iB(ab)=iBarea
!B
ii
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Phys272 18
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Chapter 29 Currents Produce Magnetic Fields
19 Phys 272
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Calculating the Magnetic Field due to a Current: Biot-Savart Law
20Phys272
!B = d
!B∫
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Magnetic Field due to a Long Straight Wire
21Phys272
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29.2: Magnetic Field due to a Long Straight Wire:
DEMO:needleandwireDEMO:ironfilingsontransparency
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Magnetic Field due to a Long Straight Wire
23Phys272
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Phys272 24
i-clicker:Whereonthex-axis(excludinginfinity)isBtot=0?a) Atapointx<0b) Atapointxsuchthat0<x<dc) Atapointx>dd) Onlyatinfinity
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Phys272 25
i-clicker:Whereonthex-axis(excludinginfinity)isBtot=0?a) Atapointx<0b) Atapointxsuchthat0<x<dc) Atapointx>dd) Onlyatinfinity
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⊗ ⊗a b
i-clicker:
Atpointsonwireb,whatdirecHondoesthemagneHcfieldduetocurrentiain“wirea”point?a)Totherightb)Tothelekc)Upd)Downe)it’szero
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⊗ ⊗a b
i-clicker:
Atpointsonwireb,whatdirecHondoesthemagneHcfieldduetocurrentiain“wirea”point?a)Totherightb)Tothelekc)Upd)Downe)it’szero
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⊗ ⊗a b
i-clicker:
WhatisthedirecHonofthemagneHcforceonwirebduetothecurrentinwirea?a)Totherightb)Tothelekc)Upd)Downe)it’szeroDEMO
!B
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⊗ ⊗a b
i-clicker:
WhatisthedirecHonofthemagneHcforceonwirebduetothecurrentinwirea?a)Totherightb)Tothelekc)Upd)Downe)it’szeroDEMO
!B
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Force Between Two Parallel Wires
30Phys272
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Magnetic Field due to a Current in a Circular Arc of Wire:
31Phys272
B = dB = µ0iR2∫ ds =∫ µ0i
R2Rφ
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Phys272 32
Ex: