Homework 1 Solutions: Kinematics of a Particleibilion/ · 2016. 2. 14. · Introduction to Dynamics...
Transcript of Homework 1 Solutions: Kinematics of a Particleibilion/ · 2016. 2. 14. · Introduction to Dynamics...
Introduction to Dynamics (N. Zabaras)
Homework 1 Solutions: Kinematics of a Particle
Prof. Nicholas Zabaras
Warwick Centre for Predictive Modelling
University of Warwick
Coventry CV4 7AL
United Kingdom
Email: [email protected]
URL: http://www.zabaras.com/
February 14, 2016
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Introduction to Dynamics (N. Zabaras)
2
A A
2
B B
18 m/s , a 2 m/s
12 m/s , a 3 m/s
B A B/AV V V
o o
B/A-12 j (-18 cos 60 i 18 sin 60 j) V
B/AV { 9 i 3.588 j} m/s
2 2
/ (9) (3.558) 9.69 m/sB A /1 1
/
( ) 3.588tan tan ( )
( ) 9
B A y
B A x
21.7o o o
Aa {2 cos 60 i 2 sin 60 j}
2 22
B n t
(12)a a i a j - i - 3 j - i 3j { 1.44i 3 j} /
100m s
B A B/Aa a a
B/Aa {-2.44 i - 4.732 j }
2 2 2
/ (2.44) (4.732) 5.32 m/sB Aa /
/
( ) 4.732tan
( ) 2.44
B A y
B A x
62.7o
At the instant shown cars A and B are traveling with
speeds of 18m/s and 12m/s, respectively. Also at this
instant A has a decrease in peed of 2m/s2 and B has an
increa. in speed of 3m/s2. Determine the velocity and
acceleration of B with respect to A.
Problem 1
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Introduction to Dynamics (N. Zabaras)
Problem 2
Position coordinate
“cord equation”
Velocity
Acceleration
3A Bs s l
3 0A B
3 0A Ba a
3A B
3A Ba a
3* 6 18 ft/sA
Determine the speed of block A in the Fig.
if block B has an upward speed of 6 ft/s.
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Introduction to Dynamics (N. Zabaras)
Problem 3
Position coordinate
“cord equation”
Velocity
Acceleration
1 22 ( )A C B B Cs s l and s s s l
4 0A B
4 0A Ba a
2 14 2A Bs s l l const
4 4* 6 24 ft/sA B
4A Ba a
Determine the speed of A in the Fig. if
B has an upward speed of 6ft/sec.
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Introduction to Dynamics (N. Zabaras)
1
2( ) ( )
C B
A C B C B
s s l
s s s s s l
Position coordinate “cord equation”
2 14 2A Bs s l l const
4 0A B
1 1*2 0.5 ft/s
4 4B B
Determine the speed of block B in the
Fig. if the end of the cord at A is pulled
down with a speed of 2m/s
Problem 4
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Introduction to Dynamics (N. Zabaras)
Problem 5
6
Establish a relation y = f(x)
Taking time derivatives gives (check it!):
2 2(15) & 15DA CDl x l y
DA CDl l l
2 230 (15) (15 )x y
2225 15 ( 10 , 20 )y x at y m x m
/ /s Ady dt and dx dt
2
1 2
2 225s
dy x dx
dt dtx
2
20
0.4 /225
S A
x m
xm s
x
Cord =30 m
A man at A is hoisting a safe A as shown by
walking to the right with a constant velocity vA
= 0.5 m/sec. Determine the velocity and
acceleration of the safe when it reaches the
elevation of 10m. The rope is 30m long and
passes over a small pulley at D.
22 2
3/2 3/2 3/22 2 2
20
225 225 2250.5 / 0.0036 /
225 225 225 20
S SS A A A
x m
d d dxa m s m s
dt dx dt x x m
Introduction to Dynamics (N. Zabaras)
Problem 6
Pulley D is attached to a collar
which is pulled down at 3 in./s. At t
= 0, collar A starts moving down
from K with constant acceleration
and zero initial velocity. Knowing
that velocity of collar A is 12 in./s as
it passes L, determine the change in
elevation, velocity, and acceleration
of block B when block A is at L.
SOLUTION:
• Define origin at upper horizontal surface
with positive displacement downward.
• Collar A has uniformly accelerated
rectilinear motion. Solve for acceleration
and time t to reach L.
• Pulley D has uniform rectilinear motion.
Calculate change of position at time t.
• Block B motion is dependent on motions
of collar A and pulley D. Write motion
relationship and solve for change of
block B position at time t.
• Differentiate motion relation twice to
develop equations for velocity and
acceleration of block B.7
Introduction to Dynamics (N. Zabaras)
Problem 6
SOLUTION:
• Define origin at upper horizontal surface with
positive displacement downward.
• Collar A has uniformly accelerated rectilinear
motion. Solve for acceleration and time t to reach
L.
2
2
020
2
s
in.9in.82
s
in.12
2
AA
AAAAA
aa
xxavv
s 333.1s
in.9
s
in.12
2
0
tt
tavv AAA
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Introduction to Dynamics (N. Zabaras)
Problem 6
• Pulley D has uniform rectilinear motion.
Calculate change of position at time t.
in. 4s333.1s
in.30
0
DD
DDD
xx
tvxx
• Block B motion is dependent on motions of collar
A and pulley D. Write motion relationship and
solve for change of block B position at time t.
Total length of cable remains constant,
0in.42in.8
02
22
0
000
000
BB
BBDDAA
BDABDA
xx
xxxxxx
xxxxxx
in.160 BB xx
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Introduction to Dynamics (N. Zabaras)
Problem 6
• Differentiate motion relation twice to develop
equations for velocity and acceleration of block B.
0s
in.32
s
in.12
02
constant2
B
BDA
BDA
v
vvv
xxx
s
in.18Bv
0s
in.9
02
2
B
BDA
v
aaa
2s
in.9Ba
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Introduction to Dynamics (N. Zabaras)
Problem 7
The slotted fork is rotating about O at a
constant rate of 3 rad/s. Determine the radial
and transverse components of velocity and
acceleration of the pin A at the instant =
360o. The path is defined by the spiral
groove r = (5+/p in., where is in radians.
2
2
35 7 in in/s 0 in/sr r r
p
p
p p p
2360 2 rad 3 rad/s 0 rad/so p
30.955 in/srv r
p
7(3) 21in/sv r
2 2 20 7(3) 63 in/sra r r
232 0 2( )(3) 5.73 in/sa r r
p
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Introduction to Dynamics (N. Zabaras)
2 o
0.5(1 cos ) ft
4 ft/s
30 ft/s at 180
find and
r
v
a
0.5(1 cos )r
0.5(sin )r
0.5(cos ) ( ) 0.5(sin )r
o
2
at 180
1 ft 0 0 5r r r - . θ
Due to the rotation of the forked rod, the ball travels
around the slotted path a portion of which is in the
shape of a cardioid r = 0.5(1 - cos) ft where in
radian s. If the ball’s velocity is v=4ft/s and its
acceleration a=30 ft /s2 at the instant = 180°,
determine the angular velocity and angular
acceleration of the fork.
Problem 8
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Introduction to Dynamics (N. Zabaras)
0.5(1 cos )r
0.5(sin )r
0.5(cos ) ( ) 0.5(sin )r o
2
at 180
1 ft 0 0 5r r r - . θ
2 2 2 2( ) ( ) (0) (1 ) 4 4 rad/sr r
2 2 2 2 2 2 2( ) ( 2 ) [ 0.5(4) 1(4) ] [1 2(0)(4)] 30a r r r r
218 rad/s
Problem 8
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Introduction to Dynamics (N. Zabaras)
Problem 9
2* 2*4 8 / 02
r m r m s rp
p
2 2(8) (12.56) 14.89 / m s 2 2 2(50.24) (64) 81.36 /a m s
A collar slides along the smooth vertical spiral rod, r =
(2) m, where is in radians. If its angular rate of
rotation is constant and equal 4 rad/s, at the instant =
90o. Determine
- The collar radial and transverse component of velocity
- The collar radial and transverse component of
acceleration.
- The magnitude of velocity and acceleration
2 2 2r r r
24 / 0 /2
rad rad s rad sp
8 m/srv r
(4) 12.56 m/sv r p
2 2 20 (4) 50.24 m/sra r r p
22 0 2(8)(4) 64 m/sa r r
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