Geotech IV 6 Seepage and Flow Net
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Geotechnical EngineeringLecture
Civil Engineering Term IV
Prof. Kazunori Tabe, Ph.D.
Civil Engineering Section
School of Engineering and TechnologySharda University
Source: http://starb.on.coocan.jp/
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Lecture Note !
LMS (read in campus only)
Search: kazunori tabe Click lecture note 1, 2, 3, 4 and 5
Sanjay (Rm#501)
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Geotechnical Engineering-SyllabusLecture Contents
1. Syllabus and Introduction (4 hrs)
2. Soil Classification (4hrs)
3. Phase Diagram (4 hrs)4. Permeability of Soils (4 hrs)
5. Effective Stress (4 hrs)
6. Seepage and Flow Nets (4 hrs)
7. Soil Compaction (4hrs)
8. Consolidation and Settlements (4hrs)
9. Shear Strength (4hrs)
10. Slope Stability (4hrs)
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Geotechnical EngineeringTerm Periods and coverage
To Mid Term Exam1. 10th Jan,-14th Jan.
2. 17th Jan. 21st Jan.
3. 24th Jan. 28th Jan.
4. 31st
Jan. 4th
Feb.5. 7th Feb. 11st Feb.
6. 14th Feb. 18th Feb.
7. 21st Feb. 25th Feb.
8. 28th Feb. 4th Mar.
9. 9th Mar. 16th Mar.
Expected coverage:
Introduction (4 hrs),
Soil Classification(4hrs),
Phase Diagram (4 hrs),
Permeability of Soils (4 hrs),
Effective Stress (4 hrs),
Seepage and Flow Nets (4 hrs)
To End Term Exam
1. 21st Mar.-25th Mar.
2. 28th Mar. 1st Apr.
3. 4th Apr. 8th Apr.
4. 11st
Apr. 15th
Apr.5. 18th Apr. 22nd Apr.
6. 25th Apr. 29th Apr.
7. 2nd May 6th May
8. 9th May 16th May
Expected coverage:
Soil Compaction (4 hrs),
Consolidation and Settlement (4hrs),
Shear Strength and Triaxial Tests (4hrs)
Slope Stability (4 hrs)
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What we learned in Geotech
lecture
Clay Atterberg Limit Tests
Soil ClassificationSystem
Phase Diagram
Permeability
Sand
Sieve Analysis
Soil ClassificationSystem
Phase Diagram
Permeability
Soils as constructionmaterials
Clay Water doesnt
move throughclay very well.
Sand
Water movesthrough sandquite well.
Clay Effective Stress
(Fluctuation of WT)
More practical?
Sand
Effective Stress(Fluctuation of WT)
More practical?
MassVolume Relationship StressVolume Relationship
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6. Seepage and Flow Net (1/4)
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Geotechnical Engineering -Syllabus
6. Seepage and Flow Nets
Learning Objectives;
Gain an understanding of seepage pressure andits role in causing the quick condition
Gain an understanding of Darcy's law. An ability to draw flow nets and determine the
water head at a given point and the water flowrate
An ability to calculate critical hydraulic gradientand factor of safety against quick condition,
Etc.
Source: jan.ucc.nau.edu
1. Introduction (4 hrs)
2. Soil Classification (4hrs)
3. Phase Diagram (4 hrs)
4. Permeability of Soils (4 hrs)
5. Effective Stress (4 hrs)6. Seepage and Flow Nets (4
hrs)
7. Soil Compaction (4hrs)
8. Consolidation andSettlements (4hrs)
9. Shear Strength (4hrs)
10. Slope Stability (4hrs)
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Core Test Page P.148-154 (esp. p.154)
P.173-199 P. 173-175 (Theory: Laplaces Equation->flow lines and
equipotential lines)
Flow Net
P. 175-180 (flow lines and equipotential lines form Flow
Nets, Use of Flow Nets) P. 180-183 (Method for obtaining Flow Nets)
P. 183-189 (flow and soil condition)
P. 190-199 (Examples and Problems)
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2D Flow-Laplaces Equation
(p.173-175) The flow of water into an element in a
saturated soil
)dim2(
,0
arg
arg
f lowensionalfor
papertheofplanethetolarperpendicudirectionytheinvelocitythev
z
hdirectionverticaltheingradienthydraulicthei
directionverticaltheinvelocityedischofcomponentthev
x
hdirectionhorizontaltheingradienthydraulicthei
directionhorizontaltheinvelocityedischofcomponentthev
planethistolarperpendiculengththedy
papertheofplanetheindirectionverticalthedz
papertheofplanetheindirectionhorizontalthedx
y
z
z
x
x
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2D Flow-Laplaces Equation
(p.173-175)
dzdxdyz
vdxdyvdxdzdy
x
vdzdyvtimeunitinelementtheleavesthatwaterofamountThe
dxdyvdzdyvtimeunitinelementtheenteringwaterofamountThe
zz
xx
zx
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2D Flow-Laplaces Equation
(p.173-175)
)1.7(0sin0
0
.:
dxdzdycez
v
x
v
ordxdyvdzdyvdzdxdyz
vdxdyvdxdzdy
x
vdzdyv
timewithconditionanyinchangenobecanthereflowstatesteadytheIn
dzdxdyz
vdxdyvdxdzdy
x
vdzdyvtimeunitinelementtheleavesthatwaterofamountThe
dxdyvdzdyvtimeunitinelementtheenteringwaterofamountThe
zx
zxz
zx
x
zz
xx
zx
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2D Flow-Laplaces Equation
(p.173-175)
)2.7(0
;
hom'min
)1.7(0sin0
0
.:
2
2
2
2
z
h
x
h
typermeabilitorespectwithisotropysoilthat
andogeneousissoilthethatandlawsDarcyofvaliditythethatgAssu
dxdzdycez
v
x
v
ordxdyvdzdyvdzdxdyz
vdxdyvdxdzdy
x
vdzdyv
timewithconditionanyinchangenobecanthereflowstatesteadytheIn
dzdxdyz
vdxdyvdxdzdyx
vdzdyvtimeunitinelementtheleavesthatwaterofamountThe
dxdyvdzdyvtimeunitinelementtheenteringwaterofamountThe
zx
zxz
zx
x
zzxx
zx
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2D Flow-Laplaces Equation
(p.173-175)
.
.int)2(
.
.2')1(
)2.7(0
;
hom'min
)1.7(0sin0
0
.:
2
2
2
2
equalisheadpotentialtotalthewherespojoining
linesarelinesialequipotenttheandf lowofdirectiontheindicatelinesFlow
linesialequipotentsetothertheandlinesf lowtheasknowniscurvesofsetOne
othereachtoorthogonalcurvesofsetsyieldsEquationsLaplacetheofsolutiongeneralThe
zh
xh
typermeabilitorespectwithisotropysoilthat
andogeneousissoilthethatandlawsDarcyofvaliditythethatgAssu
dxdzdycez
v
x
v
ordxdyvdzdyvdzdxdyzvdxdyvdxdzdy
xvdzdyv
timewithconditionanyinchangenobecanthereflowstatesteadytheIn
dzdxdyz
vdxdyvdxdzdy
x
vdzdyvtimeunitinelementtheleavesthatwaterofamountThe
dxdyvdzdyvtimeunitinelementtheenteringwaterofamountThe
zx
zxz
zx
x
zz
xx
zx
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Flow Nets (p.175-180) h=2.25-0.25=2m
Flow lines
a-b, c-d, e-f, etc.
The flow path of water in a pervious
medium Equipotential lines
The points on the flow lines where thetotal head or total head loss is thesame
Flow lines and Equipotential lines formFlow Net .
Numbers of flow lines and equipotential lines It is inconvenient to draw too many of
these lines in a flow net.
Flow lines have to cross equipotentiallines orthogonally.
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Use of Flow Net (p.176-180)
)3.7(1;1;1
;sec
,.,'
3
3
332
2
221
1
11
ab
hkqa
b
hkqa
b
hkq
tiontheofplanethetolarperpendicu
widthunitperf lowtheSokiAflowofratelawsDarcyFrom
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Use of Flow Net (p.176-180)
1
,""
3&2
2&1
)3.7(1;1;1
;sec
,.,'
3
3
2
2
1
1
32
21
3
3
332
2
221
1
11
b
a
b
a
b
a
squareselementaryasdrawnarenetflowainfieldsallIf
hhlinesialequipotentsameField
qqchannelf lowsameField
ab
hkqa
b
hkqa
b
hkq
tiontheofplanethetolarperpendicu
widthunitperflowtheSokiAf lowofratelawsDarcyFrom
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Use of Flow Net (p.176-180)
dd
d
n
Hkq
n
Hh
dropsialequipotentofnandf lowtheduringlossheadtotaltheisHIf
hkq
equalbealsowillf ieldeachacrosslossheadtheandequalbewillf ieldeachthroughflowofquantityThe
hhhh
qqqq
EqinaboveallSubstitute
b
a
b
a
b
a
squareselementaryasdrawnarenetflowainf ieldsallIf
hhlinesialequipotentsameField
qqchannelf lowsameField
ab
hkqa
b
hkqa
b
hkq
tiontheofplanethetolarperpendicu
widthunitperf lowtheSokiAflowofratelawsDarcyFrom
,#,
.
,3.7.
1
,""
3&2
2&1
)3.7(1;1;1
;sec
,.,'
321
321
3
3
2
2
1
1
32
21
3
3
332
2
221
1
11
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Use of Flow Net (p.176-180)
)6.7(
)(
)5.7(
,#
n
n
nkHq
netf lowinsquareselementarynotaref ieldsallnb
aIf
n
nkHnqq
islengthunitperchannelsf lowallthroughqf lowofrateThenisnetf lowainchannelsf lowoftheIf
d
f
d
f
f
f
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Use of Flow Net (p.176-180)
Uplift pressure (p.179)
Exit gradient and piping (p.179)
Pore-water pressure determination (p.180)
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Graphical method Upstream ground surface AB is an
equipotential line, since at every point onAB, the total head is constant and equal to
2m (pressure head=2.25m; elevationhead=-0.25m, for the datum shown)
Method for obtaining Flow Nets(p.180-183)
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Graphical method Upstream ground surface AB is an
equipotential line, since at every point onAB, the total head is constant and equal to
2m (pressure head=2.25m; elevationhead=-0.25m, for the datum shown)
Similarly, CD is an equipotential line withtotal head equal to 0m at every point on it(pressure head=0.25m and elevationhead=-0.25m)
Method for obtaining Flow Nets(p.180-183)
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Graphical method Upstream ground surface AB is an
equipotential line, since at every point onAB, the total head is constant and equal to
2m (pressure head=2.25m; elevationhead=-0.25m, for the datum shown)
Similarly, CD is an equipotential line withtotal head equal to 0m at every point on it(pressure head=0.25m and elevationhead=-0.25m)
From point A, water flows down the sheetpile on the upstream side, touched the tip ofthe sheet pile E and moves up on thedownstream face EC. Thus, AEC is a flowline.
Method for obtaining Flow Nets(p.180-183)
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Graphical method Upstream ground surface AB is an
equipotential line, since at every point onAB, the total head is constant and equal to
2m (pressure head=2.25m; elevationhead=-0.25m, for the datum shown)
Similarly, CD is an equipotential line withtotal head equal to 0m at every point on it(pressure head=0.25m and elevationhead=-0.25m)
From point A, water flows down the sheetpile on the upstream side, touched the tip ofthe sheet pile E and moves up on thedownstream face EC. Thus, AEC is a flowline.
FG is a flow line, since water must flowalong the impermeable surface and cannotpenetrate the impermeable layer.
Method for obtaining Flow Nets(p.180-183)
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Confined flowFlow space was completely defined by the 4boundary conditions and flow itself was limitedto this space.
Unconfined flowThe flow space is not fully defined.
Flow Net Conditions (p. 183-189)
Confined & Unconfined (p.183-186)
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Flow Net Conditions (p. 183-189)Unconfined (Homogeneous and Isotropic) (p.183-186)
The upstream slope AC is a boundary equipotential line (=H), since at everypoint on it, the total head is constant.
The discharge surface FH is a boundary equipotential line with zero total head.
The top flow line would begin at point C.
The exact flow path of the water is not known. However, at every point on thetop line, the pressure head is zero (=atmospheric pressure). Therefore, the totalhead is simply equal to the elevation head.
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Flow Net Conditions (p. 183-189)Unconfined (Homogeneous and Isotropic) (p.183-186)
There must be equal vertical intervals H between the points of intersection ofsuccessive equipotential lines with top flow line. (Kozeny, Casagrande)
Casagrande , A. (1937) Seepage Through Dams, reprinted in the Boston Society of Civil Engineers,Contributions to Soil Mechanics, 1925-1940. This reference quated J.S. Kozenys aproach.
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Flow Net Conditions (p. 183-189)
Anisotropic ->P.186-188
Nonhomogeneous->p.188-189
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Thank you.Source: http://starb.on.coocan.jp/
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Geotechnical EngineeringLectureCivil Engineering Term IV
Prof. Kazunori Tabe, Ph.D.
Civil Engineering Section
School of Engineering and TechnologySharda University
Source: http://starb.on.coocan.jp/
http://starb.on.coocan.jp/gallery/p127/index0.htmlhttp://starb.cool.ne.jp/daily/daily2.html -
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Source: http://starb.on.coocan.jp/
6. Seepage and Flow Net (2/4)
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Seepage and Flow Nets
What is seepage pressure? Why is it important toGeotechnical engineering?
Seepage pressure is the pressure due to viscousfriction exerted by the water flowing through soilpores. Seepage pressure can increase or decreasethe effective stress in a soil mass.
When seepage pressure acts against gravity, quick
sand condition occurs. This is important in the stability analysis of earth
structures subjected to the action of seepage.
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What are the applications of flow net? What are the characteristics offlow net?
Flow nets are used to determine hydrostatic pressure,
seepage pressure, and exit gradient under 2D or 3D flowconditions. A flow net is made up of flow lines and equipotential lines,
where they meet at right angles to each other and formapproximately square elements.
Flow lines are the path along which the water travels from
upstream to downstream in permeable saturated soil. Theequipotential lines represent lines along which the total headis constant. The quantity of water flowing through each flowchannel is the same as well as the potential drop occurringbetween two successive equipotential lines.
Seepage and Flow Nets
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Seepage and Flow Net calculation 1
A new building with deepbasement is proposed to construct
over a site. The boring data showsa thin layer of impervious clay isencountered 15m below theground water table, which is twofeet below grade. Ignoring thepressure of sheeting to support
the excavation, determine themaximum depth of excavationwithout the danger of blow out ifthe saturated unit weight of thesandy soil is 1900 kg/m3.
15m 1900kg/m3 1000kg/m3
1900kg/m3
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Seepage and Flow Net calculation 1
15m 1900kg/m3 1000kg/m3
1900kg/m3
DHP
DP
layerofbottomtheonpressureupwardandDownward
Step
wwup
wsoildown
:
:1
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Seepage and Flow Net calculation 1
15m 1900kg/m3 1000kg/m3
1900kg/m3
mH
D
DHD
PPwhenoccursoutblow
excavationofDepth
Step
DHPDP
layerofbottomtheonpressureupwardandDownward
Step
soil
ww
wwwsoil
updown
wwup
wsoildown
89.7
:
:2
:
:1
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Seepage and Flow Net calculation 1
15m 1900kg/m3 1000kg/m3
1900kg/m3
.8:
89.7
:
:2
:
:1
mthangreaterisexcavationofdepththeifoccursoutBlowAnswer
mH
D
DHD
PPwhenoccursoutblow
excavationofDepth
StepDHP
DP
layerofbottomtheonpressureupwardandDownward
Step
soil
ww
wwwsoil
updown
wwup
wsoildown
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Water is flowing through two types of soils, gravel andsand, under a constant head with an area of 20 cm2.Determine:
Seepage pressures and piezometric head at point A.
If 35% of the excess seepage pressure is lost as waterflows upward through gravel, what is the seepagepressufre and piezometric head at point B?
What is the quantity of water flowing through thegravel if its hydraulic conductivity is 2.6m/day?
What is the hydraulic conductivity of the sand?
Seepage and Flow Net calculation 2
20cm
15cm
10cm
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Seepage and Flow Net calculation 2
20cm
15cm
10cm
220
6.2,20,15,10
:
cmAday
mkcmHcmHcmH
Given
gravelwsandgravel
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Seepage and Flow Net calculation 2
20cm
15cm
10cm
cmHHHH
cmHHH
BpoatheadcpiezometriandpressureseepageeDeter
cmHHHH
cmHH
ApoatheadcpiezometriandpressureseepageeDeter
Step
cmA
day
mkcmHcmHcmH
Given
grave lwpiezoApiezoB
wseepageAseepageB
wsandgravelpiezoA
wseepageA
gravelwsandgravel
28102035.04535.0
132035.02035.0
:intmin
45101520
20
:intmin
:1
20
6.2,20,15,10
:
..
..
.
.
2
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Seepage and Flow Net calculation 2
20cm
15cm
10cm day
cmAikq
H
Hi
gravelinratef lowCalculate
Step
gravelgravel
gravel
wgravel
3
36952070.0260
70.0
10
2035.035.0
:
:2
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Seepage and Flow Net calculation 2
20cm
15cm
10cm
87.015
2035.0135.01
:
:
:3
sand
wsand
H
Hi
layersandthroughgradienthydraulic
sandtheoftyconductivihydraulicCalculate
Step
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Seepage and Flow Net calculation 2
20cm
15cm
10cm
daym
daycm
Aiqk
layersgravelandsandthroughplacetakesf lowsameThe
Step
sand
sand 12.22122087.0
3695
:4
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Water is flowing through the soil layers shown below.Determine the total stress, effective stress, and water pressure at point A and point B.
Seepage and Flow Net calculation 3
1800 kg/m31.3 cm/s
2000 kg/m30.6 cm/s
12m
9m
12m
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Seepage and Flow Net calculation 3
1800 kg/m31.3 cm/s
2000 kg/m30.6 cm/s
12m
9m
12m
32322
1311
1000,sec
6.0,2000,12
21,sec
3.1,1800,21:
m
kgcmk
m
kgmL
mHcm
km
kgmLGiven
w
w
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Seepage and Flow Net calculation 3
1800 kg/m31.3 cm/s
2000 kg/m30.6 cm/s
12m
9m
12m
mhmhhh
hhce
hh
hcmhcm
L
hi
L
hi
where
AikAik
layersoileachforlostheadwatereDeter
Step
m
kgcmk
m
kgmL
mHcm
km
kgmLGiven
w
w
3.5,7.6128.0
12)129()12912(sin
8.012sec6.021sec3.1
,
:
:min
:1
1000,sec
6.0,2000,12
21,sec
3.1,1800,21:
1222
21
21
21
2
22
1
11
222111
32322
1311
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Seepage and Flow Net calculation 3
1800 kg/m31.3 cm/s
2000 kg/m30.6 cm/s
12m
9m
12m
2
2
22211
2
211
211
498001200061800
12000121000
61800122000211800
:int,,
221001570037800
157003.5211000
37800211800
:int,,
:2
m
kg
m
kgHu
m
kgLL
BpoatstresseffectiveandpressurewaterporestresstotalCalculate
m
kg
m
kghLu
m
kgL
ApoatstresseffectiveandpressurewaterporestresstotalCalculate
Step
wwB
B
wA
A
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What is the seepage flow rate, per unit width,under the concrete dam shown below?
Seepage and Flow Net calculation 4
23m
10m
15m
3m
0.01 cm/s
0.0000001 cm/s
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Seepage and Flow Net calculation 4
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Seepage and Flow Net calculation 4
mwidthcm
kmHmHGiven sandww 1,sec
01.0,3,10: 21
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Seepage and Flow Net calculation 4
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
ww
sandww
7310
:
:1
1,sec
01.0,3,10:
21
21
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Seepage and Flow Net calculation 4
day
mcm
N
NHkq
damconcretetheunderratef lowSeepage
Step
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
f
sand
ww
sandww
33
21
21
23sec
5.2621008
370001.0
:
:2
7310
:
:1
1,sec
01.0,3,10:
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Thank you.Source: http://starb.on.coocan.jp/
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Geotechnical EngineeringLectureCivil Engineering Term IV
Prof. Kazunori Tabe, Ph.D.
Civil Engineering SectionSchool of Engineering and Technology
Sharda University
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Draw a flow net for sheet pile shownbelow:
What is the piezometric head above thedatum at point A and B?
What is the flow rate below the sheet pilein cubic meter per day if the structure is150 m wide?
Seepage and Flow Net calculation 5
3m
12m
10m
23m
=0.0000001 cm/s
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Seepage and Flow Net calculation 5
3m
12m
10m
23m
=0.0000001 cm/s
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Seepage and Flow Net calculation 5
mwidthcm
kmHmHGivensandww
150,
sec
01.0,3,10: 21
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Seepage and Flow Net calculation 5
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
ww
sandww
875.08
7
7310
:
:1
150,sec
01.0,3,10:
21
21
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Seepage and Flow Net calculation 5
mhHH
BpoatheadcPiezometri
mhHH
ApoatheadcPiezometri
headcPiezometri
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
wB
wA
d
ww
sandww
1.405.4875.08.6108.6
:int
7.86875.8875.05.1105.1
:int
:
:2
875.08
7
7310
:
:1
150,sec
01.0,3,10:
2
1
21
21
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Seepage and Flow Net calculation 5
day
m
daycm
mcm
widthN
N
Hkq
damthethroughrateFlow
Step
mhHH
BpoatheadcPiezometri
mhHH
ApoatheadcPiezometri
headcPiezometri
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
f
sand
wB
wA
d
ww
sandww
3
2
1
21
21
45361508
4
7
sec246060
100sec01.0
:
:3
1.405.4875.08.6108.6
:int
7.86875.8875.05.1105.1
:int
:
:2
875.08
7
7310
:
:1
150,sec
01.0,3,10:
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Calculate the factor of safety against downstream heave for the sheetpile shown below. The saturated unit weight of the soil is 2000 kg/m3.
Reference: Alam Singh, Modern Geotechnical Engineering, 3rd Ed.CBS, pp. 202-204.
Seepage and Flow Net calculation 6
3m
10m
15m
6m
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Calculate the factor of safety against downstream heave for the sheetpile shown below. The saturated unit weight of the soil is 2000 kg/m3.
Seepage and Flow Net calculation 6
3m
10m
15m
6m
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Seepage and Flow Net calculation 6
mDmHmHm
kg
m
kg
Given
wwsandw 6,3,10,2000,1000
:
2133
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Seepage and Flow Net calculation 6
m
HH
H
mHHH
zoneheavethebelowheadAverage
Step
mDmHmHm
kg
m
kg
Given
avg
ww
wwsandw
74.22
76
7.17
6
3
2
6
7.1
6
3
7310
:
:1
6,3,10,2000,1000
:
21
2133
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Seepage and Flow Net calculation 6
46.06
74.2
:
:2
74.22
76
7.176
3
2
6
7.1
6
3
7310
:
:1
6,3,10,2000,1000
:
21
2133
D
Hi
gradienthydraulicAverage
Step
mHH
H
mHHH
zoneheavethebelowheadAverage
Step
mDmHmHm
kg
m
kg
Given
avg
avg
avg
ww
wwsandw
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Seepage and Flow Net calculation 6
17.2
100046.0
1000
100010002000
:
:3
46.06
74.2
:
:2
74.22
76
7.17
6
3
2
6
7.1
6
3
7310
:
:1
6,3,10,2000,1000
:
3
21
2133
wavg
s
wsand
avg
avg
avg
ww
wwsandw
i
F
m
kg
heavedownstreamagainstsafetyofFactor
Step
D
Hi
gradienthydraulicAverage
Step
m
HH
H
mHHH
zoneheavethebelowheadAverage
Step
mDmHmHm
kg
m
kg
Given
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Draw a flow net for the sheet pile structureshown below.Compute the quantity of flow in cubic meter
per day.What is the head at point A & B?
Seepage and Flow Net calculation 7
12m
10m
23m
3m
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Seepage and Flow Net calculation 7
12m
10m
23m
3m
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Seepage and Flow Net calculation 7
mwidthcm
kmHmH
Given
ww 1,sec
05.0,3,10
:
21
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Seepage and Flow Net calculation 7
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmH
Given
d
ww
ww
7.010
7
7310
:
:1
1,sec05.0,3,10
:
21
21
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Seepage and Flow Net calculation 7
mhHHmhh
mhHHmhh
datumtheaboveheadcPiezometri
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmH
Given
BwBB
AwAA
d
ww
ww
33.467.510,67.57.01.81.8
67.833.110,33.17.09.19.1
:
:2
7.010
7
7310
:
:1
1,sec
05.0,3,10
:
1
1
21
21
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Seepage and Flow Net calculation 7
day
m
daycm
mcmwidth
N
HNkq
structurethebelowrateFlow
Step
mhHHmhh
mhHHmhh
datumtheaboveheadcPiezometri
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmH
Given
d
f
BwBB
AwAA
d
ww
ww
3
1
1
21
21
2.151110
57sec246060
100sec05.0
:
:3
33.467.510,67.57.01.81.8
67.833.110,33.17.09.19.1
:
:2
7.010
7
7310
:
:1
1,sec
05.0,3,10
:
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For the sheet pile shown below, using a flownet:
What is the piezometric head above the groundlevel at point A and B?
What is the flow rate below the structure incubic meter per day if the structure is100 m wide?
What is the factor of safety against down
stream heave if the saturated unit weight ofsand is 1800 kg/m3?
Reference: Alam Singh, Modern GeotechnicalEngineering, 3rd Ed. CBS, pp. 202-204.
Seepage and Flow Net calculation 8
12m
10m
23m
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Seepage and Flow Net calculation 8
12m
10m
23m P1 P2
A B
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Seepage and Flow Net calculation 8
mDm
kg
m
kg
cmkmwidthmHmHGiven
wsand
sandww
12,1000,1800
sec01.0,100,0,10:
33
21
P1 P2
A B
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Seepage and Flow Net calculation 8
mN
Hh
mHHH
dropsheadCalculate
Step
mDm
kg
m
kg
cmkmwidthmHmHGiven
d
ww
wsand
sandww
25.18
10
10010
:
:1
12,1000,1800
sec01.0,100,0,10:
21
33
21
P1 P2
A B
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Seepage and Flow Net calculation 8
mhHHBpoatheadcPiezometri
mhHH
ApoatheadcPiezometri
headcPiezometri
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mDm
kg
m
kg
cmkmwidthmHmHGiven
wB
wA
d
ww
wsand
sandww
75.125.16.6106.6:int
375.825.13.1103.1
:int
:
:2
25.18
1010010
:
:1
12,1000,1800
sec01.0,100,0,10:
1
1
21
33
21
P1 P2
A B
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Seepage and Flow Net calculation 8
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
d
f
sand
3
43201008
410
sec246060
100sec01.0
:
:3
P1 P2
A B
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Seepage and Flow Net calculation 8
:
:4
43201008
410
sec246060
100sec01.0
:
:3
3
heavestreamdownagainstsafetyofFactor
Step
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
d
f
sand
P1 P2
A B
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Seepage and Flow Net calculation 8
mPP
H
mhHP
mhHP
zoneheavethebelowheadaverageheavestreamdownagainstsafetyofFactor
Step
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
avg
w
w
d
f
sand
875.32
75.25
2
75.225.18.5108.5
525.10.4100.4
:
:4
43201008
410
sec246060
100sec01.0
:
:3
21
12
11
3
P1 P2
A B
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Seepage and Flow Net calculation 8
32.012
875.3
875.32
75.25
2
75.225.18.5108.5
525.10.4100.4
:
:4
43201008
410
sec246060
100sec01.0
:
:3
21
12
11
3
D
Hi
gradienthydraulicaverage
mPP
H
mhHP
mhHP
zoneheavethebelowheadaverage
heavestreamdownagainstsafetyofFactor
Step
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
avg
avg
avg
w
w
d
f
sand
P1 P2
A B
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Seepage and Flow Net calculation 8
5.2
100032.0
800
80010001800
32.012
875.3
875.32
75.25
2
75.225.18.5108.5
525.10.4100.4
:
:4
43201008
410
sec246060
100sec01.0
:
:3
3
21
12
11
3
wavg
s
wsand
avg
avg
avg
w
w
d
f
sand
i
F
m
kg
heavedownstreamagainstsafetyofFactor
D
Hi
gradienthydraulicaverage
mPP
H
mhHP
mhHP
zoneheavethebelowheadaverage
heavestreamdownagainstsafetyofFactor
Step
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
P1 P2
A B
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Geotechnical EngineeringLecture
Civil Engineering Term IV
Prof. Kazunori Tabe, Ph.D.
Civil Engineering SectionSchool of Engineering and Technology
Sharda University
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Source: http://starb.on.coocan.jp/
6. Seepage and Flow Net (4/4)
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87/113
For the hydraulic structure shownbelow:
What is the piezometric head above thedatum at point A, B, and C?
What is the flow rate below the
structure in cubic feet per day if thestructure is 100 m wide?
Seepage and Flow Net calculation 9
3m
30m
12m
15m
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Seepage and Flow Net calculation 9
3m
30m
12m
15m
-
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Seepage and Flow Net calculation 9
mwidthcm
kmHmHGiven ww 100,sec
01.0,3,12: 21
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Seepage and Flow Net calculation 9
7.069.013
9
9312
:
:1
100,sec
01.0,3,12:
21
21
d
ww
ww
N
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
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Seepage and Flow Net calculation 9
mhHCmhh
mhHBmhh
mhHAmhh
datumtheaboveheadcpiezometriCalculate
Step
N
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
CwC
BwB
AwA
d
ww
ww
58.442.712,42.77.06.106.10
68.632.512,32.57.06.76.7
09.1191.012,91.07.03.13.1
:
:2
7.069.013
9
9312
:
:1
100,
sec
01.0,3,12:
1
1
1
21
21
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Seepage and Flow Net calculation 9
day
m
daycm
mcmwidth
N
NHkq
structurethebelowratef lowCalculate
Step
mhHCmhh
mhHBmhh
mhHAmhh
datumtheaboveheadcpiezometriCalculate
Step
N
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
f
CwC
BwB
AwA
d
ww
ww
3
1
1
1
21
21
2392610013
49
sec246060
100sec01.0
:
:3
58.442.712,42.77.06.106.10
68.632.512,32.57.06.76.7
09.1191.012,91.07.03.13.1
:
:2
7.069.013
9
9312
:
:1
100,sec
01.0,3,12:
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Draw a flow net below the dam shownbelow:
What is the piezometric head above thedatum at point A, B, and C?
What is the flow rate between the dam incubic feet per day if the structure is 1000m wide?
Seepage and Flow Net calculation 10
3m
7.5m
25m
12m
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Seepage and Flow Net calculation 10
3m
7.5m
25m
12m
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Seepage and Flow Net calculation 10
mwidthcm
kmHmHGivensandww
1000,sec
02.0,3,5.7:21
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Seepage and Flow Net calculation 10
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
ww
sandww
5.09
5.4
5.435.7
:
:1
1000,sec
02.0,3,5.7:
21
21
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Seepage and Flow Net calculation 10
mhHH
mhHH
mhHH
datumtheaboveheadcpiezometriCalculate
Step
mN
Hh
mHHH
dropsheadCalculateStep
mwidthcm
kmHmHGiven
wC
wB
wA
d
ww
sandww
45.45.01.65.71.6
9.35.02.75.72.7
65.65.07.15.77.1
:
:2
5.09
5.4
5.435.7
::1
1000,sec
02.0,3,5.7:
1
1
1
21
21
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Seepage and Flow Net calculation 10
day
m
daycm
mcmwidth
N
NHkq
structurethebelowrateFlow
Step
mhHH
mhHH
mhHH
datumtheaboveheadcpiezometriCalculate
Step
mN
Hh
mHHH
dropsheadCalculate
Step
mwidthcm
kmHmHGiven
d
f
wC
wB
wA
d
ww
sandww
3
1
1
1
21
21
3456010009
45.4
sec246060
100sec02.0
:
:3
45.45.01.65.71.6
9.35.02.75.72.7
65.65.07.15.77.1
:
:2
5.09
5.4
5.435.7
:
:1
1000,sec
02.0,3,5.7:
Seepage through an Earth Dam on
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Seepage through an Earth Dam onImpervious Base
Das,B.M. Principles of Geotechnical Engineering, 6th Ed. Thomson, pp. 215-216
Alam Singh Modern Geotechnical Engineering , third edition, CBS Publishers &Distributors PVT. Ltd.
C. Venkatramaiah Geotechnical Engineering, revised third edition, New AgeInternational Publishers
Dr. K.R. Arora Soil Mechanics and Foundation Engineering, StandardPublishers Distributors
)sin)(tan( widthLkq soil
2
2
2
2
sincoscos
wHddL
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Seepage and Flow Net calculation 11
For the earth dam shown below,using a flow net:
What is the piezometric head atpoint A, B, and C?What is the flow rate throughthe dam in cubic meter per dayif the dam is 600 m wide?
For the earth dam shown below,using a flow net:
What is the piezometric head atpoint a, B, and C?
10m12m10m
3m
10m
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Seepage and Flow Net calculation 11
For the earth dam shown below,using a flow net:
What is the piezometric head atpoint a, B, and C?
10m12m10m
3m
10m
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Seepage and Flow Net calculation 11
mhmdmdmd
cmkmwidthmHGiven
dam
soilw
13310,10,12,10
,sec
00004.0,500,10:
321
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Seepage and Flow Net calculation 11
m
HddL
md
mHdh
damtheexistwillwaterthewhereeDeter
Step
mhmdmdmd
cmkmwidthmHGiven
w
wdam
dam
soilw
8.11.52sin
10
1.52cos
58.26
1.52cos
58.26
sincoscos
58.26)3.0(101210
75.729.1
10tan
,1.521013tantan
:min
:1
13310,10,12,10
,sec
00004.0,500,10:
2
2
2
2
2
2
2
2
1
1
1
321
-
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Seepage and Flow Net calculation 11
mHCpoatheadcPiezometri
mhHHBpoatheadcPiezometri
mhHHApoatheadcPiezometri
headcPiezometri
Step
C
B
A
0:int
4.271.07.10107.10:int
29.971.00.1100.1:int
:
:2
-
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Seepage and Flow Net calculation 11
day
m
daycm
mcmwidthLkq
damthethroughrateflowtheeertomethodSecond
day
m
daycm
mcmwidth
N
NHkq
damthethroughrateFlow
Step
soil
d
f
3
3
5.311.52sin1.52tan5008.1sec246060
100sec00004.0)sin)(tan(
:mindet
)2(
3750014
310
sec246060
100sec00004.0
:
)1(
:3
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Seepage and Flow Net calculation 12
23m23m 30m
6m
6m18m
Draw a flow net in the earth damshown below. Compute the quantityof flow in cubic meter per daythrough the dam using twomethods.What is the head at point A & B?
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Seepage and Flow Net calculation 12
23m23m 30m
6m
6m18m
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Seepage and Flow Net calculation 12
mhmLmLmLmh
cmkmHmHGiven
dam
soilww
24618,23,30,23,6
,sec00007.0,6,18:
321
21
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Seepage and Flow Net calculation 12
mHHdd
L
mxLxd
mHh
x
mHLh
damtheexistwillwaterthewhereeDeter
Step
mhmLmLmLmh
cmkmHmHGiven
ww
wdam
wdam
dam
soilww
9.18.43sin
618
8.43cos
7.56
8.43cos
7.56
sincoscos
7.56)5.123.05.12(7.17307.17)3.0(
7.178.43tan
624
8.43tan
5.1296.0
6188.43tan
,8.432324tantan
:min
:1
24618,23,30,23,6
,sec
00007.0,6,18:
2
2
2
2
2
2
21
2
2
2
2
1
1
1
321
21
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Seepage and Flow Net calculation 12
mN
HhmHHH
dropsheadCalculate
Step
d
ww 6.020
12,12618
:
:2
21
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Seepage and Flow Net calculation 12
mH
mhHH
headcPiezometri
Step
m
N
HhmHHH
dropsheadCalculate
Step
B
A
d
ww
0
84.96.09.2126.3
:
:3
6.0
20
12,12618
:
:2
21
-
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Seepage and Flow Net calculation 12
day
m
daycm
mcmwidthLkq
damthethroughf lowcalculatetomethodsSecond
daym
daycmmcmwidth
NNHkq
mwidth
damthethroughrateFlow
Step
soil
d
f
soil
3
3
08.08.43sin8.43tan19.1sec246060
100sec00007.0)sin)(tan(
:
)2(
11.0120312sec246060
100sec00007.0
1
:
)1(
:4
-
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Thank you.Source: http://starb.on.coocan.jp/
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