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GEOSYNTHETICS ENGINEERING: IN THEORY AND PRACTICE
Prof. J. N. Mandal
Department of civil engineering, IIT Bombay, Powai , Mumbai 400076, India. Tel.022-25767328email: [email protected]
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Module-5LECTURE- 22
GEOSYNTHETICS IN PAVEMENTS
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
RECAP of previous lecture…..
Design of reinforced roads
Design parameters
Design charts
Design procedure
Joining of geotextile
Rut repair
Calculation of critical dead weight of vibro-roller
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Stress reduction downwards with depth of granular fill (Rankilor/ Bonar, 1997)
The reduction in pressure downwards up to 1 m depth ofgranular fill can be calculated as,
Pr = 0.9 x Tp x 10-6D
Pr = induced pressure at any particular depth (D) from thesurface (kN/m2)
Tp = Surface pressure of tier (kN/m2)
D = Fill depth (m)
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Generally, cohesive strength of the subgrade soil shouldbe 1/5th of the load on subgrade to support the vehicle.
If the subgrade soil is within 1 m depth, the appliedpressure on the subgrade due to surface tire pressure = Pr
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Example:
Weight of heavy vehicle = 1800 kNThis weight will be equally shared by four tires.
The load on each tire = 1800/4 = 450 kN
Contact area of tire = 0.62 = 0.36 m2
Surface pressure of tire (Tp) = 450/0.36 = 1250 kN/m2
Let, the subgrade is at 0.9 m depth from the surface.
Calculate the induced pressure on subgrade soil. Alsocalculate the require cohesion of subgrade soil to supportthe vehicle.
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Solution:
Pr = 0.9 x Tp x 10-6D
= 0.9 x 1250 x 10-(6 x 0.9)
= 1125 x 10-0.54
= 1125 x 0.29 = 324 kN/m2
So, the induced load on the subgrade = 324 kN/m2
Generally, cohesive strength of subgrade soil should be1/5th of the load on subgrade to support the vehicle.
Therefore, minimum undrained shear strength of thesubgrade soil = 324/5 = 65 kN/m2
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Advantages of unpaved roads Maintain the separation between subgrade and sub-base, Reduce the required amount of good quality aggregates, Minimize rut depth, Construction of road is very easy, Site preparation is less, Reduce the depth of excavation Prevent contamination of the sub-base materials, Prevent failure of pavement structures, Improve drainage systems Provide stabilization Reduce intensity of stress on the subgrade, Reduce differential settlement Extend the life of pavements, and Reduce maintenance requirements
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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DESIGN CHARTS OF U.S. FOREST SERVICE (USFS) FOR UNPAVED ROADS
Steward et al. (1977) developed a design method for U.S.Forest service (USFS). The method has following limitations:
The aggregate layer is cohesionless (non-plastic) andcompacted to CBR = 80.
Undrained shear strength of the subgrade is about 90 kPa(CBR < 3),
Vehicle passes less than 10,000
Geosynthetics serviceability criteria should be considered
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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The method includes the following parameters:
Vehicle passes,
Tire pressure,
Subgrade strength,
Axle configuration, and
Rut depths
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Bearing capacity factor (Nc) for different ruts and traffic conditions both without and with geotextile separators
(After Stewards et al., 1977)
Condition Ruts (mm)
Traffic (passes
of 80 kN axel
equivalent)
Bearing
capacity
factor, NcWithout
geotextile
< 50
> 100
> 1000
< 100
2.8
3.3
With
geotextile
< 50
> 100
> 1000
< 100
5.0
6.0
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Single wheel load Tandem wheel load Dual wheel load
U.S. Forest Service design curves (After Steward et al., 1977)
The undrained shear strength of the soil (cu) multiplied bythe bearing capacity factors give the stress level (cu Nc).
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Design ProcedureStep 1: Calculate the strength of subgrade soil at differentlocations. The subgrade soil strength can be determinedfrom field CBR, vane shear, cone penetrometer and resilientmodulus test.
The undrained shear strength of soil (c), in kPa = 30x CBR
Step 2: Check the type of loadings• Single wheel loads,
• Dual wheel loads, and
• Maximum dual tandem wheel loads
Step 3: Check the amount of traffic (N= 6000 passes)Step 4: Check the rutting depths. It may vary from 50 mm to75 mm.
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Step 5: Determine bearing capacity factor (Nc) without andwith geotextile
Bearing capacity factor (Nc) for different ruts and traffic conditions both without and with geotextile separators
(After Stewards et al., 1977)
Condition Ruts (mm)Traffic (passes of 80 kN axel equivalent)
Bearing capacity factor, Nc
Without geotextile
< 50> 100
> 1000< 100
2.83.3
With geotextile
< 50> 100
> 1000< 100
5.06.0
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Step 6: Calculate the required thickness of aggregate fromthe USFS design charts for different loading conditions.
Step 7: Select design thickness without and with geotextile.Knowing c Nc value, determine the required design thicknessof pavement without and with geotextile.
Step 8: Determine geotextile survivability, drainage andfiltration requirements.
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Example: Design an unpaved road with proper geosyntheticlayer for the condition given:
Number of passages = 1000;
Single axel load = 80 kN;
Single wheel load = 40 kN;
Required tire pressure = 550 kPa;
Rut depth 50 mm or less.
Characteristics of the sub-grade soil,
CBR value = 0.5;
Undrained shear strength = 15 kPa.Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Solution:According to Stewart et al. 1977, Without geotextileAs per given data when number of passage = 1000 and rutdepth ≤ 50 mm, Nc = 2.8Now, cNC = 15 2.8 = 42 kPaFrom the design chart for single wheel load,Depth of aggregate (h0) = 700 mmWith geotextileAs per given data when number of passage = 1000 and rutdepth ≤ 50 mm, Nc = 5Now, cNC = 15 5 = 75 kPaFrom the same design chart,Depth of aggregate (h) = 500 mm
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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So, the thickness of aggregate saved due to application ofgeotextile, h = 0.7 – 0.5 = 0.20 m
%58.28100x70.020.0savingofpercentage
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Unpaved road without and with geosyntheticProf. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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MODIFIED CALIFORNIA BEARING RATIO (CBR) TEST
Laboratory modified CBR test for the determination of reinforcement ratio (a) without geogrid (b) with geogrid
Reinforcement ratio (LCR) = the ratio of load carried by soilwith geotextile to the load carried in unreinforced case.
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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21
2030A
CBR36P)21.2Nlog24.3(h
h = Thickness of stone aggregate (mm),N = Number of passes of traffic,P = Equivalent single wheel load (N),A = Contact area of tire (mm2)
In reinforced condition (CBR) = LCR x CBRunreinforced
The US Army Corps of Engineers modified the CBR designmethod (WES TR3-692) as reported by Koerner (2005).
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Example:Equivalent single wheel load of 40 kN for 1000 passes.
Tire contact area (A) = 300 x 450 mm2
CBRunreinforced = 1.5,
After placing geosynthetic, LCR = 1.6
Evaluate the percentage saving in aggregate thickness.
Solution:
21
2030A
CBR36P)21.2Nlog24.3(h
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Without using geosynthetic:
mm78.3092030
450x3005.136
40000)21.21000log24.3(h2
1
0
Using geosynthetic:
LCR = 1.6, CBRreinforced = 1.6 x 1.5 = 2.4
mm54.2372030
450x3004.236
40000)21.21000log24.3('h2
1
Saving in stone aggregates:
Δh = h0 – h' = (309.78 – 237.54) mm = 72.24 mm
percentage saving = (72.24/237.54) x 100 = 30.41%Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Relationship between CBR value and thickness of pavement for wheel load = 40 kN and tire area = (300 x 450) mm2 for different coverages.
CBR (%)Thickness (mm)
N = 10 N = 100 N = 1000 N = 100000.5 253.04 403.47 553.91 704.341 176.15 280.86 385.58 490.30
1.5 141.52 225.65 309.78 393.912 120.52 192.18 263.83 335.48
2.5 105.95 168.94 231.93 294.923 95.00 151.48 207.96 264.44
3.5 86.34 137.66 188.99 240.324 79.22 126.31 173.41 220.50
4.5 73.20 116.72 160.24 203.765 68.01 108.44 148.87 189.30
5.5 63.45 101.16 138.88 176.606 59.37 94.67 129.97 165.27
6.5 55.70 88.81 121.92 155.037 52.34 83.46 114.57 145.69
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Thickness of pavement for different CBR valuesWheel load = 40 kN, tire contact area (A) = (300 x 450) mm2,
LCR = 1.6Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Design chart for GG-reinforced unpaved roads, R = h/h0(After Giroud et al., 1984)
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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DESIGN OF PAVEMENT IN UNREINFORCED AND REINFORCED CONDITIONS
Design of pavement thickness without geogrid (IRC37)
Step 1: Determine axle load, wheel load (P), tire pressure (p)
Step 2: Determine sub-grade CBR
Step 3: Determine traffic loading category
Step 4: As per IRC-37- 2001,
Determine lane distribution factor (D) depending on thetype of road (IRC-37, 2001)
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Lane distribution factor (D) for different types of roads (IRC-37, 2001)
Type of roadsLane distribution factor in terms of percentage of the
total number of commercial vehicles in both directions
Single lane roads 100%Intermediate width roads 100%
Two lane single carriageway roads 75%Four lane single carriage roads 40%
Dual carriageway roads
Dual two lane 75%
> two lane Reduced by 20% for each additional laneProf. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Determine Initial traffic (A) in the year of completion ofconstruction in terms of the number of commercial vehiclesper day
DrPA x )1(
A = Initial traffic in the year of completion of construction in
terms of the number of commercial vehicles per day
P = number of commercial vehicles as per last count
r = annual growth rate of commercial vehicles (%)
x = number of years between the last count and the year of
completion of construction
D = lane distribution factor (%) Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Determine vehicle damage factor depending on the initialtraffic volume (A) during construction period from thefollowing Table (IRC-37, 2001) .
Initial traffic volume in terms of number of commercial vehicles
per day
Vehicle damage factor
Rolling/Plain Terrain
Hilly Terrain
0-150 1.5 0.5150-1500 3.5 1.5
More than 1500 4.5 2.5
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Determine cumulative number of standard axle load (Ns).
Ns = Cumulative number of standard axle load (msa)
r = annual growth rate of commercial vehicles (%)A = Initial traffic in the year of completion of construction interms of the number of commercial vehicles per dayn = design life of pavement after completion (years)
F = vehicle damage factor
Fxr
]1)r1[(A365Nn
s
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Step 5: Knowing the value of CBR and Ns, determine the totalpavement thickness (H) form the following design charts.
Design chart for determining pavement thickness, traffic 1-10 msa (IRC-37, 2001)
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Design Chart for determining pavement thickness, traffic 10-150 msa (IRC-37, 2001)
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Please let us hear from you
Any question?
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay
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Prof. J. N. Mandal
Department of civil engineering, IIT Bombay, Powai , Mumbai 400076, India. Tel.022-25767328email: [email protected]
Prof. J. N. Mandal, Department of Civil Engineering, IIT Bombay