Geometry Section 3-2 1112

38
SECTION 3-2 ANGLES AND PARALLEL LINES Wednesday, December 14, 2011

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Transcript of Geometry Section 3-2 1112

Page 1: Geometry Section 3-2 1112

SECTION 3-2ANGLES AND PARALLEL LINES

Wednesday, December 14, 2011

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ESSENTIAL QUESTIONS

HOW DO YOU USE THEOREMS TO DETERMINE THE RELATIONSHIPS BETWEEN SPECIFIC PAIRS OF ANGLES?

HOW DO YOU USE ALGEBRA TO FIND ANGLE MEASUREMENTS?

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POSTULATES AND THEOREMS

CORRESPONDING ANGLES POSTULATE

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POSTULATES AND THEOREMS

CORRESPONDING ANGLES POSTULATE

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF

CORRESPONDING ANGLES IS CONGRUENT.

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POSTULATES AND THEOREMS

CORRESPONDING ANGLES POSTULATE

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF

CORRESPONDING ANGLES IS CONGRUENT.

∠1 ≅ ∠5

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POSTULATES AND THEOREMS

ALTERNATE INTERIOR ANGLES THEOREM

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POSTULATES AND THEOREMS

ALTERNATE INTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF

ALTERNATE INTERIOR ANGLES IS CONGRUENT.

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POSTULATES AND THEOREMS

ALTERNATE INTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF

ALTERNATE INTERIOR ANGLES IS CONGRUENT.

∠4 ≅ ∠6

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POSTULATES AND THEOREMS

CONSECUTIVE INTERIOR ANGLES THEOREM

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POSTULATES AND THEOREMS

CONSECUTIVE INTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF CONSECUTIVE INTERIOR ANGLES IS

SUPPLEMENTARY.

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POSTULATES AND THEOREMS

CONSECUTIVE INTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF CONSECUTIVE INTERIOR ANGLES IS

SUPPLEMENTARY.

∠4 AND ∠5 ARE SUPPLEMENTARY

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POSTULATES AND THEOREMS

ALTERNATE EXTERIOR ANGLES THEOREM

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POSTULATES AND THEOREMS

ALTERNATE EXTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF ALTERNATE EXTERIOR ANGLES IS

CONGRUENT.

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POSTULATES AND THEOREMS

ALTERNATE EXTERIOR ANGLES THEOREM

IF TWO PARALLEL LINES ARE CUT BY A TRANSVERSAL, THEN EACH PAIR OF ALTERNATE EXTERIOR ANGLES IS

CONGRUENT.

∠2 ≅ ∠7

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EXAMPLE 1

IN THE FIGURE, m∠4 = 51°. FIND THE MEASURE OF EACH ANGLE. GIVE A JUSTIFICATION TO

YOUR ANSWER.a. m∠2

b. m∠3

c. m∠6

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EXAMPLE 1

IN THE FIGURE, m∠4 = 51°. FIND THE MEASURE OF EACH ANGLE. GIVE A JUSTIFICATION TO

YOUR ANSWER.a. m∠2

51°; VERTICAL ANGLESWITH ∠4

b. m∠3

c. m∠6

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EXAMPLE 1

IN THE FIGURE, m∠4 = 51°. FIND THE MEASURE OF EACH ANGLE. GIVE A JUSTIFICATION TO

YOUR ANSWER.a. m∠2

51°; VERTICAL ANGLESWITH ∠4

b. m∠3129°; SUPPLEMENTARY ANGLES WITH ∠4

c. m∠6

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EXAMPLE 1

IN THE FIGURE, m∠4 = 51°. FIND THE MEASURE OF EACH ANGLE. GIVE A JUSTIFICATION TO

YOUR ANSWER.a. m∠2

51°; VERTICAL ANGLESWITH ∠4

b. m∠3129°; SUPPLEMENTARY ANGLES WITH ∠4

c. m∠651°; ALTERNATE INTERIOR ANGLES WITH ∠4

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EXAMPLE 2

USE THE FIGURE, IN WHICH a||b, m∠2 = 125°, AND c||d||e, TO FIND THE MEASURE OF EACH NUMBERED ANGLE. PROVIDE A REASON FOR

THE ANSWER FOR EACH MEASURE.

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EXAMPLE 2

USE THE FIGURE, IN WHICH a||b, m∠2 = 125°, AND c||d||e, TO FIND THE MEASURE OF EACH NUMBERED ANGLE. PROVIDE A REASON FOR

THE ANSWER FOR EACH MEASURE.

m∠1 = 125°; VERTICAL

WITH ∠2

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EXAMPLE 2

USE THE FIGURE, IN WHICH a||b, m∠2 = 125°, AND c||d||e, TO FIND THE MEASURE OF EACH NUMBERED ANGLE. PROVIDE A REASON FOR

THE ANSWER FOR EACH MEASURE.

m∠1 = 125°; VERTICAL

WITH ∠2m∠3 = 55°; CONSECUTIVE

INTERIOR WITH ∠2

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EXAMPLE 2

USE THE FIGURE, IN WHICH a||b, m∠2 = 125°, AND c||d||e, TO FIND THE MEASURE OF EACH NUMBERED ANGLE. PROVIDE A REASON FOR

THE ANSWER FOR EACH MEASURE.

m∠1 = 125°; VERTICAL

WITH ∠2m∠3 = 55°; CONSECUTIVE

INTERIOR WITH ∠2m∠4 = 125°; CONSECUTIVE

INTERIOR WITH ∠3

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EXAMPLE 2

USE THE FIGURE, IN WHICH a||b, m∠2 = 125°, AND c||d||e, TO FIND THE MEASURE OF EACH NUMBERED ANGLE. PROVIDE A REASON FOR

THE ANSWER FOR EACH MEASURE.

m∠1 = 125°; VERTICAL

WITH ∠2m∠3 = 55°; CONSECUTIVE

INTERIOR WITH ∠2m∠4 = 125°; CONSECUTIVE

INTERIOR WITH ∠3

m∠5 = 55°; SUPPLEMENTARY WITH ∠4

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

2x − 10 = x + 15

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

2x − 10 = x + 15−x −x

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

2x − 10 = x + 15−x −x +10+10

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

2x − 10 = x + 15−x −x +10+10

x = 25

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

a. IF m∠2 = 2x − 10 AND

m∠6 = x + 15, FIND x.

2x − 10 = x + 15−x −x +10+10

x = 25

SINCE THE ANGLES ARE CORRESPONDING, THEY ARE CONGRUENT, MEANING THEY ARE

EQUAL.

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

4(y − 25) + 4y = 180

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

4(y − 25) + 4y = 1804y − 100 + 4y = 180

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

4(y − 25) + 4y = 1804y − 100 + 4y = 180

8y − 100 = 180

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

4(y − 25) + 4y = 1804y − 100 + 4y = 180

8y − 100 = 1808y = 280

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EXAMPLE 3

USE THE FIGURE TO FIND THE INDICATED VARIABLE. EXPLAIN YOUR REASONING.

b. IF m∠7 = 4(y − 25) AND

m∠1 = 4y, FIND y.

4(y − 25) + 4y = 1804y − 100 + 4y = 180

8y − 100 = 1808y = 280

y = 35

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CHECK YOUR UNDERSTANDING

CHECK OUT PROBLEMS 1-10 ON PAGE 181.

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PROBLEM SET

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PROBLEM SET

P. 181 #11-35 ODD

“YOU CAN FOOL TOO MANY OF THE PEOPLE TOO MUCH OF THE TIME.” - JAMES THURBER

Wednesday, December 14, 2011