Geometry 7.6 Proportional Lengths. Proportional Lengths AC and XZ are divided proportionally...
Transcript of Geometry 7.6 Proportional Lengths. Proportional Lengths AC and XZ are divided proportionally...
Geometry
7.6 Proportional Lengths
Proportional Lengths
AC and XZ are divided proportionally if…
. . .
. . .X
A B C
Y Z
=BC
XYAB
YZ
Example:
2 9
184=
2
9 18
4
Triangle Proportionality Thm. If a line parallel to one side of a triangle intersects
the other two sides, then it divides those sides
proportionally. big A
small A
whole Abig B
small B
whole B=
side C1
side C2
=
=
= = = =
whole A
small A
whole B
small B
side C1
side C2
big A
small A
big B
small B
big A
whole A
big B
whole B
whole Bwhole A
big A big B
small A
small B
big A
big B
whole A
whole B
All of these proportions, and their inverses, work.The key is to use the easiest one to solve each problem.
Think of it as two separate similar triangles.
Corollary
If three // lines intersect two transversals,…then they divide the transversals
proportionally.
a
b
c
d =ab
cd
Triangle Angle Bisector Thm. If a ray bisects an angle of a triangle,… then it divides the opposite side into
segments proportional to the other two sides.a
bc
d
=ab
cd
Directions: Use the given information and the triangle above to find the missing segment.
3. GE = 15 DE = 27 HF = 20 DH = ?
4. DE = 20 HF = 4 DH = 12 DG = ?
E F
G H
D
Directions: Use the given information and the diagram to find x.
2. AB = 27 BC = 18 DE = x + 10 EF = x
3. AB = 25 – x BC = x DE = 16 EF = 4
A
B
C
D
E
F
Directions: is and angle bisector of . Find x.
2. RP = x PQ = 12.5 RS = 8 SQ = 10
3. RP = 10 PQ = 20 RS = x RQ = 15
P
QR S
PS .RPQ
HW
P. 271 (1-7) P. 272-273 (1-14, 20, 21) Quiz 7.4-7.6 Tomorrow
A few from the HW
P. 272 #5, #14
An Example
15
520
12
416
=
18 24
=
=
= =
= =
20
5
16
4
18
24
15
5
12
4
15
20
12
161620
15 12
5
4
15
12
20
16
Solve for x. (figure not to scale)
15
27
12
20
x
= x
15
12
20
= x
5
4
20
Reduce by 3
times 4 equals
times 4 equals
x = 16
Solve for x.
18
27
x
x + 10
=18
27
x
x + 10
Reduce by 9.
=2
3
x
x + 10
2(x + 10) = 3x
2x + 20 = 3x
x = 20
20
30
Solve for x.
1512
18
x
=12
15
x
18 - x
18 - x
Reduce by 3.
=4
5
x
18 - x
4(18 – x) = 5x
72 – 4x = 5x
9x = 72
x = 8
8 10