Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing...

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Geometric Sequences and Series Unit 10.3

Transcript of Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing...

Page 1: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Geometric Sequences and Series

Unit 10.3

Page 2: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Practical Application

“The company has been growing geometrically”

Page 3: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Purpose

1. Calculate for a geometric sequence

2. Calculate for the nth term

3. Compute for geometric means

4. Calculate for sums of geometric series

5. Calculate for sum in sigma notation

Page 4: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Calculate for geometric sequence

1. 4, 11, 30.25 What are the next 4 in the series?Find common Ratio - Second term divided

by first term11 /4 = 2.75: common ratio is 2.7530.25 * 2.75 = 83.1983.19 * 2.75 = 228.77228.77 * 2.75 = 629.11

Page 5: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Page 615 Problems 1 - 6

Find the common ratio and the next 3 terms

1. Common ratio = -2 2, -4, 82. Common ratio = -.75 -27/128 81/512 -243/2,048

3. Common ratio = 1.5 1.69, 2.53, 3.8

4. Common ratio = 2.5 125, 312.5, 781.25

5. Common ratio = 5 250x, 1250x, 6250x

6. Common ratio = ¼ x, 1/4x, 1/16x

Page 6: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Formula

an = a1rn – 1

an = final term in sequence

a1 = first term in sequence

r = ratio

n = term in sequence

Page 7: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Example

1. Find the 9th term of the geometric sequence 4, 14, 49

1. Find the ratio 14/4 = 7/2 or 3.5

2. an = 4(3.5)8

3. an = 4(22518.75)

4. an = 90,075.8

Page 8: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Problems

Page 615 Problems 20 - 24

Page 9: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Geometric Means

Write a sequence that has two geometric means between 480 and -7.5

Step 1. 480, a, b, -7.5 (4 terms)Step 2. a4 = a1rn-1

-7.5 = 480r4-1

-7.5 = 480r3 -7.5/480 = r3

-1/64 = r3

-1/4 = r a2 =-120 =(480*-.25) a3 =30 = (-120*-.25)

Page 10: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Problems

Unit 10.3 Page 615

Problems 32 - 36

Page 11: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Geometric Series

Geometric Sequence

2, 4, 8, 16….

Geometric Series is the sum of the terms of a geometric sequence

2 + 4 + 8 + 16…

Formulas

Sn = a1(1 – rn)/(1 – r)

Sn = a1 – anr

(1 – r)

Page 12: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Explanation of Formulas

a) Sn = a1(1 – rn)/(1 – r)

b) Sn = a1 – anr nth partial sum

(1 – r)

Page 13: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Examples

Page 612 Guided practice 6a

Find the first 11 terms 7 + (-24.5) + 85.75

a1 = 7 r = -24.5/7 = -3.5

s11 = 7(1 – (3.5)11/(1 – (-3.5))

s11 = 1,501,877.34

Page 14: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Examples

Page 612 Guided practice 6b

Find the sum of the first n terms

a1 = -8 an = 131,072 r = -4

Sn = a1 – anr

1 – r

= -8 - (131,072)(-4) = 104,856

1 – (-4)

Page 15: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Geometric Sum in Sigma Notation

7

∑ 3(5)n – 1

n = 2

See board

Page 16: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Sum of an infinite Geometric Series

S = a1

1 – r

Problem: Find the sum of 10, -5, 2.5

r = -.5, a1 = 10

S = 10/(1 – (-.5) = 6.67

Page 17: Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing geometrically”

Problems

Page 605-6

Problems 40 – 46, 48 – 52, 56,57