Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing...
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Transcript of Geometric Sequences and Series Unit 10.3. Practical Application “The company has been growing...
Geometric Sequences and Series
Unit 10.3
Practical Application
“The company has been growing geometrically”
Purpose
1. Calculate for a geometric sequence
2. Calculate for the nth term
3. Compute for geometric means
4. Calculate for sums of geometric series
5. Calculate for sum in sigma notation
Calculate for geometric sequence
1. 4, 11, 30.25 What are the next 4 in the series?Find common Ratio - Second term divided
by first term11 /4 = 2.75: common ratio is 2.7530.25 * 2.75 = 83.1983.19 * 2.75 = 228.77228.77 * 2.75 = 629.11
Page 615 Problems 1 - 6
Find the common ratio and the next 3 terms
1. Common ratio = -2 2, -4, 82. Common ratio = -.75 -27/128 81/512 -243/2,048
3. Common ratio = 1.5 1.69, 2.53, 3.8
4. Common ratio = 2.5 125, 312.5, 781.25
5. Common ratio = 5 250x, 1250x, 6250x
6. Common ratio = ¼ x, 1/4x, 1/16x
Formula
an = a1rn – 1
an = final term in sequence
a1 = first term in sequence
r = ratio
n = term in sequence
Example
1. Find the 9th term of the geometric sequence 4, 14, 49
1. Find the ratio 14/4 = 7/2 or 3.5
2. an = 4(3.5)8
3. an = 4(22518.75)
4. an = 90,075.8
Problems
Page 615 Problems 20 - 24
Geometric Means
Write a sequence that has two geometric means between 480 and -7.5
Step 1. 480, a, b, -7.5 (4 terms)Step 2. a4 = a1rn-1
-7.5 = 480r4-1
-7.5 = 480r3 -7.5/480 = r3
-1/64 = r3
-1/4 = r a2 =-120 =(480*-.25) a3 =30 = (-120*-.25)
Problems
Unit 10.3 Page 615
Problems 32 - 36
Geometric Series
Geometric Sequence
2, 4, 8, 16….
Geometric Series is the sum of the terms of a geometric sequence
2 + 4 + 8 + 16…
Formulas
Sn = a1(1 – rn)/(1 – r)
Sn = a1 – anr
(1 – r)
Explanation of Formulas
a) Sn = a1(1 – rn)/(1 – r)
b) Sn = a1 – anr nth partial sum
(1 – r)
Examples
Page 612 Guided practice 6a
Find the first 11 terms 7 + (-24.5) + 85.75
a1 = 7 r = -24.5/7 = -3.5
s11 = 7(1 – (3.5)11/(1 – (-3.5))
s11 = 1,501,877.34
Examples
Page 612 Guided practice 6b
Find the sum of the first n terms
a1 = -8 an = 131,072 r = -4
Sn = a1 – anr
1 – r
= -8 - (131,072)(-4) = 104,856
1 – (-4)
Geometric Sum in Sigma Notation
7
∑ 3(5)n – 1
n = 2
See board
Sum of an infinite Geometric Series
S = a1
1 – r
Problem: Find the sum of 10, -5, 2.5
r = -.5, a1 = 10
S = 10/(1 – (-.5) = 6.67
Problems
Page 605-6
Problems 40 – 46, 48 – 52, 56,57