Geo Tech Engg II 8th Sem

7/23/2019 Geo Tech Engg II 8th Sem

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SYLLABUS

EC – 801 Geo Tech Engg II



Lesson Plan

Session JAN 2015-JUNE 2015

IES COLLEGE

IES COLLEGE OF TECHNOLOGY, BHOPAL

Lesson Plan

DEPARTMENT CIVIL ENGG. SESSION JAN 2015 – JULY 2015

NAME OF THE

TEACHER

Aayus! R!"a#!ya SEMESTER VIII

SU$JECT

G%&. T%"'!"a( E')).II SU$JECT CODE CE*+01

UNIT – 1

S.N

O

TOPIC PROPOS

ED.

NO.OF

LECTUR

ES

ACTUAL

NO.OF

LECTURE

S

Date NO OF THE

STUDENTS

1. Sa((&, F&u'-a!&'s / Ty% &

&u'-a!&'s sa((&, a'- -%%. $%a#!')

"aa"!y & &u'-a!&' &'

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2

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UNIT -

S.N

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TOPIC PROPOSED

. NO.OF

LECTURES

ACTUAL

NO.OF

LECTURES

Date NO OF THE

STUDENTS

1. D%% F&u'-a!&' / P!(% &u'-a!&'

Ty%s & !(%s %s!8a!&' &

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9



s&!(s.

2. Sa!" a'- -y'a8!" &#8u(a%.. P!(%

(&a- %s

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s7!' #!"!&'

4

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&# sa3!(!y !(s a'- s!s #%8%-!a(

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2

UNIT – !

S.N

O

TOPIC PROPOSED

. NO.OFLECTURES

ACTUAL

NO.OFLECTURE

S

Date NO OF

THESTUDENTS

1 S&!( I8#&%8%' T%"'!;u%s /

C&8a"!&'. F!%(- a'- (a3&#a&#y

8%&-s P#&"&# "&8a"!&'

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4

2 P#&%#!%s & s&!( a%"%- 3y

"&8a"!&'. Va#!&us

%;u!8%' &# !%(- "&8a"!&' a'-

%!# su!a3!(!y

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4 F!%(- "&8a"!&' "&'#&(. L!

!"7'%ss.

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a'- sa3!(!sa!&' 3y )#&u!').

4

9 G%&*sy'%!"s y%s u'"!&'s

8a%#!a(s a'- us%s.4

UNIT -"



S.N

O

TOPIC PROPOSED

. NO.OF

LECTURES

ACTUAL

NO.OF

LECTURES

Date NO OF THE

STUDENTS

1. S&!( E<(&#a!&' a'- F&u'-a!&'s

&' E<a's!% a'- C&((as!3(%

s&!(s / M%&-s & s&!(

%<(&#a!&'.

2

2. P(a''!') & %<(&#a!&' #&)#a88%

&# 3u!(-!')s !),ays a'- %a#

-a8s.D!su#3%- a'- u'-!su#3%- sa8(%s

a'- sa8(%#s &# "&((%"!') %8.

4

4. Ca#a"%#!s!"s & %<a's!% a'-

"&((as!3(% s&!(s %!# #%a8%'4

9. C&'s#u"!&' %"'!;u%s &'

%<a's!% a'- "&((as!3(% s&!(s.

CNS (ay%#.

2

UNIT -#

S.N

O

TOPIC PROPOSED

. NO.OF

LECTURES

ACTUAL

NO.OF

LECTURES

Date NO OF

THE

STUDENTS

1. S%% !(%s=$u(7%a-s a'- Ma"!'%

&u'-a!&' / C(ass!!"a!&' & s%%

!(%s=3u(7%a-s.

Ca'!(%%# a'- a'"&#%- s%% !(%s

4

2. C&%#-a8s 8a%#!a(s y%s a'-

a(!"a!&'s.

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2

4. Mass*s#!') a'a(&)y Nau#a(

#%;u%'"y. E%" & !3#a!&' &'

s&!(s.

V!3#a!&' !s&(a!&'.

4

9. C#!%#!a &# -%s!)'. D%s!)' & 3(&"7

&u'-a!&' &# !8a" y% &

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2

PREPARED $Y/ Aayus! R!"a#!ya APPROVED $Y/




$.E. >+

SEM? Ass!)'8%' *1G%& T%" E')) II >CE*+01?

Date o$ Ass%&n/ Date o$ S'()%ss%on*

@.1Defne Ultimate bearing Capacity. net Ultimate bearing Capacity and net

sae bearing Capacity

Ans. A) Ultimate bearing Capacity :The Ultimate bearing capacity is

the gross pressure at the base o the oundation at which the soil ails in

shear

b)net Ultimate bearing Capacity; The net Ultimate bearing capacity

is the net increase in pressure at the base o oundation that causesshear ailure o soil.It is eual to the gross pressure minus o!erburden

pressure.

nu "u#yD

c) net safe bearing Capacity: It is the net soil pressure which can be

saely appliedto the soil considering only shear ailure.It is obtained by

di!iding the net ultimate bearing capacity by a suitable actor o

saety.Thus

$ns "nu%&

2 8a#7s

@.2

'rite the e(pression or a) immediate settlement o cohesi!e soil by

C*+,IC*,-

b) the teraghi/s bearing capacity euation

c) ultimate bearing capacity euation by 0-A1DT+/s A1A+2I

Ans. A)i"3445#67)%,s)I

b) u " c/1c 8 o18.9231y

c) u"9.5cu8yD !alid only or ooting with perectly smooth base in

contact with soil

58a#7s

@.4'rite the classifcation o settlement o oundation under loads

Ans.

5.Immediate or elastic settlement4i)#It ta;es place during or

immediately ater construction o the structure.

7.Consolidation ettlement4c)#This component o the settlement occurs

due to gradual e(pulsion o water rom the !oids o soil.

<.econdary consolidation settlement4s)#This component o the

settlement is due to secondary consolidation.this settlement occurs

ater completion o the primary consolidation

Thus total settlement is gi!en by "i8c8s

5 8a#7s



@.9 'rite the assumption used in teraghi/s bearing capacity theory.

Ans. 5. The base o ooting is rough

7.The ooting is laid at a shallow depthi.e D"= 3

<.The shear strength o soil abo!e base o ooting is neglected.The soil

abo!e the base is replaced by uniorm surchargw 2D .

.The load on the ooting is !ertical and is uniormly distributed.

9.The ooting is long i.e +%3 ratio is infnite>where 3 is the width and + is

the length o the ooting.

?.The shear strength o soil is go!erned by @ohr Coulomb euation.

5 8a#7s

@.+'rite the limitation o plate load test

Ans. 4i) It has limited depth o inBuence. It could only gi!e the bearing capacity

o soils with depth up to two times the diameter o plate.

4ii) It may not pro!ide inormation on the potential or long term consolidation

o oundation soils. 4iii) There is scale eect as the sie o test plate is smaller

than actual oundation.

>!? T& )a!' a""%ss & %s &s!!&' %<"aa!&' !s "a##!%- &u ,!" "aus%s s!)'!!"a'

)#&u'- -!su#3a'"%. T% "a')% !' )#&u'- s#%ss (%a-s & % "a')% & s&!( #&%#!%s

,!" % %s !s (a''%- & !'%s!)a%.

5 8a#7s

@.Determine the ultimate bearing capacity o a strip ooting 5.7 m wide

and ha!ing the depth o oundation o 5 m .Use teraghi theory and

assume general shear ailure ta;e

/" <9E>2"5F G1%@<>and c/"59 G1%@<.

ol. u " c/1c 8 2D 18.9231y

&or /" <9E 1c"9H.F 1"5. and 1y"7.

u"599H.F 85F55. 8.95F5.77.

"7JHJ G1%@7

58a#7s

@.10Draw the diagram which show dierent type o shear ailure

Ans.Type o shear ailure is 5 8a#7s



@.11A ooting 7 m suare is laid at a depth o 5.< m below the ground

surace Determine the net ultimate bearing capacity using I code

method.Ta;e 2"7J G1%@<> /"<JE and c/"J

ol. &or /"<JE

1c"<J.5 1"5F. and 1y"77.

c"5.< "5.7 and y".F

dc " 5 8 J.74D %3)tan 49E8 /%7)

"58.745.<%7)tan?JE"5.7<

d"dy"5 8.54D %3)tan 49E8 /%7)

"5.55

nu"c1ccdcic 8 41 #5) di 8 .9231yydyiy'/

"J85.<7J45F.#5)5.75.5558J.97J777..F5.555

"5JJJ G1%m7

5 8a#7s

@.12Determine the net ultimate bearing capacity o the ooting in ue 55. I

a)the water table rise to the le!el o the base

b)the water table rises to the ground surace

c)the water table is 5 m below the base

ol.a)'/".9

Thereore>nu" 5.<7J45F.#

5)5.75.5558.97J777.J.F5.55.9

"FJ5 G1%m7

b) '/".9J. the surcharge is also reduced as the eecti!e stress is

reduced.Thus

nu"5.<47J#K.F5)45F.#5)5.75.5558.97J777.J.F(5.55.9

"9J? G1%m7

c)'/ is obtained by linear interpolation

'/"J.984.95)%7".H9

5 8a#7s



Thereore> nu"5.<745F.#5)5.75.5558.97J(777.J.F5.55.H9

"KJ5 G1%m7

@.14'rite the eect o water table on bearing capacity.

Ans. Ultimate bearing capacity has been de!eloped on the assumption

that the

water table is located at a great depth.I the water table is located close

to the

oundation>the bearing capacity euation needs

modifcation

CASE I –Water table located above the base of the footing g a The eecti!e surcharge is reduced as the eecti!e weight below the

water table is eual

to the submerged unit.

Thereore

"Dwy 8ay/

'here Dw " depth o water table below the ground surace

a "height o water table abo!e the base o ooting

abo!e euation can be written as> substituting a "D #Dw>

"y/D 8 4y#y/)Dw

CASE II –Water table located at a depth !" belo! g b

I' !s "as% s&!( a3&% % 3as% & % &&!') !s 8&!s a'- 3%(&, 3as% 8ay 3% u((y &#

a#!a((y su38%#)%-. I % ,a%# a3(% !s a % 3as% %' % 3%a#!') "aa"!y %;ua!&' !s

,#!%' as/

@u( B "N" D N; $ N R :2 * >4?

I % ,a%# a3(% !s a a -% $ 3%(&, % "as% & % &&!') %' % 3%a#!') "aa"!y !s

'& a%"%- a'- '& "&##%"!&' !s #%;u!#%-. I % ,a%# a3(% !s a a' !'%#8%-!a% -% say

:2 3%(&, % 3as% & % &&!') ,%#% 0:2$ %' % 3%a#!') "aa"!y %;ua!&' !s

:#!%' as/

@u( B "N" D N; 1=2 :2 su3 >$ – :2?N

58a#7s



@u( B "N" D N; $ N R :2 * >9?

:%#% R :2 "a' 3% &3a!'%- #&8 % %;ua!&'/

:2 su3>$ – :2? B $ R :2

:2 su3= >$ – :2? B $R :2

:2 $ – :2 B $R :2

K:2 0.5$ B $R :2

$R :2 B 0.5>:2 $?

R :2 B 0.5>1 :2=$? * >5?

:%' % ,a%# a3(% a 3as% :2 B 0 a'- R :2 B 0.5 a'- ,%' :2 B $ R :2 B 1. T!s

8%a's ,%' ,a%# a3(% !s a 3as% % ,%!) %#8 !' % 3%a#!') "aa"!y %;ua!&' !s

#%-u"%- 3y a( a'- ,%' ,a%# a3(% a )#%a -% > !.%. )#%a%# a' ,!- & &u'-a!&'

3%(&, % 3as% & &u'-a!&'? ,a%# a3(% ,!(( a% '& !'(u%'"% !' % 3%a#!') "aa"!y.

@.19A rectangular ooting 4<m7m) e(erts a pressure o 5JJ G1%m7. Ln a

cohesi!e soil 4,s"95J G1%m7and 6".9) Determine the immediate

settlement at the centre> assuming a)the ooting is Be(ible b)the ooting

is rigid.

olution. i"3445#67)%,s)I

As +%3"<%7"5.9

I"5.<?

i"5JJ7445#.97

)%495J

))5.<?5J#<

".JFmm

b)&or rigid ooting4I"5.J?)

s"5.J?%5.<?.JF"<.5Fmm

58a#7s2

@.15Determine the ultimate bearing capacity o a suare ooting 7m7m in a

soil with unit weight o 5F ;1%m<> /"7JE>c"7J;1%m7.Ta;e the depth o

5.9Jm.Use *ansen/s euation

u " c1ccdcic 81 di 8 .9231yydyiy

1c"5.F< 1"?.Jand 1y"<.9c" 5.7 "5.7 and y".?

Dc"5 8J.<5.9%7.J"5.779

D"dc"5.779

Dy"5

As ic"i"iy"5

$u"7J5.F<5.75.7795845F5.9)?.5.75.7795

8.95F7<.9.?55

"H7F.79 G1%m7




$.E. >+ SEM? Ass!)'8%' *1

G%& T%" E')) II >CE*+01?

Date o$ Ass%&n/ Date o$ S'()%ss%[email protected] 'rite the eect o water table on bearing capacity 2019 5

@.2 A rectangular ooting 4<m7m) e(erts a pressure o 5JJ G1%m7. Ln a cohesi!e

soil 4,s"95J G1%m7and 6".9) Determine the immediate settlement at the

centre> assuming a)the ooting is Be(ible b)the ooting is rigid

7J5

5

@.4 Draw the diagram which show dierent type o shear ailure 5

@.9 Determine the ultimate bearing capacity o a strip ooting 5.7 m wide and

ha!ing the depth o oundation o 5 m .Use teraghi theory and assumegeneral shear ailure ta;e

/" <9E>2"5F G1%@<>and c/"59 G1%@<.

5

@.5 'rite the basic assumption in!ol!ed in teraghi/s euation 5




$.E. >+ SEM? MID SEM 1

G%& T%" E')) II >CE*+01?

Ma<!8u8 Ma#7s/ 20 M!'!8u8 Pass Ma#7s/ N&%/ A%8 a'y &u# ;u%s!&'s. A(( ;u%s!&'s "a##y %;ua( 8a#7s. T!8%/ 2 H#s

@.1

2019

5

@.2

7J5

5



@.4

5

@.9 Determine the ultimate bearing capacity o a strip ooting 5.7 m wide and

ha!ing the depth o oundation o 5 m .Use teraghi theory and assume

general shear ailure ta;e

/" <9E>2"5F G1%@<>and c/"59 G1%@<.

5

@.5 'rite the classifcation o settlement o oundation under loads 5

Geo Tech Engg II 8th Sem

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